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Average
1.
The average of 5 numbers is 306.4. The
average of the first two numbers is 431 and
the average of the last two numbers is
214.5. Then what is the third number?
(Bank of Maharashtra PO Exam. 25.05.2008)
1) 108
2) 52
3) 321
4) Cannot be determined
5) None of these
6.
2.
7.
The sum of five numbers is 290. The
average of first two numbers is 48.5 and the
average of last two numbers is 53.5. Then
what is the third number ?
(Indian Overseas Bank PO Exam. 05.04.2009)
1) 72
2) 84
3) 96
4) 108
5) None of these
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The average weight of a group of 53 girls
was calculated as 58 kgs. It was later
discovered that the weight of one of the
girls was read as 65 kgs., where as her
actual weight was 45 kgs. Then what is the
actual average weight of the group of 53
girls? (rounded off to two digits after
decimal)
(Indian Overseas Bank PO Exam. 05.04.2009)
1) 58.62 kgs
2) 58.37 kgs
3) 57.37 kgs.
4) 57.62 kgs
5) None of these
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3.
The average of 5 numbers is 65. The
average of the first two numbers is 81 and
the average of the last two numbers is 38.
Then what is the third number?
(Indian Bank Rural Marketing Officer Exam.
03.01.2010)
1) 63
2) 87
3) 99
4) Cannot be determined
5) None of these
tio
Kamlesh bought 65 books for Rs.1,050
from one shop and 50 books for Rs.1,020
from another. Then what is the average
price he paid per book?
(Bank of Maharashtra PO Exam. 25.05.2008)
1) Rs. 36.40
2) Rs. 18.20
3) Rs. 24
4) Rs. 18
5) None of these
The average age of the family of five
members is 24. If the present age of
youngest member is 8 years, then what was
the average age of the family at the time of
the birth of the youngest member?
(Corporation Bank PO Exam. 22.11.2009)
1) 20 years
2) 16 years
3) 12 years
4) 18 years
5) 21 years
The average marks in Science subject of a
class of 20 students is 68. If the marks of
two students were misread as 48 and 65 of
the actual marks 72 and 61 respectively,
then what would be the correct average?
(Corporation Bank PO Exam. 22.11.2009)
1) 68.5
2) 69
3) 69.5
4) 69.5
5) 66
8.
The total marks obtained by student in
Physics, Chemistry and Mathematics
together is 120 more than the marks
obtained by him in Chemistry. What are the
average marks obtained by him in Physics
and Mathematics together ?
(Allahabad Bank PO Exam. 21.02.2010)
1) 60
2) 120
3) 40
4) Cannot be determined
5) None of these
9.
The average age of 80 boys in a class is 15
years. The average age of a group of 15
boys in the class is 16 and the average age
of another 25 boys in the class is 14 years.
Then what is the average age of the
remaining boys in the class?
(Corporation Bank PO Exam. 09.05.2010)
1) 15.25 years
2) 14 years
3) 14.75 years
4) Cannot be determined
5) None of these
10. The average age of seven boys sitting in a
row facing North is 26 years. If the average
age of first three boys is 19 years and the
average age of last three boys is 32 years,
then what is the age of the boy who is
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12. The average of five numbers is 56. If the
average of first four numbers is 54. Then
what is the value of the fifth number?
(Bank of India PO Exam. 31.10.2010)
1) 68
2) 72
3) 56
4) 64
5) None of these
16. The average score of Rahul, Manish and
Suresh is 63. Rahul’s score is 15 less than
Ajay and 10 more than Manish. If Ajay
scored 30 marks more than the average
score of Rahul, Manish and Suresh, then
what is the sum of Manish’s and Suresh’s
scores ?
(Corporation Bank PO Exam. 16.01.2011)
1) 120
2) 111
3) 117
4) Cannot be determined
5) None of these
n.
11. Ram’s present age is three times his son’s
present age and two fifth of his father’s
present age. The average of the present
ages of all of them is 46 years. Then what
is the difference between the Ram’s son’s
present age and Ram’s father’s present age
?
(Bank Of Baroda PO Exam. 30.05.2010)
1) 68 years
2) 88 years
3) 58 years
4) Cannot be determined
5) None of these
5) None of these
15. The sum of eight consecutive even
numbers of set-A is 376. What is the sum of
different set of five consecutive numbers
whose lowest number is 15 more than the
mean of set-A?
(Union Bank Of India PO Exam. 09.01.2001)
1) 296
2) 320
3) 324
4) 284
5) None of these
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sitting in middle of the row?
(Punjab & Sind Bank PO Exam. 16.05.2010)
1) 28 years
2) 29 years
3) 24 years
4) 24 years
5) None of these
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13. The average weight of 45 students in a class
was calculated as 36 kg. It was later found
that the weight of two students in the class
was wrongly calculated. The actual weight
of one of the boys in the class was 32 kg.,
but it was calculated as 34 kg. and the
weight of another boy in the class was 45
kg.; where as it was calculates as 40 kg.
Then what is the actual average weight of
the 45 students in the calss?
(Rounded off to two-digits after decimal)
(PNB
Management
Trainee
Exam.
19.12.2010)
1) 36.07 kg
2) 36.16 kg 3) 35.84 kg
4) Cannot be determined
5) None of these
14. Seema’s present age is four times her son’s
present age and four seventh of her father’s
present age. The average of the present
ages of all three of them is 32 years. Then
what is the difference between the seema’s
son’s present age?
(Bank of Maharashtra Exam. 19.12.2010)
1) 44 years
2) 48 years
3) 46 years
4) Cannot be determined
17. The sum of 8 consecutive odd numbers is
656. Also average of four consecutive even
numbers is 87. What is the sum of the
smallest odd number and second largest
even number ?
(Bank Of Baroda PO Exam. 13.03.2011)
1) 165
2) 175
3) 163
4) Cannot be determined
5) None of these
18. The average marks in English subject of a
class of 24 students is 56. If the marks of
three students were misread as 44, 45 and
61 of the actual marks 48, 59 and 67
respectively, then what would be the
correct average?
(IBPS Bank PO/MT CWE Exam. 18.09.2011)
1) 56
2) 55
3) 57.5
4) 58.5
5) None of these
19. Amit’s present age is three time Pratibha’s
present age and nine-thirteenth of his
father’s present age. The sum of the present
age of all of them is 150 years. Then what
is the difference between Pratibha’s present
age and Amit’s father’s present age ?
(IDBI Bank Officer Exam. 16.09.2012)
1) 56 years
2) 64 years
3) 60 years
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4)Cannot be determined
5) None of these
1) 12 years
4) 14 years
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26. In Arun’s opinion his weight is grater than
65 kg but less than 72 kg. His brother does
not agree with Arun and he thinks that
Arun’s weight is grater than 60 kg but less
than 70 kg. His mother’s view is that his
weight cannot be grater than 68 kg. If all of
them are correct in their estimation,then
what is the average of different probably
weights of Arun?
(SBI Banks PO Exam. 20.08.2000)
1) 69 kg
2) 67 kg
3) 68 kg
4) Data inadequate
5) None of these
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21. The average of four consecutive even
numbers P, Q, R and S respectively (in
increasing order) is 51. Then what is the
product of P and R?
(IBPS RRBs Office Assistance CWE Exam.
09.09.2012)
1) 2592
2) 2400
3) 2600
4) 2808
5) None of these
25. Of the three numbers, the average of the
first and the second is grate than the
average of the second and the third by 15.
Then what is the difference between the
first and the third of the three numbers?
(SBI Banks PO Exam. 20.08.2000)
1) 15
2) 45
3) 60
4) Data inadequate
5) None of these
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20. Farah was married 8 years ago. Today her
2
age is 1 times to that at the time of
7
marriage. At present her daughter’s age is
1
th of her age. Then what was her
6
daughter’s age 3 years ago?
(IBPS Specialist Officer CWE 17.03.2013)
1) 6 years
2) 7 years
3) 3 years
4) Cannot be determined
5) None of these
2) 20 years
3) 10 years
5) Data inadequate
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22. The average height of 27 persons was
recorded as 162 cm. If the height of
Shreyas was deleted from the observation,
the average height reduced by 1cm. Then
what was Shreya’s height?
(IBPS RRBs Office Assistance CWE Exam.
09.09.2012)
1) 184 cm
2) 226 cm
3) 179 cm
4) 186 cm
5) None of these
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23. If the averages of P and R are added to
twice the age of Q, the total becomes 59; if
the ages of Q and R are added to thrice age
of P, the total becomes 68 and if the age of
P is added to thrice the age of Q and thrice
the age of R, the total becomes 108. Then
what is the age of P?
(SBI Associative Banks PO Exam. 14.02.1999)
1) 15 years
2) 19 years
3) 17 years
4) 12 years
5) None of these
24. The product of the ages of Harish and
Seema is 240. If twice the age of seema is
more than Harish’s age by 4 years. Then
what is Seema’s age in years?
(SBI Associate Banks PO Exam. 14.02.1999)
27. Average weight of three boys P, T and R is
1
54 kgs while the average weight of three
3
boys, T, F and G is 53 kgs. Then what is the
average weight of P, T, R, F and H?
(SBI Associative Banks PO Exam. 21.07.2002)
1) 53.8 kgs
2) 52.4 kgs
3) 53.2 kgs
4) Data inadequate
5) None of these
28. Present age of Rahul is 5 years less than
Ritu’s present age. If 3 years ago Ritu’s age
was x, then which of the following
represents Rahul’s present age?
(SBI PO Exam. 26.11.2006)
1) x + 3
2) x – 2
3) x – 3 + 8
4) x + 3 + 8 5) None of these
29. The average weight of group of 75 girls
was calculated as 47 kgs. It was later
discovered that the weight of one of the
girls was read as 45 kgs, whereas her actual
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4
5) None of these
36. In three numbers, the first is twice the
second and thrice the third. If the average
of these three numbers is 44, then the first
number is?
1) 72
2) 24
3) 36
4) 44
5) None of these
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31. The average age of 80 girls was 20 years,
the average age of 20 of them was 22 years
and that of another 20 was 24 years. Find
the average age of the remaining girls?
(SBI PO Preliminary (Tire-I) Exam.
27.07.2008)
1) 17 years
2) 19 years
3) 21 years
4) 21 years
5) None of these
4) 52
n.
30. The difference between the present ages of
Arun and Deepak is 14 years. Seven years
ago the ratio of their ages was 5:7
respectively. Then what is Deepak’s present
age?
(SBI PO Preliminary (Tire-I) Exam.
27.04.2008)
1) 49 years
2) 42 years
3) 63 years
4) 35 years
5) None of these
by 4. What is his average after 19th
innings?
1) 22
2) 24
3) 28
4) 26
5) None of these
35. The average weight of 45 students in a class
is 52 kg. Five of them whose average
weight is 48 kg leave the class and other
five students whose average weight is 54
kg join the class. Then what is the new
average weight (in kg) of the class?
1
2
1) 52.6
2) 52
3) 52
3
3
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weight was 25 kgs. Then what is the actual
average weight of the group of 75 girls?
(Round off to two digits after decimal)
(SBI PO Preliminary (Tire-I) Exam.
27.04.2008)
1) 46.73 kgs 2) 46.64 kgs 3) 45.96 kgs
4) Cannot be determined
5) None of these
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32. The average of the ages of Sumit, Krishna
and Rishabh is 43 years and the average of
the ages of Sumit, Rishabh and Rohit is 49
years. If Rohit is 54 years old, then what is
Krishna’s age?
(SBI PO Preliminary (Tire-I) Exam.
27.07.2008)
1) 45 years
2) 24 years
3) 36 years
4) Cannot be determined
5) None of these
33. Father’s age is 30 years more than the son’s
age. Ten years hence the father’s age will
become three times the son’s age that time.
Then what is son’s present age in years?
(SBI Associative Banks PO Exam. 07.08.2011)
1) 8
2) 7
3) 5
4) Cannot be determined
5) None of these
34. A batsman makes a score of 98 runs in the
19th innings and thus increases his average
37. The batting average of 40 innings of a
cricket player is 50 runs. His highest score
exceeds his lowest score by 172 runs. If
these two innings are excluded the average
of the remaing 38 innings is 48. Then his
highest score was?
1) 172
2) 173
3) 174
4) 176
5) None of these
38. Nine persons went to a hotel for taking their
meals. Eight of them spent Rs. 12 each over
their meals and the ninth spent Rs. 8 more
than the average expending of all the nine.
Total money spent by them was?
1) Rs. 104
2) Rs. 105
3) Rs. 116
4) Rs. 117
5) None of these
39. A demographic survey of 100 families in
which two parents were present releaved
that the average age A, of the oldest child is
1
20 yr less than
the sum of the ages of the
2
two parents. If F presents the age of one
parents and M the ages of the other parents,
hten which of the following is equivalent to
A?
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4) F + M – 10
5) None of these
40. The average of three numbers is 135. The
largest number is 180 and the difference
between the others is 25. Then the smallest
number is?
1) 130
2) 125
3) 120
4) 100
5) None of these
1
2
5) None of these
46. The mean of 1, 7, 5, 3, 4 and 10 is m. The
mean of 10, 12, 3, 5, 1, 7 and p is m + 1 and
their median is q. Then, q is equal to?
1) 4
2) 5
3) 10
4) 12
5) None of these
47. In a class, the average score of girls in an
examination is 73 and that of boys is 71.
The average score for the whole class is
71.8. The percentage of the girls in the class
is?
1) 60%
2) 40%
3) 1.8%
4) 18%
5) None of these
48. The average of 10 numbers is 40.2. Later it
is found that two numbers have been
wrongly added. The first is 18 grater than
the actual number and the second number
added is 13 instead of 31. Find the correct
average.
1) 40.2
2) 40.4
3) 40.6
4) 40.8
5) None of these
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41. Of the three numbers, the first is twice the
second and the second is twice the third.
The average of these numbers is 21. Find
the largest number out of these.
1) 36
2) 28
3) 47
4) 48
5) None of these
4) 17
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F+ M
− 20
2
F+ M
+ 20
2
n.
3)
2)
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1) F + M − 20
2
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42. There are 30 students in a class. The
average age of the first 10 students is 12.5
yr. The average age of the next 20 students
is 13.1 yrs. Then the average age of the
whole class is?
1) 12.5 yr
2) 12.7 yr
3) 12.8 yr
4) 12.9 yr
5) None of these
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43. The weight in kilograms of 10 students are
52, 45, 31, 35, 40, 55, 60, 38, 44, 36. If 44
is repalce by 46 and 40 is replaced by 35,
then the new median will be?
1) 42
2) 40.5
3) 40
4) 41.5
5) None of these
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44. In the first 10 overs of a cricket game, the
run rate was only 3.2. What should be the
run rate in the remaining 40 overs to reach
the target of 282 runs?
1) 6.25
2) 6.50
3) 6.75
4) 7
5) None of these
49. The average of 11 numbers is 10.9. If the
average of the first six numbers is 10.5 and
that of the last six numbers 11.4, then the
middle number is?
1) 11.5
2) 11.4
3) 11.3
4) 11.0
5) None of these
50. The average temperature of the first four
o
days of a week is 40.2 C and that of the last
o
four days is 41.3 C. If the average
o
temperature for the whole week is 40.6 C,
then the temperature on the fourth day is?
o
o
o
2) 38.5 C
3) 41.3 C
1) 40.8 C
o
5) None of these
4) 41.8 C
45. The average (arithmetic mean) of x and y is
40. If z = 10, then what is the average of x,
y and z?
2
1) 16
2) 30
3) 25
3
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Answers
∴ Required average age =
9.
2070
= Rs.18
115
120
= 60
2
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1050 + 1020
65 + 50
(5)
Third number
= 290 – 2 × 48.5 − 2 × 53.5
= 290 − 97 − 107 = 86
(1)
Tricky Approach:
Let the required average age be x years.
∴ 80 × 15 = 15 × 16 + 25 × 14 + 40 × x
⇒ 40 x = 1200 – 240 – 350 = 610
∴x =
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(4)
Actual weight of 53 girls
= 53 × 58 + 45 − 65
= 3074 + 45 − 65 = 3054 kg.
∴ Required actual average weight
3054
=
= 57.62kg (or)
53
610
= 15.25years
40
.s
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10. (2)
Age of the fourth boy
= ( 26 × 7 – 3 × 19 – 3 × 32 ) years
= ( 182 – 57 – 96 )
= 29 years
11. (5)
Tricky Approach:
Present age of Ram's son = x years
∴ Ram's present age = 3x years
15 x
Ram's father's present age =
years
2
∴ x + 3x +
15 x
= 46 × 3
2
(2)
Difference of marks
= 72 + 61 – 48 – 65 = 20
⇒ 23x = 46 × 3
⇒x=6
20
= 69
∴ Correct average marks = 68 +
20
∴ Required difference =
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6.
(1)
Required average =
Decrease in weight = 65 – 45 = 20 kg
∴ Required actual average weight
20 ⎞
⎛
= ⎜ 58 − ⎟ kg = 57.62kg
53 ⎠
⎝
5.
8.
n.
=
4.
(2)
The third number
= 5 × 65 − 2 × 81 − 2 × 38
= 325 − 162 −76 = 87
(4)
required average =
3.
7.
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2.
(5)
According to the question,
Sum of five numbers = 5 × 306.4 = 1532
∴ Third number
= 1532 – 2 × 431 − 2 × 214.5
= 1532 − 862 − 429 = 241
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1.
80
= 16years
5
(2)
Total age of 5 members family
= 24 × 5
= 120 years
Total age, 8 years ago
= 120 – 5 × 8
= 80 years.
=
15 x
13x
−x=
2
2
13 × 6
= 39years
2
12. (4)
Fifth number = 5 × 56 – 4 × 54
= 280 – 216 = 64
13. (1)
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Actual weight of all the students
= 36 × 45 – 34 + 32 – 40 + 45
= 1620 + 3 = 1623kg.
∴ Actual average weight
1623
=
= 36.07kg.
45
24
15. (2)
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13 x
10 x
∴ Required difference =
−x=
3
3
10
= × 18 = 60 years
3
376
= 47
8
The lowest number of second set = 47 + 15
= 62
∴ Required = 62 + 63 + 64 + 65 + 66 = 320
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Man of set A ⇒
⇒ 3x + 9x + 13x = 150 × 3
⇒ 25x = 150 × 3
150 × 3
⇒x=
= 18
25
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∴ Required difference
= 7x – x = 6x
= 6 × 8 = 48 years
13 x
= 150
3
n.
∴ x + 4x + 7x = 32 × 3
⇒ 12x = 96
96
⇒x=
=8
12
∴ x + 3x +
co
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14. (2)
Let Seema's son's present age = x years
∴ Seema's present age = 4x years
∴ Seema's husband's present age
7
= 4 x × = 7 x (years)
4
24
= 57
∴ Correct average = 56 +
24
19. (3)
Pratibha's present age = x years
∴ Amit's present age = 3x years
∴ Father's present age
3x × 13 13x
=
=
years
9
3
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16. (2)
Ajay's score = 63 + 30 = 93
∴ Rahul's score = 93 – 53 = 73
∴ Sum of Manish's and Suresh's scores
= 3 × 63 – 78 = 189 – 78 = 111
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17. (3)
Average of 8 consecutive odd numbers
656
=
= 82
8
∴ Fourth number = 82 – 1 = 81
∴ First numbers = 75
Average of 4 even numbers = 87
∴ Second even number = 87 – 1 =86
Second largest even number = 88
∴ Required sum = 75 + 88 = 163
18. (5)
Difference = 48 – 59 – 67 – 44 – 45 – 61 =
20. (1)
Let Farah's age 8 years ago be x years.
Farh's present age = ( x + 8 ) years
9x
∴x +8 =
7
⇒ 7x + 56 = 9x
⇒ 2x = 56
⇒ x = 28
Farah's present age = 28 + 8 = 36 years
Her daughter's age 3 years ago
1
= 36 × = 6 years
6
21. (5)
x + x + 2 + x + 4 + x + 6 = 4 × 51
⇒ 4x + 12 = 204
⇒ 4x = 204 – 12 = 192
192
⇒x=
= 48 = P
4
∴ R = 48 + 4 = 52
∴ P × R = 48 × 52 = 2496
22. (5)
Height of Shareyas = 162 + 26 = 188 cm
23. (4)
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P=
96
= 12 years
8
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27. (4)
We are to determine the average weight of
P, T, R, F and H.
Obviously, this can't be determined as we
don't know the weight of H.
28. (2)
3 years ago Ritu's age = x
∴ Ritu's present age = x + 3
Rahul's present age = Ritu's present age – 5
=x+3–5=x–2
29. (1)
Total actual weight of all girls
= 47 × 75 – 45 + 25
= 3525 – 20 = 3505 kg.
3505
∴ Average weight =
= 46.73kg
75
240
=4
y
.s
2y −
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24. (1)
Let the ages of Harish and Seema be x and
y years respectively
∴ According to question,
x + y = 240 ...(i)
2y = x + 4
...(ii)
From equation (i) and (ii)
240
+4
2y =
y
26. (4)
Arun's opinion : 65 < W < 72
Brother's opinion : 60 < W < 70
Mother's option : W > 68 or W < 68
n.
and P + 3Q + 3R = 108 .........(iii)
⇒ P + 3 ( 2P – 9 ) + 3R = 108
⇒ P + 6P – 27 + 3R = 108
⇒ 7P + 3R = 135
From equations (ii) and (iii)
3Q + 3R + 9P – P – 3Q – 3R = 204 – 108
8P = 96
∴ x – z = 30
tio
According to question,
P + R + 2Q = 59 ........... (i)
Q + R + 2P = 68 ........... (ii)
From (i) and (ii)
Q – P + R – R + 3P – 2Q = 68 – 59
2P – Q = 9
2P = 9 + Q
9+Q
P=
2
w
2y2 – 240 = 4y
2y2 – 240 – 4y = 0
(−4) ± 16 + 4 × 2 × 240
2× 2
w
∴ Deepak's present age = 7x + 7
= 7 × 7 + 7 = 56 years
w
∴y =
=
4 ± 1936 4 ± 44 48
=
= = 12 years
4
4
4
25. (5)
Let the three numbers be x, y and z
x+ y y+z
⇒
−
= 15
2
2
=
x+ y− y−z
= 15
2
30. (5)
Seven years ago, let Arun's and Deepak's
age be 5x and 7x years respectively.
∴ Arun's present age = ( 5x + 7 ) years
Deepak' present age = ( 7x + 7 ) years
According to the question,
7x + 7 – 5x – 7 = 14
⇒ 2 x = 14
14
⇒x=
=7
2
31. (1)
Total age of remaining 40 girls
= ( 80 × 20 – 20 × 22 – 20 × 24 ) years
= ( 1600 – 440 – 480 ) years
= 680 years
∴ Required average age
680
=
= 17years
40
32. (3)
( Sumit + Krishna + Rishabh )'s age
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Thus, average after 19th innings
= x +4 = 22 + 4 = 26
w
w
w
.s
ak
sh
i
35. (2)
According to question, total weight of 45
students = 45 × 52 = 2340
Total weight of 5 students who leave
= 5 × 48 = 240
Total weight of 5 students who join
= 5 × 54 = 270
Hence, new total weight of 45 students
= 2340 – 240 + 270 = 2370
2370
2
∴ Average =
= 52 kg
45
3
36. (1)
Let the three numbers be a, b and c.
a = 2b = 3c
a
a
∴ b = and,c =
2
3
a+
Given,
a a
+
2 3 = 44
3
co
m
⇒ a = 72
37. (3)
According to total 40 innings
= 40 × 50 = 2000
Total of 38 innings
= 38 × 48 = 1824
∴ Sum of highest and lowest score
x + y = 2000 – 1824
⇒ x + y = 176
and x – y = 172
Solving Eqs. (i) and (ii), we get
x = 174
38. (4)
Let the nineth person spend Rs. x
Then, average of all the nine
12 × 8 + x 96 + x
⇒
=
9
9
ed
uc
a
34. (4)
Let us suppose that the average of 18
innings be x.
18 x + 98
Then,
= x+4
19
11a
= 44
18
n.
33. (3)
Let the son's present age be x years.
∴ Father's present age = ( x + 30 ) years
After 10 years,
x + 40 = 3 ( x + 10 )
⇒ x + 40 = 3x + 30
⇒ 2x = 10
⇒ x = 5 years
⇒
tio
= 43 × 3 = 129 years
...(i)
( Sumit + Rishabh + Rohit )'s age
= 3 × 49 = 147 years
...(ii)
By equation (i) – (ii), we have
Krishna's age – Rohit's age
= 129 – 147 = – 18
⇒ Krishna's age = 54 – 18
= 36 years
Given, x =
96 + x
+8
9
9x = 96 + x + 72
⇒ 8x = 168
⇒ x = 21
Hence, total money spent
= 96 + 21 = Rs. 117
39. (3)
According to question
F+ M
A=
− 20
2
40. (4)
According to question,
(x − 25) + (x) + 180
= 135
3
∴ 2x + 155 = 405
250
⇒x=
= 125
2
Hence, the smallest number
= 125 – 25 = 100
41. (1)
Let the numbers be a, b and c.
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Then,
2b + b +
Then,
⇒
3
b
2
38 + p
= m +1
7
∴ p = 42 – 38 = 4
∴ Numbers are 1, 3, 4, 5, 7, 10, 12
∴ Median q = 5
b
2 = 21
47. (2)
Let the number of boys be x and that of
girls be y.
Then,
total score of boys = 71x
total score of girls = 73y
71x + 73 y
∴
= 71.8
(x + y )
7b
= 21 ⇒ b = 18
6
co
m
∴ Numbers are 36, 18 and 9
∴ The largest number is 36.
42. (4)
Total age of 10 students = 125 yr
Total age of 20 students = 262 yr
∴ Average age of 30 students
125 + 262
⇒
= 12.9 years
30
n.
⇒ 71x + 73y = 71.8x + 71.8y
⇒ 0.8 x = 1.2 y
x 1.2 3
=
=
y 0.8 2
ak
sh
i
ed
uc
a
43. (4)
According to question, replacing the two
number and arranging them in ascending
order, we get
31, 35, 35, 36, 38, 45, 46, 52, 55, 60
38 + 45 83
∴ Median =
=
= 41.5
2
2
tio
a = 2b and b = 2c or c =
⇒
w
.s
44. (1)
Total runs in the first 10 overs
= 10 × 3.2 = 32
Runs rate in the remaining 40 overs
282 − 32 250
=
=
= 6.25
40
40
w
w
45. (2)
Total of x and y = 40 × 2 = 80
∴ Average of x,y and z
80 + 10 90
=
=
= 30
3
3
46. (2)
According to question,
m=
1 + 7 + 5 + 3 + 4 + 10
6
∴ Percentage of girls in the class
2
× 100 = 40%
5
48. (1)
Sum of 10 numbers = 402
Correct sum of 10 numbers
= 402 – 13 + 31 – 18 = 402
402
= 40.2
Hence, new average =
10
49. (1)
Sum of 11 numbers = 11 × 10.9
Sum of first 6 numbers = 6 × 10.5
Sum of last 6 numbers = 6 × 11.4
∴ The middle number
= 6 × 10.5 + 6 × 11.4 – 11 × 10.9
= 63 + 68.4 − 119.9
= 131.4 − 119.9 = 11.5
50. (4)
Temperature on the fourth day
= 40.2 × 4 + 41.3 × 4 − 40.6 × 7
= 160.8 + 165.2 − 284.2 = 41.8 0C
⇒m=5
and ( m + 1 )
10 + 12 + 3 + 5 + 1 + 7 + p
m=
7
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