4/1/2014 Chapter Outline 7.1 Chemical reactions and the Conservation of Mass 7.2 Balancing Chemical Equations 7.3 Combustion Reactions 7.4 Stoichiometric Calculations and the Carbon Cycle 7.5 Percent Composition and Empirical Formulas 7.6 Empirical and Molecular Formulas Compared 7.7 Combustion Analysis 7.8 Limiting Reactants and Percent Yield Percent Composition: the composition of a compound in terms of the percentage by mass of each element in the compound n x molar mass of element x 100% molar mass of compound n is the number of moles of the element in 1 mole of the compound 3 x (1.008 g) x 100% = 3.086% 97.99 g 1 x (30.97 g) %P = x 100% = 31.60% 97.99 g 4 x (16.00 g) %O = x 100% = 65.31% 97.99 g %H = H3PO4 M = 98.00 g/mol Sample Exercise 7.4 – Calculating Percent Composition from a Chemical Formula The mineral forsterite: Mg2SiO4 3.086% + 31.60% + 65.31% = 99.996% = 100.00% Empirical Formulas A formula showing the smallest whole number ratio of elements in a compound, e.g. Benzene: » Empirical = CH » Molecular = C6H6 Glucose » Empirical = CH2O » Molecular = C6H12O6 Empirical Formula from % Composition Sample Exercise 7.6 A sample of the carbonate mineral dolomite is 21.73% Ca, 13.18% Mg, 13.03% C, and the rest is oxygen. What is its empirical formula? Assume 100 g and divide by atomic weight Divide by fewest number of moles 1 4/1/2014 Empirical and Molecular Formulas Compared Chapter Outline 7.1 Chemical reactions and the Conservation of Mass 7.2 Balancing Chemical Equations 7.3 Combustion Reactions 7.4 Stoichiometric Calculations and the Carbon Cycle 7.5 Percent Composition and Empirical Formulas 7.6 Empirical and Molecular Formulas Compared 7.7 Combustion Analysis 7.8 Limiting Reactants and Percent Yield The molecular formula can be determined if the molecular weight of the compound is known. empirical = CH2O molecular = C2H4O2 Note that molecular = empirical x 2 glycolaldehyde C2H4O2 = (CH2O)2 Or more generally – molecular = (empirical)n Empirical and Molecular Formulas Compared Molecular Mass and Mass Spectrometry The molecular formula can be determined if the molecular weight is known. e.g. glucose Acetylene C2H2 Benzene C6H6 Sample Exercise 7.7 – Using Percent Composition and Molecular weight to Derive a Molecular Fomula Pheromones are chemical substances secreted by members of a species to stimulate a response in other individuals of the same species. The percent composition of eicosene, a compound similar to the Japanese beetle mating pheromone, is 85.63% C and 14.37% H. Its molecular mass, as determined by mass spectrometry, is 280 amu. What is the molecular formula of eicosene? 2
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