Warm Up 5-5 Simplify the Radical. 1) 5 32 4 Complete the square. 5) π₯ 2 + 18π₯ + 56 Solve equations using the square root. 2) =0 25 3 3) π₯ 2 = β11 4) 2π₯ 2 β 54 = 0 Solve equations using the zero product. 6) π₯ 2 β 11π₯ + 18 = 0 Solve equation using the zero product. 7) π₯ 2 +π₯ = 4 Unit 8 Day 7: Graphing Quadratic Equations Essential Question: How do we graph a quadratic function? 1) Function: y = x2 β 3x + 2 a =1 b = -3 c=2 Leading Coefficient: The graph opens: a= β’ up (circle one) 1 β’ down Discriminant: (-3)2 - 4(1)(2) 9-8 1 Quadratic Formula: How many solutions does the equation have? (circle one) β’ TWO β’ ONE β’ NO REAL SOLUTIONS Find the solutions by using the quadratic formula/factoring. (x - 2)(x - 1) = 0 OR factor if you can! x-2=0 x-1=0 x=2 x=1 Quadratic Formula: Find the solutions by using the quadratic formula. 2&1 Vertex: 3 x= = 3/2 2(1) x Table of Values: y = x2 β 3x + 2 0 (0)2 - 3(0) + 2 = 0 - 0 + 2 =2 2 1 (1)2 - 3(1) + 2 =0 0 vertex: 3/2 =1-3 +2 y (3/2)2 - 3(3/2) + 2 = 9/4 - 9/2 + 2 = -1/4 -1/4 2 (2)2 - 3(2) + 2 =4-6 +2 =0 0 3 (3)2 - 3(3) + 2 = 9- 9 + 2 =2 2 The Graph! Now use all the information you found to graph the parabola. x y 0 1 3/2 2 3 2 0 -1/4 0 2 Graph: 1. The vertex (and how it opens). 2. The x-intercepts (where it crosses the x-axis). 3. The (x , y) values from the table. 4. Connect the dots! 10 5 -10 -5 5 You can do it! -5 -10 10 2) Function: y = -2x2 + 6x - 3 a = -2 b= 6 c = -3 Leading Coefficient: The graph opens: a= β’ up (circle one) -2 β’ down Discriminant: (6)2 - 4(-2)(-3) 36 - 24 12 Quadratic Formula: OR factor if you can! How many solutions does the equation have? (circle one) β’ TWO β’ ONE β’ NO REAL SOLUTIONS Find the solutions by using the quadratic formula/factoring. x= -6 ± 12 2 (-2) = -3 + 3 -2 -6 ± 2 3 -4 -3 - 3 -2 Quadratic Formula: Find the solutions by using the quadratic formula. -3 + 3 -2 Vertex: -6 x= = 3/2 2(-2) & -3 - 3 -2 x Table of Values: y = -2x2 + 6x - 3 y 0 -2(0)2 + 6(0) - 3 -3 1 -2(1)2 + 6(1) - 3 1 3/2 -2(3/2)2 + 6(3/2) - 3 3/2 2 -2(2)2 + 6(2) - 3 1 3 -2(3)2 + 6(3) - 3 -3 vertex: The Graph! Now use all the information you found to graph the parabola. x y 0 1 3/2 2 3 -3 1 3/2 1 -3 Graph: 1. The vertex (and how it opens). 2. The x-intercepts (where it crosses the x-axis). 3. The (x , y) values from the table. 4. Connect the dots! 10 5 -10 -5 5 You can do it! -5 -10 10 3) Function: y = x2 - 8x + 16 a= 1 b = -8 c = 16 Leading Coefficient: The graph opens: a= β’ up (circle one) 1 β’ down Discriminant: (-8)2 - 4(1)(16) 64 - 64 0 Quadratic Formula: How many solutions does the equation have? (circle one) β’ TWO β’ ONE β’ NO REAL SOLUTIONS Find the solutions by using the quadratic formula/factoring. (x - 4)(x - 4) = 0 OR factor if you can! x-4=0 x=4 Quadratic Formula: Find the solutions by using the quadratic formula. 4 Vertex: 8 x= =4 2(1) x Table of Values: y = x2 β 8x + 16 y 2 (2)2 - 8(2) + 16 4 3 (3)2 - 8(3) + 16 1 4 (4)2 - 8(4) + 16 0 5 (5)2 - 8(5) + 16 1 6 (6)2 - 8(6) + 16 4 vertex: The Graph! Now use all the information you found to graph the parabola. x y 2 3 4 5 6 4 1 0 1 4 Graph: 1. The vertex (and how it opens). 2. The x-intercepts (where it crosses the x-axis). 3. The (x , y) values from the table. 4. Connect the dots! 10 5 -10 -5 5 You can do it! -5 -10 10 4) Function: y = x2 - x + 1 a= 1 b = -1 c=1 Leading Coefficient: The graph opens: a= β’ up (circle one) 1 β’ down Discriminant: (-1)2 - 4(1)(1) 1-4 -3 Quadratic Formula: OR factor if you can! How many solutions does the equation have? (circle one) β’ TWO β’ ONE β’ NO REAL SOLUTIONS Find the solutions by using the quadratic formula/factoring. We donβt need to use this because there are no solutions! Quadratic Formula: Find the solutions by using the quadratic formula. NRS Vertex: 1 x= = 1/2 2(1) x Table of Values: y = x2 β x + 1 y -1 (-1)2 - (-1) + 1 3 0 (0)2 - (0) + 1 1 1/2 (1/2)2 - (1/2) + 1 3/4 1 (1)2 - (1) + 1 1 2 (2)2 - (2) + 1 3 vertex: The Graph! Now use all the information you found to graph the parabola. x y -1 0 1/2 1 2 3 1 3/4 1 3 Graph: 1. The vertex (and how it opens). 2. The x-intercepts (where it crosses the x-axis). 3. The (x , y) values from the table. 4. Connect the dots! 10 5 -10 -5 5 You can do it! -5 -10 10 Summary Respond to the essential question in the summary potion of your notes. Essential Question: How do we graph a quadratic function?
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