Name: Date: Block: Graphing using Standard Form (Intercept Form) Standard form is written as . This form is also called . Using this form will aid in determining the . An π₯-intercept of a graph is the . A π¦-intercept of a graph is the of a point where the . Example #1 - Changing from slope-intercept form to standard form. 2 x ο«7 3 y = -3x + 4 y= y = 5x + 2 y=- 1 x+1 2 Example #2 β Identify the π₯-intercept and the π¦-intercept of each of the graphs. Line A: π₯-intercept: π¦-intercept: Line A Line B: π₯-intercept: π¦-intercept: Line B Example #3 β Find the π₯-intercept and the π¦-intercept of each of the following: a) 2π₯ + 7π¦ = 28 b) 4π₯ β 2π¦ = 16 c) 3x ο y ο½ 3 d) x ο« y ο½ 5 Example #4 - Write an equation in standard form of the line has the given information. m = 2, b = 4 m = 5, b = 6 Example #5 β Graph the following equations on the same set of axes by finding the π₯-intercept and the π¦-intercept. Label the intersection point. a) π₯ + 2π¦ = 4 b) 4π₯ + 8π¦ = 24 Write the equation of the lines graphed below in standard form. Intercept Form Practice Directions β Graph each equation by finding the x- and y-intercepts. 1. x+y=5 2. x + y = 3 3. x β y = 1 4. 2x β 3y = 6 5. 2x + y = 2 6. 5x β 3y = β15 7. 3x β 5y = 10 8. 3x β 4y = 16 9. 4x + 3y = 9 7. Circle or shade any of the following equations below that have an x-intercept of 4 & a y-intercept of β8. 8x ο 4 y ο½ 32 5x ο 10 y ο½ 20 ο16 x ο« 8 y ο½ ο64 6 x ο 3 y ο½ 24
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