Solutions Big Idea Chemical and Physical Properties of materials can be explained by the structure and the arrangement of atoms, ions or molecules and the forces between them. Essential Knowledge Chemical Analysis provides a method for determining the relative number of atoms in a substance, which can be used to identify the substance or determine its purity. Page 1 1 Solution Vocabulary The solvent does the dissolving. The solute is dissolved. There are examples of all types of solvents dissolving all types of solvent. We will focus on aqueous solutions. Various Types of Solutions State of Solution Example State of Solute State of Solvent Air, natural gas Gas Gas Gas Vodka, antifreeze Liquid Liquid Liquid Brass Solid Solid Solid Carbonated water (soda) Liquid Gas Liquid Seawater, sugar solution Liquid Solid Liquid Hydrogen in platinum Solid Gas Solid 5 Copyright © Cengage Learning. All rights reserved Concentration of Solutions Molarity = moles of solute Liters of solution % mass = Mass of solute x 100 Mass of solution Mole fraction of component A χA = nA nA + nB Page 2 2 Concentration of Solutions Molality = Molality is abbreviated m Normality moles of solute Kilograms of solvent -skip Exercise What is the percent-by-mass concentration of glucose in a solution made my dissolving 5.5 g of glucose in 78.2 g of water? 6.6% 8 Copyright © Cengage Learning. All rights reserved Exercise A solution of phosphoric acid was made by dissolving 8.00 g of H3PO4 in 100.0 mL of water. Calculate the mole fraction of H3PO4. (Assume water has a density of 1.00 g/mL.) 0.0145 9 Copyright © Cengage Learning. All rights reserved Page 3 3 Exercise A solution of phosphoric acid was made by dissolving 8.00 g of H3PO4 in 100.0 mL of water. Calculate the molality of the solution. (Assume water has a density of 1.00 g/mL.) 0.816 m 10 Copyright © Cengage Learning. All rights reserved Inquiry Question Consider two aqueous solutions, A and B (which contain different solutes). Is it possible for solution A to have a greater concentration than solution B in terms of mass percent, but a smaller concentration in terms of molarity? If no, explain why not. If yes, provide an example. What if the solutions contained the same solute? Concentration Vocabulary Dilute vs Concentrated Activity Page 4 4 Big Idea Chemical and Physical Properties of materials can be explained by the structure and the arrangement of atoms, ions or molecules and the forces between them. Essential Knowledge Net changes in energy for a chemical reaction or a physical change can be endothermic or exothermic. Energy of Making Solutions Heat of solution ( ∆Hsoln ) is the energy change for making a solution. Most easily understood if broken into steps. 1.Break apart solvent 2.Break apart solute 3. Mixing solvent and solute Page 5 5 Steps in the Dissolving Process 16 Copyright © Cengage Learning. All rights reserved 1. Break apart Solvent Have to overcome attractive forces. ∆H1 >0 2. Break apart Solute. Have to overcome attractive forces. ∆H2 >0 3. Mixing solvent and solute This explains the rule “Like dissolves Like” ∆H3 depends on what you are mixing. If molecules can attract each other ∆H3 is large and negative. Molecules can’t attract- ∆H3 is small and negative. Page 6 6 Enthalpy (Heat) of Solution 19 Copyright © Cengage Learning. All rights reserved Enthalpy (Heat) of Solution 20 Copyright © Cengage Learning. All rights reserved Enthalpy (Heat) of Solution If ∆Hsoln is small and positive, a solution will still form because of entropy. There are many more ways for them to become mixed than there is for them to stay separate. Page 7 7 Big Idea Chemical and Physical Properties of materials can be explained by the structure and the arrangement of atoms, ions or molecules and the forces between them. Essential Knowledge The solubility of a substance can be understood in terms of chemical equilibrium. Solubility Def ≡ The amount of substance solute that dissolves in a given volume of solvent at a given temperature Page 8 8 Solubility Solubility Ksp Solubility product constants are used to describe saturated solutions of ionic compounds of relatively low solubility. Solubility A saturated solution is in a state of dynamic equilibrium between the dissolved, dissociated, ionic compound and the undissolved solid. MxAy(s) --> x My+(aq) + y Ax-(aq) The general equilibrium constant for such processes can be written as: Ksp = [My+]x[Ax-]y Page 9 9 Solubility Ksp If an ionic compound is “insoluble”, what kind of value would you expect? Soluble? Ksp Calculation Calculating Ksp's from Solubility Data In order to calculate the Ksp for an ionic compound you need the equation for the dissolving process so the equilibrium expression can be written. You also need the concentrations of each ion expressed in terms of molarity, or moles per liter, or the means to obtain these values. Calculating Ksp Calculate the solubility product constant for lead(II) chloride, if 50.0 mL of a saturated solution of lead(II) chloride was found to contain 0.2207 g of lead(II) chloride dissolved in it. Page 10 10 Calculating Ksp First, write the equation for the dissolving of lead(II) chloride and the equilibrium expression for the dissolving process. PbCl2(s) --> Pb2+(aq) + 2 Cl-(aq) Ksp = [Pb2+][Cl-]2 Calculating Ksp Second, convert the amount of dissolved lead(II) chloride into moles per liter. (0.2207 g PbCl2)(1/50.0 mL solution)(1000 mL/1 L)(1 mol PbCl2/278.1 g PbCl2) = 0.0159 M PbCl2 Calculating Ksp Place Values in the Solubility Product Expression PbCl2(s) --> Pb2+(aq) + 2 Cl-(aq) [0.0159] [0.0159] [0.0318] 2+ 2 Ksp = [Pb ][Cl ] Ksp = [0.0159][0.0318]2 = 1.61 x 10-5 Page 11 11 Big Idea Chemical and Physical Properties of materials can be explained by the structure and the arrangement of atoms, ions or molecules and the forces between them. Essential Knowledge Intermolecular forces play a key role in determining the properties of substances, including biological structures and interactions. Factors Affecting Solubility Structure of the molecule • Polarity Pressure • Henry’s Law Temperature • Affect on aqueous solutions Page 12 12 Factors Affecting Solubility: Structure soluble molecules must have dipole moments -polar bonds. To be soluble in nonpolar solvents the molecules must be non polar. Read Vitamin A - Vitamin C, water soluble vitamins Water Factors Affecting Solubility: Structure Structure of Soap CH2 CH3 CH2 CH2 P CH2 CH2 CH2 O- CH2 O- O- Page 13 13 Structure of Soap CH2 CH3 CH2 CH2 CH2 CH2 O- P CH2 CH2 O- O- Hydrophobic non-polar end Soap CH2 CH3 CH2 OO- O- CH2 CH2 CH2 P CH2 CH2 Hydrophilic polar end O- CH2 CH3 CH2 CH2 P CH2 CH2 CH2 CH2 O- O- _ Page 14 14 A drop of grease in water Grease is non-polar Water is polar Soap lets you dissolve the non-polar in the polar. Hydrophobic ends dissolve in grease Hydrophilic ends dissolve in water Page 15 15 Water molecules can surround and dissolve grease. Helps get grease out of your way. Factors Affecting Solubility: Pressure Changing the pressure doesn’t affect the amount of solid or liquid that dissolves • They are incompressible. Changing the pressure does affect gases. • Why is it important to understand this? – Blood gases, Manufacture of Pop Dissolving Gases Pressure affects the amount of gas that can dissolve in a liquid. The dissolved gas is at equilibrium with the gas above the liquid. Page 16 16 The gas is at equilibrium with the dissolved gas in this solution. The equilibrium is dynamic. If you increase the pressure the gas molecules dissolve faster. The equilibrium is disturbed. Pressure Effects 51 Henry’s law: Amount of gas dissolved in a solution is directly proportional to the pressure of the gas above/outside of the solution. Copyright © Cengage Learning. All rights reserved Page 17 17 Application of Henry’s Law When people work in a space where the air pressure is much above normal, they have to be careful to return slowly to the atmosphere. Otherwise, they face the danger of the "bends." The bends are severe pains in the joints and muscles, fainting, possible deafness, paralysis, and death. Workers building deep tunnels, where higher than normal air pressure is maintained to keep water out, are at risk, so are deep-sea divers and scuba divers who stay down for to prolonged a period. The bends develop because the solubilities of both nitrogen and oxygen are higher under higher pressure, as Henry's Law states. Once the blood is enriched in these gases it must not be allowed to lose them suddenly. If the person returns to normal atmospheric pressure to rapidly the blood will act like a soda pop bottle and fizz. If microbubbles of nitrogen and oxygen appear at blood capillaries, they will block the flow of blood. Such a loss is particularly painful at joints, and any reduction in blood flow to the brain can be extremely serious. Application of Henry’s Law Henry’s Law: Pressure Effects Henry’s law: C = kHP C = concentration of dissolved gas, M kH P = = Henry’s Law constant, M/atm partial pressure of gas solute above the solution, atm Conditions when this holds true: • • 54 Dilute solutions Gas does not interact with solvent Copyright © Cengage Learning. All rights reserved Page 18 18 Henry’s Law Example How many grams of carbon dioxide gas is dissolved in a 1.00 L bottle of carbonated water if the manufacturer uses a pressure of 2.40 atm in the bottling process at 25 °C? Given: KH of CO2 in water = 29.76 atm/(mol/L) at 25 °C Henry’s Law Example P = KHC P is the partial pressure of the gas above the solution KH is the Henry's Law constant for the solution C is the concentration of the dissolved gas in solution C = P/KH C = 2.40 atm/29.76 atm/(mol/L) C = 0.0806 mol/L since we only have 1 L of water, we have 0.08 mol of CO2. Henry’s Law Example Convert moles to grams g of CO2 = 0.0806 mol x 44 g/mol g of CO2 = 3.52 g There are 3.52 g of CO2 dissolved in a 1 L bottle of carbonated water from the manufacturer. Page 19 19 Factors Affecting Solubility: Temperature Increased temperature increases the rate at which a solid dissolves. We can’t predict whether it will increase the amount of solid that dissolves. We must read it from a graph of experimental data. The Solubilities of Several Solids as a Function of Temperature 59 Copyright © Cengage Learning. All rights reserved Gases are predictable As temperature increases, solubility decreases. Gas molecules can move fast enough to escape. Thermal pollution. Page 20 20 Temperature Effect on Gas Solubility The Solubilities of Several Gases in Water 62 Copyright © Cengage Learning. All rights reserved Big Idea Chemical and Physical Properties of materials can be explained by the structure and the arrangement of atoms, ions or molecules and the forces between them. Page 21 21 Essential Knowledge Intermolecular forces play a key role in determining the properties of substances, including biological structures and interactions. Vapor Pressure of Pure Solvent vs Solution Vapor Pressure of Solutions A nonvolatile solvent lowers the vapor pressure of the solution. The molecules of the solvent must overcome the force of both the other solvent molecules and the solute molecules. Page 22 22 Water has a higher vapor pressure than a solution Aqueous Solution Pure water Water evaporates faster from for water than solution Aqueous Solution Pure water The water condenses faster in the solution so it should all end up there. Aqueous Solution Pure water Page 23 23 Skills Needed for Today’s Notes mole fraction of particles of solvent Raoult’s Law: Psoln = χsolvent x Psolvent Vapor pressure of the solution • mole fraction of solvent • vapor pressure of the pure solvent Applies only to an ideal solution where the solute doesn’t contribute to the vapor pressure • “Nonvolatile solute” • Vapor Pressures of Solutions Nonvolatile solute lowers the vapor pressure of a solvent. Raoult’s Law: Psolution = Psolvent χsolvent Psolution = observed vapor pressure of solution χ solvent = mole fraction of particles of solvent Psolvent= vapor pressure of pure solvent On the AP HELP SHEET: 72 PA = Ptotal χ A Copyright © Cengage Learning. All rights reserved Page 24 24 Vapor Pressures of Solutions Raoult’s Law: PA = Ptotal χA • Complete the following statement: • The vapor pressure of the solvent will change when… • The adjusted vapor pressure depends on # solute components. • How would the TYPE of solute affect the mole fraction? • How would a molecular solute behave when dissolved in water? An ionic solute? 73 Copyright © Cengage Learning. All rights reserved 4 Types of Raoult’s Law Problems Solution of nonvolatile nonelectrolytic solute in a solvent Solution of a nonvolatile electrolytic solute in a solvent Solution of 2 volatile substances Finding Molar Mass using Raoult’s law Raoult’s Law General Problem A solution of cyclopentane with a nonvolatile compound has vapor pressure of 211 torr. If vapor pressure of the pure liquid is 313 torr, what is the mole fraction of the cyclopentane? Page 25 25 Raoult’s Law Nonvolatile nonelectrolytic solute A solution of cyclopentane with a nonvolatile compound has vapor pressure of 211 torr. If vapor pressure of the pure liquid is 313 torr, what is the mole fraction of the cyclopentane? • The adjusted vapor pressure depends on # solute components. • How is this formula affected by an electrolytic compound? • For example: • 2 moles of Copper II chloride is dissolved in 10 moles of water Raoult’s Law Nonvolatile electrolytic solute Calculate the vapor pressure of the solution when 55 grams of KI are added to 325 mL of water at 25°C. The vapor pressure of water at 25°C is 23.8 mm Hg. Page 26 26 Raoult’s Law Finding Molar Mass of the Solute Solute and Solvent are volatile Liquid-liquid solutions where both are volatile. Both contribute to the vapor pressure Modify Raoult’s Law to PA + PB = χAPAtotal + χBPBtotal Ptotal = expected vapor pressure of mixture PAtotal= vapor pressure of pure A Ptotal = Solute and Solvent are volatile Reminder Σ about χ χ = _______ A solution is made up of 2 volatile substances, a & b. If χa = .452, what is χb ? Page 27 27 Practice Question is the composition of a pentane-hexane solution that has a vapor pressure of 350 torr at 25ºC ? The vapor pressures at 25ºC are • pentane 511 torr • hexane 150 torr. What is the composition of the vapor? Vapor Pressure What P of pure A P of pure B χA χb Deviations (Nonideal Solutions) If solvent has a strong affinity for solute (ex.H bonding) or concentrated solution Lowers solvent’s ability to escape. Lower vapor pressure than expected. Negative deviation from Raoult’s law. ∆Hsoln is large and negative exothermic. Endothermic ∆Hsoln indicates positive deviation. Page 28 28 Vapor Pressure Positive deviationsWeak attraction between solute and solvent Positive ∆Hsoln Vapor Pressure χA χb Negative deviationsStrong attraction between solute and solvent Negative ∆Hsoln χA χb Big Idea Chemical and Physical Properties of materials can be explained by the structure and the arrangement of atoms, ions or molecules and the forces between them. Page 29 29 Essential Knowledge Intermolecular forces play a key role in determining the properties of substances, including biological structures and interactions. Colligative Properties Because dissolved particles affect vapor pressure - they affect phase changes. Colligative properties depend only on the number - not the kind of solute particles present Useful for determining molar mass Molal Freezing Point/Boiling Point Constants pg 517 Page 30 30 Boiling point Elevation Because a non-volatile solute lowers the vapor pressure it raises the boiling point. ∆T = Kbmsolute ∆T is the change in the boiling point Kb is a constant determined by the solvent. msolute is the molality of the solute Boiling Point Elevation ∆T = Kbmsolute At what temperature will a solution that is composed of 0.73 moles of glucose in 650.0 mL of water begin to boil? At what temperature will a sucrose solution, C11H22O11, boil if it contains 175 grams of sucrose in 750. mL of water? Boiling Point Elevation What mass (in g) of a nonelectrolytic molecular substance (MW = 50.0 g/mol) must be added to 500. g of water to produce a solution that boils at 101.56 ºC? Page 31 31 Freezing Point Depression Because a non-volatile solute lowers the vapor pressure of the solution it lowers the freezing point ∆T = Kf msolute ∆T is the change in the freezing point Kf is a constant determined by the solvent msolute is the molality of the solute Freezing Point Depression ∆T = Kf msolute At what temperature will an methanol solution, CH3OH, freeze if it contains 55.0 grams of methanol in 1200. mL of water? At what temperature will a solution of ethylene glycol (C2H6O2)freeze if it contains 120. grams of ethylene glycol in 500.0 mL of water? Calculating Molar Mass Vitamin B2, riboflavin, is soluble in water. If 0.833 g of riboflavin is dissolved in 18.1 g H2O, the resulting solution has a freezing point of -0.227 ºC. What is the molar mass of riboflavin? Page 32 32 Background: Van’t Hoff factor, i Van’t Hoff corrects for the fact that the number of particles you thrown into solution is not always the number of particles that determine the magnitude of the property. Van’t Hoff factor, i For example, think about what happens when you put the following one mole quantities into a liter of water. Which one raises the boiling point the most? Van’t Hoff factor, i Electrolytes have a bigger impact on on melting and freezing points per mole because they make more pieces. Relationship is expressed using the van’t Hoff factor i i = Moles of particles in solution Moles of solute dissolved The expected value can be determined from the formula of the compound. Page 33 33 Example Predict the van't Hoff factor for Sr(OH) 2 What is the van't Hoff factor for Fe(NO 3 ) 3 Example Determine the freezing point of a 1.77 m solution of NaCl in H 2 O Example Determine the boiling point of a solution made up of dissolving 49.19 g of CaCl 2 in 500. mL of H 2 O Page 34 34 Big Idea Chemical and Physical Properties of materials can be explained by the structure and the arrangement of atoms, ions or molecules and the forces between them. Essential Knowledge Intermolecular forces play a key role in determining the properties of substances, including biological structures and interactions. Osmotic Pressure When two solutions of different concentrations are separated by the right kind of membrane, their concentrations change in the direction of becoming equal. Page 35 35 Example of Osmotic Pressure In living things, membranes of various kinds keep mixtures organized and separated. These membranes are semipermeable, which means that they let water molecules as well as small ions and other small molecules pass through. However they do not allow the passage of very large molecules, like those of proteins. Example (continued) This phenomenon, the selective passage of small ions and molecules through a membrane, is called dialysis, and the membrane is a dialyzing membrane. Example (continued) In the limiting case of dialysis, osmosis, only solvent molecules can get through the membrane, now called an osmotic membrane. Such membranes are rare, but they can be made. Page 36 36 What is osmosis? One theory that can be used to explain osmosis is that an osmotic membrane separates two solutions from each other, one solution being more concentrated in solute than the other. The solvent in each solution has its own "escaping tendency", which is just like the vapor pressure of a solution. What is osmosis? The solution with the lower solute concentration has, of course, the higher mole fraction of solvent. Therefore, solvent molecules in the less concentrated solution (or the pure solvent) have a higher escaping tendency than those in the more concentrated solution. What is osmosis? So solvent molecules escape through the membrane more frequently from the less concentrated side and pass into the more concentrated solution. Page 37 37 Osmosis The effect is a net shift of solvent through the membrane from the less concentrated side to the more concentrated side. This is osmosis, and it will continue, in principle, until the concentrations of the solutions become equal. http://molit.concord.org/database/activities/23.html Application To Biology Osmotic Pressure = MRT molarity of solute R: ideal gas law constant • 0.0821 L atm/mol K T: temperature, K π: Osmotic pressure, atm π M: Page 38 38 Osmotic Pressure = MRT A very dilute solution, 0.0010 M sugar in water, is separated from pure water by an osmotic membrane. What osmotic pressure developed at 25oC ? π Inquiry Question: Your Choice Why would it be deadly to give a hospital patient distilled water instead of saline? Why would it be a major problem for a salt water fish to be placed in fresh water? Inquiry Lab Design an experiment that would demonstrate different types of solutes dissolved in the solvent water and their effects on osmotic pressure of an egg. Hint: First step in the lab will be to get rid of the shell of the egg. Page 39 39
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