Lecture 10 HEAT Phases of matter Temperature Temperature Scales Thermal expansion Phases of matter Solid rigid retains shape Molecules linked by spring-like forces average positions fixed Liquid flows does not retain shape. Molecules freer to move remain close to each other Gas flows does not retain shape Molecules move anywhere little interaction Temperature and Heat Molecules are in constant disordered motion Velocities distributed over a large range Average kinetic energy directly related to temperature Greater their average kinetic energy •Higher the temperature Temperature is a characteristic of an object related to the average kinetic energy of atoms and molecules of the object. Heat Energy exchange between two objects at different temperatures Temperature Temperature is a measure of the average kinetic energy of atoms and molecules. Robert Brown, botanist noticed in 1828 that tiny particles (pollen grains) exhibited an incessant, irregular motion in a liquid. Brownian motion Remained largely unexplained until Einstein paper in 1905 “On the motion of small particles suspended in a stationary liquid demanded by the molecular-kinetic theory of heat” A suspended small particle is constantly and randomly bombarded from all sides by molecules of the liquid. indirect confirmation of existence of molecules and atoms Temperature and Heat Brownian motion polystyrene particles, 1.9 mm in diameter, in water T = 25 C in any short period of time •random number of impacts •random strength •random directions Brownian motion is a clear demonstration of the existence of molecules in continuous motion Temperature scales There are 3 temperature scales: Anders Celsius (1701-1744) - Celsius (C) Gabriel Fahrenheit (1686 -1736) - Fahrenheit (F) Lord Kelvin (1824-1907) - Kelvin (K) Differ by (a) the basic unit size or degree () (b) lowest & highest temperature Celsius and Fahrenheit are defined by the freezing point and the boiling point of water (at standard atmospheric pressure): Freezing point of water: 0C or 32F Boiling point of water: 100C or 212F Range- freezing to boiling point of water Celsius, 100 degrees. Fahrenheit, 180 degrees Temperature scales Water Boiling 100 212 Freezing 0 32 Absolute zero -273.15 -459.69 373.15 273.15 0 CelsiusoC Fahrenheit oF Kelvin, K (absolute) Absolute zero: Temperature at which all thermal motion ceases Room temperature 20o Celsius 68o Fahrenheit 293 Kelvin SI unit of temperature is the Kelvin Temperature scales Gas pressure depends on temperature Example Tyres have higher pressure when hot compared with cold. Ideal gas: Is a collection of atoms or molecules • move randomly •considered to be point-like •exert no long-range forces on each other. •occupy negligible volume. Most gases at atmospheric pressure and room temperature behave approximately as ideal gases Kelvin Temperature Scale Ideal gas Constant volume Constant pressure P V -273.15 -200 -273.15 T oC 200 Linear relationship exists between pressure and temperature at constant volume -200 T oC 200 Linear relationship exists between volume and temperature at constant pressure All plotted lines extrapolate to a temperature intercept of -273.15 oC regardless of initial low pressure (or volume) or type of gas Unique temperature called absolute zero Fundamental importance Kelvin Temperature Scale Unique temperature of -273.15oC is called absolute zero, below which further cooling will not occur Fundamental importance and the basis of the Kelvin temperature scale Kelvin Scale defined by 2 points. absolute zero -273.15oC Triple point of water- temperature at which 3 phases, solid, liquid, and gas are in equilibrium 0.01 oC Kelvin (K) scale ●same basic unit size as Celsius T K T C 273.15 Example: Freezing point of water : 273.15 K Boiling point of water: 373.15 K Converting Temperatures Celsius to Fahrenheit : T F 9 T C 32 5 Fahrenheit to Celsius : T C 5 T F 32 9 Celsius and Fahrenheit scales allow for negative temperature Thermometers •Alcohol in glass •Mercury in glass Depends on thermal expansion Example. Body temperature can increase from 98.60F to 1070F during extreme physical exercise or during viral infections. Convert these temperatures to Celsius and Kelvin and calculate the difference in each case. T C 5 T F 32 9 T C 5 98.6F 32 37oC 9 T C 5 107F 32 41.7oC 9 Difference DT(0C)= [41.7-37]0C = 4.70C T K T C 273.15 T K 37C 273.15 310.15K T K 41.7C 273.15 314.85K Difference DT(K) = [314.85-310.15]K = 4.7K Temperature and Heat Applications Oral environment temperature is not constant; Hot and cold food and drink Dental pulp is sensitive, may be damaged if its temperature increases >5oC) Dental drilling Rise in temperature of pulp during drilling should be less than 5 oC Dental materials: Important characteristics transfer of heat Dimensional changes: expansion and contraction Thermal expansion Most materials •expand when temperature is increased •contract when temperature is decreased this is called thermal expansion and contraction Low Temperature High Temperature Origin: When the average kinetic energy (or ‘speed’) of atoms is increased, they experience stronger collisions, increasing the separation between atoms. Thermal expansion Thermal expansion depends on: •Material •Size, •Temperature change. Assume no change in phase Linear Thermal Expansion Important, for example, for metals in buildings, bridges and dental filling materials etc. Thermal expansion Temperature T L Temperature (T DT ) DL L DL Bar of initial length L changes by an amount DL when its temperature changes by an amount DT. Coefficient of linear expansion a for the material is defined as: Fractional change in length a= Change in temperature DL/L DT Thermal expansion linear expansion: DL (L)(a )(DT ) units m m oC-1 or K-1 C or K DL = change in length L = original length DT = change in temperature (C or K) a coefficient of linear expansion units (°C-1 or K- 1)* a depends on the type of material. *Temperature interval is the same for Celsius and Kelvin scales Thermal expansion Important in dental restorations Decayed dentine removed and replaced by filling. Coefficient of thermal expansion of the restorative material should be similar to that of the tooth Thermal expansion/contraction due to hot and cold foods should not cause separation at the tooth-filling interface Large mismatch in expansion coefficients: •Fluids leakage between filling and surrounding tooth Thermal expansion Dimensional changes minimised by transient nature of thermal stimuli relatively low “thermal diffusivity” of non-metallic restorative materials Example 10oC temperature change for 1 sec Little change in bulk material dimensions Coefficient of Thermal linear expansion Enamel Dentine Amalgam Composite filling material Gold 11.4* x 8.3 X 10-6 K-1 10-6 K-1 25 x 10-6 K-1 14.5x 10-6 K-1 ≈ 30 x 10-6 K-1 Composite material: repeated thermal cycling: bonded joint between the filling and the tooth may loosen. Thermal expansion Coefficient of Thermal linear expansion Enamel Dentine Amalgam Composite filling material 11.4 x 8.3 X 10-6 K-1 10-6 K-1 25 x 10-6 K-1 ≈30 x 10-6 K-1 Gold 14.5x 10-6 K-1 Example Amalgam 8 mm wide, oral temperature decreases by 5 oC. Calculate relative thermal contraction. DL (L)(a )(DT ) Amalgam contracts by DL (8mm)(25 106 C 1 )(5 oC ) 110 3 mm Tooth enamel contracts by DL (8mm)(11.4 106 C 1 )(5 oC ) 0.45 103 mm Relative thermal contraction = 0.55 mm Thermal expansion Application Thermostat Thermally activated Electrical switch Bimetallic strip brass steel 20oC Switch closed Brass has larger coefficient of thermal expansion 23oC Switch open Mercury or Alcohol thermometer . − Why is there a reservoir at the bottom of a thermometer? − − − − amercury = 60 x 10-6 °C-1 − − Column Assume length of the column is 10cm, range of temperature is 35 to 43°C, − − − − − − − − thermal expansion of the column is: − − Reservoir DL ( L)(a )(DT ) (0.1m)(60 x 10-6 )(8.0) DL 4.8 x 10 m = 0.048mm -5 This increase in length due to thermal expansion would never be visible using a simple column. Adding a reservoir increases the volume of mercury and thus the expansion. Area Thermal expansion linear thermal expansion: T T+DT DL ( L)(a )(DT ) L L DL area thermal expansion: DA = ? A A DA Consider square, side length L, area A = L2 New area: A+ DA = (L+ DL)2 = L2 + 2L DL + DL2 A+ DA ≈ L2 + 2L DL Thus DA = 2L DL = 2L(LaDT) DA = L2(2a)DT = A(2a)DT Thus, the coefficient of area expansion is approximately 2a Volume expansion DV = V(g)DT g = coefficient of volume expansion Example A 50 ml glass container is filled to the brim with methanol at 0.0oC. If the temperature is raised to 40oC will any methanol spill out? If so, how much? g glass ≈ 9 x10-6 (oC-1) g methanol ≈ 1200 x10-6 (oC-1) Volume spilled = DV(methanol) – DV(glass) DV(glass) = 50.0ml(9 x10-6 (oC-1)(40oC) = 0.018ml DV(methanol) = 50.0ml(1200 x10-6 (oC-1)(40oC) = 2.4ml Therefore 2.4ml – 0.018ml = 2.38 ml will spill out Exercise: A steel measuring tape used by a civil engineer is 50metres long and calibrated at 20oC. The tape measures a distance of 35.694m at 35oC. What is the actual distance measured? Coefficient of linear expansion of steel a = 1.2 x10-5 oC-1 DL ( L)(a )(DT ) DL = (50 m)(15oC)(1.2x10-5 oC-1) DL = 900x10-5m =0.009m Length of tape at 35oC = 50.009m 20oC 35oC 50.009m (35.694m) = 35.700m 50.0000 Error =6mm Example. Concrete slabs of length 25 m are laid end to end to form a road surface. What is the width of the gap that must be left between adjacent slabs at a temperature of -150C to ensure they do not buckle at a temperature of +450C.Coefficient of thermal expansion for concrete a = 12x10-6 0C Slabs should barely touch at the higher temperature. Each slab must expand at either end by an amount equal to half the gap. The total expansion of each slab should be equal to the gap. DL ( L)(a )(DT ) DT =600C DL = 25m*12x10-6(0C-1)* 600C = 18 x10-3m
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