Name: __ANSWER KEY__ Date: __________________
DIRECTIONS: Match the formula with the graph. Put the letter of the graph in
the blank. Some graphs may be used more than once.
___f.__ 1. v = vo
Non-zero horizontal line, slope = 0.
Shows velocity doesn´t change,
and is constant
___i____ 2. v = vo + at
Line with a positive slope = a, and
a positive y-intercept, vo. Shows
increasing linear horizontal
velocity due to positive
acceleration.
___g.____ 3. x = vot
Line with a positive slope = vo, and
a y intercept = 0. Shows
increasing linear horizontal
distance because of constant
velocity.
___n.____ 4. v = vo gt
Line with a negative slope = −g,
and a negative y-intercept = − vo.
Shows initial negative vertical
velocity getting more negative due
to gravity.
2
___k.____ 5. y = ½gt
Parabola with a y-intercept of 0,
that opens downward (− sign).
Shows distance fallen by an object
in free fall with no initial velocity.
2
___d.____ 6. x = ½at
Parabola with a y-intercept of 0,
that opens upwards (+ sign).
Shows horizontal distance moved
by object that is accelerating with
no initial velocity.
a.
c.
b.
f.
j.
___j.____ 7. v = gt
Line with a negative slope = −g with
y-intercept = 0. Shows vertical
velocity of a falling object in free
fall
2
___e.___ 8. x = vot + ½at
Parabola that opens upward. Has a
y-intercept = 0. Shows horiz.
distance moved by an object that
has an initial velocity of vo m/s and
2
an acceleration of a m/s .
2
___l.____ 9. y = vot  ½gt
Parabola that opens downward.
Has a y-intercept = 0. Shows height
of an object that has a negative
initial vert. velocity of −vo m/s and
is falling.
2
___m.____ 10. y = vot  ½gt
Parabola that opens downward.
Has a y-intercept = 0. Shows height
of an object that has a positive
initial vert. velocity of −vo m/s and
is falling.
___h.____ 11. v = vo  gt
Line with a negative slope = −g,
and a positive y-intercept, vo.
Shows decreasing positive vertical
velocity due to gravity pulling
downwards.
2
___m.____ 12. x = vot  ½at
Parabola that opens downward.
Has a y-intercept = 0. Shows
distance traveled by an object that
has a positive initial horiz. velocity
of vo m/s and is decelerating
2
according to −a m/s .
2
d.
g.
k.
___a.___ 13. y = yo + vot  ½gt
Parabola that opens downward.
Has a y-intercept = yo. Shows height
of an object that has an initial
positive vertical velocity of vo m/s
and is being accelerated
downwards by gravity, g.
2
___c.___ 14. y = yo  vot  ½gt
Parabola that opens downward.
Has a y-intercept = yo. Shows height
of an object that has an initial
negative vertical velocity of vo m/s
and is being accelerated
downwards by gravity, g.
___f.____ 15. y = yo
Non-zero horizontal line, slope = 0.
Shows height doesn´t change, and
is constant
___g.____ 16. v = at
Line with a positive slope = a, and a
y intercept = 0. Shows increasing
linear horizontal distance because
2
of acceleration of a m/s .
2
___b.____ 17. y = yo  ½gt
Parabola that opens downward.
Has a y-intercept = yo. Shows height
of an object in free fall vo = 0 m/s
and is being accelerated
downwards by gravity, g.
____h.___ 18. v = vo  at
Line with a negative slope = −a, and
a positive y-intercept, vo. Shows
decreasing positive horizontal
velocity due to a deceleration of −a
2
m/s .
e.
h.
l.
i.
m.
n.