Section 6.1 Inverse Circular Functions Recall from College Algebra that not every function has an inverse function. In order for a function to have an inverse function, it must be one-to-one. Properties of Inverse Functions The inverse of a function f is denoted by f 1 , read βf-inverseβ. Since x and y values switch roles between inverses, if (x, y) is onπ(π₯), then (y, x) is on π (π₯ ). The domain of f is the range of f 1 and the range of f is the domain of f 1 . The graphs of f and f 1 are reflections of each other across the line π¦ = π₯. A function is one-to-one, or has an inverse function, if and only if NO horizontal line crosses the graph more than once. Recall the function, π(π₯ ) = π₯ . What is its inverse function? π How could we restrict the domain to make it one-to-one? What is its domain? What is its range? What is its range? (π₯ ) = Inverse Sine Function ORIGINAL FUNCTION INVERSE FUNCTION π = π¬π’π§ π = π¬π’π§ π π π OR π = ππ«ππ¬π’π§ π **y is the angle in the interval Restricted domain: Input β , whose sine value is π₯. ** π π Angles from β π , π Domain: Input Sine values from[β1,1] Range: Output Range: Output Sine values from[β1,1] Angles from β , Example 2: Find the exact value of y in each equation. a) π¦ = arcsin β b) π¦ = sin β Inverse Cosine Function ORIGINAL FUNCTION π = ππ¨π¬ π INVERSE FUNCTION π = ππ¨π¬ π π OR π = ππ«πππ¨π¬ π **y is angle in the interval [π, π ]whose cosine value is π₯. ** Restricted domain: Input Domain: Input Angles from [π, π ] Cosine values from[β1,1] Range: Output Coine values from[β1,1] Range: Output Angles from [π, π ] Example 2: Find the exact value of y in each equation. a) π¦ = arccos β b) π¦ = cos β Inverse Tangent Function ORIGINAL FUNCTION π = πππ§ π INVERSE FUNCTION π = πππ§ π π OR π = ππ«ππππ§ π **y is the angle in the interval Restricted domain: Input Angles from β , β , whose tangent value is π₯. ** Domain: Input Tangent values from(ββ, β) Range: Output Tangent values from (ββ, β) Range: Output Angles from β , Example 3: Find the exact value of y in each equation. a) π¦ = arctan 1 b) π¦ = tan ββ3 Inverse Functions for Cotangent, Secant, and Cosecant π₯ can be evaluated by cot To evaluate these inverse functions, we can use the reciprocal relationship. sec π₯ ππ¨π¬ can be evaluated by ππ π csc πππ§ ππ π if x > 0 πππ§ ππ + π πππ° if x < 0 π₯ can be evaluated by π¬π’π§ ππ π *NOTE: cot 0= Example 4: For each expression, find the exact measure, in degrees, if it exists. Do not use a calculator. a) arccsc β β b) arcsec(β β ) c) cot β β Example 5: Use a calculator to give each value in decimal degrees. Round to the nearest 2 decimal places. a) π = arccos (β0.13348122) b) π = csc 1.9422833 Example 6: Use a calculator to give each real number value. (Radians) Round to the nearest 6 decimal places. a) π¦ = sin (β0.13348122) b) π¦ = arcsec(β1.2671684) Summary of the domain and ranges of the Inverse Functions Inverse Function Domain RANGE Interval in Degrees Quadrants [βππ°, ππ°] I and IV π π , π) βͺ (π, π π [βππ°, π°) βͺ (π°,ππ°] I and IV π π , π π (βππ°, ππ°) I and IV Interval in Radians π π β , π π π¦ = sin π₯ [β1,1] π¦ = csc π₯ (ββ, β1] βͺ [1, β) π¦ = tan π₯ (ββ, β) β π¦ = cot π₯ (ββ, β) (π, π ) (π°, πππ°) I and II π¦ = cos π₯ [β1,1] [π, π ] [π°, πππ°] I and II π¦ = sec π₯ (ββ, β1] βͺ [1, β) [π°, ππ°) βͺ (ππ°, πππ°] I and II β π, π π βͺ ,π π π
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