Answer on Question#55150 – Chemistry –Physical Chemistry
Question:
What is the amount of Neon atoms in 20.2g of Neon?
What is the number of oxygen molecules in 49.6g of oxygen gas?
What is the number of atoms of oxygen in 132g of carbon dioxide?
What is the number of chlorinde ions in 129.9g of iron (III) chloride?
Solution:
NA – Avogadro constant; 6.02 × 1023 mol-1;
N – number of the particles (molecules, atoms, ions etc.)
ν – the number of moles (mol);
m – mass (g);
M – molar mass (g×mol-1);
m
N
ν = M ; ν = NA ; N =
m×NA
M
;
1) What is the amount of Neon atoms in 20.2g of Neon?
M(Ne) = 20 g×mol-1;
m(Ne) = 20.2 g;
N(Ne) =
m(Ne)×NA
M(Ne)
;
N(Ne) = 6.08×1023;
2) What is the number of oxygen molecules in 49.6g of oxygen gas?
M(O2) = 32 g×mol-1;
m(O2) = 49.6 g;
N(O2) =
m(O2)×NA
M(O2)
;
N(O2) = 9.33×1023;
3) What is the number of atoms of oxygen in 132g of carbon dioxide?
M(CO2) = 44 g×mol-1;
m(CO2) = 132 g;
N(CO2) =
m(CO2)×NA
M(CO2)
;
N(CO2) = 1.806×1024;
The molecule of CO2 contains 2 atoms of O. According to this statement: N(O) = 2×N(CO2);
N(O) = 3.612×1024;
4) What is the number of chlorine ions in 129.9g of iron (III) chloride?
M(FeCL3) = 162.5 g×mol-1;
m(FeCL3) = 129.9 g;
N(FeCL3) =
m(FeCL3)×NA
M(FeCl3)
;
N(FeCl3) = 4.81×1023;
N(Cl-) = 3×N(FeCl3);
N(Cl-) = 1.44×1024;
Answer:
1) What is the amount of Neon atoms in 20.2g of Neon?
6.08×1023
2) What is the number of oxygen molecules in 49.6g of oxygen gas?
9.33×1023
3) What is the number of atoms of oxygen in 132g of carbon dioxide?
3.61×1024
4) What is the number of chlorine ions in 129.9g of iron (III) chloride?
1.44×1024
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