Name: ___________________________________
Period:_______Date:
Physics: Final Review – Units 1 and 2
Answer the following showing ALL work including equations used, substitutions with units, and correct
answer. For short answer questions, just fill in the blank.
1. Convert 10 miles to centimeters 10 miles 1609 m 100 cm = 1,609,000 cm
1
1 mile 1 m
2. Convert 10 kg to mg
10. kg = 10 000 000mg
k h da b d c m
move decimal 1 2 3 4 5 6 spaces to the right
3. Divide 105.2 mg by 0.050 L. Give the answer with the appropriate # of significant digits.
2104 mg/L
in Sig Figs - 2100 mg/L
4. Round 999, 557, 315 mg to 6 significant digits.
999,557,315 so
5. List how many significant digits there are in the following #’s:
0.0050 (2)
1.05 (3)
100 (1)
3.2 x 1011 (2)
999,557,000
100.00 (5)
6. A shopping cart given an initial velocity of 2.0 m/s undergoes a constant acceleration of 3.0 m/s2. What is
the magnitude of the cart's final velocity after the first 4.0 s of its motion?
Vf = Vi + at
= 2.0m/s + (3.0 m/s2)(4.0s)
= 14 m/s
7. If you drive 3.2 km north from your house for breakfast, and at lunchtime you travel 2.4 km south, what is
your displacement?
displacement = 3.2km[N] - 2.4km [S] = .8 km [N]
8. A tourist accidentally drops a camera from a 40.0 m high bridge and it falls for 2.85 seconds. If g = 9.81 m/s2
and air resistance is disregarded, what is the speed of the camera as it hits the water?
v = gt
= (9.8 m/s2) (2.85s)
= 27.93 m/s
9. A sports car accelerates at a constant rate from rest to a speed of 27.8 m/s in 8.00 s. What is the
acceleration of the sports car in this time interval?
a = Vf – Vi / t
= (27.8 – 0 m/s) / 8.00 s
= 3.48 m/s2
10. The Steamboat geyser in Yellowstone National Park, Wyoming is capable of shooting its hot water up from
the ground with a speed of 48.0 m/s. How long would a drop of water be in the air during this journey
upward and back down again?
a = Vf – Vi / t
t = Vf – Vi / a
= (48.0 – 0 m/s) / 9.8 m/s2
= 4.9 s one way……so we would have to multiply by 2…..4.9 x 2 = 9.8s
11. A baseball is released at rest from the top of the Washington Monument. It hits the ground after falling for
6.00 s. What was the height from which the ball was dropped? (Disregard air resistance. g = 9.80 m/s2.)
height = ½ gt2
= ½ (9.8m/s2)(6.00s)2
= 176.4 m
12 A car travels 23.3 m due north in 13 s. Then the car turns around and travels 84.9 m due south in
4.0 s. What is the displacement of the car in meters during this 20.-second interval? The north
direction is designated as positive. 23.3 m 84.9m
23.3 m[N] – 84.9 m [S] = - 61.6 m [S]
[N] [S] 13. If water from a sprinkler is tossed up in the air with an initial speed of 12 m/s, what speed will it have
when it returns to the ground? 12 m/s
14. How far will a horizontal projectile have fallen:
a. in 1 s? 4.9m or 5m
b. in 2 s? 19.6m or 20m
c. in 3 s? 44.1m or 45m d. in 4 s? 78.4m or 80m
15. A turkey, trying to outrun a hunter in the forest, runs 10.0 m due north, 3.0 m due south, and another 5.0 m
due east. What is the final displacement of the turkey?
5m E
c2 = a2 + b2
N
= 72 + 52
7m
= 49 + 25
c
c2 =
74
c = 8.6m
16. A raccoon (trying avoiding the turkey and hunter) runs 35.0 m across the forest floor at an angle of 40°
north of east. What are the east and north components, respectively, of the raccoon’s displacement?
N
Ex = cos(40) • 35m = 26.8 m E
Ny = sin(40) • 35m = 22.5m N
E
17. A rope holds a balloon at an angle of 70.0° with the ground. If 85.0 m of rope was extended into the air,
what was the horizontal displacement of the balloon?
X = cos(70) • 85.0m = 29.1m
85.0m 70°
x
18. A scared armadillo jumps into the air at an angle of 60° above the horizontal with a velocity of 7.5 m/s.
What is the horizontal component of the armadillo’s velocity?
X = cos(60) • 7.5 = 3.8m/s
19. A salmon, who has a velocity of 3.8 m/s due west, tries to hold swim up a river that is flowing with a velocity
of 2.0 m/s due east. What is the resultant velocity of the salmon (relative to the bank of the river)?
3.8m/s W
2.0m/s E
3.8 - 2.0 = 1.8m/s W
20. Squirrel-bird drops his peanut from the top of a pine tree. The peanut hits the ground after falling for 0.45 s.
What is the height of the tree? (Disregard air resistance. g = 9.81 m/s2)
height = distance
d = Vit +
=
=
=
½ gt2
(0)(.45s) + ½ (9.81)(.45s)2
0 + (4.905)(.2025)
.99m
21. A zoo worker 4.0 m away from a giraffe directs a stream of water from a hose at an angle of 50.0° above
the horizontal. Assuming the water hits the top of the giraffe and travels in a straight line, what is the height
of the giraffe?
dy
50°
4m
x = cos( ) • dy
4m = sin(50) • dy
5.22m = dy