Overall Review 1
.06
200(1 + ( ))(4β3.5)
4
The log graph is reflected across the x axis and y axis
D:{x|xβ 0} R: all reals
x = -2,2, no y-intercepts
no horizontal asymptotes
x=0
y = -5x
βπ₯ 2 + 24π₯ = π’ then u2 + u = 30 = 0
(u+6)(u-5) = 0 u = 5
βπ₯ 2 + 24π₯ = 5
X2 + 24X β 25 = 0
(X+25)(X-1) = 0
5( x2 ) + 3
(5x+3 )2 FOIL OUT
5(5x+3) + 3
(π₯ 2 )2
x=
2
2
(7 , β)
7
(-β, 1)
x=1
(1,5)
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