11-3 Exponential Growth and Decay Why learn this? Exponential growth and decay describe many real-world situations, such as the value of artwork. (See Example 1.) Objective Solve problems involving exponential growth and decay. Vocabulary exponential growth compound interest exponential decay half-life Exponential growth occurs when a quantity increases by the same rate r in each time period t. When this happens, the value of the quantity at any given time can be calculated as a function of the rate and the original amount. Exponential Growth An exponential growth function has the form y = a(1 + r) , where a > 0. t y represents the final amount. a represents the original amount. r represents the rate of growth expressed as a decimal. t represents time. EXAMPLE 1 Exponential Growth The original value of a painting is $1400, and the value increases by 9% each year. Write an exponential growth function to model this situation. Then find the value of the painting in 25 years. In Example 1, round to the nearest hundredth because the problem deals with money. This means you are rounding to the nearest cent. Step 1 Write the exponential growth function for this situation. y = a (1 + r) t Write the formula. = 1400(1 + 0.09) = 1400(1.09) t t Substitute 1400 for a and 0.09 for r. Simplify. Step 2 Find the value in 25 years. y = 1400(1.09)t = 1400(1.09)25 ≈ 12,072.31 Substitute 25 for t. Use a calculator and round to the nearest hundredth. The value of the painting in 25 years is $12,072.31. 1. A sculpture is increasing in value at a rate of 8% per year, and its value in 2000 was $1200. Write an exponential growth function to model this situation. Then find the sculpture’s value in 2006. 11-3 Exponential Growth and Decay 805 A common application of exponential growth is compound interest. Recall that simple interest is earned or paid only on the principal. Compound interest is interest earned or paid on both the principal and previously earned interest. Compound Interest ( r A=P 1+_ n ) nt A represents the balance after t years. P represents the principal, or original amount. r represents the annual interest rate expressed as a decimal. n represents the number of times interest is compounded per year. t represents time in years. EXAMPLE 2 Finance Application Write a compound interest function to model each situation. Then find the balance after the given number of years. A $1000 invested at a rate of 3% compounded quarterly; 5 years Step 1 Write the compound interest function for this situation. r nt A=P 1+_ Write the formula. n ( ) ( 0.03 = 1000 1 + _ 4 ) 4t Substitute 1000 for P, 0.03 for r, and 4 for n. Simplify. = 1000(1.0075)4t For compound interest, • annually means “once per year” (n = 1). • quarterly means “4 times per year” (n = 4). • monthly means “12 times per year” (n = 12). Step 2 Find the balance after 5 years. Substitute 5 for t. A = 1000(1.0075)4(5) = 1000(1.0075)20 ≈ 1161.18 Use a calculator and round to the nearest hundredth. The balance after 5 years is $1161.18. B $18,000 invested at a rate of 4.5% compounded annually; 6 years Step 1 Write the compound interest function for this situation. r nt A=P 1+_ Write the formula. n ( ( ) ) 0.045 = 18,000 1 + _ 1 = 18,000(1.045) t t Substitute 18,000 for P, 0.045 for r, and 1 for n. Simplify. Step 2 Find the balance after 6 years. Substitute 6 for t. A = 18,000(1.045)6 Use a calculator and round to the ≈ 23,440.68 nearest hundredth. The balance after 6 years is $23,440.68. Write a compound interest function to model each situation. Then find the balance after the given number of years. 2a. $1200 invested at a rate of 3.5% compounded quarterly; 4 years 2b. $4000 invested at a rate of 3% compounded monthly; 8 years 806 Chapter 11 Exponential and Radical Functions Exponential decay occurs when a quantity decreases by the same rate r in each time period t. Just like exponential growth, the value of the quantity at any given time can be calculated by using the rate and the original amount. Exponential Decay An exponential decay function has the form y = a (1 - r) , where a > 0. t y represents the final amount. a represents the original amount. r represents the rate of decay as a decimal. t represents time. Notice an important difference between exponential growth functions and exponential decay functions. For exponential growth, the value inside the parentheses will be greater than 1 because r is added to 1. For exponential decay, the value inside the parentheses will be less than 1 because r is subtracted from 1. EXAMPLE 3 Exponential Decay The population of a town is decreasing at a rate of 1% per year. In 2000 there were 1300 people. Write an exponential decay function to model this situation. Then find the population in 2008. Step 1 Write the exponential decay function for this situation. In Example 3, round your answer to the nearest whole number because there can only be a whole number of people. y = a (1 - r) t Write the formula. = 1300(1 - 0.01) = 1300(0.99) t t Substitute 1300 for a and 0.01 for r. Simplify. Step 2 Find the population in 2008. y = 1300(0.99)8 ≈ 1200 Substitute 8 for t. Use a calculator and round to the nearest whole number. The population in 2008 is approximately 1200 people. 3. The fish population in a local stream is decreasing at a rate of 3% per year. The original population was 48,000. Write an exponential decay function to model this situation. Then find the population after 7 years. A common application of exponential decay is half-life. The half-life of a substance is the time it takes for one-half of the substance to decay into another substance. Half-life A = P (0.5) t A represents the final amount. P represents the original amount. t represents the number of half-lives in a given time period. 11-3 Exponential Growth and Decay 807 EXAMPLE 4 Science Application Fluorine-20 has a half-life of 11 seconds. A Find the amount of fluorine-20 left from a 40-gram sample after 44 seconds. Step 1 Find t, the number of half-lives in the given time period. 44 s = 4 _ 11 s Step 2 A = P(0.5) Divide the time period by the half-life. The value of t is 4. t Write the formula. = 40(0.5) 4 Substitute 40 for P and 4 for t. = 2.5 Use a calculator. There are 2.5 grams of fluorine-20 remaining after 44 seconds. B Find the amount of fluorine-20 left from a 40-gram sample after 2.2 minutes. Round your answer to the nearest hundredth. Step 1 Find t, the number of half-lives in the given time period. 2.2(60) = 132 132 s = 12 _ 11 s Find the number of seconds in 2.2 minutes. Divide the time period by the half-life. 132 = 12. The value of t is ___ 11 Step 2 A = P (0.5) Write the formula. = 40(0.5)12 Substitute 40 for P and 12 for t. ≈ 0.01 Use a calculator. Round to the nearest hundredth. There is about 0.01 gram of fluorine-20 remaining after 2.2 minutes. t 4a. Cesium-137 has a half-life of 30 years. Find the amount of cesium-137 left from a 100-milligram sample after 180 years. 4b. Bismuth-210 has a half-life of 5 days. Find the amount of bismuth-210 left from a 100-gram sample after 5 weeks. (Hint: Change 5 weeks to days.) THINK AND DISCUSS 1. Describe three real-world situations that can be described by exponential growth or exponential decay functions. 2. The population of a town after t years can be modeled by t P = 1000(1.02) . Is the population increasing or decreasing? By what percentage rate? 3. An exponential function is a function of the form y = ab x. Explain why both exponential growth functions and exponential decay functions are exponential functions. 4. 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