11(2x – 3y = 20) 3(4x – 7y = -5) 2 (11x + 2y) = -1 4(3x – 2y =

11(2x – 3y = 20)
3(4x – 7y = -5)
2 (11x + 2y) = -1
4(3x – 2y = -7)
22x – 33y =220
12x – 21y = -15
22x + 4y = -2
12x – 8y = -28
-37y = 222
-13y = 13
y = -6
y = -1
2x – 3(-6) =20
2x = 2
x =1
4x – 7(-1) = -5
4x + 7 = -5
4x = -12
x = -3
2n-4 -4n = -5
a = 1 + 2b
-2n – 4 = -5
3(1 + 2b) –b = -4
-2n = -1
3 + 6b –b = -4
n=½
3 + 5b = -4
m = 2(1/2) -4
5b = -7
m=1–4
b = -7/5
m = -3
a = 1 + 2(-7/5)
a = 1 + -14/5
a = 5/5 + -14/5
a = -9/5
s = students
s + a = 805
a = adults
3(s + a = 805)
555 adult tickets and 250 student tickets
3s + 4a = 2970
3s + 3a = 2415
a = 555
s = 805 – 555
s = 250
a = airfare
n = nights
150 + 55n = 210 + 40n
-40n
-40n
150 + 15n = 210
-150
-150
15n = 60
n = 4 nights
x + y = 25
x- y =7
2x = 32
x = 16
y= 9
s = Susie
b = Bob
b = 24 + 2s
b + s = 150
24 + 2s + s = 150
24 + 3s = 150
-24
3s = 126
s = 42
b = 108
-24
Susie has $42 and Bob has $108