Cup Dimensions
• Volume = 12oz = c 22in^3
• 22in^3 = piR^2h h=22/piR^2
• Using optimazion…
SA = piR^2 + 2piRh
SA = piR^2 + 44/R^2
• f(r)=piR^2 + 44/R
• f’(r)= 2piR – 44/R^2
• R = (22/pi)^(1/3) which is approximately 1.91in
• Using h=22/piR^2… h=1.91in
• SA = piR^2 + 2piRh
• SA = 34.38in^2
Plate and Bowl Dimensions
• Plate
• 9 in diameter
• SA = piR^2
• SA = 63.62in^2
• Bowl
• 9 oz bowl
• Diamter approx. 6.5in
• SA=1/2(4piR^2) = 2piR^2
• SA = 2pi(3.25)^2 = 66.37in^2