Evaluate: Homework and Practice EVALUATE • Online Homework • Hints and Help • Extra Practice Factor the polynomial, or identify it as irreducible. 1. x 3 + x 2 - 12x 2. x(x + x - 12) 2 x3 + 5 Irreducible. x(x + 4)(x - 3) 3. x 3 - 125 4. x = (1x) 3 125 = (5) ( 8x 3 + 125 125 = (5) 216x 3 + 64 8. 8(27x 3 + 8) 27x = (3x) 3 3 8 = (2) 2x 3 + 6x Example 1 Factoring Out the Greatest Common Monomial Factor First Exercises 1–2, 4, 6, 10–12 8x 3 - 64 Example 2 Recognizing Special Factoring Patterns Exercises 3, 5, 7–9 8(x - 2)(x 2 - 2x + 4) Example 3 Factoring by Grouping Exercises 13–18 Example 4 Solving a Real-World Problem by Factoring a Polynomial Exercises 19–22 2x(x 2 + 3) 8x 3 + 125 = (2x + 5)(4x 2 - 10x + 25) 8(x 3 - 8) 3 a 3 + b 3 = (a + b)(a 2 - ab + b 2) 216x 3 + 64 = 8(3x + 2)(9x 2 - 6x + 4) 10x 3 - 80 10. 2x 4 + 7x 3 + 5x 2 10(x - 8) x 2(2x 2 + 7x + 5) 3 x 3 = (1x) 3 8 = (2) 3 2 2 10x - 80 = 10(x - 2)(x 2 + 2x + 4) 11. x + 10x + 16x x (x + 1)(2x + 5) 2 12. x + 9769 2 x(x + 10x + 16) 3 2 ( ) x (x(2x + 5) + 1(2x + 5)) ) 2 3 3 ( x 2 (2x 2 + 5x) + (2x + 5) 3 a - b = (a - b)(a + ab + b 3 © Houghton Mifflin Harcourt Publishing Company 9. Irreducible. ) x (x + 2x) + (8x + 16) 2 x(x(x + 2) + 8(x + 2)) Practice Explore Analyzing a Visual Model for Polynomial Factorization 2x 3 + 6x 3 a 3 + b 3 = (a + b)(a 2 - ab + b 2) 7. Concepts and Skills x(x + 2)(x + 3) 6. 3 ) x(x(x + 2) + 3(x + 2)) x 3 - 125 = (x - 5)(x 2 + 5x + 25) 8x 3 = (2x) ASSIGNMENT GUIDE x (x 2 + 2x) + (3x + 6) 3 a 3 - b 3 = (a - b)(a 2 + ab + b 2) 5. x 3 + 5x 2 + 6x x(x 2 + 5x + 6) 3 INTEGRATE TECHNOLOGY Emphasize that students should use caution when checking answers on a graphing calculator. The calculator provides support that the answer is correct, but it cannot be used to prove correctness. x(x + 2)(x + 8) Module 6 Lesson 4 316 Exercise A2_MNLESE385894_U3M06L4.indd 316 Depth of Knowledge (D.O.K.) Mathematical Practices 1–18 1 Recall of Information MP.5 Using Tools 19–22 2 Skills/Concepts MP.4 Modeling 23 1 Recall of Information MP.2 Reasoning 24 1 Recall of Information MP.3 Logic 25–26 2 Skills/Concepts MP.3 Logic 27–29 3 Strategic Thinking MP.2 Reasoning 3/19/14 1:37 PM Factoring Polynomials 316 Factor the polynomial by grouping. AVOID COMMON ERRORS 13. x 3 + 8x 2 + 6x + 48 x (x + 8) + 6(x + 8) 14. x3 + 4x 2 - x - 4 x 2(x + 4) - 1(x + 4) 2 Students may not recognize that a polynomial can sometimes be factored if they regroup the terms. Give students a pattern they can follow to test if factoring by grouping applies to a polynomial: first, rearrange the terms so that when they are grouped, they will have common factors; group the terms; factor each group, using factoring patterns if necessary; then, rearrange and assemble the factors using the distributive property (x 2 + 6)(x + 8) 15. 8x + 8x + 27x + 27 4 3 (x 2 - 1)(x + 4) (x - 1)(x + 1)(x + 4) 16. 27x 4 + 54x 3 - 64x - 128 8x 3(x + 1) + 27(x + 1) 27x 3(x + 2) - 64(x + 2) (8x 3 + 27)(x + 1) (2x + 3)(4x 2 - 6x + 9)(x + 1) 17. x 3 + 2x 2 + 3x +6 x (x + 2) + 3(x + 2) (27x 3 - 64)(x + 2) (3x - 4)(9x 2 + 12x + 16)(x + 2) 18. 4x 4 - 4x 3 - x + 1 4x 4 - 4x 3 - x + 1 2 (x 2 + 3)(x + 2) INTEGRATE MATHEMATICAL PRACTICES Focus on Math Connections MP.1 After students have solved a polynomial 19. Engineering A new rectangular outbuilding for a farm is being designed. The outbuilding’s side and bottom should be 4 feet thick. Its outer length should be twice its outer width and height. What should the outer dimensions of the outbuilding be if it is to have a volume of 2304 cubic feet? 2304 = (2x − 8)(x − 8)(x − 4) 2304 = 2x 3 - 32x 2 + 160x - 256 0 = 2x 3 - 32x 2 + 160x - 2560 0 = 2x 2(x - 16) + 160(x - 16) 0 = 2(x 2 + 80)(x - 16) The only real solution is x = 16. The outbuilding is 32 feet long, 24 feet wide, and 24 feet high. 20. Arts A piece of rectangular crafting supply is being cut for a new sculpture. You want its length to be 4 times its height and its width to be 2 times its height. If you want the wood to have a volume of 64 cubic centimeters, what will its length, width, and height be? V = (4x)(2x)(x) V = 8x 3 64 = 8x 3 8 = x3 2=x The length of the piece of crafting supply will be 8 cm, the width 4 cm, and the height 2 cm. Module 6 A2_MNLESE385894_U3M06L4 317 317 Lesson 6.4 (4x 3 - 1)(x - 1) Write and solve a polynomial equation for the situation described. © Houghton Mifflin Harcourt Publishing Company • Image Credits: ©Alex Ramsay/Alamy equation using the zero-product property, help them understand and recall that the zeros of the polynomial function f(x) associated with the polynomial equation are the values of x where the graph of the polynomial function crosses the x-axis. The zeros of a function f(x) are also equivalent to the solutions of the equation f(x) = 0 and are related to the factors of the polynomial. 4x 3(x - 1) - 1(x - 1) 317 Lesson 4 6/27/14 2:50 PM
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