Cross Section`s Area Second Moment, Section Modulus, Rotation

Cross Section's Area Second Moment, Section Modulus, Rotation Radius
Cross section area
A
Distance from neutral Second moment of
axis to farthest portion area
e
I
a
Section modulus
I
Z=
e
a3
3
a
=0.577a
3
e
a4
3
Rotation radius
I
p=
A
a2
b
a
Shape of cross section
a2-b2
1
a
2
a4-b4
12
a4-b4
6a
bd
1
d
2
bd3
12
bd2
6
bd -hk
1
d
2
bd3-hk3
12
bd3-hk3
6d
1
bd
2
2
d
3
bd3
36
bd2
24
d
=0.236d
18
bd3
12
bd2
12
a
=0.408d
6
b
e
a
a
a2+b2
12
= 0.289 a2+b2
e
d
a
d
=0.289d
12
k
h
e
d
b
d
e
b
1
bd
2
e
d
b
=0.289
e
d
2
e
3d2tan30°
=0.866d2
2
d
=0.577d
2cos30°
e
2
230°
A d(1+2cos
)
12
4cos230°
3d2tan30°
=0.866d2
2
πd2
=0.7854d2
4
bd3-hk3
bd -hk
2
230°
d(1+2cos
)
48cos230°
= 0.6d4
d
d
b
d
bd3-hk3
12(bd -hk)
= 0.264d
A d(1+2cos230°
)
6
4cos230°
= 0.6d4
= 0.104d3
d
2
πd4
=0.049d4
64
πd3
=0.098d3
32
d
2
π
(D4-d4 )
64
= 0.049(D4-d4)
π
(D4-d4 )
32D
D4-d4
=0.098
D
πa3b
=0.7854a3b
4
πa2b
=0.7854a2b
4
2
230°
)
d(1+2cos
48cos230°
= 0.264d
π
(D2-d2 )
4
2- 2
= 0.7854(D d )
a
e
e
D
d
d
2
230°
)
A d(1+2cos
4cos230°
12
πab=3.1416ab
a
d
4
D4-d4
4
a
2
t
d
s
a
h
l n
e
b
dt+2a(s+n)
d
2
where g =
inclination
of flange
b
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1
1
bd3- (h4-l4 )
6d
4g
1
1
bd3- (h4-l4 )
12
4g
dt+2a(s+n)
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