It’s lecture 6 – the end of Chapt 3 • Announcements • Solutions • Molarity • Dilutions • Bonus Feature! The chemical formula for the molecule shown is? 25% 25% 25% 25% 1. 2. 3. 4. C2H4O C4O2H8 C4H8N2 C4H8O2 The empirical formula for the molecule shown is? 25% 25% 25% 25% 1 1. 2. 3. 4. 2 3 C2H4O C4H8O2 C2H4N C4H8N2 4 5 Announcements • Seminar Friday – the new Dean • End Chapt 3 today, start Chapt 4 Wed. • What follows Chapt 4 ? Recognizing Ionic Compounds Correction to my correction Figure 3-12 p.79 Solutions • Solution – a homogeneous mixture of two or more substances, in which one is called the solvent and the other is the solute – Solvent – main medium, what is there in the largest quantity – Solute – dissolved in the solvent Sugar and Water Sugar (solute); Water (solvent) Blood Many solutes; Water (solvent) Solution or No Solution? Sugar water Solution Muddy water No Solution Gasoline Solution Milk No Solution Concentration • Concentration – the amount of a solute dissolved in a given quantity of solvent • A concentrated solution has a large amount of solute in it. • A dilute solution has a small amount of solute in it. • Measured quantitatively with a variety of units – Most common is Molarity Molarity • Molarity – the number of moles of solute dissolved in 1 L of solution • To calculate molarity: n quantity of A (mol) Molarity of A (M) = = Volume of Solution (L) V For example: 68.5 G of sucrose (C12H22O11) are dissolved in 100.0 mL of water. What is the concentration? Sucrose Example 68.5 G of sucrose (C12H22O11) are dissolved in 100.0 mL of water. 1. Find # moles of sucrose a. Need molar mass of sucrose 12mol C 12.011g 22mol H 1.0079g 11mol O 15.999g 342.2948 g × + × + × = 1 mol Sucrose 1mol C 1 mol Sucrose 1mol H 1mol Sucrose 1mol O 1mol Sucrose b. Now we can determine # moles sucrose 68.5 g Sucrose × 2. 1 mol Sucrose = 0.200120 mol Sucrose 342.2948 g Sucrose Divide moles by volume to get concentration n 0.200120 mol Sucrose = = 2.00120 Molar = 2.00 Molar 0.1000 L V (roughly maple syrup) More solution info • Dissolved substances are either molecules or ions – Molecules are neutral (e.g. sucrose, some proteins, caffeine) – Ions are charged (e.g. Na+, NO3– , C2O42– ) • Many everyday solutions have water as the solvent – These are aqueous solutions (aq) Do you know your ions and solutions? If 2 moles of ammonium sulfite are dissolved in 1 L of water, what is true about the resulting solution? 25% 25% 25% 25% 1 1. 2. 3. 4. 2 3 It is 2 M in SO42– It is 4 M in N3+ It is 2 M in NH4+ None of the above 4 5 Dilution • Creating a solution that is less concentrated from one that is more concentrated • How do you make 4 L of tree sap from maple syrup? – Syrup is about 2 M, tree sap is about 0.058 M 1. Determine # moles of sucrose that are needed for dilute solution 0.058 M sucrose = 2. 0.058 mol sucrose × 4 L solution = 0.232 mol sucrose 1 L solution Determine volume of concentrated solution needed to get those moles 1 L solution 0.232 mol sucrose × = 0.116 L solution 2 mol sucrose So, put 116 mL of syrup in a container and fill until the total volume is 4 L. Remember: You are done with the homework when you understand it! Today • Finish CAPA #3 By Wednesday • Get a start on CAPA set #4 • Read 4.1-4.2
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