Primary 3
Chapter 7 Division
Notes (I)
Sub-titles are used to
identify the different
learning objectives of
the topic.
Quotient and Remainder
Worked Example 1
Nicole has 19 keys. She wants to divide them into 6 equal bunches.
(a) How many keys are there in each bunch?
(b) How many keys will be left over?
Solution:
(a)
From the picture above, we can see that
Visuals help our students
to grasp the concept
quickly.
19 ÷ 6 = 3 with remainder 1
=3R1
Quotient → 3
Remainder → 1
19 ÷ 6 = 3 R 1
The workings are as follows:
Quotien
t
3
6 19
–18
01
2 × 6 = 12
3 × 6 = 18
4 × 6 = 24
Remainder
We subtract the largest possible.
There are 3 keys in each bunch.
(b) 1 key will be left over.
-1-
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd
Worked Example 2
Andy has 16 teddy bears and 15 toy planes.
He wants to put the toys into groups of 2.
(a) How many groups of teddy bears will he have?
(b) How many groups of toy planes will he have?
Solution:
(a)
Key words are in bold
to emphasise their
importance.
16 ÷ 2 = 8
16 is an even number.
When even numbers are divided by 2,
there is no remainder.
Andy will have 8 groups of teddy bears.
(b)
15 ÷ 2 = 7 R 1
15 is an odd number.
When odd numbers are divided by 2,
there is a remainder of 1.
Andy will have 7 groups of toy planes with 1 toy plane left over.
-2-
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd
Practice questions to
further enhance students
understanding of new
topic.
1)
23 worms are to be shared equally among 4 birds.
(a)
Circle the worms below to show the grouping.
Find the number of worms each bird will get.
(b)
How many worms are left over?
Workings:
4 23
–
The quotient is _________ and the
remainder is _________.
23 ÷ 4 =
(a)
(b)
R
Each bird will get
worms.
worms are left over.
-3-
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd
As much as we would love
to show you everything,
we cannot be showing you
the best. 
Do drop by any JustEdu centre to view
the full set!
-4-
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd
Sub-titles are used to
identify the different
learning objectives of
the topic.
Division of 2-digit numbers without Regrouping
Worked Example 3
Divide 36 by 3.
Solution:
Think of the multiplication
table of 3!
Those that are less than
10 can fit here!
36 ÷ 3 = 12
Step 1:
Divide 3 tens by 3.
3 tens ÷ 3 = 1 ten
Step 2:
Divide 6 ones by 3.
6 ones ÷ 3 = 2 ones
T O
0
3
6
1
3 3 6
3
We choose to
write 3 as it is
equal or less than
the number on
the top.
-5-
1 2
3 3 6
3
6
6
0
Note that
there is no
remainder!
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd
Worked Example 4
Divide 61 by 3.
Solution:
Step 2:
Divide 1 one by 3.
1 one ÷ 3 = 0 ones R 1 one
Step 1:
Divide 6 tens by 3.
6 tens ÷ 3 = 2 tens
T O
T O
2
3 6 1
6
2 0
3 6 1
6
1
0
1
61 ÷ 3 = 20 R 1
Practice questions to
further enhance student’s
understanding of new
topic.
4)
Divide 86 by 2.
2
T
O
8
6
8 tens ÷ 2 = ______ tens
6 ones ÷ 2 = ______ ones
6
86 ÷ 2 =
-6-
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd
Do drop by our centre
to view the full set of
materials.
6
-7-
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd
Our notes are complemented
with 2-3 sets of comprehensive
practice papers each week.
This is to ensure our students
are able to apply the concepts into
different types of Mathematical sums.
Primary 3
Chapter 7 Division
Practice 1
1)
Fill in the boxes to complete the following families of
multiplication
and division facts.
‘Recall’ section as part
of scaffolding technique.
Serves as a reminder of
what students have learnt
in the previous
level.
(a)
1
(b)
× 10 = 80
35 ÷ 5 =
80 ÷ 10 =
(c)
(c)
× 4 = 36
4×
(d)
× 3 = 24
3×
= 36
36 ÷ 4 =
36 ÷
× 5 = 35
= 24
24 ÷ 3 =
=4
24 ÷
-8-
=3
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd
Fill in the blanks with the correct answers.
2)
Circle groups of 3 cakes.
There are
cakes divided into groups of 3.
cakes are left without a group.
20 ÷ 3 =
R
Quotient → __________
Remainder → __________
3)
Circle groups of 4 flowers.
There are
flowers divided into groups of
.
flowers are left without a group.
35 ÷ 4 =
R
Quotient → __________
Remainder → __________
-9-
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd
Work out the sums.
4)
17 ÷ 2 =
2
T
O
1
7
R
5)
26 ÷ 3 =
R
6)
38 ÷ 6 =
R
7)
31 ÷ 4 =
R
8)
49 ÷ 5 =
R
9)
65 ÷ 7 =
R
10)
70 ÷ 8 =
R
11)
88 ÷ 9 =
R
-10-
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd
Do drop by our centre
to view the full set of
materials.
-11-
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd
Do drop by our centre
to view the full set of
materials.
-12-
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd
12)
Christopher wants to challenge himself. Help him complete the
table below by filling in the remainder of each sum.
(a)
54 ÷ 9
55 ÷ 9
56 ÷ 9
57 ÷ 9
58 ÷ 9
59 ÷ 9
60 ÷ 9
61 ÷ 6
62 ÷ 6
63 ÷ 6
Remainder
Remainder
(b) The possible remainders when a number is divided by 9 are
.
(c) The greatest possible remainder when a number is divided
by 9 is
.
-13-
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd
13)
(a) The possible remainders when a number is divided by 4 are
.
(b) The greatest possible remainder when a number is divided
by 4 is
.
Do drop by our centre
to view the full set of
materials.
-14-
P3 | Chapter7 Division | Notes (I)
© JustEdu Holdings Pte Ltd