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Algebra 1
Using the Discriminant to Tell How Many Solutions There Are for a Quadratic Equation
Given ax2 + bx + c = 0, the Discriminant = 𝒃𝟐 − 𝟒𝒂𝒄
If 𝑏 2 − 4𝑎𝑐 > 0, then the equation has two real solutions.
If 𝑏 2 − 4𝑎𝑐 = 0, then the equation has one real solution.
If 𝑏 2 − 4𝑎𝑐 < 0, then the equations has zero real solutions (two imaginary solutions).
1. How many and what type of solutions are there for each equation.
x2 + 3x + 2 = 0
-4x2 + 20x – 25 = 0
-3x2 +5x – 3 = 4x + 1
x2 – 3x + 4 = 2x2 – 3