CHEM 110 (BEAMER)
PRACTICE REVIEW-02
EXAM 2 REVIEW
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Exam 2 Review Practice 2
Electron Configurations
General Information

This assignment is not due. This assignment is to provide you the opportunity to practice the material.

Refer to Class Notes-035 for this material. (I have yet to write and post them.)

Appendix 6 will be helpful with this material. You will not get Appendix 6 on Exam 2.

Textbook: Chapter 4, Section 10

You do not have to show your work for these types of questions.

Max Time: Remember that if you answer all questions at exactly Max Time, you will not finish the Exam.

The last two pages include the solutions. I highly suggest that you work from your notes first.

Don’t work backwards from the answer key. It didn’t work for you last time.
Problems

PART 1

Write the full electron configurations for the following elements.

You may not write abbreviated electron configurations.

On this review sheet, I will give you larger atoms. However, on the test, I probably won’t ask you to write
electron configurations for anything larger than radium (#88). (These questions are very hard to grade with
partial credit.)

Depending upon the length of the conversion factor, each question may be worth anywhere between 3 points
and 9 points.

Max Time: 2 min/each
1)
vanadium (V)
6)
bismuth (Bi)
2)
astatine (At)
7)
aluminum (Al)
3)
oxygen (O)
8)
helium (He)
4)
yttrium (Y)
9)
iron (Fe)
5)
magnesium (Mg)
10)
osmium (Os)
Page 1 of 7
CHEM 110 (BEAMER)
PRACTICE REVIEW-02
EXAM 2 REVIEW
Problems

11)
PART 2

If the electron configuration is correct, write “CORRECT” in the space given.

If the electron configuration is incorrect, write the correct electron configuration.

Each answer is worth 3 points (all or nothing)

Max Time: 2 min/each
lithium
Li:
12)
2p1
1s2
2s2
2p6
3s2
3p6
4s2
1s2
2s2
2p6
3s2
3p6
3d10
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p6
5s2
4d10
5p6
6s2
5d10
6p5
nickel
Ni:
14)
2s1
lead
Pb:
13)
1s1
titanium
Ti:
3d2
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CHEM 110 (BEAMER)
15)
2s4
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p6
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p6
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p6
5s2
4d10
5s2
5p3
5p3
germanium
Ge:
18)
1s2
antimony
Sb:
17)
EXAM 2 REVIEW
carbon
C:
16)
PRACTICE REVIEW-02
niobium
Nb:
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CHEM 110 (BEAMER)
PRACTICE REVIEW-02
EXAM 2 REVIEW
Solutions

Because point values are based upon the length of the electron configuration, you will be given general point ranges.

The number of electrons in each orbital is written as a

Partial credit is highly subjective. I apologize for this in advance.
1)
vanadium (6 pts total)
V:
(2 pts)
2)
(2 pts)
(2 pts)
(2 pts)
3p6
4s2
3d3
(4 points – the highest energy level that needs to be used is “4”)
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p6
5s2
4d10
5p6
6s2
5p6
6s2
(6 points – the highest energy level that needs to be used is “6”)
1s2
2s2
2p4
(2 points – the highest energy level that needs to be used is “2”)
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p6
5s2
4d1
(5 points – the highest energy level that needs to be used is “5”)
magnesium (5 pts total)
Mg:
(2 pts)
6)
3s2
will earn a 2-point penalty.
yttrium (7 pts total)
Y:
5)
2p6
subscripts
oxygen (4 pts total)
O:
4)
2s2
. Number of electrons written as
astatine (8 pts total)
At:
3)
1s2
superscript
1s2
2s2
2p6
3s2
(3 points – the highest energy level that needs to be used is “5”)
bismuth (8 pts total)
Bi:
(2 pts)
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p6
5s2
4d10
4f14
5d10
6p3
(6 points – the highest energy level that needs to be used is “6”)
Page 4 of 7
CHEM 110 (BEAMER)
7)
(2 pts)
(2 pts)
(2 pts)
(2 pts)
12)
2p6
3s2
3p1
(3 points – the highest energy level that needs to be used is “3”)
1s2
(1 points – the highest energy level that needs to be used is “1”)
1s2
2s2
2p6
3s2
3p6
4s2
3d6
(4 points – the highest energy level that needs to be used is “4”)
osmium (8 pts total)
Os:
11)
2s2
iron (6 pts total)
Fe:
10)
1s2
helium (3 pts total)
He:
9)
EXAM 2 REVIEW
aluminum (5 pts total)
Al:
8)
PRACTICE REVIEW-02
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p6
5s2
4d10
5p6
6s2
4f14
5d6
(6 points – the highest energy level that needs to be used is “6”)
lithium
Li:
1s1
2s1
Li:
1s2
2s1
lead
2p1
Out of 8 points, this would only earn 2 points of credit for the chemical symbol and the colon. The first mistake occurs at “1s1”
Pb:
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p6
5s2
4d10
5p6
6s2
5d10
6p5
Pb:
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p6
5s2
4d10
5p6
6s2
4d14
5d10
6p5
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CHEM 110 (BEAMER)
13)
14)
PRACTICE REVIEW-02
EXAM 2 REVIEW
nickel
Ni:
1s2
2s2
2p6
3s2
3p6
3d10
Ni:
1s2
2s2
2p6
3s2
3p6
4s2
3d8
1s2
2s2
2p6
3s2
3p6
4s2
3d2
3s2
3p6
4s2
3d10
4p6
titanium
Ti:
CORRECT
15)
16)
carbon
C:
1s2
2s4
C:
1s2
2s2
2p2
1s2
2s2
2p6
antimony
Sb:
5s2
4d10
5p3
CORRECT
17)
germanium
Ge:
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p6
Ge:
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p2
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CHEM 110 (BEAMER)
18)
PRACTICE REVIEW-02
EXAM 2 REVIEW
niobium
Nb:
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p6
5s2
5p3
Nb:
1s2
2s2
2p6
3s2
3p6
4s2
3d10
4p6
5s2
4d3
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