CALCULUS AP Night Practice Test SECTION I: Part A Time-- 30 minutes Number of questions – 12 CALCULATORS MAY NOT BE USED ON THIS PORTION Directions: Solve each of the following problems. After examining the form of the choices, decide which is the best of the choices given and write down the corresponding letter on your answer page. No credit will be given for answers circled on the practice test. Do not spend too much time on any one problem. In this practice test: (1) The exact numerical value of the correct answer does not always appear among the choices given. When this happens, select from among the choices the number that best approximates the exact numerical value. 1) The graph of which function has y = -1 as an asymptote? A) B) C) D) Look for a function that has a limit of 1 as → ∞. Let’s look at the limit of each possible answer: y = e-x y= y = ln (x + 1) y= A. lim B. lim E) y = → → D. lim → E. lim → 0 lim 1 using L’Hospital’s Rule → → C. lim lim → ln 1 lim → ∞ 1 lim using L’Hospital’s Rule using L’Hospital’s Rule → AnswerE Note: The lesson on this question is to first look at the rational functions, eliminate all terms except the ones with the highest exponents, and consider their limits. Doing this on Problem 1 gives a quick answer. 2) lim A) 1 B) 10 C) -1 D) E) → Do the same thing suggested in orange above in Problem 1. This gives: lim → 10 10 10 10 10 lim → 10 10 AnswerB Page1 3) If A) B) C) D) E) 3 8 , then lim → Notice that the limit shown is the definition of the derivative of : 10 14 20 -14 -20 2 lim 2 2 2 → Then, 2 3 8 6 16 6∙2 16 6 16 2 12 2 AnswerB 4) Let f and g be differentiable functions such that f (1) = 4, g (1) = 3, f ‘(3) = -5 f ’(1) = -4, g’(1) = -3, g’(4) = 2 If h(x) = g (f (x)), then h’(1) = A) -8 B) 12 C) -15 D) -5 E) -12 Use the chain rule in Lagrange (Prime) Notation. ∙ ′ ∙ 1 , where: 1 ∘ ∙ 2 ∙ Answer:A 5) If e y = x, then A) 1 B) C) D) ln x E) ln y implies: Then, AnswerB Page2 6) If the line y = 4x + 3 is tangent to the curve y = x2 + c, then c is A) B) C) D) E) 2 4 7 11 15 Now, since the slope at the point of intersection is , we have: So, Then, the point of tangency is on both curves, so: 4 3 4∙ 3 11 4 and so AnswerC 7) Find the second derivative of f (x) if f (x) = (2x + 3)4. A) B) C) D) E) 4(2x + 3)3 8(2x + 3)3 12(2x + 3)2 24(2x + 3)2 48(2x + 3)2 2 ′ 3 4∙ 2 3 8∙ 2 3 3∙8∙ 2 ∙ 2 3 ∙ ∙ 2 AnswerE 8) If the nth derivative of y is denoted as y(n) and y = -sin x, then y(7) is the same as A) B) C) D) E) dy/dx d2y/dx2 y d3y/dx3 none of these sin sin cos sin sin cos cos cos Notice the cyclical nature of the derivatives of the sine and cosine functions (reminiscent of the cyclical nature of powers of – note: this is not a coincidence because the two are related through: cos sin ). AnswerD Page3 9) Evaluate the limit, if possible: lim A) B) C) D) E) ¼ -¼ 1 0 DNE √ → First, we need to see if the limit is indeterminate: √ 5 2 9 √9 5 2 9 9 9 0 0 Since the limit is indeterminate, we can apply L’Hospital’s Rule. 5 lim 2 9 → 1 lim 2 5 1 → lim → 1 2 1 5 2 ∙ √9 5 AnswerA 10) A particle moves along the x-axis so that its position at any time t (in seconds) is s (t ) 2t 2 3t 5 . The acceleration of the object at t = 2 seconds is (A) 19 units/s 2 (B) 11 units/s 2 (C) 16 units/s 2 (D) 4 units/s 2 (E) 0 units/s 2 2 3 5 ′ 4 3 ′ is velocity ′′ 4 ′′ is acceleration ′′ 2 4 11) AnswerD If f ( x) 16 x then f "(4) is equal to 1 2 (B) -32 (C) -4 (D) -2 (E) -16 (A) - 16√ 16 1 ∙ 16 2 ′ ′ 4 is position 8 1 ∙ 8 2 4 √4 4 √ AnswerA Page4 12) If g ( x ) f ( x ) h( x ) , lim g ( x) 4 , and lim h( x) 4 then x 3 x 3 (A) f ( x) is continuous at x 3 (B) f (3) 4 (C) lim f ( x) 4 x 3 (D) g (3) 4 (E) none of these Squeeze Theorem: If , and lim → lim → Then lim → 4 and so Implication: → AnswerC 13) A point moves along the curve y = x2 + 1 in such a way that when x = 3, the x-coordinate is increasing at the rate of 5 ft/sec. At what rate is the y-coordinate changing at that time? A) 80 ft/sec B) 45 ft/sec C) 30 ft/sec D) 85 ft/sec E) 40 ft/sec 1 2 and so 2∙3 ∙ ∙ ft/sec AnswerC Page5 14) Let f be defined as follows, where a , for 0. , 0, for . Which of the following are true about f ? I. lim → exists. II. f (a) exists. III. f (x) is continuous at x = a. A) B) C) D) E) None I only II only I and II only I, II, and III only Consider these one at a time: I. The limit exists if it is the same from the left and right. lim → lim 2 fromboththeleftandtheright. → Therefore, the limit exists and it is equal to 2 . IisTRUE II. 0 and so it exists. IIisTRUE Continuity: A function, , is continuous at III. iff: a. is defined, b. lim → exists, and c. lim → lim , so the third condition in the definition is violated. → IIIisFALSE AnswerD Page6 15) The slope of the tangent line to the curve y3x + y2x2 = 6 at (2, 1) is A) B) -1 C) ∙ ∙ ∙ 6 ∙ D) E) 0 ∙ ∙ ∙ ∙ ∙ ∙ 0 0 ∙ 2 and Then, substitute ∙ ∙ ∙ ∙ ∙ 1 to get: 5 ∙ 6 8 AnswerC 16) Find dy/dx for y = 4sin2 (3x). A) B) C) D) E) 8sin(3x) 24sin(3x) 8sin(3x)cos(3x) 12sin(3x)cos(3x) 24sin(3x)cos(3x) ∙ ∙ 8 sin 3 ∙ ∙ AnswerE 18) = First, simplify the given function: A) B) C) x3 D) 3x2 E) 3 Then, take the derivative: 3 AnswerD Page7 CALCULUS SECTION II, PART A Calculators may not be used for any questions on this section. 1) Consider the curve given by y2 = 2 + xy. (a) Show that . (b) Find all points (x, y) on the curve where the line tangent to the curve has slope . (c) Show that there are no points (x, y) on the curve where the line tangent to the curve is horizontal. (d) Let x and y be functions of time t that are related by the equation y2 = 2 + xy. At time t = 5, the value of y is 3 and dy/dt = 6. Find the value of dx/dt at time t = 5. 2 (a) 2 0 ∙ 2 (b) ∙ which implies Going back to the original function, 2 (c) ∙ which implies The points, then are 2 (d) and Then, Going back to the original function, Then, note that: ∙ which implies 2 2∙ . Also we are given ∙ , 2 , then If the slope is 0, then the numerator of the fraction is 0, so . Since this is not possible, cannot be . , √2 2 If 2 ∙ ∙ ⇒ Page8 2) (a) Use the Pythagorean Theorem to get the value of the hypotenuse, . ⇒ 3 4 ⇒ (b) 2 Note that is negative since the movement is 2 2 ∙ towards the lighthouse, whereas, is positive since movement is away from the lighthouse. Substitute in values: , , Note that cos ∙ ∙ 2 ∙ ∙ 2 ∙ ∙ / , , (c) sin 2∙ 10 ∙ 60 ⇒ Next, take a derivative with respect to ∙ ∙ ⇒ ∙ ∙ ∙ ⇒ rad/sec Page9 CALCULUS SECTION II, PART B Time: 15 minutes Number of Problems: 1 Calculators are required for some portions of this section. 3) A 12,000-liter tank of water is filled to capacity. At time t = 0, water begins to drain out of the tank at a rate that is modeled by r(t), measured in liters per hour, where r is given by the piecewise function below. a) Is r continuous at t = 5? Show analytical work that leads to your answer. b) Find r’(3). Using correct units, explain the meaning of that value in the context of the this problem. (a) Continuity: A function, , is continuous at is defined, d. e. lim → exists, and f. lim → lim lim lim 1000 → → → (b) 600 3 lim 3,000 8 375 1000 . 367.879 → ′ ′ 3 at Continuity requires the limits from the left and right be equal, which they are not. Therefore, the function is not continuous at . 3 ∙ ∙ ∙ ∙ ∙ Note: the units of iff: , liters/hour2 are liters/hour, so the units of are liters/hour/hour or liters/hour2. Meaning: ′ liters/hour2 means that the rate of flow from the tank is increasing at a rate of liters/hour2. Page10
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