2-8 Literal Equations and Dimensional Analysis Solve each equation or formula for the variable indicated. 1. 5a + c = –8a, for a ANSWER: k = –7n – m 4. q = p (r + s), for p SOLUTION: SOLUTION: ANSWER: p= ANSWER: 5. PACKAGING A soap company wants to use a cylindrical container to hold their new liquid soap. a= 2. 7h + f = 2h + g, for g SOLUTION: ANSWER: 5h + f = g 3. a. Solve the formula for h. b. What is the height of a container if the volume is 56.52 cubic inches and the radius is 1.5 inches? Round to the nearest tenth. SOLUTION: a. = n, for k SOLUTION: b. Replace V with 56.52 and r with 1.5 in the equation h = . Then, solve for h. ANSWER: k = –7n – m 4. q = p (r + s), for p SOLUTION: So, the height is about 8 inches. ANSWER: a. h = ANSWER: p= eSolutions Manual - Powered by Cognero 5. PACKAGING A soap company wants to use a cylindrical container to hold their new liquid soap. b. 8.0 in. Solve each equation or formula for the variable indicated. Page 1 8. u = vw + z, for v SOLUTION: ANSWER: ANSWER: a. h = 2-8 Literal Equations and Dimensional Analysis b. 8.0 in. Solve each equation or formula for the variable indicated. 8. u = vw + z, for v 11. 10m – p = –n, for m SOLUTION: SOLUTION: ANSWER: ANSWER: m= v= 12. , for t 9. x = b – cd, for c SOLUTION: SOLUTION: ANSWER: ANSWER: c= t= (r – v) 10. fg – 9h = 10j , for g SOLUTION: 13. , for v SOLUTION: ANSWER: ANSWER: 11. 10m – p = –n, for m v= SOLUTION: (z – w) 14. , for a SOLUTION: eSolutions Manual - Powered by Cognero Page 2 ANSWER: ANSWER: 2-8 Literal and Dimensional Analysis v = (zEquations – w) 14. , for a SOLUTION: f= 16. FITNESS The formula to compute a person’s body mass index is . B represents the body mass index, w is the person’s weight in pounds, and h represents the person’s height in inches. a. Solve the formula for w. b. What is the weight to the nearest pound of a person who is 64 inches tall and has a body mass index of 21.45? SOLUTION: a. ANSWER: a= 15. , for f SOLUTION: b. To find the weight to the nearest pound of a person who is 64 inches tall and has a body mass index of 21.45, replace h with 64 and B with 21.45 in the equation w = . Then, solve for w. ANSWER: f= 16. FITNESS The formula to compute a person’s body mass index is . B represents the body mass index, w is the person’s weight in pounds, and h represents the person’s height in inches. a. Solve the formula for w. b. What is the weight to the nearest pound of a person who is 64 inches tall and has a body mass index of 21.45? SOLUTION: a. A person who is 64 inches tall and has a body mass index of 21.45 is about 125 pounds. ANSWER: a. w = b. 125 lb 17. PHYSICS Acceleration is the measure of how fast a velocity is changing. The formula for acceleration is a = . a represents the acceleration rate, vf is the final velocity, vi is the initial velocity, and t eSolutions Manual - Powered by Cognero represents the time in seconds. a. Solve the formula for vf . b. What is the final velocity of a runner who is accelerating at 2 feet per second squared for 3 Page 3 ANSWER: a. w = 2-8 Literal Equations and Dimensional Analysis b. 125 lb 17. PHYSICS Acceleration is the measure of how fast a velocity is changing. The formula for acceleration is a = . a represents the acceleration rate, vf ANSWER: a. vf = at + vi b. 10 ft/s2 Solve each equation or formula for the variable indicated. 20. –14n + q = rt – 4n, for n SOLUTION: is the final velocity, vi is the initial velocity, and t represents the time in seconds. a. Solve the formula for vf . b. What is the final velocity of a runner who is accelerating at 2 feet per second squared for 3 seconds with an initial velocity of 4 feet per second? SOLUTION: a. ANSWER: n= 21. 18t + 11v = w – 13t, for t SOLUTION: b. To find the final velocity of a runner who is accelerating at 2 feet per second squared for 3 seconds with an initial velocity of 4 feet per second, replace a with 2, t with 3, and vi with 4. ANSWER: 2 The final velocity is 10 ft/s . 22. ax + z = aw – y, for a ANSWER: a. vf = at + vi SOLUTION: b. 10 ft/s2 Solve each equation or formula for the variable indicated. 20. –14n + q = rt – 4n, for n SOLUTION: ANSWER: 23. 10c – f = –13 + cd, for c eSolutions Manual - Powered by Cognero Page 4 SOLUTION: ANSWER: ANSWER: 2-8 Literal Equations and Dimensional Analysis 23. 10c – f = –13 + cd, for c SOLUTION: ANSWER: eSolutions Manual - Powered by Cognero Page 5
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