1) Using the given point, what is the equation of this straight line in Point-Slope Form?
A y = 5x + 2
B y - 3 = 5(x - (-1))
C y - (-3) = 5(x -(-1))
D y - (-3) = 5(x -1)
2) Using the given point, what is the equation of this straight line in Point-Slope Form?
A y = 3x – 1
B y - 2 = 1/3(x - 1) C y - 2 = 3(x - 1)
D y - 1 = 3(x - 2)
3) What is the equation of this straight line in Slope-intercept Form?
A y = 0.8x - 3.6
B y = 0.8x - 4.5
C y - (-2) = 1.25(x - 2)
D
y = 1.25x - 4.5
4) What is the equation of this straight line in Slope-intercept Form?
Ay = -4/3x + 2/3
B y = -4/3x + 32/3
C y = 4/3x + 2/3
D y - 6 = -4/3(x - (-4))
5) What is the General Form of the equation of a straight line for this graph?
A3x - 5y - 10 = 0
B 3x + 5y - 10 = 0 C 3y - 5x - 6 = 0
D 3y + 5x - 6 = 0
6) What is the General Form of the equation of a straight line for this graph?
A4x + 7y + 28 = 0
B 4x + 7y - 28 = 0 C 7x + 4y + 28 = 0
D 7x + 4y - 28 = 0
7)
What is the general form of the equation?
A 2x + 3y - 7 = 0 B 2x - 3y - 7 = 0 C 2x + 3y + 7 = 0 D 2x - 3y + 7 = 0
8)
What is the general form of the equation?
A 2x - 7y + 11 = 0 B 2x - 7y + 31 = 0 C 2x + 7y + 11 = 0 D 2x + 7y + 31 = 0
9) The General form of the equation of a straight line is 3x + 5y - 15 = 0
What is the slope-intercept form of the equation?
A
B
C
D
10) The General form of the equation of a straight line is 5x - 9y + 55 = 0 and it passes
through the point (-2, 5)
Using this point, what is the point - slope form of the equation?
A
B
C
D
ANSWERS
1) C y - 2 = 3(x - 1)
First find the slope:
m = Rise/Run = 3/1 = 3
Next use the formula y - y1 = m(x - x1)
Substiute x1 = 1, y1 = 2 and m = 3
Therefore y - 2 = 3(x - 1)
Note that, although answer A is also correct for the equation of the line, it is not in PointSlope Form
2) C y - (-3) = 5(x -(-1))
First find the slope:
m = Rise/Run = 5/1 = 5
Next use the formula y - y1 = m(x - x1)
Substiute x1 = -1, y1 = -3 and m = 5
Therefore y - (-3) = 5(x - (-1))
Note that, although answer A is also correct for the equation of the line, it is not in Point-Slope Form
3) D
y = 1.25x - 4.5
First find the slope:
m = Rise/Run = 5/4 = 1.25
Next use the formula y - y1 = m(x - x1)
Substitute x1 = 2, y1 = -2 and m = 1.25
⇒ y - (-2) = 1.25(x - 2)
⇒ y + 2 = 1.25x - 2.5
⇒ y = 1.25x - 2.5 - 2
⇒ y = 1.25x - 4.5
Note that, although answer C is also correct for the equation of the line, it is not in slope-intercept
form
4) Ay = -4/3x + 2/3
Next use the formula y - y1 = m(x - x1)
Substiute x1 = -4, y1 = 6 and m = -4/3
⇒ y - 6 = -4/3(x - (-4))
⇒ y - 6 = -4/3(x + 4)
⇒ y - 6 = -4/3x -16/3
⇒ y = -4/3x -16/3 + 6
⇒ y = -4/3x - 16/3 + 18/3
⇒ y = -4/3x + 2/3
5) B 3x + 5y - 10 = 0
Substitute these values into the equation of a straight line y = mx + b
⇒ y = -0.6x + 2
Now put this into the General Form:
Mutiply throughout by 5:
⇒ 5y = -3x + 10
Move all terms onto the left side of the equation by adding 3x and subtracting 10:
⇒ 3x + 5y - 10 = 0
6) B 4x + 7y - 28 = 0
First find the slope
and the y-intercept b = -4
Substitute these values into the equation of a straight line y = mx + b
Now put this into the General Form:
Mutiply throughout by 7:
⇒ 7y = -4x -28
Move all terms onto the left side of the equation by adding 4x and 28:
⇒ 4x + 7y + 28 = 0
7) A 2x + 3y - 7 = 0
8) C 2x + 7y + 11 = 0
⇒ 7(y + 3) = -2(x - 5)
⇒ 7y + 21 = -2x + 10
⇒ 2x + 7y + 11 = 0
9) B
3x + 5y - 15 = 0
Subtract 3x and add 15 to both sides:
⇒ 3x + 5y - 15 - 3x + 15 = 0 - 3x + 15
⇒ 5y = -3x + 15
Divide all terms by 5 :
10) D
It's easier to put it in slope-intercept form first in order to find the slope:
5x - 9y + 55 = 0
Add 9y to both sides:
⇒ 5x - 9y + 55 + 9y = 0 + 9y
⇒ 9y = 5x + 55
Divide both sides by 9
Now we know the slope and the point it passes through, (-2, 5), we can write the equation in
point-slope form: