Lesson 1: Generating Equivalent Expressions

Lessons 1-6
NYS COMMON CORE MATHEMATICS CURRICULUM
7β€’3
Lesson 1: Generating Equivalent Expressions
Variable (description): A variable is a symbol (such as a letter) that represents a number, i.e., it is a placeholder for a number.
Numerical Expression (description): A numerical expression is a number, or it is any combination of sums, differences,
products, or divisions of numbers that evaluates to a number.
Value of a Numerical Expression: The value of a numerical expression is the number found by evaluating the expression.
Expression (description): An expression is a numerical expression, or it is the result of replacing some (or all) of the numbers in
a numerical expression with variables.
Equivalent Expressions: Two expressions are equivalent if both expressions evaluate to the same number for every
substitution of numbers into all the letters in both expressions.
An Expression in Expanded Form: An expression that is written as sums (and/or differences) of products whose factors are
numbers, variables, or variables raised to whole number powers is said to be in expanded form. A single number, variable, or a
single product of numbers and/or variables is also considered to be in expanded form. Examples of expressions in expanded
form include: 324, 3π‘₯, 5π‘₯ + 3 βˆ’ 40, π‘₯ + 2π‘₯ + 3π‘₯, etc.
Term (description): Each summand of an expression in expanded form is called a term. For example, the expression 2π‘₯ +
3π‘₯ + 5 consists of 3 terms: 2π‘₯, 3π‘₯, and 5.
Coefficient of the Term (description): The number found by multiplying just the numbers in a term together. For example,
given the product 2 βˆ™ π‘₯ βˆ™ 4, its equivalent term is 8π‘₯. The number 8 is called the coefficient of the term 8π‘₯.
An Expression in Standard Form: An expression in expanded form with all its like terms collected is said to be in standard
form. For example, 2π‘₯ + 3π‘₯ + 5 is an expression written in expanded form; however, to be written in standard form, the like
terms 2π‘₯ and 3π‘₯ must be combined. The equivalent expression 5π‘₯ + 5 is written in standard form.
An Expression in Expanded Form: An expression that is written as sums (and/or differences) of products whose factors are
numbers, variables, or variables raised to whole number powers is said to be in expanded form. A single number, variable, or a
single product of numbers and/or variables is also considered to be in expanded form. Examples of expressions in expanded
form include: 324, 3π‘₯, 5π‘₯ + 3 βˆ’ 40, π‘₯ + 2π‘₯ + 3π‘₯, etc.
Term: Each summand of an expression in expanded form is called a term. For example, the expression 2π‘₯ + 3π‘₯ + 5 consists of
3 terms: 2π‘₯, 3π‘₯, and 5.
Coefficient of the Term: The number found by multiplying just the numbers in a term together. For example, given the
product 2 βˆ™ π‘₯ βˆ™ 4, its equivalent term is 8π‘₯. The number 8 is called the coefficient of the term 8π‘₯.
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Generating Equivalent Expressions
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Lessons 1-6
NYS COMMON CORE MATHEMATICS CURRICULUM
7β€’3
An Expression in Standard Form: An expression in expanded form with all its like terms collected is said to be in standard
form. For example, 2π‘₯ + 3π‘₯ + 5 is an expression written in expanded form; however, to be written in standard form, the liketerms 2π‘₯ and 3π‘₯ must be combined. The equivalent expression 5π‘₯ + 5 is written in standard form.
Problem Set
For problems 1–9, write equivalent expressions by combining like terms. Verify the equivalence of your expression and the
given expression by evaluating each for the given values: π‘Ž = 2, 𝑏 = 5, and 𝑐 = βˆ’3. An example has been done for you.
1.
πŸ‘π’‚ + πŸ“π’‚
3(2) + 5(2)
2.
8𝑏 βˆ’ 4𝑏
3.
5𝑐 + 4𝑐 + 𝑐
6 + 10
16
4.
3π‘Ž + 6 + 5
5.
8𝑏 + 8 βˆ’ 4𝑏
6.
5𝑐 βˆ’ 4𝑐 + 𝑐
7.
3π‘Ž + 6 + 5π‘Ž βˆ’ 2
8.
8𝑏 + 8 βˆ’ 4𝑏 βˆ’ 3
9.
5𝑐 βˆ’ 4𝑐 + 𝑐 βˆ’ 3𝑐
Use any order, any grouping to write equivalent expressions by combining like terms. In the 2nd column, substitute for the
variable. In the 3rd column, solve the expression. Show your work. An example has been done for you.
Expression
10. πŸ‘(πŸ”π’‚); for 𝒂 = πŸ‘
Substitute
Solve
3 ● (6 ● 3)
3 (18)
54
11. 5𝑑(4); for 𝑑 = βˆ’2
12. (5π‘Ÿ)(βˆ’2); for π‘Ÿ = βˆ’3
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Lessons 1-6
NYS COMMON CORE MATHEMATICS CURRICULUM
Expression
Substitute
7β€’3
Solve
13. 3𝑏(8) + (βˆ’2)(7𝑐); for 𝑏 = 2, 𝑐 = 3
1
14. βˆ’4(3𝑠) + 2(βˆ’π‘‘); for 𝑠 = , 𝑑 = βˆ’3
2
15. 9(4𝑝) βˆ’ 2(3π‘ž) + 𝑝; for 𝑝 = βˆ’1, π‘ž = 4
1
1
2
3
16. 7(4𝑔) + 3(5β„Ž) + 2(βˆ’3𝑔); 𝑔 = , β„Ž =
17. Jack got the expression 7π‘₯ + 1, then wrote his answer as 1 + 7π‘₯. Is his answer an equivalent expression? How do you
know?
18. Jill also got the expression 7π‘₯ + 1, then wrote her answer as 1π‘₯ + 7. Is her expression an equivalent expression? How do
you know?
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Lessons 1-6
NYS COMMON CORE MATHEMATICS CURRICULUM
7β€’3
Lesson 2: Generating Equivalent Expressions
Additive inverses have a sum of zero. Multiplicative inverses have a product of 1.
Fill in the center column of the table with the opposite of the given number or expression, then show the proof that they are
opposites. The first row is completed for you.
Expression
Opposite?
Proof of Opposites
1
βˆ’1
1 + (βˆ’1) = 0
3
βˆ’7
βˆ’
1
2
π‘₯
3π‘₯
π‘₯+3
3π‘₯ βˆ’ 7
Example 1: Subtracting Expressions Horizontally
a.
Subtract: (πŸ’πŸŽ + πŸ—) βˆ’ (πŸ‘πŸŽ + 𝟐).
b.
Subtract: (πŸ‘π’™ + πŸ“π’š βˆ’ πŸ’) βˆ’ (πŸ’π’™ + 𝟏𝟏).
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NYS COMMON CORE MATHEMATICS CURRICULUM
7β€’3
Example 2: Combining Expressions Vertically
a.
Find the sum by aligning the expressions vertically. Here is an example.
(5π‘Ž + 3𝑏 βˆ’ 6𝑐)
+(2π‘Ž βˆ’ 4𝑏 + 13𝑐)
b.
Find the difference by aligning the expressions vertically.
(2π‘₯ + 3𝑦 βˆ’ 4) βˆ’ (5π‘₯ + 2)
Example 3: Using Expressions to Solve Problems
A stick is π‘₯ meters long. A string is 4 times as long as the stick.
a.
Express the length of the string in terms of π‘₯.
b.
If the total length of the string and the stick is 15 meters long, how long is the string?
Example 5: Extending Use of the Inverse to Division
Find the multiplicative inverses of the terms in the first column. Show that the given number and its multiplicative inverse
have a product of 1. Then, use the inverse to write each corresponding expression in standard form. The first row is
completed for you.
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NYS COMMON CORE MATHEMATICS CURRICULUM
Given
7β€’3
Multiplicative
Inverse?
Proof – Show that their
product is 1.
Use each inverse to write its corresponding
expression below in standard form.
𝟏
πŸ‘
𝟏
πŸ‘
πŸ‘ 𝟏
βˆ™
𝟏 πŸ‘
πŸ‘
=𝟏
πŸ‘
𝟏𝟐 ÷ πŸ‘
𝟏
𝟏𝟐 βˆ™
πŸ‘
πŸ’
πŸ‘βˆ™
πŸ‘
Lessons 1-6
5
βˆ’2
βˆ’
3
5
π‘₯
2π‘₯
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Lessons 1-6
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7β€’3
Problem Set
1. It costs Margo a processing fee of $3 to rent a storage unit, plus $17 per month to keep her belongings in the unit. Her
friend Carissa wants to store a box of her belongings in Margo’s storage unit and tells her that she will pay her $1 toward
the processing fee and $3 for every month that she keeps the box in storage. Write an expression, in standard form, that
represents how much Margo will have to pay for the storage unit if Carissa contributes. Then, determine how much
Margo will pay if she uses the storage unit for 6 months.
2.
Write each expression in standard form. Verify that your expression is equivalent to the one given by evaluating each
expression using π‘₯ = 5. Use the order of operations. The first one has been completed for you.
a.
πŸ‘π’™ + (𝟐 βˆ’ πŸ’π’™) =
b.
3π‘₯ + (βˆ’2 + 4π‘₯)
c.
βˆ’3π‘₯ + (2 + 4π‘₯)
πŸ‘(πŸ“) + (𝟐 βˆ’ πŸ’ βˆ™ πŸ“)
πŸπŸ“ + (𝟐 βˆ’ 𝟐𝟎)
πŸπŸ“ (βˆ’πŸπŸ–)
βˆ’πŸ‘
3.
d.
3π‘₯ + (βˆ’2 βˆ’ 4π‘₯)
e.
3π‘₯ βˆ’ (2 + 4π‘₯)
f.
3π‘₯ βˆ’ (βˆ’2 + 4π‘₯)
g.
3π‘₯ βˆ’ (βˆ’2 βˆ’ 4π‘₯)
h.
3π‘₯ βˆ’ (2 βˆ’ 4π‘₯)
i.
βˆ’3π‘₯ βˆ’ (βˆ’2 βˆ’ 4π‘₯)
Write each expression in standard form. Verify that your expression is equivalent to the one given by evaluating each
expression for the given value of the variable. The first one has been done for you.
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a.
πŸ’π’š βˆ’ (πŸ‘ + π’š); π’š = 𝟐
7β€’3
b.
(2𝑏 + 1) βˆ’ 𝑏; 𝑏 = βˆ’4
c.
(6𝑐 βˆ’ 4) βˆ’ (𝑐 βˆ’ 3); 𝑐 = βˆ’7
(4 βˆ™ 𝟐) – (3 + 2)
8–5
3
4.
1
d.
(𝑑 + 3𝑑) βˆ’ (βˆ’π‘‘ + 2); 𝑑 = 3
e.
(βˆ’5π‘₯ βˆ’ 4) βˆ’ (βˆ’2 βˆ’ 5π‘₯); π‘₯ = 3
f.
11𝑓 βˆ’ (βˆ’2𝑓 + 2); 𝑓 =
g.
βˆ’5𝑔 + (6𝑔 βˆ’ 4); 𝑔 = βˆ’2
h.
(8β„Ž βˆ’ 1) βˆ’ (β„Ž + 3); β„Ž = βˆ’3
i.
(7 + 𝑀) βˆ’ (𝑀 + 7); 𝑀 = βˆ’4
j.
(2𝑔 + 9β„Ž βˆ’ 5) βˆ’ (6𝑔 βˆ’ 4β„Ž + 2); 𝑔 = βˆ’2 and β„Ž = 5
2
Write each expression in standard form. Verify that your expression is equivalent to the one given by evaluating both
expressions for the given value of the variable. The first one has been done for you.
a.
βˆ’πŸ‘(πŸ–π’™); 𝒙 =
𝟏
πŸ’
3
b.
5 βˆ™ π‘˜ βˆ™ (βˆ’7); π‘˜ =
e.
8(5π‘š) + 2(3π‘š); π‘š = βˆ’2
5
3
c.
2(βˆ’6π‘₯) βˆ™ 2; π‘₯ =
f.
βˆ’6(2𝑣) + 3π‘Ž(3); 𝑣 = ; π‘Ž =
4
𝟏
-3(8 βˆ™ )
πŸ’
-3( 2)
-6
d.
5.
βˆ’3(8π‘₯) + 6(4π‘₯); π‘₯ = 2
1
2
3
3
Write each expression in standard form. Verify that your expression is equivalent to the one given by evaluating both
expressions for the given value of the variable. The first one has been done for you.
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a.
πŸ–π’™ ÷ 𝟐; 𝒙 = βˆ’
𝟏
πŸ’
7β€’3
b.
18𝑀 ÷ 6; 𝑀 = 6
c.
25π‘Ÿ ÷ 5π‘Ÿ; π‘Ÿ = βˆ’2
e.
56π‘˜ ÷ 2π‘˜; π‘˜ = 3
f.
24π‘₯𝑦 ÷ 6𝑦; π‘₯ = βˆ’2; 𝑦 = 3
𝟏
8 (βˆ’ ) ÷ 𝟐
πŸ’
8 βˆ™ βˆ’πŸ’ ÷ 𝟐
βˆ’32 ÷ 𝟐
βˆ’16
d.
6.
33𝑦 ÷ 11𝑦; 𝑦 = βˆ’2
Write each word problem in standard form as an expression. The first one has been done for you.
a.
Find the sum of βˆ’πŸ‘π’™ and πŸ–π’™.
βˆ’πŸ‘π’™ + πŸ–π’™ = πŸ“π’™
b.
Find the sum of – 7𝑔 and 4𝑔 + 2.
c.
Find the difference when 6β„Ž is subtracted from 2β„Ž βˆ’ 4.
d.
Find the difference when βˆ’3𝑛 βˆ’ 7 is subtracted from 𝑛 + 4.
e.
Find the result when 13𝑣 + 2 is subtracted from 11 + 5𝑣.
f.
Find the result when βˆ’18π‘š βˆ’ 4 is added to 4π‘š βˆ’ 14.
g.
What is the result when βˆ’2π‘₯ + 9 is taken away from βˆ’7π‘₯ + 2?
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7.
7β€’3
Marty and Stewart are stuffing envelopes with index cards. They are putting π‘₯ index cards in each envelope. When they
are finished, Marty has 15 envelopes and 4 extra index cards, and Stewart has 12 envelopes and 6 extra index cards. Draw
a picture and then write an expression in standard form that represents the number of index cards the boys started with.
2𝑏 ft
8.
The area of the pictured rectangle below is 24𝑏 ft 2 . Its width is 2𝑏 ft. Find the height
of the rectangle and name any properties used with the appropriate step.
___ ft
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24𝑏 ft 2
Generating Equivalent Expressions
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Lessons 1-6
NYS COMMON CORE MATHEMATICS CURRICULUM
7β€’3
Sprint – Round 1
Write each as an equivalent expression in standard form as quickly and accurately as possible within the allotted time.
1.
1+1
23. 4π‘₯ + 6π‘₯ βˆ’ 12π‘₯
2.
1+1+1
24. 4π‘₯ βˆ’ 6π‘₯ + 4π‘₯
3.
(1 + 1) + 1
25. 7π‘₯ βˆ’ 2π‘₯ + 3
4.
(1 + 1) + (1 + 1)
26. (4π‘₯ + 3) + π‘₯
5.
(1 + 1) + (1 + 1 + 1)
27. (4π‘₯ + 3) + 2π‘₯
6.
π‘₯+π‘₯
28. (4π‘₯ + 3) + 3π‘₯
7.
π‘₯+π‘₯+π‘₯
29. (4π‘₯ + 3) + 3π‘₯
8.
(π‘₯ + π‘₯) + π‘₯
30. (4π‘₯ + 3) + 6π‘₯
9.
(π‘₯ + π‘₯) + (π‘₯ + π‘₯)
31. (11π‘₯ + 2) βˆ’ 2
10. (π‘₯ + π‘₯) + (π‘₯ + π‘₯ + π‘₯)
32. (11π‘₯ + 2) βˆ’ 3
11. (π‘₯ + π‘₯ + π‘₯) + (π‘₯ + π‘₯ + π‘₯)
33. (11π‘₯ + 2) βˆ’ 4
12. 2π‘₯ + π‘₯
34. (11π‘₯ + 2) βˆ’ 7
13. 3π‘₯ + π‘₯
35. (3π‘₯ βˆ’ 9) + (3π‘₯ + 5)
14. 4π‘₯ + π‘₯
36. (11 βˆ’ 5π‘₯) + (4π‘₯ + 2)
15. 7π‘₯ + π‘₯
37. (2π‘₯ + 3𝑦) + (4π‘₯ + 𝑦)
16. 7π‘₯ + 2π‘₯
38. (5π‘₯ + 3𝑦) + (2π‘₯ βˆ’ 𝑦)
17. 7π‘₯ + 3π‘₯
39. (2π‘₯ βˆ’ 𝑦) + (6π‘₯ βˆ’ 𝑦)
18. 10π‘₯ βˆ’ π‘₯
40. (2π‘₯ βˆ’ 𝑦) + (βˆ’6π‘₯ βˆ’ 𝑦)
19. 10π‘₯ βˆ’ 5π‘₯
41. (βˆ’2π‘₯ βˆ’ 𝑦) + (βˆ’6π‘₯ βˆ’ 𝑦)
20. 10π‘₯ βˆ’ 10π‘₯
42. (5π‘₯ βˆ’ 2𝑦) + (βˆ’3π‘₯ + 4π‘₯)
21. 10π‘₯ βˆ’ 11π‘₯
43. (5π‘₯ βˆ’ 2𝑦) βˆ’ (βˆ’3π‘₯ + 4π‘₯)
22. 10π‘₯ βˆ’ 12π‘₯
44. (7π‘₯ βˆ’ 2𝑦) βˆ’ (βˆ’π‘¦ βˆ’ 𝑦)
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Lessons 1-6
NYS COMMON CORE MATHEMATICS CURRICULUM
7β€’3
Sprint – Round 2
Write each as an equivalent expression in standard form as quickly and accurately as possible within the allotted time.
1.
1+1+1
23. 3π‘₯ + 5π‘₯ βˆ’ 4π‘₯
2.
1+1+1+1
24. 8π‘₯ βˆ’ 6π‘₯ + 4π‘₯
3.
(1 + 1 + 1) + 1
25. 7π‘₯ βˆ’ 4π‘₯ + 5
4.
(1 + 1 + 1) + (1 + 1)
26. (9π‘₯ βˆ’ 1) + π‘₯
5.
(1 + 1 + 1) + (1 + 1 + 1)
27. (9π‘₯ βˆ’ 1) + 2π‘₯
6.
π‘₯+π‘₯+π‘₯
28. (9π‘₯ βˆ’ 1) + 3π‘₯
7.
π‘₯+π‘₯+π‘₯+π‘₯
29. (9π‘₯ βˆ’ 1) + 5π‘₯
8.
(π‘₯ + π‘₯ + π‘₯) + π‘₯
30. (9π‘₯ βˆ’ 1) + 6π‘₯
9.
(π‘₯ + π‘₯ + π‘₯) + (π‘₯ + π‘₯)
31. (βˆ’3π‘₯ + 3) βˆ’ 2
10. (π‘₯ + π‘₯ + π‘₯) + (π‘₯ + π‘₯ + π‘₯)
32. (βˆ’3π‘₯ + 3) βˆ’ 3
11. (π‘₯ + π‘₯ + π‘₯ + π‘₯) + (π‘₯ + π‘₯)
33. (βˆ’3π‘₯ + 3) βˆ’ 4
12. π‘₯ + 2π‘₯
34. (βˆ’3π‘₯ + 3) βˆ’ 5
13. π‘₯ + 4π‘₯
35. (5π‘₯ βˆ’ 2) + (2π‘₯ + 5)
14. π‘₯ + 6π‘₯
36. (8 βˆ’ π‘₯) + (3π‘₯ + 2)
15. π‘₯ + 8π‘₯
37. (5π‘₯ + 𝑦) + (π‘₯ + 𝑦)
16. 7π‘₯ + π‘₯
38. (5π‘₯ + 𝑦) + (π‘₯ βˆ’ 𝑦)
17. 8π‘₯ + 2π‘₯
39. (6π‘₯ βˆ’ 2𝑦) + (2π‘₯ βˆ’ 𝑦)
18. 2π‘₯ βˆ’ π‘₯
40. (6π‘₯ βˆ’ 2𝑦) + (βˆ’2π‘₯ + 𝑦)
19. 2π‘₯ βˆ’ 2π‘₯
41. (π‘₯ βˆ’ 𝑦) + (βˆ’π‘₯ + 𝑦)
20. 2π‘₯ βˆ’ 3π‘₯
42. (π‘₯ βˆ’ 2𝑦) + (βˆ’π‘₯ + 2π‘₯)
21. 2π‘₯ βˆ’ 4π‘₯
43. (π‘₯ βˆ’ 2𝑦) βˆ’ (βˆ’π‘₯ + 2π‘₯)
22. 2π‘₯ βˆ’ 8π‘₯
44. (5π‘₯ βˆ’ 6𝑦) βˆ’ (βˆ’4𝑦 βˆ’ 2𝑦)
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7β€’3
Lesson 3: Writing Products as Sums and Sums as Products
Example 1
Solve the problem using a tape diagram. A sum of money was shared between George and Brian in a ratio of 3: 4. If the sum
of money was $56.00, how much did George get?
Example 2
Fill in the blanks.
Example 3
Find an equivalent expression by modeling with a rectangular array and applying the distributive property 5(8π‘₯ + 3).
Problem Set
1.
a.
Write two equivalent expressions that represent the rectangular array below.
b.
Verify informally that the two equations are equivalent using substitution.
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7β€’3
2. Use a rectangular array to write the products as sums.
3.
4.
c.
2(π‘₯ + 10)
d.
3(4𝑏 + 12𝑐 + 11)
Use the distributive property to write the products as sums. The first one has been done for you.
a.
πŸ‘(πŸπ’™ βˆ’ 𝟏) = 6x - 1
g.
(40𝑠 + 100𝑑) ÷ 10
b.
10(𝑏 + 4𝑐)
h.
(48𝑝 + 24) ÷ 6
c.
9(𝑔 βˆ’ 5β„Ž)
i.
(2𝑏 + 12) ÷ 2
d.
7(4𝑛 βˆ’ 5π‘š βˆ’ 2)
j.
(20π‘Ÿ βˆ’ 8) ÷ 4
e.
π‘Ž(𝑏 + 𝑐 + 1)
k.
(49𝑔 βˆ’ 7) ÷ 7
f.
(8𝑗 βˆ’ 3𝑙 + 9)6
l.
(14𝑔 + 22β„Ž) ÷ 1⁄2
Write the expression in standard form by expanding and collecting like terms. The first one has been done for you.
a.
πŸ’(πŸ–π’Ž βˆ’ πŸ•π’) + πŸ”(πŸ‘π’ βˆ’ πŸ’π’Ž)
32m – 28n + 18n – 24m
8m – 10n
b.
9(π‘Ÿ βˆ’ 𝑠) + 5(2π‘Ÿ βˆ’ 2𝑠)
c.
12(1 βˆ’ 3𝑔) + 8(𝑔 + 𝑓)
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7β€’3
Lesson 4: Writing Sums as Products and Products as Sums
Exercise 1
Rewrite the expressions as a product of two factors. An example has been done for you.
d.
πŸ•πŸπ’• + πŸ– = 8 (9t + 1)
f.
36𝑧 + 72
e.
55π‘Ž + 11
g.
144π‘ž βˆ’ 15
h.
3π‘Ÿ + 3𝑠
Exercise 2
a.
Factor 48𝑗 + 60π‘˜ + 24 by finding the greatest common factor of the terms.
Example 3
For each expression, write each sum as a product of two factors. Emphasize the importance of the distributive property. The
first one has been done for you.
b.
𝟐 βˆ™ πŸ‘ + πŸ“ βˆ™ πŸ‘ = 3 (2 + 5)
c.
(2 + 5) + (2 + 5) + (2 + 5)
d.
2 βˆ™ 2 + (5 + 2) + (5 βˆ™ 2)
e.
π‘₯βˆ™3+5βˆ™3
f.
(π‘₯ + 5) + (π‘₯ + 5) + (π‘₯ + 5)
g.
2π‘₯ + (5 + π‘₯) + 5 βˆ™ 2
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h.
π‘₯βˆ™3+π‘¦βˆ™3
i.
(π‘₯ + 𝑦) + (π‘₯ + 𝑦) + (π‘₯ + 𝑦)
j.
7β€’3
2π‘₯ + (𝑦 + π‘₯) + 2𝑦
Example 4
A new miniature golf and arcade opened up in town. For convenient ordering, a play package is available to purchase. It
includes two rounds of golf and 20 arcade tokens, plus three dollars off. There is a group of six friends purchasing this package.
Let 𝑔 represent the cost of a round of golf and let 𝑑 represent the cost of a token. Draw a picture and write two different
expressions that represent the total amount this group spent.
Example 6
Expand each expression and collect like terms. The first one has been done for you.
k.
βˆ’πŸ‘(πŸπ’‘ βˆ’ πŸ‘π’’) = βˆ’πŸ”π’‘ + πŸ—π’’
l.
βˆ’π‘Ž βˆ’ (π‘Ž βˆ’ 𝑏)
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7β€’3
Problem Set
Write each expression as the product of two factors. The first one has been done for you.
1.
2.
3.
a.
𝟏 βˆ™ πŸ‘ + πŸ• βˆ™ πŸ‘ = πŸ‘(𝟏 + πŸ•)
b.
(1 + 7) + (1 + 7) + (1 + 7)
c.
2 βˆ™ 1 + (1 + 7) + (7 βˆ™ 2)
d.
β„Žβˆ™3+6βˆ™3
e.
(β„Ž + 6) + (β„Ž + 6) + (β„Ž + 6)
f.
2β„Ž + (6 + β„Ž) + 6 βˆ™ 2
g.
π‘—βˆ™3+π‘˜βˆ™3
h.
(𝑗 + π‘˜) + (𝑗 + π‘˜) + (j + k)
i.
2𝑗 + (π‘˜ + 𝑗) + 2π‘˜
Write each sum as a product of two factors. The first one has been done for you.
a.
πŸ”βˆ™πŸ•+πŸ‘βˆ™πŸ• =
πŸ•(πŸ” + πŸ‘)
b.
(8 + 9) + (8 + 9) + (8 + 9)
c.
4 + (12 + 4) + (5 βˆ™ 4)
d.
2y βˆ™ 3 + 4 βˆ™ 3
e.
(x + 5) + (x + 5)
f.
3x + (2 + x) + 5 βˆ™ 2
g.
fβˆ™6+gβˆ™6
h.
(c + d) + (c + d) + (c + d) +
(c + d)
i.
2r + r + s + 2s
Use the following rectangular array to answer the questions below.
a.
Fill in the missing information.
b.
Write the sum represented in the rectangular array.
c.
Use the missing information from part (a) to write the sum from part (b) as a product of two factors.
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7β€’3
4.
Xander goes to the movies with his family. Each family member buys a ticket and two boxes of popcorn. If there are five
members of his family, let 𝑑 represent the cost of a ticket and 𝑝 represent the cost of a box of popcorn. Draw a picture and
write two different expressions that represent the total amount his family spent.
5.
Write each expression in standard form. The first one has been done for you.
6.
a.
βˆ’πŸ‘(𝟏 βˆ’ πŸ–π’Ž βˆ’ πŸπ’) = βˆ’πŸ‘ + πŸπŸ’π’Ž + πŸ”π’
b.
5 βˆ’ 7(βˆ’4π‘ž + 5)
c.
βˆ’(2β„Ž βˆ’ 9) βˆ’ 4β„Ž
d.
6(βˆ’5π‘Ÿ βˆ’ 4) βˆ’ 2(π‘Ÿ βˆ’ 7𝑠 βˆ’ 3)
Combine like terms to write each expression in standard form. The first one has been done for you.
a. (𝒓 βˆ’ 𝒔) + (𝒔 βˆ’ 𝒓) = 𝒓 βˆ’ 𝒓 + 𝒔 βˆ’ 𝒔 = 𝟎
b.
(βˆ’π‘Ÿ + 𝑠) + (𝑠 βˆ’ π‘Ÿ)
c.
(βˆ’π‘Ÿ βˆ’ 𝑠) βˆ’ (βˆ’π‘  βˆ’ π‘Ÿ)
d.
(π‘Ÿ βˆ’ 𝑠) + (𝑠 βˆ’ 𝑑) + (𝑑 βˆ’ π‘Ÿ)
e.
(π‘Ÿ βˆ’ 𝑠) βˆ’ (𝑠 βˆ’ 𝑑) βˆ’ (𝑑 βˆ’ π‘Ÿ)
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Lessons 1-6
7β€’3
Lesson 5: Using the Identity and Inverse to Write Equivalent
Expressions
1. In the morning, Harrison checked the temperature outside to find that it was βˆ’12℉. Later in the afternoon, the
temperature rose 12℉. Write an expression representing the temperature change. What was the afternoon
temperature?
Example 1
Write the sum and then write an equivalent expression by collecting like terms and removing parentheses. The first one has
been done for you.
f. πŸπ’™ and βˆ’πŸπ’™ + πŸ‘ = 𝟐𝐱 + (βˆ’πŸπ±) + πŸ‘ = πŸ‘
g.
g. 2π‘₯ βˆ’ 7 and the opposite of 2π‘₯
h.
The opposite of (5π‘₯ βˆ’ 1) and 5π‘₯
Example 2: Solve
3
4
ο‚§
(4) βˆ™ (3)
ο‚§
4βˆ™
ο‚§
1
9
ο‚§
(βˆ’ 3) βˆ™ βˆ’3
ο‚§
(βˆ’ 5) βˆ™ (βˆ’ 6)
1
4
βˆ™ 9
1
6
5
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Lessons 1-6
7β€’3
Write the product and then write the expression in standard form by removing parentheses and combining like terms. Justify
each step. The first one has been done for you.
i.
𝟏
The multiplicative inverse of
𝟏
βˆ™
πŸ“
πŸ“
𝟏
πŸ“
𝟏
and (πŸπ’™ βˆ’ )
πŸ“
πŸ“
= = 𝟏, so 5 is the multiplicative inverse of 1/5.
πŸ“
𝟏
5 (πŸπ’™ βˆ’ ) 𝑼𝒔𝒆 𝒕𝒉𝒆 π’…π’Šπ’”π’•π’“π’Šπ’ƒπ’–π’•π’Šπ’—π’† π’‘π’“π’π’‘π’†π’“π’•π’š.
πŸ“
πŸπŸŽπ’™ βˆ’ 𝟏
j.
The multiplicative inverse of 2 and (2π‘₯ + 4)
k.
The multiplicative inverse of (
1
3π‘₯+5
) and
1
3
Exercise 2
Write the product and then write the expression in standard form by removing parentheses and combining like terms. Justify
each step. The first one has been done for you.
l.
The reciprocal of πŸ‘ and βˆ’πŸ”π’š βˆ’ πŸ‘π’™
Reciprocal of 3 =
𝟏
πŸ‘
𝟏
πŸ‘
πŸ‘
because
𝟏
βˆ™
𝟏
πŸ‘
=1
(βˆ’πŸ”π’š βˆ’ πŸ‘π’™) Use the distributive Property
𝟏
βˆ™ βˆ’πŸ”π’š βˆ’
πŸ‘
βˆ’πŸ”π²
πŸ‘
βˆ’
πŸ‘π±
πŸ‘
𝟏
πŸ‘
βˆ™ πŸ‘π’™ =
βˆ’πŸ”π²
πŸ‘
βˆ’
πŸ‘π±
πŸ‘
Combine like terms
= βˆ’πŸπ’š βˆ’ 𝒙
m. The multiplicative inverse of 4 and 4β„Ž βˆ’ 20
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n.
1
1
6
6
7β€’3
The multiplicative inverse of βˆ’ and 2 βˆ’ 𝑗
Problem Set
1. Write the sum and then rewrite the expression in standard form by removing parentheses and collecting like terms. The
first one has been done for you.
a. πŸ” and 𝒑 βˆ’ πŸ”
b. 10𝑀 + 3 and – 3
6+p–6
p
c. βˆ’π‘₯ βˆ’ 11 and the opposite of – 11
d. The opposite of 4π‘₯ and 3 + 4π‘₯
e. 2𝑔 and the opposite of (1 βˆ’ 2𝑔)
2.
Write the product and then rewrite the expression in standard form by removing parentheses and collecting like terms.
The first one has been done for you.
a.
πŸ•π’‰ βˆ’ 𝟏 and the multiplicative inverse of πŸ•
𝟏
(πŸ•π’‰ βˆ’ 𝟏)
πŸ•
𝟏
π’‰βˆ’
πŸ•
b.
The multiplicative inverse of βˆ’5 and 10𝑣 – 5
c.
9 βˆ’ 𝑏 and the multiplicative inverse of 9
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1
1
4
4
d.
The multiplicative inverse of and 5𝑑 βˆ’
e.
The multiplicative inverse of βˆ’
1
10π‘₯
and
1
10π‘₯
βˆ’
7β€’3
1
10
5. Write the expressions in standard form. The first one has been done for you.
𝟏
f.
πŸ’
1
g.
6
4
h.
5
1
i.
8
3
j.
4
1
k.
5
(πŸ’π’™ + πŸ–) =
𝟏
πŸ’
βˆ™ πŸ’π± +
𝟏
πŸ’
βˆ™πŸ–=𝐱+ 𝟐
(π‘Ÿ βˆ’ 6)
(π‘₯ + 1)
(2π‘₯ + 4)
(5π‘₯ βˆ’ 1)
(10π‘₯ βˆ’ 5) βˆ’ 3
Lesson 6: Collecting Rational Number Like Terms
Do the computations, leaving your answers in simplest/standard form. Show your steps.
ο‚·
Terry weighs 40 kg. Janice weighs 2
ο‚·
23 βˆ’ 12 βˆ’ 5
ο‚·
1
5
2
1
3
4
kg less than Terry. What is their combined weight?
4
+ (βˆ’4)
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7β€’3
3
5
ο‚·
4( )
ο‚·
Mr. Jackson bought 1 lbs of beef. He cooked of it for lunch. How much does he have left?
ο‚·
2
𝑛
3
3
1
3
3
5
4
2
βˆ’ 4𝑛 +6𝑛 + 29 𝑛
Example 1
Rewrite the expression in standard form by collecting like terms.
𝟏
𝟐
𝟏
𝟏
𝟏
πŸ‘
πŸ‘
πŸ’
πŸ‘
πŸ“
πŸ’
𝟐
πŸ“
πŸ’
πŸ“
The problem
𝒂+𝟐 𝒃+ βˆ’ π’‚βˆ’πŸ 𝒃+ + π’‚βˆ’πŸ’βˆ’ 𝒃
𝟐
1
2
1
1
1
3 3
4
π‘Ž + 2 𝑏 + + (βˆ’ π‘Ž) + (βˆ’1 𝑏) + + π‘Ž + (βˆ’4) + (βˆ’ 𝑏)
2
3
5
4
2
5 4
5
Subtraction as adding the inverse
1
1
3
2
1
4
1 3
π‘Ž + (βˆ’ π‘Ž) + π‘Ž + 2 𝑏 + (βˆ’1 𝑏) + (βˆ’ 𝑏) + + + (βˆ’4)
2
4
4
3
2
5
5 5
Any order property (commutative
property)
1
1
3
2
1
4
4
( + (βˆ’ ) + ) π‘Ž + (2 + (βˆ’1 ) + (βˆ’ )) 𝑏 + ( + (βˆ’4))
2
4
4
3
2
5
5
π‘Ž+
11
30
π‘βˆ’
16
5
=π‘Ž+
11
30
π‘βˆ’3
Collecting like terms by applying
distributive property
Arithmetic rules for rational numbers
1
5
The expression with eight terms can be rewritten with a minimum of three terms.
Exercise 1
For the following exercises, predict how many terms the resulting expression will have after collecting like terms. Then, write
the expression in standard form by collecting like terms.
l.
2
5
1
3
6
10
π‘”βˆ’ βˆ’π‘”+
π‘”βˆ’
4
# of Terms Prediction: __________
5
3
1
1
1
7
3
2
4
m. 𝑖 + 6𝑖 βˆ’ 𝑖 + β„Ž + 𝑖 βˆ’ β„Ž + β„Ž
Lesson 1:
Date:
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7β€’3
Example 3
Writing a proof. Write each expression in standard form by collecting like terms. Justify each step.
1
1 1
1
5 βˆ’ (3 ) ( π‘₯ βˆ’ )
3
3 2
4
16
10 1
10
1
+ (βˆ’ ) ( π‘₯) + (βˆ’ ) (βˆ’ )
3
3 2
3
4
Write mixed numbers as improper fractions, then distribute.
16
5
5
+ (βˆ’ π‘₯) +
3
3
6
Any grouping (associative) and arithmetic rules for multiplying rational numbers
5
32 5
βˆ’ π‘₯+( + )
3
6 6
Commutative property and associative property of addition, collect like terms
5
37
βˆ’ π‘₯+
3
6
Apply arithmetic rule for adding rational numbers
Exercise 3
Rewrite the following expressions in standard form by finding the product and collecting like terms.
n.
o.
1
1 1
3
2 2
βˆ’6 βˆ’ ( + 𝑦)
2
3
1 1
1
3 4
3
+ ( π‘“βˆ’1 )
Example 4
Model how to write the expression in standard form using rules of rational numbers.
π‘₯
2π‘₯ π‘₯ + 1 3π‘₯ βˆ’ 1
+
+
+
20 5
2
10
π‘₯
4(2π‘₯) 10(π‘₯ + 1) 2(3π‘₯ βˆ’ 1)
+
+
+
20
20
20
20
π‘₯ + 8π‘₯ + 10π‘₯ + 10 + 6π‘₯ βˆ’ 2
20
25π‘₯ + 8
20
5
2
π‘₯+
4
5
Lesson 1:
Date:
© 2013 Common Core, Inc. Some rights reserved. commoncore.org
1
2
1
1 3
1
π‘₯+ π‘₯+ π‘₯+ +
π‘₯βˆ’
20
5
2
2 10
10
1 2 1 3
1 1
( + + + )π‘₯ + ( βˆ’ )
20 5 2 10
2 10
1
8 10 6
5
1
( +
+
+ )π‘₯ + ( βˆ’ )
20 20 20 20
10 10
5
2
π‘₯+
4
5
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Lessons 1-6
NYS COMMON CORE MATHEMATICS CURRICULUM
7β€’3
Evaluate the original expression and their answers when π‘₯ = 20. Do you get the same number?
π‘₯
2π‘₯ π‘₯ + 1 3π‘₯ βˆ’ 1
+
+
+
20 5
2
10
20 2(20) 20 + 1 3(20) βˆ’ 1
+
+
+
20
5
2
10
21 59
1+8+
+
2 10
105 59
9+
+
10 10
164
9+
10
4
9 + 16
10
2
25
5
5
2
π‘₯+
4
5
5
2
(20) +
4
5
2
25 +
5
2
25
5
Exercise 4
Rewrite the following expression in standard form by finding common denominators and collecting like terms.
2β„Ž β„Ž β„Ž βˆ’ 4
βˆ’ +
3 9
6
Example
Method 1:
Method 2a:
1(3π‘₯ βˆ’ 4) 5π‘₯ + 2
βˆ’
3
8
8(3π‘₯ βˆ’ 4) 3(5π‘₯ + 2)
βˆ’
24
24
((24π‘₯ βˆ’ 32) βˆ’ (15π‘₯ + 6))
24
(24π‘₯ βˆ’ 32 βˆ’ 15π‘₯ βˆ’ 6)
24
9π‘₯ βˆ’ 38
24
9π‘₯ 38
βˆ’
24 24
Method 2b:
6π‘₯ βˆ’ 8 5π‘₯ + 2
βˆ’
6
8
4(6π‘₯ βˆ’ 8) 3(5π‘₯ + 2)
βˆ’
24
8
(24π‘₯ βˆ’ 32 βˆ’ 15π‘₯ βˆ’ 6)
24
9π‘₯ βˆ’ 38
24
9π‘₯ 38
βˆ’
24 24
6
8 5
2
π‘₯βˆ’ βˆ’ π‘₯βˆ’
6
6 8
8
4 5π‘₯ 1
π‘₯βˆ’ βˆ’
βˆ’
3 8 4
5
4 1
1π‘₯ βˆ’ π‘₯ βˆ’ βˆ’
8
3 4
3
16 3
π‘₯βˆ’
βˆ’
8
12 12
3
19
π‘₯βˆ’
8
12
Method 3:
1
5π‘₯ 1
(3π‘₯ βˆ’ 4) βˆ’ ( + )
3
8 4
4 5
1
π‘₯βˆ’ βˆ’ π‘₯βˆ’
3 8
4
5
4 1
1π‘₯ βˆ’ π‘₯ βˆ’ βˆ’
8
3 4
3
16 3
π‘₯βˆ’
βˆ’
8
12 12
3
19
π‘₯βˆ’
8
12
3
19
π‘₯βˆ’
8
12
3
19
π‘₯βˆ’
8
12
Lesson 1:
Date:
© 2013 Common Core, Inc. Some rights reserved. commoncore.org
Generating Equivalent Expressions
1/21/15
S.25
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Lessons 1-6
NYS COMMON CORE MATHEMATICS CURRICULUM
7β€’3
Exercise 5
Write the following expression in standard form. Which method do you like? Look at the method box on the last page.
a.
b.
2(3π‘₯βˆ’4)
6
2π‘₯βˆ’11
4
βˆ’
βˆ’
5π‘₯+2
8
3(π‘₯βˆ’2)
10
Problem Set
1. Write the indicated expressions. The first one has been done for you.
a.
𝟏
𝟐
1
2
π’Ž inches in feet.
π’Žβˆ™
1
12
=
1
24
π’Ž. =
1
24
π’Ž ft.
2
b. The perimeter of a square with 𝑔 cm sides.
3
c. The number of pounds in 9 oz.
3
d. The average speed of a train that travels π‘₯ miles in hour.
4
e.
1
1
Devin is 1 years younger than Eli. April is as old as Devin. Jill is 5 years older than April. If Eli is 𝐸 years old, what
4
5
is Jill’s age in terms of 𝐸?
Lesson 1:
Date:
© 2013 Common Core, Inc. Some rights reserved. commoncore.org
Generating Equivalent Expressions
1/21/15
S.26
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
26
Lessons 1-6
NYS COMMON CORE MATHEMATICS CURRICULUM
2.
Rewrite the expressions by collecting like terms. The first one has been done for you.
a.
𝟏
𝟐
πŸ’
πŸ–
𝟏
πŸ–
c.
e.
3.
7β€’3
πŸ‘
π’Œβˆ’ π’Œ
b.
πŸ–
πŸ‘
πŸ–
π’Œ
1
7
5
7π‘Ÿ
+ 15
π’Œβˆ’ π’Œ
1
3
1
2
3
5
1
1
1
1
d. βˆ’π‘ + 5 π‘ž βˆ’ 10 π‘ž + 9 βˆ’ 9 𝑝 + 2 3 𝑝
βˆ’3π‘Ž βˆ’ 2𝑏 βˆ’ 4 + 2𝑏 βˆ’ 3𝑏 + 6π‘Ž
5
2π‘Ÿ
𝑦
𝑦 βˆ’ 14
f.
3𝑛
8
𝑛
𝑛
βˆ’4 +22
Rewrite the expressions by using the distributive property and collecting like terms. The first one has been done for you.
a.
πŸ’
πŸ“
(πŸπŸ“π’™ βˆ’ πŸ“)
b.
πŸ’
πŸ’
(πŸπŸ“π’™) βˆ’ (πŸ“)
πŸ“
πŸ“
𝟏𝟐𝐱 βˆ’ πŸ’
d.
g.
1
1
8
2
8 βˆ’4( π‘Ÿ βˆ’ 3 )
1
4
3
(𝑝 + 4) + (𝑝 βˆ’ 1)
5
e.
h.
Lesson 1:
Date:
© 2013 Common Core, Inc. Some rights reserved. commoncore.org
4 1
( 𝑐 βˆ’ 5)
c.
(14π‘₯ + 7) βˆ’ 5
f.
5 4
1
7
7
8
5
(𝑀 + 1) + (𝑀 βˆ’ 3)
6
i.
4
2
1
5
3
6
2 𝑣 βˆ’ (4𝑣 + 1 )
1
5
4
5
(5π‘₯ βˆ’ 15) βˆ’ 2π‘₯
1
(𝑐 βˆ’ 1) βˆ’ (2𝑐 + 1)
8
Generating Equivalent Expressions
1/21/15
S.27
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Lessons 1-6
NYS COMMON CORE MATHEMATICS CURRICULUM
j.
m.
p.
s.
2
3
π‘˜
2
3
1
3
4
3
4
(β„Ž + ) βˆ’ (β„Ž + )
4π‘˜
βˆ’
5
βˆ’3
3(5π‘”βˆ’1)
4
1+𝑓
5
βˆ’
βˆ’
1+𝑓
3
k.
n.
2𝑔+7
6
+
2
3
3
2
3
4
3
4
(β„Ž + ) βˆ’ (β„Ž βˆ’ )
3𝑑+2
7
q. βˆ’
+
3𝑑+1
5
π‘‘βˆ’4
o.
14
+
l.
π‘‘βˆ’5
2
7
+ 10
r.
2
3
3
2
3
4
3
4
7β€’3
(β„Ž + ) + (β„Ž βˆ’ )
9π‘₯βˆ’4
10
9𝑀
6
+
+
3π‘₯+2
5
2π‘€βˆ’7
3
βˆ’
π‘€βˆ’5
4
3βˆ’π‘“
6
Lesson 1:
Date:
© 2013 Common Core, Inc. Some rights reserved. commoncore.org
Generating Equivalent Expressions
1/21/15
S.28
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
28