Gases Worksheet #1
25
Convert (1 point)
1. 72.9 cm Hg = _?_ kPa
7J,,·Oj em H~)C
IO'M(!11-\-:>
1<
I eM I+~
2..980' atm = _?_ mm Hg
5. \ eL-h'v\)(
101. '3lt.-f.-
.:: 6~O ~ p~
1A.-tW'-
Complete - include given, formula, setup, answer, sig. figs and units (3 pts)
4. The pressure on a 6.24 L sample of gas is increased from 1.04 atm to 2.18 atm. What will be the new volume of the gas (at constant temperature)? Law? e,o,/ \e 's VI ~ (P.lL!- L
V-z.:: ~,v I :; ( 1. oy ~:tl'Y\ ) (~. 2."1 L)
'1
.:.2.
ct
B
L
Pi
f
2. l8Cl.1v
Vr.~
~
P2, 0:; J.I SA.fn....
5. What pressure (in atmospheres) is required to compress 1.00 L of gas at 768 mm Hg pressure to a volume of 50.0 mL? Law?
~oy I.e's 'P,V,
P 2 _- ---'-
Vj::.\.OOL. p, ::: 7hSMM \i~,
Vz. = -So. 0", L."
p-z
,
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O.0500L.
Pa. : ?
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r:
::. 01O. 3&\.oh-] - '
6. If a 25.0 mL sample of nitrogen gas at 26.2 °C is cooled to 15.4 oC, what is
the new volume of the gas? Law? CnM\.e s' VI :~.OMl,.., :; Z (p • z. °C
T...
0::
v~::
-t 2.., ~ ;.
2't"1. 2. \l.
V,I%.
V] -. -
-r.
_ (Z5.0P'\L.) (Z58.4-IL)
Zqq . Z. \L ,tS.Y°C,+2''3 :: 268. LI '"
?
7. To what temperature must 500. mL of gas at 22 °C be cooled, at constant pressure, so that the volume of the gas is reduced to 1.00 mL? Law? Ch;\f\ t' S ' VI
V.,..
--,-, =--
-r""
O(
,;2. O~"'hIr 'IOU conved
1>,
f)(~
+
8. If 0.214 mol of argon gas occupies a volume of 652 mL at a particular
temperature and pressure, how many moles would 1.145 L argon occupy
under the same conditions? Law? 1}yD~,-,-r=D""",s_ _
V I:: {QS2..M\...K~
V2- ::-;.~Q'5l..
.l.
~ -:;!:l:-I).t,'52.t..~~J.~&4SL._
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.~5ZL O.37(.p(Y\.OII
"'9.'2. If- 0.500
. mol of nitrogen gas occupies a volume of 11.2 L at 0 oC,_
what volume will 2.00 mol of nitrogen occupy under the same conditions? Law? AVDOa.qlO) 's n. -.: O.60~1
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~ _~
r\,
\
\.z.\.... VI::
-
II. 2 !,...
Y"\z.
..-
b.S~\
~
V~~) =(Z.w,...01 ) (II.Z..L.)
t
2.00m.o l
z.. 001\'1...0'
('\ a. :;
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O.~OO"".\
7
v,. :: ? v.. : . 1/'1. tJ L ,
10.A container filled with helium gas has a pressure of 127.5 kPa a a temperature of 290. K. What is the temperature when the pressure is 3.51 kPa? Law? GAy - LIltSSAC .~ T2.~= (2.IfO. It:)(a.,"I~)
P I ~ I 2./. 5" ~ Po..
- PI
_ .1z
'I:;
-.,z
.~_
127.S'J4.t'A....
-.
:: 3.51 Ilf_
T ~ p~
1:
z.qo.J{.
1
11.The pressure in a car tire is 2.50 atmat a temperature of 33°C. What would the pressure be if the tire were allowed to cool to O°C? Assume that the tire does not change volume. Law? (jay - Lt.cs.s~c. 's
.
PI;::2.501l.4N'~ 33·C.'" 2."7~ ;:
-r.
.
~
P.
~,,\<-
p~
T, .. ~
pa.=iz.'P•.
(Z73~)(2.60(A-\,i'YI)
-r,:; 30CPk!.
J
=p ..23«f~
:: ~
i ... ::
o·c + 213 ::
2'73 "
12.A scientist has a sample of gas that was collected several days earlier. The sample has a volume of 392 cm 3 at a pressure of 0.987 atm and a temperature of 21°c' On the day the gas was collected, the temperature was 13°C and the pressure was 0.992 atm. What volume did the gas have on the day it was collected? Law? COm.b'o.t. qL VI: Yi\2cl'Y'~
~ .. "2V~
'P1::O.qB1A~
,.
V~:. V.v,la. ;:: (o.~~n~)(31z(tv\')(2.3<P")
-r~
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i l : 2t\L\'I(.S Z\'t..t-Z,3
,..:& = Ia·c "z'n::; Z s(' 'f'..
p,. " O.'lq-l~
V,:: ~
13. A gas sample oc.cupi~s 3.25 liters at 24.5 °c and 1825 mm Hg. Determine the
temperature at which the gas will occupy 4250 mL at 1.50 atm.
Law? Com..\oi~
],vJ,._ f~v'!:... (Z:t.tot-iAt".)(~.2-tOL.~04tm){4':ZSL..)
pz: J.5o(irb-.
IJ, : ?
VI:: 3. '2-'5 1-
II":.
'PI::
1"'1
2't· 5 'C.-t213:= 2~1.'5'f'..
lS1.SmMHj)(.
V,.": Lf250WVIt..x
1) 97.2 kPa
4) 2.98 L
~:tM~ = 2.1401 A--k-
IlL
&..:;
"'.1.'51.. 2) 745 mmHg
5) 20.3 atm
'IL.
let7. 5 K
,/ -
T~
1a.~~ -:: (z"'."\(..HI.5Ds,....,...,)(q·Z,S'L')
L~')(~
l2.·L\OI~)(3.Z.~L ~
'1'3.: Z4o~
3) 3900 torr; 520 kPa
(P /J) 24.1 mL
7 ~) 9.S99K--
o. '5'10 K..
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