2/22/13 Assessment Summer 2010 Test 1 Started: February 22, 2013 8:07 AM Submitted: February 22, 2013 8:07 AM Time spent: 00:00:04 Total score: 0/20 = 0% Done 1. Which type of intermolecular/interparticle force exists in all solid substances? Student Value Response Correct Answer Feedback A. Ionic B. London Dispersion C. None there are different types of IMF/IPF depending on the substance D. Dipoledipole E. Hydrogen bonding Score: 0/1 2. Which of the following substances would be expected to have the highest melting point? Student Response Value Correct Answer Feedback A. CH3OCH3 B. CH3CH2CH2OH C. CH3CH2OH D. HOCH2CH2OH E. CH3CH2CH2CH2CH3 Score: 0/1 3. https://learn.uh.edu/webct/urw/tp7206949219101.lc7206946852101/gradeAssessment.dowebct 1/11 2/22/13 Assessment Rank the various "heats" of water in order of increasing size. Student Response Value Correct Answer Feedback A. heat of sublimation < heat of vaporization < heat of fusion B. heat of sublimation < heat of fusion < heat of vaporization C. heat of fusion = heat of sublimation = heat of vaporization D. heat of fusion < heat of vaporization < heat of sublimation E. heat of fusion < heat of sublimation < heat of vaporization Score: 0/1 4. How much energy in J is needed to convert 80 g of liquid ethanol at 70 oC to vapor at 101oC. You might need to know that: mp = -114 oC and bp = 78oC The heat of fusion is 4.6 kJ/mol and the heat of vaporization is 46.0 kJ/mol. Finally, the specific heats of the solid, liquid and gas are, respectively 2.1, 3.2 and 1.8 J/g oC. Student Value Response Correct Answer Feedback A. 87200 B. 5360 C. 3,685,000 https://learn.uh.edu/webct/urw/tp7206949219101.lc7206946852101/gradeAssessment.dowebct 2/11 2/22/13 Assessment D. 85400 E. 13400 Score: 0/1 5. For a pure substance, three phases are present simultaneously at Student Value Response Correct Answer Feedback A. none of these B. the critical point C. the normal boiling point D. the triple point E. the normal melting point Score: 0/1 6. Which of the following statements is true? Student Response Value Correct Answer Feedback A. A solution can only have one volatile component. B. The difference between the vapor pressure of a pure solvent and the vapor pressure of a solution is proportional to the concentration of the solute. https://learn.uh.edu/webct/urw/tp7206949219101.lc7206946852101/gradeAssessment.dowebct 3/11 2/22/13 Assessment C. Water and pentane form a solution when mixed. D. Ideal colligative properties do not depend on the nature of the solute particles in a given solution. E. The solubilities of solids in liquids are dependent of the pressure above the solution. Score: 0/1 7. Which solvent will be better able to dissolve the given solute? (I) HCl(g) in water or hexane(l) (II) methane(g) in water or carbon tetrachloride(l) (III) NaCl(s) in ethanol or in hexane Student Response Value Correct Answer Feedback A. hexane, carbon tetrachloride, hexane B. water, water, ethanol C. hexane, water, ethanol D. water, carbon tetrachloride, ethanol E. water, water, hexane Score: 0/1 https://learn.uh.edu/webct/urw/tp7206949219101.lc7206946852101/gradeAssessment.dowebct 4/11 2/22/13 Assessment 8. Calculate the molarity of an aqueous solution that is 15.6% by mass calcium chloride. You might need to know that the density is 1.16 g/mL. Student Value Response Correct Answer Feedback A. 0.163 B. 1.63 C. 1.405 D. 2.40 E. 2.07 Score: 0/1 9. If the freezing point constant for water is 1.86 ºC/m and assuming ideal conditions, determine the freezing point of a 0.0100 m aqueous solution of Na2SO4. Student Value Response Correct Answer Feedback A. -0.0558 ºC B. -0.0062 ºC C. -0.0372 ºC D. -0.0186 ºC E. -0.0744 ºC Score: 0/1 10. A solution that is a mixture of 0.4 mol C2H4Br2 and 0.6 mol C3H6Br2 has a vapor pressure of 145 mmHg at a particular temperature. Determine the vapor pressure of pure C3H6Br2 at this temperature, given that the vapor pressure of pure C2H4Br2 is 173 mmHg at this temperature and that the solution obeys Raoult's law. Student Value Response Correct Answer Feedback A. 75.8 mmHg B. 69.2 mmHg https://learn.uh.edu/webct/urw/tp7206949219101.lc7206946852101/gradeAssessment.dowebct 5/11 2/22/13 Assessment C. 126 mmHg D. 28 mmHg E. 117 mmHg Score: 0/1 11. 3.21 grams of a protein that has a molar mass of 16,000 g/mol are dissolved in 25.0 mL of water at 25 ºC. Calculate the osmotic pressure in mmHg. Student Value Response Correct Answer Feedback A. 19.9 B. 0.196 C. 3141 D. 0.149 E. 149 Score: 0/1 12. A water-soluble compound has an empirical formula of CH2O. When 1.00 g of the compound are dissolved in 50.0 g of water, the solution freezes at -0.62 ºC. Given that the freezing point constant of water is 1.86 ºC/m, what is the molecular formula of the compound? Student Value Response Correct Answer Feedback A. CH2O B. C2H4O2 C. C5H10O5 D. C3H6O3 E. C4H8O4 Score: 0/1 13. For the reaction, N2O4(g) → 2 NO2(g), the number of moles of N2O4(g) present at certain times is, Time = 0, moles N2O4(g) = 0.200 Time = 5 minutes, moles N2O4(g) = 0.170 Time = 10 minutes, moles N2O4(g) = 0.140 How many moles of NO2 are present after 10 minutes (assuming there were 0 at time = 0)? Student Value Correct Answer Feedback https://learn.uh.edu/webct/urw/tp7206949219101.lc7206946852101/gradeAssessment.dowebct 6/11 2/22/13 Assessment Response A. 0.120 moles B. 0.140 moles C. 0.060 moles D. 0.110 moles E. 0.280 moles Score: 0/1 14. The reaction between NO and I2 is first order in NO and second order in I2. What change in rate will result when the initial concentrations of both are tripled? Student Value Response Correct Answer Feedback A. 81-fold increase B. 6-fold increase C. 27-fold increase D. 3-fold increase E. 18-fold increase Score: 0/1 15. For the reaction, S2O82-(aq) + 2 I-(aq) => I2(aq) + 2 SO42-(aq), the following data were obtained at constant temperature. The times listed are those taken to reach a measurable amount of iodine. Experiment Initial [S2O82-], mol/L Initial [I-], mol/L Time, sec 1 0.0400 0.0800 40 2 0.0400 0.0400 80 3 0.0100 0.0800 160 4 0.0200 0.0200 ? What is the expected time for experiment 4? https://learn.uh.edu/webct/urw/tp7206949219101.lc7206946852101/gradeAssessment.dowebct 7/11 2/22/13 Assessment Student Value Response Correct Answer Feedback A. 320 B. 5 C. 160 D. 240 E. 80 Score: 0/1 16. For the reaction, A → B, the rate constant is 0.0208 sec -1. How long would it take for [A] to decrease from 0.100 to 0.0450 M? Student Value Response Correct Answer Feedback A. 16.7 sec B. 588 sec C. 107 sec D. 38.4 sec E. 0.0166 sec Score: 0/1 17. The first-order disappearance of a substance has a half-life of 34.0 s. How long does it take for the concentration of the substance to fall to 12.5% of the original value? Student Value Response Correct Answer Feedback A. 4.25 s B. 102 s C. 68 s D. 11 s E. 272 s Score: 0/1 18. The rate law of a particular reaction is found to be, rate = k[A]2[B]. Which of the following statements is FALSE? Student Response Value Correct Answer Feedback https://learn.uh.edu/webct/urw/tp7206949219101.lc7206946852101/gradeAssessment.dowebct 8/11 2/22/13 Assessment A. Tripling the concentration of A will result in a nine-fold increase in the rate B. The units of k could be (L2/mol2 sec) C. The reaction is third order overall. D. The actual value of k will depend on the concentrations of A and B. E. The actual value of k will depend on the temperature Score: 0/1 19. The kinetics of the decomposition of dinitrogen pentoxide are studied at 50 ºC and 75 ºC. Which of the following statements about these studies is correct? Student Response Value Correct Answer Feedback A. The rate at 75 ºC will be greater than that at 50 ºC because the concentration of a gas increases with increasing temperature B. The rate at 75 ºC will be lower than that at 50 ºC because the molecules with higher speeds do not interact as well as the https://learn.uh.edu/webct/urw/tp7206949219101.lc7206946852101/gradeAssessment.dowebct 9/11 2/22/13 Assessment ones at lower speeds C. The rate at 75 C will be greater than that at 50 ºC because the activation energy is lower at 75 ºC D. The rate at 75 ºC will be greater than that at 50 ºC because the number of molecules with enough energy to react increases with temperature E. The rate at 75 ºC will be greater than that at 50 ºC because the activation energy is higher. Score: 0/1 20. A reaction has a rate constant of 1.23 x 10-2 s-1 at 20.0 °C and an activation energy of 52.0 kJ/mol. What is the rate constant at 40.0 °C? Student Value Response Correct Answer Feedback A. 4.81 x 10-2 B. 1.23 x 10-2 C. 9.02 x 10-3 D. 3.14 x 10-3 https://learn.uh.edu/webct/urw/tp7206949219101.lc7206946852101/gradeAssessment.dowebct 10/11 2/22/13 Assessment E. 1.68 x 10-2 Score: 0/1 Done https://learn.uh.edu/webct/urw/tp7206949219101.lc7206946852101/gradeAssessment.dowebct 11/11
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