Energy Management :: 2007/2008 Class # 2P Energy Transformation João Parente [email protected] Energy Management Types of Energy The energy transformation processes are countless and there are several energy sources and types. Within this course we propose to divide the energy in four main types, based on the energy t transformation f ti chain: h i Primary energy Final energy Useful energy Productive energy Class # 2P :: Energy Transformation Slide 2 of 53 Energy Management Types of Energy Primary Energy The primary energy can be defined as the “real” source of energy - before any transformation by mankind. Primary energy can assume the shape of renewable energy, fossil energy, or result from the use of residues (e.g., solar energy, oil, natural gas, ...). Taking the final energy as a reference point, the primary energy results from the summing up to the fi l energy off allll energy “l“loses”” (d final (degradation) d ti ) associated i t d tto th the process off ttransformation f ti off primary i energy into final energy. EPrimary = EFinal + ETransformation + ECapital TOE (Tone of Oil Equivalent) Primary Energy Unit Th tone The t off oilil equivalent i l t (toe) (t ) is i the th world ld reference f primary i energy unit, it as it is i th the JJoule l (J) ffor th the final energy. conversion to tep = (Primary ( Energy / Final Energy)) Considering that the reference technology is based on crude oil. In practice, toe corresponds to an hypothetic crude oil that during combustion releases a corresponding heat to 10 Gcal/ton (41.9 GJ/ton; 0,086 kgep/kWh). Class # 2P :: Energy Transformation Slide 3 of 53 Energy Management Types of Energy Final energy Final energy is defined as the commercial form of energy, in the way that this is available to the final consumer (e.g., gasoline, electricity, hydrogen, ...). Final energy is obtained through the transformation of primary energy resources. Although g the reference unit for final energy gy is Joule ((J), ), the pphysical y unit for final energy gy used in practice depends on the form that the final energy assumes - kWh for electricity, litres for gasoline, m3 for natural gas, kg for fuel-oil, ... Conversion to Joule (J) For the electricity the amount of final energy can be obtained by a direct unit equivalence: 1 kWh = 1 k(J/s)* h = 1 k(J/s) * 3600s = 3600 kJ In fuels, the final energy is evaluated based on the energy released in the combustion of that fuel, i.e., based on the heating values of the fuel. Whenever the fuel contains hydrogen (as in all hydrocarbons) two heating values are usually presented in literature: the Higher Heating Value ((HHV), ), and a d the t e Lower o e Heating eat g Value a ue ((LHV). ) For o ppropane opa e wee have a e LHV = 46000 6000 kJ/kg J/ g and a d HHV = 50400 kJ/kg. Class # 2P :: Energy Transformation Slide 4 of 53 Energy Management Types of Energy Useful Energy Useful energy is directly related to the way that the consumer assimilates the final energy, and it is the result from the transformation of the final energy into an energy service. service (e (e.g, g lighting, lighting heating, transport, communication…). For example, useful energy can assume the following forms: light, heat, movement, … Productive energy The productive energy corresponds to the portion of useful energy that is actually used by the final consumer, i.e., the concept of productive energy reports directly to the efficiency of the energy use. It should be highlighted that the concept of productive energy is somehow subjective, and closely related to the concepts of productivity/comfort. Class # 2P :: Energy Transformation Slide 5 of 53 Energy Management Energy transformation Sankey Diagramm Supplly Energy Transformation: Primary energy Dams, thermal power stations, wind mills, ... Refineries, R fi i … Fuel transport, electricity networks, … Primary energy degradation Energy conversion: Final energy gy Internal combustion engines, ... Lamps, … Heaters, … Demand Final energy degradation Energy use Useful energy Waste energy Productive energy Class # 2P :: Energy Transformation Slide 6 of 53 Energy Management Energy transformation Example – Reading light Supplly Energy transformation: 100% Natural gas Drilling Combined C bi d cycle l Electricity transport 45% Heat, … Energy Conversion: Electricityy 55% Lamps 90% Demand Heat, invisible radiation Energy use 5,5% Light 50% Light absorbed by the walls 2,75% Class # 2P :: Energy Transformation Reading light on the book Slide 7 of 53 Energy Management Energy Transformation Example – Transport from home to IST Supplly Energy transformation: 100% Oil Extraction Refinery R fi Fuel transport 5% Heat, … Energy conversion: Gasoline 95% Internal combustion engine 70% Demand Heat, … Energy use 66% Movement 20% Trafic jam, … 13% Class # 2P :: Energy Transformation Transport from home to IST Slide 8 of 53 Energy Management Types of Energy Examples of conversion coefficients to TOE Electricity 0.29 kgoe/kWh Thick fuel-oil 0.969 toe/ton Propane 1.140 toe/ton Natural gas 0.82 toe/103 m3 Diesel 0 872575 toe/m3 0.872575 Marginal g Consumption p Concept p The concept of marginal consumption implies that the increment in the energy demand (ΔE) is supplied by the power source with the lower energy conversion efficiency efficiency, since remaining power sources are already in used at maximum supply rate to fulfill the actual energy demand (E). Class # 2P :: Energy Transformation Slide 9 of 53 Energy Management Energy transformation Examples of efficiency values in the transformation of final into useful energy Production Consumption ‐ Degradation η= = Consumption Consumption Electrical resistence Electric motor Boiler Fluorescent lamp Internal combustion engine g Incandescent lamp Class # 2P :: Energy Transformation ~ 100% ~ 90% ~ 85% ~ 50% ~ 35% ~ 5% Slide 10 of 53 Energy Management Energy transformation Examples of efficiency values in the transformation of final into useful energy HEAT PUMP Oil Heat COP = Electricity consumptio n COP – Coeficient of Performance Elect Elect. Heat • Industrial heat pump COP ~ 5 • Residential heat pump COP ~ 3 Class # 2P :: Energy Transformation Slide 11 of 53 Energy Management Energy transformation Problems Class # 2P :: Energy Transformation Slide 12 of 53 Energy Management Energy transformation PROBLEM 01 Considering that the Portuguese electricity production sector is characterized by the following data: 1) 2) 3) Electricity losses in the network ~ 10% Efficiency of the worst power plant (gas turbine) ~ 33% Average effiency of the thermal power stations ~ 45% Determine the conversion coefficient form final energy energy, in the form of electricity electricity, to primary energy in the units of kgoe/kWh, considering: 1) average values for the electricity production 2) the concept of marginal consumer. consumer Source Hydro 23.38% Thermal 70.47% Wind 5.96% Geothermal 0.17% Photovoltaics 0 01% 0.01% TOTAL Class # 2P :: Energy Transformation Contribution 100% Slide 13 of 53 Energy Management Coeficientes de conversão para tep SOLUTION P02 1) Marginal consumer: Th transformation The t f ti efficiency ffi i off primary i energy iinto t final fi l energy iis: ηG = ηPS * ηEN = 33% * (100% - 10%) = 30% Considering 1kWhFE of final energy (elecricity): Æ Primary energy = 1 / ηG = 3,33 kWhPE (or 0,3 kWhFE/kWhPE ) = 3,33 kWhPE * 0,086 kgoe/kWhPE = 0,28 kgoe ((1 kgoe g = 41,9 MJ = ((41,9*103 kJ)) / ((3600 kJ/kWh)) = 11,64 kWh => 0,086 kgoe/kWh) g ) Æ Conversion coef. = PE / FE = 0,29 kgoe / 1 kWhFE = 0,29 kgoe/kWhFE FE – Final Energy; PE - Primary Energy Class # 2P :: Energy Transformation Slide 14 of 53 Energy Management Coeficientes de conversão para tep SOLUTION P02 2) Using the average production efficiencies: The transformation efficiency of primary energy into final energy is: ηG = ηTPP * ηEN = 45% * (100% - 10%) = 40% - for thermal power plants ηG = ηREN * ηEN = 100% * (100% - 10%) = 90% - for renewables Considering 1kWhFE of final energy in both cases: Æ PE = 1 / ηG = 2,5 kWhPE * 0,086 kgoe/kWhPE = 0,22 kgoe - for thermal power plants Æ PE = 1 / ηG = 1,11 kWhPE * 0,086 kgoe/kWhPE = 0,095 kgoe - for renewables Æ Conversion coef. = PE / FE = 0,22 kgoe / 1 kWhFE = 0,22 kgoe/kWhFE - for thermal power plants Æ Conversion coef. = PE / FE = 0,095 kgoe / 1 kWhFE = 0,095 kgoe/kWhFE - for renewables Æ Average A conversion i coef.f Class # 2P :: Energy Transformation = (0,095*29,5%) (0 095*29 5%) kgoe/kWh k /kWhFE + (0,22*70,5%) (0 22*70 5%) kgoe/kWh k /kWhFE = 0,183 kgoe/kWhFE Slide 15 of 53 Energy Management Energy transformation PROBLEM 02 Considering that you need to heat a house, and that you have 3 different solutions available. 1) 2) 3) Electric heating by Joule effect; Propane Boiler central heating; Air heating using an heat pump; Consider: 0.075 €/kWhe, 0.5 €/kgpropane, PCIpropane = 46 MJ/kg Determine the ranking list for these solutions in terms of: Final energy consumption, Primary energy consumption and cost. Support your calculation with the Sankey diagram. Class # 2P :: Energy Transformation Slide 16 of 53 Energy Management Energy transformation SOLUTION P02 Supplly Energy transformation: Electricity 0.29 kgoe/kWh Propane P 11.14 14 kkgoe/kg /k x1 kgoe x2 kgoe x3 kgoe 100% Transformation losses Energy conversion: Electrical resistances η = 100% Boiler η = 85% Heat pump COP = 3 (η = 300%) x1 kWh (electricity) x2 kWh (p (propane) p ) x3 kWh (electricity) Demand Conversion losses Energy use: 1kWh of heat (for 1,2 e 3) Heating Losses trough the building envelope… Useful area at the confort temperature (T = 21ºC ?) Class # 2P :: Energy Transformation Slide 17 of 53 Energy Management Energy transformation SOLUTION P02 For all solutions: EU = 1 kWhth 1) Electric heating by Joule effect: η ~ 100%, EF = 1/η = 1 kWhe/kWhth EP = EF * 00.29 29 kgoe/kWh k /kWhe = 1 kWhe/kWhth * 00.29 29 kgoe/kWh k /kWhe = 0.29 0 29 kgoe/kWh k /kWhth Cost = EF * 0.075 €/kWhe = 1 kWhe/kWhth * 0.075 €/kWhe = 0.075 €/kWhth 2) Propane Boiler central heating: η ~ 85%, EF = 1/η = 1.18 kWhp/kWhth mp = EF / LHV = (1.18 kWhp/kWhth * 3600 kJ/kWh) / 46 000 kJ/kg = 0.092 kg/kWhth EP = mp*1.14 kgoe/kg = 0.092 kg/kWhth * 1.14 kgoe/kg = 0.10 kgoe/kWhth Cost = 0.5€/kg * mp = 0.5€/kg * 0.092 kg/kWhth = 0.046€/kWhth. 3) Air heating using an heat pump: η ~ 250%, EF = 1/η = 0.4 kWhe/kWhth EP = EF * 0.29 kgoe/kWhe = 0.4 kWhe/kWhth * 0.29 kgoe/kWhth = 0.12 kgoe/kWhth Cost = EF * 0.075 €/kWhe = = 0.4 kWhe/kWhth * 0.075 €/kWhe = 0.03 €/kWhth Prefernce in terms of Final Energy Class # 2P :: Energy Transformation Prefernce in terms of Primary Energy Prefernce in terms of Energy Cost 1st Heat Pump 1st Boiler 1st Heat Pump 2nd Eletric resistances 2nd Heat Pump 2nd Boiler 3rd Boiler 3rd Eletric resistances 3rd Eletric resistances Slide 18 of 53
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