Foundation Worksheet 6:02 Equations with Grouping Symbols Name: Class: Examples 1 Expand. a 4(x − 3) = 4 × x − 4 × 3 = 4x − 12 2 Expand, then solve. a 3(y − 4) = 24 3y − 12 = 24 3y = 36 ∴ y = 12 b 7(3c + 5) = 7 × 3c + 7 × 5 = 21c + 35 b 5(2h + 1) = 35 10h + 5 = 35 10h = 30 ∴h=3 Exercise 1 Expand. a 5(x + 3) d 8(3m − 1) g 6(2y + 1) j 8(2x + 1) b 7(a − 4) e 4(k − 7) h 5(4x − 3) k 7(t − 5) 2 Expand, then solve. a 2(a + 3) = 8 d 8(x + 5) = 80 g 3(r + 1) = 33 j 10(2a − 3) = 50 m 6(d − 10) = 18 p 3(b + 5) = 36 b e h k n q 5(m − 1) = 10 4(2y − 3) = 20 2(x − 4) = 30 2(3t + 5) = 10 5(x + 2) = 40 2(3c − 5) = −4 c f i l 9(2y + 3) 3(q + 8) 10(4n + 5) 12(c + 1) c f i l o r 7(2n + 1) = 21 8(7k − 3) = 144 9(c + 6) = 63 3(4y + 3) = 63 7(m − 4) = 56 5(2p − 1) = −25 Fun Spot 6:02 | What bear goes around scaring other animals? Expand these, then match the letters with the answers below. B 4(a + 5) E 7(a − 4) H 5(2a − 1) N −2(2a − 3) O −4(a + 2) T −3(4a + 3) −a + 4 3a + 18 −4a + 6 −4a + 6 I 3(a + 6) W −(a − 4) 3a + 18 7a − 28 ! −12a − 9 10a − 5 Answers can be found in the Interactive Student CD. INTERNATIONAL MATHEMATICS 4 FOUNDATION WORKSHEETS 7a − 28 4a + 20 29 −4a − 8 −4a − 8 Copyright © Pearson Australia 2009 (a division of Pearson Australia Group Pty Ltd) This page may be photocopied for classroom use. IM4_Ch06_3pp.fm Page 141 Friday, March 13, 2009 4:54 PM 2 Expand each set of grouping symbols and then solve the equations. a 3(a + 7) = 4(a − 2) b 3(x + 4) + 2(x + 5) = 4 3a + 21 = 4a − 8 3x + 12 + 2x + 10 = 4 − 3a − 3a Collect like terms. 21 = a − 8 5x + 22 = 4 +8 +8 − 22 − 22 29 = a 5x = −18 ∴ a = 29 ÷5 ÷5 ∴ x = −3 3--5- Exercise 6:02 Just take it one step at a time. Foundation Worksheet 6:02 Equations with grouping symbols 1 Expand these grouping symbols. a 5(x + 3) b 7(a − 4) c 9(2y + 3) 2 Solve these equations. a 2(a + 3) = 8 b 5(m − 1) = 10 c 7(2n + 1) = 21 1 Expand the grouping symbols and then solve each equation. (Answers are all integers.) a 4(x + 1) = 20 b 8(a − 3) = 56 c 6(y − 3) = 18 d 3(2x + 1) = 21 e 5(3 − 4m) = 75 f 7(2b + 3) = 12b − 9 g a + 1 = 3(5 − 2a) h 9(2x + 3) = 3(7x − 1) i 14 + 4(2x − 1) = 2(5x − 2) j 3(5x − 2) + 2(5x − 2) = 5x + 10 2 Solve each equation using the worked examples as a guide. a 4(x − 3) = 5(x + 1) b 7(a + 5) = 3(5 − a) d 4(t − 1) = 2(t + 3) e 3(2x − 1) = 7(x − 5) g 9(x − 5) = 4(3x − 1) + 9 h 2(4m − 3) = 5m + 5(2m + 1) j 3t + 2(6 − 5t) − 4 = 9 − 10t k 5(2a − 1) + 3(2a − 1) = 10 m 4(3a − 1) + 2(5a + 6) = 10 n 6(5 − 3n) + 5(3n + 1) = 5 p 5x + 5(x + 5) − 9 = 0 q 7(1 − 2t) + 5(t − 8) + 5 = 0 c f i l o r Solve each equation. Use Worked Example 2(b) as a guide. a 3(a + 2) + a + 5 = 15 b 5(m − 1) + 2m = 2 d 3(x + 2) + 2(x − 3) = 10 e 5(p + 1) + 2(p + 4) = 20 g 4(2a + 3) + 2(a − 5) = 22 h 2(2m + 3) + 3(m − 5) = 5 c 2(m + 3) + 5(m + 2) = 23 f 4(t − 2) + 2(t + 5) = 14 i 5(a − 3) + 3(2 + 3a) = 19 3 4 5 6(5 − y) = 3(y + 1) 7(x + 1) = 2(2x − 3) 4(2a + 7) + 3a − 6 = 0 3(5 − 3y) + 12(y + 5) = 90 2(2y − 9) + (y + 8) = 5 4(4 + 3a) + 3(2 − a) = 7 Solve these equations, but first read the warning sign! a 3(x − 2) − 5(x + 2) = 0 b 7(2a + 3) − 3(a − 5) = 12 c 9(2t − 3) − (t + 5) = 2 d 5(3y − 5) − 6(1 − y) = 11 e 4(6 − 3b) − 2(7b − 1) = 26 f 9(3q + 7) − 6(2q + 5) = 14 g 2(3w + 1) − 3(5 − 4w) = 4(2w + 3) h 17 − 6(2x − 5) = 17 1 3 1 i --- (4x + 3) − 2(2x − 1) = 7 j --- (8x − 9) − --- (8x − 9) = 15 2 4 4 Try solving these equations, but first read the warning sign! ■ Warning! a 3(a + 2) − 2(a + 1) = 6 b 5(m + 3) − 4(m + 2) = 10 Remember how to expand c 5(n + 4) − 3(n − 2) = 30 d 6(a + 2) − 4(a − 1) = 20 with a negative term: e 4(a + 3) − (a + 2) = 13 f 2·4(p + 5) − (p + 3·8) = 11 −2(x + 4) = −2x − 8 or −3(a − 1) = −3a + 3 CHAPTER 6 EQUATIONS, INEQUATIONS AND FORMULAE 141
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