LCM of Monomials and Polynomials A. Find the LCM of 15a2bc3, 16b5c2, and 20a3c6. 15a2bc3 = 3 5 a2 16b5c2 = 24 b5 c2 20a3c6 = 22 5 a3 b c3 Factor the first monomial. Factor the second monomial. c6 Factor the third monomial. LCM = 3 ● 5 ● 24● a3 ● b5 ● c6 Use each factor the greatest number of times it appears. LCM of Monomials and Polynomials = 240a3b5c6 Answer: 240a3b5c6 Simplify. A. Find the LCM of 6x2zy3, 9x3y2z2, and 4x2z. A. x2z B. 36x2z 0% B A 0% A B C 0% D D D. 36xyz C C. 36x3y3z2 A. B. C. 0% D. LCM of Monomials and Polynomials B. Find the LCM of x3 – x2 – 2x and x2 – 4x + 4. x3 – x2 – 2x = x(x – 2)(x + 1) Factor the first polynomial. x2 – 4x + 4 = (x – 2)2 Factor the second polynomial. LCM = x(x – 2)2(x + 1) Answer: x(x – 2)2(x + 1) Use each factor the greatest number of times it appears as a factor. B. Find the LCM of x3 + 2x2 – 3x and x2 + 6x + 9. A. x(x + 3)2(x – 1) B. x(x + 3)(x – 1) 0% B A 0% A B C 0% D D D. (x + 3)(x – 1) C C. x(x – 1) A. B. C. 0% D. Monomial Denominators Simplify . The LCD is 42a2b2. Simplify each numerator and denominator. Add the numerators. Monomial Denominators Answer: Simplify . A. A 0% 0% B D. A B C 0% D D C. A. B. C. 0% D. C B. Polynomial Denominators Simplify . Factor the denominators. The LCD is 6(x – 5). Subtract the numerators. Polynomial Denominators Distributive Property Combine like terms. Simplify. Simplify. Answer: Simplify . A. B. 0% A B C 0% D D A 0% B D. C C. A. B. C. 0% D.
© Copyright 2025 Paperzz