Outcome FC1:
1. Name the Type of Reaction, complete and balance it.
a. (single replacement) 2Al + 6HCl  2AlCl3 + 3H2
b. (double replacement [neutralization]) Ca(OH)2 + 2HNO3  Ca(NO3)2 + 2H2O
(single replacement) Mg + Zn(NO3)2  Mg(NO3)2 + Zn
c. (Synthesis b) N2O5 + H2O 2 HNO3
d. (decomposition d) ZnCO3  ZnO + CO2
e. (Synthesis a) 2K + F2  2KF
f. (Synthesis c) Li2O + H2O  2 LiOH
g. (Combustion) CH4 + 2 O2  CO2 + 2 H2O
h. (synthesis d) MgO + CO2 MgCO3
2. See notes.
3. CaCl2(aq) + AgNO3(aq)  AgCl2(s) + Ca(NO3)2(aq)
Ba(OH)2(aq) + Cu(NO3)2(aq)  Ba(NO3)2(aq) + Cu(OH)2(s)
Outcome FC2:
1. C2H4O2 = 60.06 g/mol
Au = 196.97 g/mol
Cl2 = 70.9 g/mol
AgNO3 = 169.88 g/mol
2. Determine the number of molecules in the following amount:
a. 1.16 x 1024 molecules
b. 1.22 x 1024 molecule
c. 8.63 x 1023 molecules
3. Determine the mass in the following amount:
a. 0.21 x 78.12 g/mol = 16 g
b. 0.0071L x 1mol/22.4L x 4.00g/mol= 0.0013g
c. 3.32 x 10-24 mol x 63.55g/mol = 2 x 10-22 g
d. 2.2mol x 102.89g/mol =230g
4. Determine the Litres given the following amount:
a. 5.62L
b. 1 L
c. 6.0g x 1 mol/80.91g = 0.07416mol x 1L / 2.1mol =0.035L
d. 6.5 mol x 22.4L/mol = 150L