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1. The number of parents who attended parent teacher conferences at a local elementary school is an example of what type of
variable?
Numerical variable
Categorical variable
Neither
ID: 1.2-8
2. The two-way table below shows the survey results when sixty adults were asked whether they had made a clothing
purchase in the last thirty days. Of the adult males surveyed, what percentage had made a clothing purchase in the last
thirty days?
Purchased clothing in the last thirty days
Had not purchased clothing in the last thirty days
Male
10
10
Female
29
11
A. 50%
B. 33%
C. 65%
D. 35%
ID: 1.3-7
*3. Identify the type of sampling used.
An education researcher randomly selects 25 of the nation's junior colleges and interviews all of the professors at each
school.
stratified
convenience
simple random
systematic
cluster
ID: 1.4-11
4. Indicate whether the study described is an observational study or a controlled experiment.
A group of cancer patients is divided into two groups. One group is given a new drug to fight the side effects of
chemotherapy and the other group is given a placebo. After three months, they are asked to respond to a questionnaire
about the frequency and severity of their side effects to see whether the new drug improved the overall negative side effects
of chemotherapy.
Observational study
Controlled experiment
ID: 1.4-4
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5. Researchers conducted a study and determined that students who participate in sports are happier than students who do
not. Can we conclude that participating in sports makes students happier?
A. No, this is an observational study and we cannot conclude causation.
B. Yes, this is an observational study and we can conclude causation.
C. Yes, this is an experiment and we can conclude causation.
D. No, this is an experiment and we cannot conclude causation.
ID: 1.4-16
6. A dot plot of the speeds of a sample of 50 cars passing a policeman with a radar gun is shown below. What proportion of
the motorists were driving above the posted speed limit of 55 miles per hour?
A. 0.50
B. 0.64
C. 0.14
D. 7.00
ID: 2.1-2-8
7.
The histogram shows the distribution of pitch speeds for a
sample of 75 pitches for a college pitcher during one season.
Which of the following statements best describes the
distribution of the histogram below?
A. The distribution is symmetric around a
pitch speed of about 93 mph.
B. The distribution is left-skewed and shows
that most of the pitches were less than
95 mph.
C. The distribution is right-skewed and
shows that most of the pitches were
more than 90 mph.
D. The distribution has a large amount of
variation which can be seen by
comparing the heights of the bars in the
histogram.
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8. What are two commonly used graphs to display the distribution of a sample of categorical data?
Choose the correct answer below.
Dotplots and bar graphs
Bar graph and stemplot
Bar graph and pie chart
Histograms and dotplots
ID: 2.3.RA-1
9. Two Physics classes at Jefferson High School took the same quiz. Mr. Spears had 20 students in his class with a mean
score of 80. Mrs. Guyton's class of 30 students had a mean score of 90. Overall, what was the mean score for all students
on the quiz?
A. 85
B. 84
C. 86
D. 87
ID: 3.1-13
10. Find the standard deviation for the given sample data. Round your answer to one more decimal place than is present in
the original data.
The top nine scores on the organic chemistry midterm are as follows.
72, 89, 87, 74, 28, 46, 53, 48, 73
A. 22.0
B. 20.6
C. 7.9
D. 19.4
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11. For the pair of accompanying histograms, determine which distribution has the larger standard deviation.
1
Click the icon to view the distributions.
A. (i) has a larger standard deviation than (ii).
B. (ii) has a larger standard deviation than (i).
C. Both histograms have the same standard deviation.
D. There is no way to determine which one is larger.
1: Distributions
ID: 3.1-19
12. Use the following information to answer the question. The mean age of lead actresses from the top ten grossing movies of
2010 was 29.6 years with a standard deviation of 6.35 years. Assume the distribution of the actresses' ages is
approximately unimodal and symmetric.
Between what two values would you expect to find about 95% of the lead actresses ages?
A. 16.9 and 42.3 years
B. 23.25 and 35.95 years
C. 10.55 and 48.65 years
D. None of these
ID: 3.2-1
13. Exam 1 scores have a mean of 500 and a standard deviation of 90, while exam 2 scores have a mean of 20 and a
standard deviation of 3. Assuming both types of scores have distributions that are unimodal and symmetric, which is more
unusual: an exam 1 score of 750 or an exam 2 score of 28?
Choose the correct answer below.
A. They are the same.
B. The exam 1 score is more unusual.
C. The exam 2 score is more unusual.
D. It cannot be determined which exam score is more unusual.
ID: CR.3.91
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14. Use the accompanying information to answer the question. Here is a table recording the number of deaths for the top
thirteen worst U.S. tornados since 1925. A histogram showing the distribution is also included. Estimate the most
appropriate measure of variability.
2
Click the icon to view the table and histogram.
A. IQR; 574
B. IQR; 156
C. Standard Deviation; 169.4
D. Standard Deviation; 178.5
2: Table of number of deaths and histogram of distribution
ID: 3.3-3
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15. Use the side-by-side boxplots below to answer the question. The boxplots summarize the number of sentenced prisoners
by state in the Midwest and West. Based on the boxplot for the West, which of the following is true?
3
Click the icon to view the side-by-side boxplots.
A. 50% of the states sentenced less than 15,706 prisoners.
B. 25% of the states sentenced less than 3,888 prisoners.
C. 25% of the states sentenced more than 15,706 prisoners.
D. 50% of the states sentenced less than 22,662 prisoners.
3: Side-by-side boxplots of sentences prisoners
ID: 3.5-4
16.
Doctors hypothesize that smoking cigarettes
inflames the bronchial tubes and so makes it
harder to breathe. They measured the lung
capacity (in liters) and the number of cigarettes
smoked in a typical day for a sample of adults.
Is the scatterplot to the right consistent with the
researcher's hypothesis?
A. Yes, it is consistent.
B. No, it contradicts this hypothesis.
C. There is no evidence in support or contradiction of the hypothesis.
ID: 4.1-6
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17. Three scatterplots are shown below. The calculated correlations are − 0.88, 0.00, and 0.68. Determine which correlation
goes with which scatterplot.
(a)
(b)
(c)
Match each scatterplot with its corresponding correlation.
(a) (1)
(b) (2)
(c) (3)
(1)
0.68
(2)
− 0.88
(3)
− 0.88
0.00
0.68
0.68
− 0.88
0.00
0.00
ID: 4.2.19
18. Use the following regression equation regarding professor salaries to answer the question.
Salary = 95000 + 1280 • (Years)
Note that Years is the number of years a professor has worked at a college, and Salary is the annual salary (in dollars) the
professor earns. Interpret the slope in the context of the data.
A. The slope is 95000. For every additional year a professor works at a college, his/her salary is
predicted to increase by $95,000.
B. The slope is 95000. If a professor has never worked at a college, his/her salary is expected
to be $95,000.
C. The slope is 1280. If a professor has never worked at a college, his/her salary is expected to
be $1,280.
D. The slope is 1280. For every additional year a professor works at a college, his/her salary is
predicted to increase by $1,280.
ID: 4.3-18
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19. The accompanying scatterplot shows the relationship between the ages of women when they first married and the ages
when they had their first child. The correlation coefficient between the values is 0.9315.
4
Click the icon to view the scatterplot.
The regression equation for the data is
Age − first child = 6.404 + 0.955 • (Age-married)
Can we use the regression equation to predict the age at which a woman has her first child for a woman who first married
at the age of 50?
A. No, we cannot make a prediction because the correlation coefficient does not equal 1.
B. Yes, we can always make predictions once we have a regression equation.
C. Yes, we can make a prediction because the scatterplot shows a strong positive linear
relationship.
D. No, we cannot make a prediction because a woman who marries at age 50 is outside the
range of our data. We would be extrapolating.
4: Scatterplot
ID: 4.4-12
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20. Use the following table to answer the question. A random sample of college students was asked to respond to a survey
about how they spend their free time on weekends. One question, summarized in the table below, asked each respondent
to choose the one activity that they are most likely to participate in on a Saturday morning. The activity choices were
homework, housework, outside employment, recreation, or other.
If one student is randomly chosen from the group, what is the probability that the student is female?
A. 0.50
B. 0.52
C. 0.48
D. None of these
ID: 5.2-3
21. A university conducted a survey of 277 Sophomore, Junior, and Senior undergraduate students regarding satisfaction with
student government. Results of the survey are shown in the table by class rank.
Sophomore
Junior
Senior
Total
Satisfied
51
61
60
172
Neutral
15
17
12
44
Not satisfied
20
15
26
61
Total
86
93
98
277
A survey participant is selected at random. What is the probability that he or she is a Junior or Senior?
The probability that a student is a Junior or a Senior is
(Round to three decimal places as needed.)
.
ID: CR.5.111
22. Use the following table to answer the question. A random sample of college students was asked to respond to a survey
about how they spend their free time on weekends. One question, summarized in the table below, asked each respondent
to choose the one activity that they are most likely to participate in on a Saturday morning. The activity choices were
homework, housework, outside employment, recreation, or other.
What is the probability that a female college student from the group chose "housework" as their most likely activity on
Saturday mornings? Round to three decimal places.
A. 0.531
B. 0.163
C. 0.520
D. None of these
ID: 5.3-1
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23. Suppose that a recent poll of American households about car ownership found that for households with a car, 39% owned
a sedan, 33% owned a van, and 7% owned a sports car. Suppose that three households are selected randomly and with
replacement.
What is the probability that none of the three randomly selected households own a van? (Round to the nearest
thousandth)
A. 0.699
B. 0.036
C. 0.060
D. 0.301
ID: 5.3-9
24. Determine whether the variable would best be modeled as continuous or discrete.
The number of cups dispensed from a beverage vending machine during a 24-hour period.
Continuous
Discrete
ID: 6.1-2
*25. A random number generator is set to generate single digits between 0 and 9. One hundred fifty random numbers are
generated. The probability distribution for this random number generator is given below. What is the mean of this
distribution? Round to the nearest tenth.
x
P(x)
0
0.09
1
0.12
2
0.11
3
0.08
4
0.09
5
0.13
6
0.10
7
0.07
8
0.10
9
0.11
7
6.6
5
4.5
ID: 6.1-18
26. Suppose that the probability that a person books a hotel using an online travel website is 0.68. For the question that
follows, consider a sample of fifteen randomly selected people who recently booked a hotel.
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What is the probability that at least fourteen out of fifteen people used an online travel website when they booked their
hotel? Round to three decimal places.
A. 0.323
B. 0.028
C. 0.978
D. 0.022
ID: 6.3-13
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27. The length of time it takes college students to find a parking spot in the library parking lot follows a normal distribution with
a mean of 3 minutes and a standard deviation of 1 minute. Find the probability that a randomly selected college student
will take between 1.5 and 4 minutes to find a parking spot in the library lot. Round to four decimal places.
A. 0.7745
B. 0.4938
C. 0.2255
D. 0.0919
ID: 6.2-25
28. The average travel time to work for a person living and working in Kokomo, Indiana is 17 minutes. Suppose the standard
deviation of travel time to work is 4.5 minutes and the distribution of travel time is approximately normally distributed.
Approximately what percentage of people living and working in Kokomo have a travel time to work that is less than 15.5
minutes? Round to the nearest whole percent.
A. 37%
B. 63%
C. 25%
D. None of these.
ID: 6.2-19
29. The amount of rainfall in January in a certain city is normally distributed with a mean of 3.6 inches and a standard
deviation of 0.6 inches. Find the value of the 25th percentile, rounded to the nearest tenth.
A. 3.4
B. 4.0
C. 0.9
D. 3.2
ID: 6.2-36
30. A magazine publisher mails a survey to every subscriber asking about the timeliness of its subscription service. The
publisher finds that only 6% of the subscribers responded. This 6% represents what?
The population
The sample
ID: 7.1-7
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31. A researcher is interested in knowing how many students of a particular college would be interested in having a sandwich
shop open within a block of campus. She surveys 300 students on campus at different times of day by asking students
randomly if they would answer a few questions. She receives a response from 35. Of those who responded, 65% favored
having a sandwich shop within a block of campus. This scenario describes sampling bias. Which statement most
accurately describes the bias?
I. The researcher asked only one question which results in bias.
II. The students voluntarily responded which could result in bias.
III. Not enough students responded which can result in bias.
A. II only
B. III only
C. I only
D. both II and III
ID: 7.1-16
32. A group of battery powered toys produced in a day at a factory has a defect rate of 0.5%. Suppose a quality inspector
randomly inspects 200 of the toys. Complete the following statement: The quality inspector should expect ____defective
toys, with an error of ____.
A. 1; 0.5%
B. 1; 5%
C. 10; 0.5%
D. 10; 5%
ID: 7.2-15
33. A pollotarian is a person who eats poultry but no red meat. A wedding planner does some research and finds that
approximately 3.5% of the people in the area where a large wedding is to be held are pollotarian. Treat the 300 guests
expected at the wedding as a simple random sample from the local population of about 200,000.
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Suppose the wedding planner assumes that 5% of the guests will be pollotarian so she orders 15 pollotarian meals. What
is the approximate probability that more than 5% of the guests are pollotarian and therefore she will not have enough
pollotarian meals? Round to four decimal places.
A. 0.421
B. 0.079
C. 0.489
D. None of these
ID: 7.3-3
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34. In a recent poll of 1200 randomly selected adult office workers, 32% said they had worn a Halloween costume to the office
at least once.
Report the 95% confidence interval for the proportion of all adult office workers who have worn a Halloween costume to
the office at least once. Round final calculations to the nearest tenth of a percent.
A. (30.7%, 33.4%)
B. (28.0%, 36.1%)
C. (29.4%, 34.6%)
D. None of these
ID: 7.4-3
35. A random sample of 830 adult television viewers showed that 52% planned to watch sporting event X. The margin of error
is 3 percentage points with a 95% confidence. Does the confidence interval support the claim that the majority of adult
television viewers plan to watch sporting event X? Why?
A. No; the confidence interval means that we are 95% confident that the population proportion
of adult television viewers who plan to watch sporting event X is between 50.5% and 53.5%.
The lower limit of the confidence interval is just too close to 50% to say for sure.
B. Yes; the confidence interval means that we are 95% confident that the population proportion
of adult television viewers who plan to watch sporting event X is between 49% and 55%.
Since the confidence interval is mostly above 50% it is likely that the true proportion is
greater than 50%.
C. No; the confidence interval means that we are 95% confident that the population proportion
of adult television viewers who plan to watch sporting event X is between 49% and 55%. The
true proportion could be less than 50%.
D. Yes; the confidence interval means that we are 95% confident that the population proportion
of adult television viewers who plan to watch sporting event X is between 50.5% and 53.5%.
This is strong evidence that the true proportion is greater than 50%
ID: 7.4-5
36. In hypothesis testing, the null hypothesis is best described by which of the following statements?
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Choose the correct answer below.
A. The null hypothesis always gets the benefit of the doubt and is assumed to be true
throughout the hypothesis testing procedure.
B. The null hypothesis is always assumed to be false throughout the hypothesis testing
procedure.
C. The null hypothesis can be chosen by a computer.
D. Both A and C are correct
ID: 8.1.RA-3
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37. Read the following problem description then choose the correct null and alternative hypothesis. A new drug is being tested
to see whether it can reduce the rate of asthma attacks in children ages 5 to 14. The rate of asthma attacks in the
population of concern is 0.0744.
A. H0 : p = 0.0744; Ha : p < 0.0744
B. H0 : p > 0.0744; Ha : p ≠ 0.0744
C. H0 : p < 0.0744; Ha : p < 0.0744
D. H0 : p = 0.0744; Ha : p > 0.0744
ID: 8.1-1
38. A janitor at a large office building believes that his supply of light bulbs has too many defective bulbs. The janitor's null
hypothesis is that the supply of light bulbs has a defect rate of p = 0.07 (the light bulb manufacturer's stated defect rate).
Suppose he does a hypothesis test with a significance level of 0.05. He randomly selects 300 light bulbs and finds 27 that
are defective. Symbolically, the null and alternative hypothesis are as follows
H0 : p = 0.07 and Ha : p > 0.07.
The janitor calculates a p-value for the hypothesis test of approximately 0.087. Choose the correct interpretation for the
p-value.
A. The p-value tells us that if the defect rate is 0.07, then the probability that the janitor will have
27 or more defective light bulbs out of 300 is approximately 0.087. At a significance level of
0.05, this would not be an unusual outcome.
B. The p-value tells us that the probability of concluding that the defect rate is equal to 0.07,
when in fact it is greater than 0.07, is approximately 0.087.
C. The p-value tells us that the true population rate of defective light bulbs is approximately
0.087.
D. None of these
ID: Instructor-created question
39. A researcher conducts a hypothesis test on a population proportion. Her null and alternative hypothesis are
H0 : p = 0.6 and Ha : p < 0.6 . The test statistic and p-value for the test are z = − 1.51 and p value = 0.0655. For a
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significance level of
= 0.05, choose the correct conclusion regarding the null hypothesis.
A. There is insufficient evidence to reject the null hypothesis that the population proportion is
equal to 0.6.
B. There is insufficient evident to determine the significance.
C. There is sufficient evidence to accept the null hypothesis that the population proportion is
equal to 0.6.
D. There is sufficient evidence to conclude that the population proportion is significantly different
from 0.6.
ID: 8.3-10
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40. In a poll of 500 adults in July 2010, 280 of those polled said that schools should ban sugary snacks and soft drinks.
Complete parts a and b below.
a. Do a majority of adults (more than 50%) support a ban on sugary snacks and soft drinks? Perform a hypothesis test
using a significance level of 0.05.
State the null and alternative hypotheses. Note that p is defined as the population proportion of people who believe
that schools should ban sugary foods.
A. H0 : p = 0.50
Ha : p ≠ 0.50
B. H0 : p < 0.50
Ha : p > 0.50
C. H0 : p = 0.50
Ha : p > 0.50
D. H0 : p = 0.56
Ha : p > 0.56
Find the value of the test statistic z.
z=
(Round to two decimal places as needed.)
Find the value of the corresponding p-value for this test statistic z.
p-value =
(Round to three decimal places as needed.)
Do you reject or not reject the null hypothesis?
Reject H0 .
Do not reject H0 .
b. Choose the best interpretation of the results you obtained in part a.
A. The percentage of all adults who favor banning is significantly more than 50%.
B. The percentage of all adults who favor banning is not significantly more than 50%.
ID: 8.2.36
41. A sprint duathlon consists of a 5 km run, a 20 km bike ride, followed by another 5 km run. The mean finish time of all
participants in a recent large duathlon was 1.67 hours with a standard deviation of 0.25 hours. Suppose a random sample
of 30 participants in the 40-44 age group was taken and the mean finishing time was found to be 1.62 hours with a
standard deviation of 0.40 hours.
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Suppose we were to make a histogram of the finishing times of the 30 participants in the 40-44 age group. Would the
histogram be a display of the population distribution, the distribution of a sample, or the sampling distribution of means?
A. sampling distribution of means
B. distribution of a sample
C. population distribution
ID: 9.1-6
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42. Feature movie lengths (in hours) were measured for all movies shown in the past year in the U.S. The mean length of all
feature length movies shown was 1.80 hours with a standard deviation of 0.15 hours. Suppose the length of a random
sample of 20 movies was recorded from all movies released this year. The mean length of the feature length movies was
found to be 1.72 hours with a standard deviation of 0.18 hours.
What is the standard error for the estimated mean feature length movie time of the 20 randomly selected movies? Round
to the nearest thousandth.
A. 0.034
B. 0.356
C. 0.040
D. 0.055
ID: 9.1-12
43. Fill in the blank.
A useful estimator for the population mean is the _______.
A useful estimator for the population mean is the (1)
(1)
population proportion.
sample size.
sample mean.
population standard deviation.
ID: 9.1.RA-1
44. What can a confidence level of a confidence interval be thought of as?
Choose the correct answer below.
A. The probability that the confidence interval includes the parameter
B. The "job performance" of the confidence interval
C. The width of the confidence interval
D. The margin of error of the confidence interval
ID: 9.3.RA-2
45. The weights at birth of five randomly chosen baby Orca whales were 425, 454, 380, 405, and 426 pounds. Assume the
distribution of weights is normally distributed. Find a 95% confidence interval for the mean weight of all baby Orca whales.
Use technology for your calculations. Give the confidence interval in the form "estimate ± margin of error". Round to the
nearest tenth of a pound.
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A. There is not enough information given to calculate the confidence interval.
B. 384.0 ± 68.0 pounds
C. 418.0 ± 34.5 pounds
D. 418.0 ± 34.1 pounds
ID: 9.3-14
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46. Many couples believe that it is getting too expensive to host an "average" wedding in the United States. According to the
website www.costofwedding.com, the average cost of a wedding in the U.S. in 2009 was $24,066. Recently, in a random
sample of 40 weddings in the U.S. it was found that the average cost of a wedding was $23,224, with a standard deviation
of $2,903. On the basis of this, a 95% confidence interval for the mean cost of weddings in the U.S. is $22,296 to $24,152.
Does the confidence interval provide evidence that the mean cost of a wedding has decreased?
No
Yes
ID: 9.3-2
47. According to the website www.costofwedding.com, the average cost of flowers for a wedding is $698. Recently, in a
random sample of 40 weddings in the U. S. it was found that the average cost of the flowers was $734, with a standard
deviation of $102. On the basis of this, a 95% confidence interval for the mean cost of flowers for a wedding is $701 to
$767.
Choose the statement that is the best interpretation of the confidence interval.
I. That probability that the flowers at a wedding will cost more than $698 is greater than 5%.
II. In about 95% of all samples of size 40, the resulting confidence interval will contain the mean cost of flowers at
weddings.
III. We are extremely confident that the mean cost of flowers at a wedding is between $701 and $767.
A. III only
B. II and III are both correct.
C. II only
D. I only
ID: 9.3-13
48. Which of the following is measured by the test statistic?
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Choose the correct answer below.
A. How far away the observed mean lies from the hypothesized value of the sample mean.
B. The probability that the hypothesized mean is correct.
C. How far away the observed mean lies from the true population mean.
D. The level of confidence one has in our conclusion.
ID: 9.4.RA-2
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49. An economist conducted a hypothesis test to test the claim that the average cost of eating a meal away from home
decreased from 2009 to 2010. The average cost of eating a meal away from home in 2009 was $7.15 per person per
meal. Assume that all conditions for testing have been met. He used technology to complete the hypothesis test. Following
is his null and alternative hypothesis and the output from his graphing calculator. Choose the statement that contains the
correct conclusion regarding the hypothesis and the original claim.
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5
Click the icon to view the hypotheses and graphing calculator output.
A. Reject the null hypothesis; there is not sufficient evidence to support the claim that the
average cost of eating away from home has decreased since 2009.
B. Fail to reject the null hypothesis; there is sufficient evidence to support the claim that the
average cost of eating away from home has decreased since 2009.
C. Reject the null hypothesis; there is sufficient evidence to support the claim that the average
cost of eating away from home has decreased since 2009.
D. Fail to reject the null hypothesis; there is not sufficient evidence to support the claim that the
average cost of eating away from home has decreased since 2009.
5: Hypothesis and graphing calculator output
H0 :
= $7.15
Ha :
< $7.15
ID: 9.4-3
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50. The following numbers are the differences in pulse rate (beats per minute) before and after running for 12 randomly
selected people. Positive numbers mean the pulse rate went up. Test the hypothesis that the mean difference in pulse rate
was more than 0, using a significance level of 0.05. Assume the population distribution is Normal.
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23, 13, 10, 10, 14, 9, 0, 2, 10, 41, 0, and 15
Determine the null and alternative hypotheses. Choose the correct answer below.
A. H0 :
Ha :
=0
=0
<0
B. H0 :
Ha :
>0
>0
C. H0 :
Ha :
D. H0 :
≠0
Ha :
=0
E. H0 :
<0
F. H0 :
=0
Ha :
≥0
Ha :
≠0
≤0
The test statistic is
.
(Round to two decimal places as needed.)
The p-value is
.
(Round to three decimal places as needed.)
Interpret the results of the test.
Since the p-value is (1)
(3)
of 0.05.
(1)
the significance level, (2)
H0 . There is
evidence to conclude that the population mean is more than 0 beats per minute at a significance level
less than or equal to
greater than
(2)
reject
do not reject
(3)
sufficient
insufficient
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1. Numerical variable
2. A. 50%
3. cluster
4. Controlled experiment
5. A. No, this is an observational study and we cannot conclude causation.
6. A. 0.50
7. A. The distribution is symmetric around a pitch speed of about 93 mph.
8. Bar graph and pie chart
9. C. 86
10. B. 20.6
11. A. (i) has a larger standard deviation than (ii).
12. A. 16.9 and 42.3 years
13. B. The exam 1 score is more unusual.
14. B. IQR; 156
15. C. 25% of the states sentenced more than 15,706 prisoners.
16. A. Yes, it is consistent.
17. (1) 0.00
(2) 0.68
(3) − 0.88
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18. D.
The slope is 1280. For every additional year a professor works at a college, his/her salary is predicted to increase by
$1,280.
19. D.
No, we cannot make a prediction because a woman who marries at age 50 is outside the range of our data. We would be
extrapolating.
20. B. 0.52
21. 0.690
22. B. 0.163
23. D. 0.301
24. Discrete
25. 4.5
26. D. 0.022
27. A. 0.7745
28. A. 37%
29. D. 3.2
30. The sample
31. D. both II and III
32. A. 1; 0.5%
33. B. 0.079
34. C. (29.4%, 34.6%)
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35. C.
No; the confidence interval means that we are 95% confident that the population proportion of adult television viewers
who plan to watch sporting event X is between 49% and 55%. The true proportion could be less than 50%.
36. A.
The null hypothesis always gets the benefit of the doubt and is assumed to be true throughout the hypothesis testing
procedure.
37. A. H0 : p = 0.0744; Ha : p < 0.0744
38. A.
The p-value tells us that if the defect rate is 0.07, then the probability that the janitor will have 27 or more defective light
bulbs out of 300 is approximately 0.087. At a significance level of 0.05, this would not be an unusual outcome.
39. A. There is insufficient evidence to reject the null hypothesis that the population proportion is equal to 0.6.
40. C. H0 : p = 0.50Ha : p > 0.50
2.68
0.004
Reject H0 .
A. The percentage of all adults who favor banning is significantly more than 50%.
41. B. distribution of a sample
42. A. 0.034
43. (1) sample mean.
44. B. The "job performance" of the confidence interval
45. D. 418.0 ± 34.1 pounds
46. No
47. B. II and III are both correct.
48. A. How far away the observed mean lies from the hypothesized value of the sample mean.
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49. D.
Fail to reject the null hypothesis; there is not sufficient evidence to support the claim that the average cost of eating away
from home has decreased since 2009.
50. B. H0 :
= 0Ha :
>0
3.78
0.002
(1) less than or equal to
(2) reject
(3) sufficient
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