LECTURE 2 PASCAL’S PRINCIPLE Lecture Instructor: Kazumi Tolich Lecture 2 2 ¨ Reading chapter 11-4 to 11-6 ¤ Pressure and depth ¤ Pascal’s principle Force and depth in static fluid 3 ¨ ¨ ¨ Consider a cylinder with a cross-sectional area of A, filled with a fluid with a density ρ. The force pressing at the top is less than the force pressing at the bottom because of the weight of the water. At the surface, the pressure must be at atmospheric pressure. Ftop = Pat A Fbottom = Ftop + ρ ( Ah ) g Pressure and depth 4 ¨ Since the pressure is the force divided by area, if the force increases as you go deeper, the pressure also increases as you go deeper in the fluid. P2 = P1 + ρ gh Demo: 1 5 ¨ Pressure vs. Depth in water and alcohol ¤ Demonstration pressure P2 = P1 + ρ gh of the depth and density dependence of Clicker question: 1 6 Example: 1 7 ¨ A diver swims to a depth of d = 3.2 m in a freshwater lake. What is the increase in the force pushing in on her eardrum, compared to what it was at the lake surface? The area of the eardrum is A = 0.60 cm2. Example: 2 8 ¨ Many people have imagined that if they were to float the top of a flexible snorkel tube out of the water, they would be able to breathe through it while walking underwater. However, they generally do not take into account just how much water pressure opposes the expansion of the chest and the inflation of the lungs. Suppose you can just breathe while lying on the floor with a 400-N (90-lb) weight on your chest. How far below the surface of the water could your chest be for you still to be able to breathe, assuming your chest has a frontal area of 0.090 m2? Mercury barometer 9 ¨ ¨ A barometer can measure atmospheric pressure using the variation of pressure with depth of a fluid. A glass tube is filled with a fluid with a density ρ and placed upside-down in the same fluid in a bowl. Pat = ρ gh ¨ Mercury is often used because of its high density. 1 atmosphere ≡ Pat ≡ 760 mmHg vacuum Demo: 2 10 ¨ Mercury barometer in vacuum ¤ Demonstration pressure of mercury barometer to measure Clicker question: 2 11 Water level 12 ¨ Fluids flow until equilibrium is reached. ¨ The pressure at the surface exposed to air is at Pat. ¨ In equilibrium, the net force on each section of the fluid is zero. ¨ The pressure in the fluid Demo: 3 13 ¨ Pascal’s vases ¤ Demonstration of water levels Demo: 4 14 ¨ Water and mercury in U-tube ¤ Measurement of relative densities of water and mercury from the heights of liquid boundaries Clicker question: 3 15 Example: 3 16 ¨ A U-shaped tube is filled mostly with water, but a small amount of oil has been added to both sides. The density of water is ρw = 1.00 × 103 kg/m3, and the density of the oil is ρo = 9.20 × 102 kg/m3. On the left side of the tube, the depth of the oil is dL = 3.00 cm, and on the right side of the tube, the depth of the oil is dR = 5.00 cm. Find the difference in fluid level between the two sides of the tube. Pascal’s principle 17 ¨ ¨ According to Pascal's principle, an externally applied pressure changes the pressure at every point in a confined liquid or gas by the same amount. An example of Pascal’s principle in action is hydraulic lift. F1 F2 ΔP = = A1 A2 A1d1 = A2 d2 Example: 4 18 A hydraulic lift has two pistons with different diameters initially at the same height. The smaller piston has a diameter of D1 = 1.5 m, and the larger piston has a diameter of D2 = 21 m. ¨ a) b) If a weight with a mass m = 2000 kg is placed on the large piston, what weight on the small piston will be required to keep the pistons at the same height? Through what distance must the large piston be pushed down to raise the small piston a distance of d1 = 3.5 m? Demo: 5 19 ¨ Hydraulic press ¤ Demonstration of Pascal’s principle
© Copyright 2024 Paperzz