1
CLASS 2
(Sections 1.3)
Exponential and Sinusoidal Signals
β
They arise frequently in applications, and many other signals can be constructed from them.
Continuous-time complex exponential and sinusoidal signals:
π₯(π‘) = πΆπππ‘
where πΆ and π are in general complex numbers.
Real exponential signals: πΆ and π are reals.
at
0
β
C>0 and a<0.
Ce
Ce
at
C>0 and a>0.
C
0
t
0
C
0
t
The case π > 0 represents exponential growth. Some signals in unstable systems exhibit exponential
growth.
β
The case π < 0 represents exponential decay. Some signals in stable systems exhibit exponential
decay.
2
Periodic complex exponential:
πππ€0 π‘
where π =
β
β1, π€0 β= 0 is real, and π‘ is the time.
Eulerβs formula: πππ€0 π‘ = cos(π€0 π‘) +π sin(π€0 π‘) . Note that
| {z }
| {z }
Re{πππ€0 π‘ }
Im{πππ€0 π‘ }
1
jw t
sin(w t)
e
Im
0
0
0
cos(w0t)
β1
β1
β
β£πππ€0 π‘ β£ = 1 and β πππ€0 π‘ = π€0 π‘.
β
ππ2ππ = 1, for π = 0, ±1, ±2, . . . .
0
Re
1
Since
(
)
2π
ππ€0 π‘+ β£π€
β£
π
0
π€
π2π β£π€0 β£
= πππ€0 π‘ π
0
ππ€0 π‘
0)
= πππ€0 π‘ π|π2πsign(π€
{z } = π
=1
we have
πππ€0 π‘ is periodic with fundamental period
2π
.
β£π€0 β£
Note that
β
πππ€0 π‘ and πβππ€0 π‘ have the same fundamental period.
β
Energy in πππ€0 π‘ :
β
Average Power in πππ€0 π‘ : limπ ββ
β
{ππππ€0 π‘ }π=0,±1,... , are all periodic with period
β«β
ββ
β£πππ€0 π‘ β£ππ‘ =
β«β
ββ
1
2π
1.ππ‘ = β
β«π
βπ
β£πππ€0 π‘ β£ππ‘ = limπ ββ
2π
.
β£π€0 β£
1
2π
β«π
βπ
1.ππ‘ = 1.
They are called a harmonically related set of
complex exponentials with ππππ€0 π‘ being the πβth harmonic.
3
Sinusoidal signals:
π΄ cos(π€0 π‘ + π)
and
π΄ sin(π€0 π‘ + π).
where π΄ is real, π€0 is real, π is real, and π‘ is the time. (Graph one of the signals!)
β
β
They arise in systems that conserve energy such as an ideal LC circuit or an ideal mass-spring system.
β Periodic with the same fundamental period π0 = 2π/β£π€0 β£
β β£π€0 β£ is the fundamental frequency
β π0 := 1/π0 = β£π€0 β£/(2π) is the number of cycles per unit time (large π0 means more oscillatory)
β β£π΄β£ is the amplitude
β β£πβ£ is the size of the phase shift.
β
Since
ππ(π€0 π‘+π) = cos(π€0 π‘ + π) + π sin(π€0 π‘ + π)
we can write
π΄ cos(π€0 π‘ + π) = π΄Re(ππ(π€0 π‘+π) )
π΄ sin(π€0 π‘ + π) = π΄Im(ππ(π€0 π‘+π) ).
β
Recall, for any complex number π§,
π§ = Re(π§) + πIm(π§)
π§ β = Re(π§) β πIm(π§)
therefore
Re(π§) =
π§ + π§β
2
Im(π§) =
π§ β π§β
.
2π
Hence, we can also write
)
π΄ ( π(π€0 π‘+π) ( π(π€0 π‘+π) )β ) π΄ ( π(π€0 π‘+π)
π
+ π
=
π
+ πβπ(π€0 π‘+π)
2
2
π΄
π΄
= πππ πππ€0 π‘ + πβππ πβππ€0 π‘
2
2
(
)
π΄ π(π€0 π‘+π) ( π(π€0 π‘+π) )β ) π΄ βππ/2 ( π(π€0 π‘+π)
π΄ sin(π€0 π‘ + π) =
π
β π
= π
π
β πβπ(π€0 π‘+π)
2π
2
π΄
π΄
= ππ(πβπ/2) πππ€0 π‘ β πβπ(π+π/2) πβππ€0 π‘ .
2
2
π΄ cos(π€0 π‘ + π) =
4
General complex exponential signals:
πΆπππ‘
where πΆ and π are complex numbers.
If
πΆ = β£πΆβ£πππ
and
π = π + ππ€0
then
πΆπππ‘ = β£πΆβ£πππ π(π+ππ€0 )π‘ = β£πΆβ£πππ‘ ππ(π€0 π‘+π) = β£πΆβ£πππ‘ cos(π€0 π‘ + π) +π β£πΆβ£πππ‘ sin(π€0 π‘ + π) .
|
{z
}
|
{z
}
Re(πΆπππ‘ )
Im(πΆπππ‘ )
r>0.
r<0.
|C|ert
at
Re(Ce )
at
Re(Ce )
|C|ert
0
0
β|C|ert
0
β|C|e
0
t
rt
t
β
If π = 0, the real and imaginary part are sinusoidals.
β
If π > 0, the real and imaginary part are sinusoidals multiplied by a growing exponential.
Such signals arise in unstable systems.
β
If π < 0, the real and imaginary part are sinusoidals multiplied by a decaying exponential.
Such signals arise in stable systems, for example, in RLC circuits, or in mass-spring-friction system,
where the energy is dissipated due to the resistors, friction, etc.
5
Discrete-time complex exponential and sinusoidal signals:
π₯[π] = πΆππ½π
where πΆ and π½ are complex numbers.
Analogous to the continuous-time case with the following differences: (π€0 is real below)
β
πππ€0 π‘ = πππ€1 π‘ are different signals if π€0 β= π€1 , whereas
πππ€0 π = πππ€1 π
if
π€0 β π€1 = 2ππ, for some π β {0, ±1, . . . }.
(Explain this on the unit circle!)
Therefore, it is sufficient to consider only the case π€0 β [0, 2π) or π€0 β [βπ, π).
β
As π€0 increases πππ€0 π oscillates at higher frequencies, whereas this is not the case for πππ€0 π .
In the figure below, the frequency of oscillations increases as π€0 changes from 0 to π then it decreases
as π€0 changes from π to 2π.
β
πππ€0 π‘ is periodic with fundamental period 2π/β£π€0 β£, whereas
πππ€0 π is periodic
β πππ€0 π = πππ€0 (π+π ) for some integer π > 0, for all π
β πππ€0 π = 1 for some integer π > 0
β π€0 π = 2ππ for some integers π, π > 0
β
β
If
π€0
2π
=
is π =
π
π
π€0
is rational.
2π
for some integers π and π which have no common factors, then the fundamental period
2ππ
π€0
because
πππ€0 (π+π ) = πππ€0 π ππ
The same observations hold for discrete-time sinusoids.
2ππ
π
π
.
6
w =1Ο/8
w =0Ο/8
0
n=4
n=5
n=3
n=6
n=2
n=7
n=1
n=8
n=0
n=9
n=15
n=10 n=14
n=11
n=13
n=12
n=3
Im
n=0
Im
Im
w =2Ο/8
0
0
n=4
n=6
n=7
Re
Re
w =4Ο/8
w =8Ο/8
w =12Ο/8
0
0
n=2
n=0
n=1
n=0
Im
n=3
Im
Im
n=0
n=5
n=1
n=3
n=2
n=0
n=1
Re
Re
w0=14Ο/8
w0=15Ο/8
w0=16Ο/8
n=4
n=7
n=0
n=3
n=2
Re
n=1
Im
n=6
n=12
n=11
n=13
n=10 n=14
n=9
n=15
n=8
n=0
n=7
n=1
n=6
n=2
n=5
n=3
n=4
Im
Re
n=5
Im
n=1
Re
0
Fig. 1.
n=2
Re
To determine the fundamental period, count the number of steps to get back to 1!
n=0
Re
7
Examples:
1) Is π₯[π] = πππ2π/3 + πππ3π/4 periodic? If it is periodic, whatβs its fundamental period?
For πππ2π/3 , π€0 /(2π) = 1/3, so πππ2π/3 is periodic with fundamental period 3.
For πππ3π/4 , π€0 /(2π) = 3/8, so πππ3π/4 is periodic with fundamental period 8.
π₯[π] is periodic with fundamental period 24 = πππ(3, 8).
2) Is π₯[π] = sin(3π/4) periodic? If it is periodic, whatβs its fundamental period?
Since
π€0
2π
=
3
8π
is irrational, π₯[π] is not periodic; see the figure where π₯[π] = 0 only at π = 0.
sin(3t/4) and sin(3n/4)
1
0
β1
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
t
3) Is π₯[π] = sin(8ππ/31) periodic? If it is periodic, whatβs its fundamental period?
Since π€0 /(2π) = 4/31, π₯[π] is periodic with fundamental period 31; see the figure where π₯[0] =
π₯[31] = 0. Note that the continuous-time signal sin(8ππ‘/31) has fundamental period 31/4, hence it
is 0 at π‘ = 31/4. But π₯[π] has no 31/4βth sample and it misses 0 between π₯[7] and π₯[8].
sin(8Ο t/31) and sin(8Ο n/31)
1
0
β1
0 1 2 3 4 5 6 7 8 9 1011121314151617181920212223242526272829303132333435
t
8
Harmonically related discrete-time periodic exponentials:
ππ [π] = {πππ(2π/π )π }π=0,±1,... , are all periodic with period π .
However, unlike the continuous-time signals, these signals are not all distinct because
ππ+π [π] = ππ(π+π )(2π/π )π = πππ(2π/π )π ππ2ππ = ππ [π].
This implies that there are only π distinct signals in this set, for example,
π0 [π] = 1
π1 [π] = ππ2ππ/π
π2 [π] = ππ4ππ/π
..
.
π1 [π] = ππ2(π β1)π/π .
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