CHEM 233, Spring 2016 Midterm #1 Ian R. Gould COMPLETE THIS SECTION : Up to TWO POINTS will be removed for incorrect/missing information! ANSWER KEY PRINTED FIRST NAME PRINTED LAST NAME Person on your LEFT (or Empty or Aisle) Person on your RIGHT (or Empty or Aisle) ASU or Posting ID Class you are REGISTERED FOR (onground or hybrid) The room where most students will take the test for your class, i.e. LS A-191 for onground and PS H-152 for hybrid) **YOU ARE NOT ALLOWED TO TAKE SPARE COPIES OF THIS EXAM FROM THE TESTING ROOM** • PRINT YOUR NAME ON EACH PAGE! 1____________/12 • READ THE DIRECTIONS CAREFULLY! 2____________/22 • USE BLANK PAGES AS SCRATCH PAPER 3____________/24 work on blank pages will not be graded... 4____________/40 Points Removed 5____________/30 (cover errors) ____/2 • DO NOT USE RED INK 6____________/16 Extra Credit_____/5 • DON'T CHEAT, USE COMMON SENSE! 7____________/31 • WRITE CLEARLY! • MOLECULAR MODELS ARE ALLOWED H He Li Be B Na Mg K Total (incl Extra)________/175+5 Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Rb Sr Y Cs Ba Lu Hf Ta W Zr Nb Mo Tc Ru Rh Pd Ag Cd Re Os Ir Pt Au Hg small range range of values broad peak C N O F Ne Al Si P S Cl Ar Ga Ge As Se Br Kr In Sn Sb Te I Xe Tl Pb Bi Po At Rn O H C N N H C O C C H 2720–2820 2 peaks C O N C H O C O H R R 3500 O CH 2200 C R C OH (δ, ppm) 11 220 10 200 9 180 8 160 6 120 R C C R2C Aromatic C 1650 1500 NR2 O C CH3 –H2C NR2 7 140 O X –H2C C CH2 O R C OH O 1710 NMR Correlation Charts Aromatic Ar H mainly 8 - 6.5 H 1600 2000 2500 –OCH2– NH2 variable and condition dependent, ca. 2 - 6 δ OH O 1680 C 3000 O OR 1735 C broad ~3000 (cm-1) N O 2200 2850–2960 broad ~3300 1600–1660 C C broad with spikes ~3300 O H C C H H 3000– 3100 N H Infrared Correlation Chart usually strong O C H 3300 Interaction Energies, kcal/mol Gauche Eclipsing ~1.0 ~0.9 H/H Me/Me ~1.4 ~0.95 H/Me Et/Me Me/Me ~2.6 i-Pr/Me ~1.1 Me/Et ~2.9 t-Bu/Me ~2.7 CR2 5 100 N 4 80 RC C CH 3 60 –OCH2– CR Alkyl 3° > 2° > 1° 2 40 C C NR2 1 20 Alkyl X 3° > 2° > 1° 0 0 -2- CHEMISTRY 233, Fall 2016, MIDTERM #1 NAME Question 1 (12 pts.) Circle and identify all functional groups in the following structure, ignore alkyl groups. Indicate any amines, amides or alcohols as primary, secondary or tertiary, as appropriate. 2° amine HN aromatic N N 3° amine 3° amine O F halide O ketone Ciprofloxacin, the only drug specifically approved by the FDA for treatment of inhalation anthrax exposure carboxylic acid OH Question 2 (22 pts.) Rank the pairs of electrons indicated, A, B, C and D in order of increasing energy. Give an explanation for your choice, most of the points are for the explanation, not the order. B (σ-bonding) A (non-bonding) B < D < A < C H O C (non-bonding) highest energy lowest energy P H D (π-bonding) non-bonding electrons are higher in energy than bonding electrons, therefore A and C are highest in energy, phosphorus is larger and less electronegative than oxygen, C are thus highest π-bonding electrons are higher in energy than σ-bonding electrons, thus D is next highest and B is lowest Question 3 (24 pts.) For the structures A and B below: a) Indicate (in words, do not draw on the structures) the largest BOND DIPOLE moment(s) in each the largest bond dipole moment in A is that associated with the C-N triple bonds the largest dipole moment in B is that associated with the C-F bond b) Between these two largest bond dipole moments (the one from A and the one from B), which would be larger? Give a brief explanation. A has a larger MOLECULAR dipole moment because it has two larger bond dipole moments that add in (roughly) the same direction as the two smaller bond dipole moments in B c) Draw the MOLECULAR DIPOLE MOMENTS ON TOP OF THE STRUCTURES. Your drawings do not need to illustrate the size of the dipole, only the direction. If there is no molecular dipole, indicate so. BRIEFLY explain which structure would have the larger MOLECULAR dipole moment. N C A C N Br F B the C-N triple bond dipole moment is larger because even though F is more electronegative than N, the electrons in the pi-bonds in the triple bond are highly polarizable CHEMISTRY 233, Fall 2016, MIDTERM #1 NAME -3- Question 4 (40 pts.) For the molecular formula C4H8O a) Give the degrees of unsaturation 1 degree of unsaturation b) Draw SEVEN structural isomers that obey the normal rules of valence for each atom. Include all non-bonding electrons. You can draw Lewis structures or line-angle structures (your choice). If you draw line-angle structures, don't forget to include the H atoms that are normally included as part of the functional groups. O H O O O H O O O O H O H O O O O O H H H O H H H O O O O here are a few...... O H c) Draw TWO PAIRS of stereoisomers that obey the normal rules of valence for each atom. Include all non-bonding electrons. If you draw line-angle structures, don't forget to include the H atoms that are normally included as part of the functional groups. DO NOT INCLUDE ANY STRUCTURES in part c) THAT WERE DRAWN AS PART OF YOUR ANSWER TO PART b) OF THIS QUESTION O H O + O + O H here are four pairs O H + O H O H + O Extra Credit (5 pts.) BRIEFLY give ONE way in which anti-bonding orbitals are used by organic molecules they accept electrons in chemical reactions AND they are where the electrons "go to" upon photochemical excitation H CHEMISTRY 233, Fall 2016, MIDTERM #1 -4- NAME Question 5 (30 pts.) The structure shown is a protonated aldehyde, we will discuss the chemistry of these next semester. All non-bonding electrons and formal charges are shown. a) What is the hybridization of the oxygen atom? the oxygen is sp2 hybridized O H3C C H H b) This next question asks if you know what hybridization really means. Give a list of ALL of the atomic orbitals that the oxygen uses in this molecule according ot the hybridization model, AND, state exactly how the oxygen uses each one, e.g. the oxygen uses an sp3 orbital to make a π-bond to sulfur, it uses a p orbital to hold a non-bonding pair of electrons, it uses an sp orbital to make a σ-bond to nitrogen, etc. (I know that these examples are nonsense, they are just to illustrate the FORMAT you should use to answer the question) the oxygen uses an sp2 hybridized atomic orbital to make a sigma-bond to carbon the oxygen uses an sp2 hybridized atomic orbital to make a sigma-bond to hydrogen the oxygen uses an sp2 hybridized atomic orbital to hold the non-bonding pair of electrons the oxygen uses a p atomic orbital to make a pi-bond to carbon c) Directly ON TOP of the protonated aldehydes that are redrawn for you below, draw a picture of the Ψ OR Ψ2 as requested, for the indicated orbitals, AND, in each case write down the atomic orbital or orbitals that you used, as appropriate H H O sp3 A.O. on carbon H3C O C sp2 A.O. on carbon H Ψ for the C-C σ M.O. (ignore any influence of hybridization on electronegativity) sp2 A.O. on carbon C H3C H 1s A.O. on hydrogen Ψ2 for the C-H σ* M.O. Question 6 (16 pts). Give line-angle structures for both stereoisomers of the following condensed formula. Do not forget to add all non-bonding electrons. Label each stereosiomer as either cis- or trans-. CH3CH2CHCHOCH3 O O cis- trans- -5- CHEMISTRY 233, Fall 2016, MIDTERM #1 NAME Question 7 (31 pts.) a) Rank the bonds indicated A, B and C in terms of increasing bond dissociation energy, give a brief explanation. H B B < C A N H < H smallest largest BDE BDE O P C A H H bond C is from H to the most electronegative and smallest element, C thus has the largest BDE bond A is to the largest and least electronegative element, it thus has the smallest BDE b) Draw an energy versus bond separation distance (rZ-H) diagram for homolysis of the three bonds A, B and C above, all on the same diagram provided below. Clearly indicate which diagram refers to which bond cleavage and clearly indicate the three bond dissociation energies. Energy BDE B BDE C BDE A rZ–H c) Treat homolytic bond dissociation as a simple chemical reaction. For BOND A below, add the curved arrows to the structure that illustrate bond-breaking and show the products of homolytic bond breaking (i.e. what you get after breaking the bond) on the "product side" of the reaction arrow below. A H H H H H H H C H C H C C H H C C C C + H H H H H H H H H
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