The Quadratic Formula
Name
Algebra I
Level 1 – I can use substitution to evaluate an expression with no grouping symbols.
1.
If a = 2, b = −3, c = −2 , then
2
b − 4ac = _______________
2.
If a = −4, b = 5, c = −1 , then
b 2 − 4ac = _______________
Level 2 – I can use substitution to evaluate an expression where there are grouping symbols.
3. If a = −1, b = −3, c = −2 , then
2
− b + b − 4ac
= _______________
2a
5. If a = 1, b = −3, c = −4 , then
− b + b 2 − 4ac
= _______________
2a
4. If a = −1, b = −3, c = −2 , then
− b − b 2 − 4ac
= _______________
2a
6. If a = 1, b = −3, c = −4 , then
− b − b 2 − 4ac
= _______________
2a
Level 3 – I can solve a quadratic equation with no grouping symbols.
7. Solve: 4 x 2 + 9 = 12 x
8. Solve: 3 x 2 − 13 x = 10
9. Solve: x 2 − 13 = 12
10. Solve: 2 x 2 − 3 x − 6 = 0
Level 4– I can solve a quadratic equation where there are grouping symbols.
11. Solve: ( x + 3) 2 = 16
12. Solve: − 3( x − 2) 2 + 5 = 0
Deep Practice Answers to Multiply Polynomials: Algebraic Fluency
1. 25
2. 9
3. − 2
4. − 1
3
x
=
7.
2
8. x = 5, x =
−2
3
x = 2±
5
3
11.
x = −19, x = 13
12.
Or
5. 4
6. − 1
9. x = 5, x = −5
10.
x=
3 ± 57
4
Quadratic Formula
Name
Formative Assessment
Table of Specifications
Date
Period
Circle the number of each question where you missed something.
In the Percent Correct column, record the percent of questions worked correctly for each category.
Simple
More study
Percent (%)
Content
Question Number
Mistake
needed
Correct
EL: I can solve quadratic equation.
I can use substitution to
evaluate an expression with no
1, 2
grouping symbols.
I can use substitution to
evaluate an expression where
3, 4, 5, 6
there are grouping symbols.
I can solve a quadratic
equation no grouping
7, 8, 9, 10
symbols.
I can solve a quadratic
equation where there are
11, 12
grouping symbols.
Identify the level where your work is most consistently correct.
I am here
Level I can demonstrate computational fluency by expanding expressions involving
multiplication.
4
I can solve a quadratic equation where there are grouping symbols.
3
I can solve a quadratic equation no grouping symbols.
2
I can use substitution to evaluate an expression where there are grouping symbols.
1
I can use substitution to evaluate an expression with no grouping symbols.
The Quadratic Formula
Name
Algebra I
Level 1 – I can use substitution to evaluate an expression with no grouping symbols.
1.
If a = 2, b = −3, c = −2 , then
2
b − 4ac = _______________
2.
If a = −4, b = 5, c = −1 , then
b 2 − 4ac = _______________
Level 2 – I can use substitution to evaluate an expression where there are grouping symbols.
3. If a = −1, b = −3, c = −2 , then
2
− b + b − 4ac
= _______________
2a
5. If a = 1, b = −3, c = −4 , then
− b + b 2 − 4ac
= _______________
2a
4. If a = −1, b = −3, c = −2 , then
− b − b 2 − 4ac
= _______________
2a
6. If a = 1, b = −3, c = −4 , then
− b − b 2 − 4ac
= _______________
2a
Level 3 – I can solve a quadratic equation with no grouping symbols.
7. Solve: 4 x 2 + 9 = 12 x
8. Solve: 3 x 2 − 13 x = 10
9. Solve: x 2 − 13 = 12
10. Solve: 2 x 2 − 3 x − 6 = 0
Level 4– I can solve a quadratic equation where there are grouping symbols.
11. Solve: ( x + 3) 2 = 16
12. Solve: − 3( x − 2) 2 + 5 = 0