MATH 136 0 / 0 Indeterminate Limits Give an algebraic derivation to find the exact value of the limit. 3 1 − 1. lim 93 x 2 x → 4 x − 64 3. x3 +8 x → −2 2 − x + 6 lim 12x 2 − 100 x − 72 2. lim x −3 x→ 9 10 −2 x 4. lim 2 x → 5 x − 25 Exercises Solutions 1. Initially the limit is 0/0. So we algebraically manipulate the function to cancel terms x − 4 (or 4 − x ) and eliminate the 0/0 indeterminate: € 3 1 − 6 + 9x 6 − 9x 36 − 9 x 9x 2 = = €3 2 x − 64 2 9x ( x − 4)(x + 4 x + 16) 6 + 9 x 2 9 x (x − 4)(x 2 + 4x + 16)( 6 + 9x ) = −9( x − 4) −9 = , provided x ≠ 4. 2 2 2 9x ( x − 4)( x + 4x + 16)(6 + 9 x ) 2 9 x ( x + 4x + 16) (6 + 9x ) Re-evaluate: 3 1 − −9 −9 −1 . lim 93 x 2 = lim = = 2 768 x → 4 x − 64 x → 4 2 9 x (x + 4 x + 16)( 6 + 9x ) 6912 --------------------------------------------------------------------------------------------------------------------2. Because 9 is a root of the quadratic in the numerator, x − 9 is a factor; thus, 12 x 2 − 100x − 72 (x − 9)(12x + 8) x + 3 (x − 9)(12 x + 8) ( x + 3 ) = = x −3 x −3 x€ + 3 x −9 = (12 x + 8)( x + 3 ), provided x ≠ 9. 12x 2 − 100 x − 72 = lim (12 x + 8)( x + 3 ) = 116 × 6 = 696. x −3 x→ 9 x→9 --------------------------------------------------------------------------------------------------------------------Re-evaluate: lim 3. Because x = −2 is causing the 0/0 indeterminate, we try to eliminate x + 2 from the numerator and denominator: 3 2 €x + 8 = ( x + 2)( x − 2x + 4) 2 + 2− x+6 2− x+6 2+ 2 x + 4)( 2 + x + 6 (x + 2)(x − 2€ = x +6 4 − ( x + 6) ( x + 2)( x 2 − 2x + 4) ( 2 + x + 6 ) = = −(x 2 − 2 x + 4)( 2 + −x− 2 x + 6) x + 6 ), provided x ≠ 2. x3 + 8 = lim − ( x 2 − 2x + 4) ( 2 + x + 6 ) = −12 × 4 = −48 . 2 − x + 6 x → −2 x → −2 --------------------------------------------------------------------------------------------------------------------10 −2 10 − 2x 2(5 − x) −2 x = = = , provided x ≠ 5 4. 2 x − 25 x(x − 5)( x + 5) x(x − 5)( x + 5) x( x + 5) Re-evaluate: lim 10 −2 −2 −2 1 = lim = =− . Re-evaluate: lim x2 50 25 x → 5 x − 25 x → 5 x (x + 5)
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