10/29/2014 Introduction to Intermolecular Forces How the forces between molecules influence physical and chemical properties Today: ◦ Intermolecular bonds vs. intramolecular bonds ◦ Coulomb’s Law ◦ London Dispersion Forces ◦ Dipole-Dipole Forces ◦ Hydrogen Bonding ◦ How do these forces influence: Boiling Points Melting Points Solubilities Visoscities Surface Tension Problem Set 5 DUE tonight at 11 pm Problem Set 6 DUE next Monday, Nov. 3rd at 11 pm Midterm Exam 2 Study Guide on CANVAS REMINDER: Poster Presentation Topics DUE next Monday Valence Shell Electron Pair Repulsion (VSEPR) Theory: Molecules and polyatomic ions take on particular shapes based on the number of electron regions located around a central atom: • Valence Shell (VS…): Consider ONLY the valence electrons: • Lone pair electrons & bonding electrons are all treated the same: • A single bond counts the same as a double or triple bond • Lone pairs are considered the same as bonding electrons • Electron Pair Replusions (…EPR): electrons are negative charges that naturally REPEL from other electrons. These repulsive forces between electrons determines molecular shape. TRIGONAL PLANAR Molecular Geometry Electron Dot Structure Total # of ELECTRON Regions # of BONDING Regions # of LONE PAIRS 3 3 0 120° Trigonal planar 1 10/29/2014 TRIGONAL PLANAR Electron Geometry BENT MOLECULAR GEOMETRY Electron Dot Structure Total # of ELECTRON Regions # of BONDING Regions # of LONE PAIRS 3 2 1 The Total # of Electron Regions determines the Electron Geometry: 3 REGIONS = TRIGONAL PLANAR Electron Geometry TRIGONAL PLANAR Electron Geometry TRIGONAL PLANAR MOLECULAR GEOMETRY When lone pairs are present on the central atom, the molecular geometry is DIFFERENT from the electron geometry. • Molecular Geometry only considers the positions of the atoms TRIGONAL PLANAR Electron Geometry BENT MOLECULAR GEOMETRY 4 REGIONS = TETRAHEDRAL Electron Geometry Electron Dot Structure Total # of ELECTRON Regions # of BONDING Regions # of LONE PAIRS 4 4 0 109.5° Tetrahedral 2 10/29/2014 4 REGIONS = TETRAHEDRAL Electron Geometry ONE LONE PAIR = TRIGONAL PYRAMIDAL MOLECULAR GEOMETRY Electron Dot Structure Total # of ELECTRON Regions # of BONDING Regions # of LONE PAIRS 4 3 1 109.5° Tetrahedral Trigonal Pyramid 4 REGIONS = TETRAHEDRAL Electron Geometry TWO LONE PAIRS = BENT MOLECULAR GEOMETRY Electron Dot Structure Total # of ELECTRON Regions # of BONDING Regions # of LONE PAIRS 4 2 2 109.5° Tetrahedral Bent Is Carbon Tetrachloride POLAR or NONPOLAR? Tetrahedral ΔEN: 3.0-2.5 = 0.5 1. First write the Lewis dot structure. 2. Use a table of electronegativities to calculate ΔEN for all bonds present. • If ΔEN is less than or equal to 0.4, the bonds are NONPOLAR. STOP HERE. The molecule must also be NONPOLAR. • If ΔEN is greater than 0.4, polar bonds are present & the molecule MIGHT be polar (depending on molecular shape). 3. Next, use the dot structure to count the number of electron regions & determine the MOLECULAR GEOMETRY. • If the molecule is ASYMMETRIC, it is POLAR. • If the molecule is SYMMETRIC, it is NONPOLAR. 3 10/29/2014 Coulomb’s Law: q2 - q1 + The larger the charges, The stronger the electrostatic interaction +2 q1 -2 q2 The smaller the distance, The stronger the electrostatic interaction • Ability distort and shift the electron distribution within a molecule or atom. Br—Br δ- δ+ London Dispersion Forces (LDFs) • Ability to distort and shift electron distribution within a molecule or atom. • Scales with volume occupied by electrons Cl2 (g) Br2 (l) • LDFs increase as total number of electrons & molecular surface area increase. I2 (s) 4 10/29/2014 Refining Crude Oil: A cornerstone of our current economy Light hydrocarbons with few carbon atoms boil easier (they have weaker IMFs), and move farther up a distillation column. HEAVY hydrocarbons with MANY carbon atoms have a harder time melting or boiling (they have STONGER IMFs) Plastics are long chains of carbon atoms strung together polyethylene Intermolecular Forces in Polar Molecules Dipole-Dipole Force: STRONGER than London Dispersion Forces δ+ HCl: HF: NaCl: δ- Boiling Point Difference in Electronegativity -85.0 oC 3.0 – 2.1 = 0.9 Increasing 19.5 oC 4.0 – 2.1 = 1.9 Charge o 801 C 3.0 – 0.9 = 2.1 Separation 5 10/29/2014 Intermolecular Forces • Intermolecular forces must be partially broken to change phase (to go from solid to liquid or liquid to gas) Boiling Point: temperature at which a liquid is converted into a gas A high boiling point means it takes a lot of energy to break the intermolecular forces between molecules Down a group: Boiling point increases with increasing molecular weight Water is a liquid under standard conditions because it has STRONG intermolecular forces (hydrogen bonds) keeping H2O molecules held together If H2O was LINEAR, it would be NONPOLAR and would likely be a GAS under standard conditions 6 10/29/2014 Hydrogen Bonding Network in Kevlar δ+ δ- δ- δ+ δδ- δ- δ+ δ+ δ- δ- δ+ δ+ δ- δ+ δδ+ δδ- δ+ δ+ δ+ δ- δ+ Hydrogen Bonding Network in Kevlar δ- δ+ Hydrogen Carbon Nitrogen Oxygen Animation produced with Camtasia & Jmol Model from ChemIT Hydrogen Bonding: Transpiration in Plants 7 10/29/2014 Predicting Boiling Points Which molecule would have the highest boiling point? A. CH4 → NONPOLAR B. CO2 → NONPOLAR C. NH3 → N—H Bonds: POLAR D. N2 → NONPOLAR E. CH3CH2CH3 → NONPOLAR Solubility: “Like dissolves Like” Substances of similar polarity mix together. Substances of different polarity don’t easily mix. Structure-Property Relationships Match the substances at the front of the room with the most likely hydrocarbon structures below. A. 1 = CH3(CH2)5CH3, 2 = C40H82, 3 = C20H42 B. 2 = CH3(CH2)5CH3, 1 = C40H82, 3 = C20H42 C. 3 = CH3(CH2)5CH3, 2 = C40H82, 1 = C20H42 D. 2 = CH3(CH2)5CH3, 3 = C40H82, 1 = C20H42 E. All of these substances would have the same formula 8
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