POLAR ZENITHAL MAP Part 1 PROJECTIONS Five basic projections by Keith Selkirk, School of Education, University of Nottingham Map projections used to be studied as part of the geography syllabus, but have disappeared from it in recent years. They provide some excellent practical work in trigonometry and calculus, and deserve to be more widely studied for this alone. In addition, at a time when world-wide travel is becoming increasingly common, it is unfortunate that few people are aware of the effects of map projections upon the resulting maps, particularly in the polar regions. In the first of these articles we shall study five basic types of projection and in the second we shall look at some of the mathematics which can be developed from them. The zenithal and cylindrical projections are limiting cases of Polar Zenithal Projections the conical projection. This is illustrated in Figure 1. The A football cannot be wrapped in a piece of paper without either stretching or creasing the paper. This is what we mean when semi-vertical angle of a cone is the angle between its axis and a we say that the surface of a sphere is not developable into a plane. As a result, any plane map of a sphere must contain distortion; the way in which this distortion takes place is determined by the map projection. There are three fundamental types of projection, the zenithal, the conical, and the cylindrical. In the first of these, the map is regarded as part of a plane, in the second as part of a cone and in the third as part of a cylinder. In the latter two cases the cone and the cylinder are unrolled straight line on its surface through its vertex. Figure l(b) and (c) shows cones of semi-vertical angles 600 and 300 respectively resting on a sphere. If the semi-vertical angle is increased to 900, the cone becomes a disc as in Figure l(a) and this is the zenithal case. If the semi-vertical angle decreases, the vertex moves and laid flat, these two surfaces, unlike the sphere's surface towards the top of the diagram and in the limit, when it tends to infinity, the cone tends to a cylinder as in Figure 1(d). Because they start with a plane, the zenithal projections are easier to visualise, and we shall restrict ourselves to them, even though they are less common in practice than the other types. being developable into planes. The point where the plane touches the sphere is called the Fig. 1 The conical projection and its limiting cases. 300 600o (a) Zenithal 2 (b) Conical (c) Conical (semi-vertical angle 600) (semi-vertical angle 300) Mathematics in School, (d) Cylindrical March 1982 zenith, and this point may be anywhere on the sphere. There is no fundamental difference in the projection wherever the zenith is, but because of the way in which we define position on the surface of the earth by means of latitude and longitude, the case where the zenith is at a pole is the easiest to study from show that NSQ= 1/2 (900 - 0), whence NQ= 2R tan /2 (900 -0). The important advantage of the stereographic projection is that it is shape-preserving or orthomorphic. Although the scale is not constant, the shape at any point is correct because the distortion is the same in all directions. We shall show why this is the case in the second article. a mathematical point of view. These are the polar zenithal projections we shall examine below. The Gnomonic Projection The Orthographic Projection In the gnomonic projection the map may be considered as a plane touching the earth at the north pole. A light at the centre of the earth then casts a shadow of the earth's surface on the If the light source is now removed a long way off so that a parallel beam of light is produced, then Figure 4 is the result. In this figure K is the foot of the perpendicular from P onto the equatorial plane. In this diagram plane map. Thus the word projection may be used literally, and this is illustrated in the lower half of Figure 2. This shows a cross-section through the earth and the map, the centre of the earth being labelled O and the north pole N. The point P is a NQ=R cos 0. typical point in the northern hemisphere with latitude 0 The orthographic projection gives a view of the earth as seen from outer space. The projection would be a suitable one to (measured in degrees). The point P maps or projects onto the point Q of the map. The upper part of the figure shows the map itself with the pole N and the circle of latitude for P. If R is the radius of the earth, then use when mapping the visible surface of the moon for earthbound astronomers. The Equidistant Projection NQ=R cot 0 The above three projections are called perspective projections since they are views of the northern hemisphere when seen from particular points, namely the centre of the earth, the south pole and an infinitely distant point in a southerly direction respectively. (In fact we are in these cases viewing the map On the map, therefore, the radius of the circle of latitude 0 will be R cot 0. (In practice this will be reduced by the scale of the map, but we can ignore this for these articles, and imagine the map drawn at full scale.) The gnomonic projection has some grave disadvantages as from behind.) The last two projections do not have this we shall see, but it has one outstanding advantage. The shortest distance between any two points on the surface of the earth is an arc of a circle on the surface whose centre is at the centre property and are therefore known as conventional projections. The equidistant projection is designed in such a way that distances measured from the zenith are correct. This means of the earth. This is called a great circle to distinguish it from smaller circles which may also be drawn on the earth's surface that the concentric circles forming the circles of latitude on the such as circles of latitude. Since the projection is from the map have their radii equally spaced. This makes it a very centre of the earth which is the centre of all great circles, any natural map to use, since this is the most obvious way to draw the basic grid of the map. In Figure 5 it means that given great circle will have a shadow which is a plane, and which must intersect the plane of the map in a straight line. Thus great circles project into straight lines on the map, and any straight line on the map is the projection of a great circle. The gnomonic projection is therefore of great use in navigation since it makes it easier to plan the shortest route on the surface of the earth. We shall return to this point in the second article. NQ=arc NP _ (900 - 0) 2tnR 3600 This property makes it suitable for use in cases where distances from the zenith need to be compared, remembering that the zenith can be placed anywhere we wish. The Stereographic Projection The Equal Area Projection If the light (or centre of projection) is placed at the south pole, S, Figure 2 changes to Figure 3 and the stereographic projection is obtained. To determine NQ in this case, we must first In the equal area projection, equal areas on the earth correspond, as might be expected, to equal areas on the map. Fig. 2 Polar zenithal Fig. 3 Polar zenithal gnomonic projection. Fig. 4 Polar zenithal stereographic projection. orthographic projection. N 0 N ao N A N N x o N x ---- p X x N Fig. 6 Polar zenithal equal area projection. N 0Q i N NcN 0 Q Fig. 5 Polar zenithal equidistant projection. a/ p 0 il '0 Xt p 0 0 0 K 0 0 Mathematics in School, March 1982 3 Figure 6 illustrates this as far as is possible on a plane diagram. The crux of the matter is that for all points P, the area of the spherical "cap" of the earth bounded by the circle of latitude on which P lies must equal the area of the circle of radius NQ on the map, where Q is the point onto which P projects. The cap is indicated by the shaded area of Figure 6; clearly because of the curvature of the earth, the radius XP of its bounding circle is less than NQ. The area of the cap is impossible to find without the use of the integral calculus, or some method such as the Greeks used which effectively assumes the methods of the integral calculus. The result is, however, comparatively well known and rather surprising. It states that the area of the cap is equal to the area of the curved surface of the cylinder of radius R and height XN. Thus the area of the cap is 27tR .XN (The same result for the whole sphere shows that the surface area of the sphere is 4itR2 and is illustrated in the crest of the Mathematical Association.) Now XN= R(1 - sin 0) Hence 7tNQ2= 2r R2 (1 - sin 0) and NQ=R,2 (1--sin 0) This type of projection is of great importance and should be used whenever symbols are used to indicate the density of a feature on the earth's surface. If this is not done, a very misleading impression of the relative densities in different parts of the map may be given. Getting the answer wrong by Lesley R. Booth, SESM Project, Chelsea College Teachers are quite used to the idea that children sometimes get mathematics questions wrong. Sometimes the wrong answer is due to a "careless" mistake which is easily corrected; often however, the teacher feels that the error is symptomatic of some and-pencil tests of understanding in different topic areas, such as ratio, generalised arithmetic, measurement, fractions, graphs and so on. Examples of the kinds of wrong answer which were found are shown in Figure 1. misunderstanding on the part of the child. If only we could find out why the child had made that error, we might be able to help the child restructure his or her concept of the problem, and so avoid the error. Unfortunately, teachers usually don't have time to diagnose every child's mistakes in this way. Nor, of course, do research workers, but they may have a chance of studying "common errors" - particular wrong programme, it was possible to suggest reasons why these particular errors may have occurred. In essence it was suggested that many of these errors might be due to children's use of intuitive "child-methods" which are answers which are made by large numbers of children. This is the task which the Strategies and Errors in Secondary perfectly adequate for handling "easy" problems, but which do not generalise to harder questions, where success really Mathematics (SESM) Project1 has set itself. Funded by the Social Science Research Council and based at Chelsea College, this project aims to investigate particular mathematical errors identified by the earlier Concepts in Secondary Mathematics and Science (CSMS) Project2'34,"5. The errors chosen for study were those which were made by a large proportion (in some cases 50% or more) of the children tested by CSMS on paperPercentage CSMS item "Error" giving (abridged) answer answer (13 year olds) 2+3 7 4 5 30 11 Add 4 onto 3n 3n4, 7n 45 By carefully examining these wrong answers, and the responses which children had given when asked about their answers in interviews conducted as part of the CSMS test development requires the use of the "proper" mathematical methods taught in the classroom6,7. In addition, of course, it was thought highly likely that there would be specific kinds of misconception associated with the different areas of mathematics - algebra8, number""., fractions", and so on. Consequently, the SESM Project set out to examine these ideas by interviewing individual children on relevant problems, in order to discover precisely which kinds of misunderstanding contribute most to the particular errors under study. While the results of this (still continuing) examination seem to support the notion that children often do have their own methods which break down when the questions get harder, the investigation into children's work on beginning algebra, or "generalised arithmetic", has also revealed another source of error. It seems that in this topic at least, some of the mistakes which children make are due not to their misinterpretation of the question or their ideas of what letters mean, nor to the methods which they use to solve the problem, but rather to their misconceptions concerning the way in which the answer Percentage CSMS "Error" giving Perimeter s s 2u556, 2ul 6 46 item answer answer (13 year olds) 6 c C and D are 48 LD I 1 same length 912 13 1. What can you write for 5e2, e 10, 10e, 42 the area of this e + 10 rectangle: 44 21 I e I Fig. 1 4 21 Fig. 2 Mathematics in School, March 1982
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