A sprinter reaches his maximum speed in 2.5 second from rest with

Answer on Question #40600, Physics, Mechanics
Question:
A sprinter reaches his maximum speed in 2.5 second from rest with constant
acceleration. he then maintains that speed and finishes the 100 yards in the
overall time of 9.6 seconds. Determine the maximum speed?
Answer:
Acceleration:
𝑣 = π‘Žπ‘‘π‘Ž
π‘‘π‘Ž – time of acceleration, π‘Ž is acceleration
π‘‘π‘Ž =
𝑣
π‘Ž
Distance travelled:
π‘Žπ‘‘π‘Ž2 π‘£π‘‘π‘Ž
π‘™π‘Ž =
=
2
2
For uniform motion distance equals:
𝑙𝑒 = 𝑣 β‹… 𝑑𝑒
𝑑𝑒 = 𝑑 βˆ’ π‘‘π‘Ž – time of uniform motion
Total distance equals:
𝑣
𝑣𝑑𝑒 + π‘‘π‘Ž = 𝑙
2
𝑣=
Answer: 12.9
𝑙
𝑙
91.44π‘š
π‘š
=
=
=
=
12.9
𝑑
𝑑
𝑑
𝑠
𝑑𝑒 + π‘Ž 𝑑 βˆ’ π‘‘π‘Ž + π‘Ž 𝑑 βˆ’ π‘Ž 9.6𝑠 βˆ’ 2.5𝑠
2
2
2
π‘š
𝑠
𝑙