Stoichiometry Practice – Level 1 (part 2) 1. Na2SiO3 (s) + 8 HF(aq

Stoichiometry Practice – Level 1 (part 2)
1. Na2SiO3 (s) + 8 HF(aq)  H2SiF6 (aq) + 2 NaF(aq) + 3 H2O (l)
a. How many moles of HF are needed to react with 0.300 mol of Na 2SiO3?
b. How many grams of NaF form when 0.500 mol of HF reacts with excess Na2SiO3?
c. How many grams of Na2SiO3 can react with 0.800 g of HF?
2. C6H12O6 (aq)  2 C2H5OH (aq) + 2 CO2 (g)
a. How many moles of CO2 are produced when 0.400 mol of C6H12O6 reacts in this fashion?
b. How many grams of C6H12O6 are needed to form 7.50 g of C2H5OH?
c. How many Liters of CO2 form when 7.50 g of C2H5OH are produced?
3. Fe2O3 (s) + 3CO (g)  2Fe(s) + 3CO2 (g)
a. Calculate the number of grams of CO that can react with 0.150 kg of Fe 2O3
b. Calculate the number of liters of CO2 formed when 0.150 kg of Fe2O3 reacts
4. 2 NaOH (s) + CO2 (g)  Na2CO3 (s) + H2O (l)
a. How many liters of CO2 are needed to completely react with 15.2 grams of NaOH
b. How many moles of Na2CO3 can be produced from 1.85 moles of NaOH?
5. C6H6 + Br2  C6H5Br + HBr
a. How many grams of C6H6 is needed in this reaction to produce 30.0 g of C6H5Br?
b. How many liters of Br2 is needed to completely react and form 12.5 grams of HBr
6. 4 Si2H3 + 17 O2  8 SiO2 + 6 H2O3
a. How many grams of Silicon dioxide will be formed if 6x1028 molecules of oxygen react completely?
b. How many moles of oxygen are equal to 6.02x1025 molecules of oxygen?
Answer Key (sig figs not accounted for): 1a.) 2.4 mol HF 1b.) 5.2 g NaF 1c.) 0.61 g Na2SiO3 2a.) 0.8 mol CO2
2b.) 14.66 g C6H12O6 2c.) 3.65 L CO2 3a.) 78.9 g CO 3b.) 63.1 L CO2 4a.) 4.3 L CO2 4b.) 0.925 mol Na2CO3
5a.) 14.93 g C6H6 5b.) 3.46 L Br2 6a.) 2.81 x 106 g SiO2 6b.) 100 moles O2