%0/05&%*5$IBOHFTNVTUCFNBEFUISPVHI'JMFJOGP $PSSFDUJPO,FZ59" LESSON 6.1 Name Class Date Slope-Intercept Form 6.1 Texas Math Standards Essential Question: How can you represent a linear function in a way that reveals its slope and y-intercept? The student is expected to: A1.2.B …write linear equations in two variables in various forms, including y = mx + b… Also A1.2.C, A1.3.C A1.2.B Write linear equations in two variables in various forms, including y = mx + b..., given one point and the slope and given two points. Also A1.2.C, A1.3.C Graphs of linear equations can be used to model many real-life situations. Given the slope and y-intercept, you can graph the line, and use the graph to answer questions. Andrew wants to buy a smart phone that costs $500. His parents will pay for the phone, and Andrew will pay them $50 each month until the entire amount is repaid. The loan repayment represents a linear situation in which the amount y that Andrew owes his parents is dependent on the number x of payments he has made. A1.1.D Communicate mathematical ideas, reasoning, and their implications using multiple representations, including symbols, diagrams, graphs, and language as appropriate. time is –$50 per month. 2.C.3, 2.C.4, 2.I.3, 2.I.4, 3.D, 4.G Explain to a partner how to write a linear function in slope-intercept form. The y-intercept of the graph of the equation that represents the situation is 500 . The slope is –50 . Use the y-intercept to plot a point on the graph of the equation. The y-intercept is 500 , so plot the point (0, 500) . Amount Andrew Owes Amount ($) ª)PVHIUPO.JGGMJO)BSDPVSU1VCMJTIJOH$PNQBOZt*NBHF$SFEJUTª&DIP $VMUVSB(FUUZ*NBHFT You can determine the slope m of the graph of the function and its y-intercept b and write the equation y = mx + b, called the slope-intercept form of the equation. When x = 0, y = $500 . The rate of change in the amount Andrew owes over Language Objective Essential Question: How can you represent a linear function in a way that reveals its slope and y-intercept? 500 450 400 350 300 250 200 150 100 50 0 y x 1 2 3 4 5 6 7 8 9 Time (Months) PREVIEW: LESSON PERFORMANCE TASK View the Engage section online. Discuss the photo and how a gym membership may require a one-time sign-up fee as well as regular monthly fees. Also discuss how a graph of this type of data might look. Then preview the Lesson Performance Task. Module 6 Lesson 1 247 Date Class Name a way that cept Form Slope-Inter on: 6.1 y-intercept? Questi Essential linear equatio A1.2.B …write A1.3.C Also A1.2.C, ns in two Graphing in various variables reveals its slope Resource Locker g y = mx forms, includin + b… ercept e and y-int n Slop Lines Give and the slope y-intercept, HARDCOVER PAGES 195–202 HARD you can Given situations. many real-life will pay them used to model ns. and Andrew which the ns can be questio in the phone, linear equatio graph to answer situation will pay for Graphs of use the nts a linear His parents line, and made. costs $500. loan repayment represe graph the ts he has phone that The r x of paymen to buy a smart amount is repaid. on the numbe Andrew wants until the entire dependent parents is month owes his $50 each that Andrew amount y Explore $500 . 0, y = owes over t Andrew the amoun change in The rate of –$50 per month. nts time is n that represe the equatio graph of cept of the The y-inter 500 . n is the situatio Tu to these pages to Turn fi find this lesson in the ha hardcover student ed edition. When x = –50 . cept is is n. The y-inter of the equatio the graph a point on cept to plot Use the y-inter (0, 500) . point so plot the Owes Andrew Amount 500 , )BSDPVSU PO.JGGMJO ª)PVHIU FT FUUZ*NBH $VMUVSB( 1VCMJTIJO Zt*NBHF H$PNQBO y 500 450 400 350 300 250 200 150 100 50 ($) Amount $SFEJUTª &DIP The slope x 0 7 8 9 4 5 6 1 2 3 s) Time (Month Lesson 1 247 Module 6 247 Lesson 6.1 Resource Locker Graphing Lines Given Slope and y-intercept Explore Mathematical Processes ENGAGE Slope-Intercept Form Using the definition of slope, plot a second point. –50 Change in y Slope = __ = _ = –50 . 1 Change in x Start at the point you plotted. Count 50 units down and 1 unit right and plot another point. Amount ($) 500 450 400 350 300 250 200 150 100 50 0 Draw a line through the points you plotted. y EXPLORE Amount Andrew Owes Amount ($) Amount Andrew Owes 500 450 400 350 300 250 200 150 100 50 0 Graphing Lines Given Slope and y-Intercept y INTEGRATE TECHNOLOGY Students have the option of completing the activity either in the book or online. x 1 2 3 4 5 6 7 8 9 Time (Months) CONNECT VOCABULARY x 1 2 3 4 5 6 7 8 9 Remind students that the word intercept means to come together. When a player intercepts a football, the player and football come together at a certain point. Help students make the connection to the y-intercept on a graph, the place where the line “comes together” with the y-axis. Time (Months) Reflect 1. Discussion How can you use the same method to find two more points on that same line? Possible answer: You can begin at the second point, (1, 450), and move 50 units down and 1 unit to the right. Then repeat this process beginning at the new point. 2. How many months will it take Andrew to pay off his loan? Explain your answer. 10 months; the point (10, 0) represents the number of months, 10, for which the amount to be repaid is $0. Explain 1 © Houghton Mifflin Harcourt Publishing Company You can use the slope formula to derive the slope-intercept form of a linear equation. Consider a line with slope m and y-intercept b. y2 - y1 The slope formula is m = _ x2 - x1 . Substitute (0, b) for (x 1, y 1) and (x, y) for (x 2, y 2). y-b m=_ x-0 y-b m=_ x mx = y - b mx + b = y Multiply both sides by x(x ≠ 0). Add b to both sides. y = mx + b Slope-Intercept Form of an Equation If a line has slope m and y-intercept (0, b), then the line is described by the equation y = mx + b. Module 6 EXPLAIN 1 Creating Linear Equations in Slope-Intercept Form 248 Lesson 1 Creating Linear Equations in Slope-Intercept Form AVOID COMMON ERRORS Some students may not understand how to use the coordinates (x 1, y 1) and (x 2, y 2) to calculate the slope. Explain that the subscripts show which x-value goes with which y-value; for example the x-value of the first point is x 1, the y-value of the second point is y 2. Remind students that the change in the y-coordinates goes in the numerator and the change in x-coordinates goes in the denominator. PROFESSIONAL DEVELOPMENT Learning Progressions In this lesson, students build on their understanding of linear functions. They focus on the relationships between linear equations and their graphs, including: r The slope-intercept form of a linear equation is y = mx + b, where m represents the slope, and b represents the y-intercept. r A linear function can be graphed by plotting the y-intercept and using the slope to find other points that lie on the line. r The slope-intercept form of a linear equation can be used to write functions that model real-world situations. In future lessons, students compare functions represented in different forms. Slope-Intercept Form 248 Example 1 Write the equation of each line in slope-intercept form. Slope is 3, and (2, 5) is on the line. Step 1: Find the y-intercept. y = mx + b 5 = 3(2) + b 5=6+b 5-6=6+b-6 -1 = b Write the slope–intercept form. Substitute 3 for m, 2 for x, and 5 for y. Multiply. Subtract 6 from both sides. Simplify. Step 2: Write the equation. y = mx + b y = 3x + (-1) y = 3x - 1 Write the slope–intercept form. Substitute 3 for m and -1 for b. The line passes through (0, 5) and (2, 13). Step 1: Use the points to find the slope. y2 - y1 The slope formula is m = _. x2 - x1 Substitute (0, 5) for (x 1, y 1) and ( 2 , 13 ) for (x , y ). 2 2 © Houghton Mifflin Harcourt Publishing Company 8 13 - 5 m=_=_= 4 2 2-0 ( 2 )+b Step 2: Substitute the slope and x- and y-coordinates of either of the points in the equation y = mx + b. 13 = 4 4 Substitute for m and the x- and y-coordinates of the point (2, 13) for x and y. 13 = 8 + b 4 for m and 5 Step 3: Substitute b in the equation y = mx + b. The equation of the line is y = 4x + 5 13 - 8 = 8 + b - 8 for 5 =b . Module 6 249 Lesson 1 COLLABORATIVE LEARNING Peer-to-Peer Activity Group students in pairs. Have each student write slope-intercept equations for four lines: one whose slope is a positive integer, one whose slope is a negative integer, and one whose slope is a fraction. Then have partners trade equations. Partners should first check that the three conditions are met, then graph the lines. 249 Lesson 6.1 Reflect 3. EXPLAIN 2 Discussion How would the equation change if (0, 5) were used for (x 2, y 2) and (2, 13) were used for (x 1, y 1) in the slope formula? Explain your reasoning. The equation would not change at all. It doesn’t make a difference which point Graphing from Slope-Intercept Form -5 - 13 _____ is used for (x 1, y 1) and which point is used for (x 2, y 2) because 13 = 5_____ . 2-0 0-2 INTEGRATE MATHEMATICAL PROCESSES Focus on Reasoning Your Turn Write the equation of each line in slope-intercept form. 4. Slope is −1, and (3, 2) is on the line. 5. The line passes through (1, 4) and (3, 18). 18 - 4 _ = 14 = 7 3-1 2 y = mx + b y = mx + b m= 2 = -1(3) + b 5= b Explain to students that one or both intercepts are often used to calculate the slope of a linear equation because they are easy to determine. However, any two points that satisfy the given equation can be used to determine the slope. 4 = 7(1) + b The equation of the line is y = -x + 5. -3 = b The equation of the line is y = 7x 7 - 3. Explain 2 Graphing from Slope-Intercept Form Writing an equation in slope-intercept form can often make it easier to graph the equation. Example 2 QUESTIONING STRATEGIES Write each equation in slope-intercept form. Then graph the line described by the equation. y = 5x - 4 4 The equation y = 5x - 4 is already in slope-intercept form. 5 Slope: m = 5 = _ 1 y-intercept: b = -4 2 x -4 4 0 -2 2 -2 Step 2: Count 5 units up and 1 unit to the right and plot another point. -4 4 2x + 6y 6 =6 4 Step 1: Write the equation in slope-intercept form by solving for y. 2 1 Slope: -_ 3 2x + 6y 6 - 2x = 6 - 2x 6 = -2x + 6 6y y-intercept: 1 y x -4 4 0 -2 2 2 4 -2 _1 y = -3 x + 1 -4 Step 2: Graph the line. r Plot ( 0 , 1 ). r Move 1 unit down and 3 units to the right to plot a second point. r Draw a line through the points. Module 6 250 Lesson 1 © Houghton Mifflin Harcourt Publishing Company Step 1: Plot (0, -4). 2 Step 3: Draw a line through the points. How does the value of b indicate whether the graph is above or below the origin where it intersects the y-axis? If b is positive, the y-intercept is positive and the graph intersects the y-axis above the origin. If b is negative, the y-intercept is negative and the graph intersects the y-axis below the origin. y What is the advantage of graphing from slope-intercept form? The intercept is one point on the line and a second point can be found easily by using the slope. INTEGRATE MATHEMATICAL PROCESSES Focus on Math Connections Remind students that slope is the ratio of rise over 1 run. Graph a line such as y = -_ x + 2 in two ways, 2 -1 _ once using a slope of and once using a slope of 2 1 _ , to show that both result in the same line. -2 DIFFERENTIATE INSTRUCTION Communicating Math Have students list the steps for writing a linear function from two given points. Sample steps are shown. 1. Use the slope formula to find the slope m. 2. Substitute m and the coordinates of one point into f(x) = mx + b. 3. Solve for the y-intercept b. 4. Substitute m and b into f(x) = mx + b. Slope-Intercept Form 250 Your Turn EXPLAIN 3 Write each equation in slope-intercept form. Then graph the line described by the equation. 6. Determining Solutions of Equations in Two Variables 2x + y = 4 y = -2x + 4 4 7. 2x + 3y = 6 2 x+2 y = -_ 3 y 4 2 2 QUESTIONING STRATEGY For a real-world problem described by a graph of a linear function in which the value of y indicates the solution for a given value of x, what do you need to do to solve the problem? Apply the units from the graph to the solution. For example if x is time in hours and y is cost in dollars, then the solution is y dollars for a time of x hours. Explain 3 0 -2 2 -4 4 0 -2 -2 -2 -4 -4 2 4 Determining Solutions of Equations in Two Variables Given a real-world linear situation described by a table, a graph, or a verbal description, you can write an equation in slope-intercept form. You can use that equation to solve problems. Example 3 INTEGRATE MATHEMATICAL PROCESSES Focus on Modeling Remind students that when time is one of the quantities in a real-world problem, it is usually the independent variable. Identify the slope and y-intercept of the graph that represents each linear situation and interpret what they mean. Then write an equation in slope-intercept form and use it to solve the problem. For one taxi company, the cost y in dollars of a taxi ride is a linear function of the distance x in miles traveled. The initial charge is $2.50, and the charge per mile is $0.35. Find the cost of riding a distance of 10 miles. The rate of change is $0.35 per mile, so the slope, m, is 0.35. The initial cost is the cost to travel 0 miles, $2.50, so the y-intercept, b, is 2.50. © Houghton Mifflin Harcourt Publishing Company Some students may think that the coefficient of x is the slope of the line of the equation regardless of the form of the equation. Remind them that if the equation is not in the form y = mx + b, the coefficient of x may not be the slope. x x -4 AVOID COMMON ERRORS y Then an equation is y = 0.35x + 2.50. To find the cost of riding a distance of 10 miles, substitute 10 for x and simplify. y = 0.35x + 2.50 = 0.35(10) + 2.50 = 3.5 + 2.5 =6 (6, 10) is a solution of the equation, and the cost of riding a distance of 10 miles is $6. Module 6 251 Lesson 1 LANGUAGE SUPPORT Connect Vocabulary Caution students that a figure called a graph of a line should not be confused with a line graph. A line graph is a graph that uses line segments to connect data points. A graph of a line is a graph of a linear equation. 251 Lesson 6.1 %0/05&%*5$IBOHFTNVTUCFNBEFUISPVHI'JMFJOGP $PSSFDUJPO,FZ59# %0/05&%*5$IBOHFTNVTUCFNBEFUISPVHI'JMFJOGP $PSSFDUJPO,FZ59# A chairlift descends from a mountain top to pick up skiers at the bottom. The height in feet of the chairlift is a linear function of the time in minutes since it begins descending as shown in the graph. Find the height of the chairlift 2 minutes after it begins descending. Height (ft) Height of a Chairlift y 5400 (0, 5400) 4800 4200 (2, 3900) 3600 3000 (4, 2400) 2400 1800 1200 600 0 x 1 2 3 4 5 6 7 8 9 Time (min) 4 , 2400). The graph contains the points (0, 5400 ) and ( 2400 - 5400 The slope is __ = -750 . 4 -0 It represents the rate at which the chairlift descends . The graph passes through the point (0, 5400 ), so the y-intercept is 5400 . It represents the height of the chairlift 0 minutes after it begins descending. Let x be the time in minutes after the chairlift begins to descend. ª)PVHIUPO.JGGMJO)BSDPVSU1VCMJTIJOH$PNQBOZt*NBHF$SFEJUT ª.PPECPBSE$PSCJT Let y be the height of the chairlift in feet. The equation is y = -750x + 5400 . To find the height after 2 minutes, substitute 2 for x and simplify. y = -750 ( 2 ) + 5400 = -1500 + 5400 = 3900 (2, 3900) is a solution of the equation, and the height of the chairlift 2 minutes after it begins descending is 3900 feet. Reflect 8. In the example involving the taxi, how would the equation change if the cost per mile increased or decreased? How would this affect the graph? Increasing the cost per mile would increase the value of m and make the graph steeper. Decreasing the cost per mile would decrease the value of m and make the graph less steep. Module 6 252 Lesson 1 Slope-Intercept Form 252 Identify the slope and y-intercept of the graph that represents each linear situation and interpret what they mean. Then write an equation in slope-intercept form and use it to solve the problem. ELABORATE Your Turn QUESTIONING STRATEGIES 9. How would you graph the equation c = 35t + 50? The equation is in slope-intercept form. 35 is the slope and 50 is the y-intercept. Plot the point that corresponds to the y-intercept (0, 50). Then use the slope to locate a second point on the line. Draw a line through the two points. A local club charges an initial membership fee as well as a monthly cost. The cost C in dollars is a linear function of the number of months of membership. Find the cost of the membership after 4 months. Membership Cost Time (months) 0 3 6 Cost ($) 100 277 454 277 - 100 - 277 177 177 _______ _______ = ___ = 59 and 454 = ___ = 59, so the rate of change in the cost is $59 per 3-0 3 6-3 3 month. The slope, m, is 59. The initial cost is the cost for 0 months, $100, so the y-intercept, b, is 100. Let x be the number of months and y be the cost in dollars. The equation is y = 59x + 100. When x = 4, y = 59(4) + 100 = 336. So, (4, 336) is a solution of the equation, and the membership costs $336 for 4 months. SUMMARIZE THE LESSON How do you write an equation of a line in slope-intercept form when given the slope and y-intercept or when given the slope and a point on the line? Using the form y = mx + b, substitute slope for m and the y-intercept for b. If you are given the slope and a point on the line, substitute the slope into y = mx + b, substitute the coordinates of the point for x and y, and solve for b. Elaborate 10. What are some advantages to using slope-intercept form? When graphing, it’s easy to recognize the slope and y-intercept. It’s also easy to find y-values for corresponding x-values. 11. What are some disadvantages of slope-intercept form? The x-intercept may not be easily visible, and if a y-value is given, the x-value may not be © Houghton Mifflin Harcourt Publishing Company easily obtained. 12. Essential Question Check-In When given a real-world situation that can be described by a linear equation, how can you identify the slope and y-intercept of the graph of the equation? To find the slope, identify the rate of change for the situation. To find the y-intercept, identify the initial value for the situation, that is, the value of the dependent variable when the value of the independent value is 0. Module 6 253 Lesson 6.1 253 Lesson 1
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