Question 1
Find the Area and Perimeter of the
following figure…
15ft
25ft
A = 375ft2
P = 80ft
Question 2
Find the Area and Perimeter of the
following figure… (A = ½bh)
12in
11in
12in
A = 55in2
10in
P = 34in
Question 3
Find the Area and Perimeter of the
following figure… ( A = ½h(b1+b2) )
20cm
31cm
15cm
16cm
18cm
A = 367.5cm2
P = 85cm
Question 4
Find the Area and Perimeter of the
following figure… (A = bh)
15km
13km
12km
A = 180km2
P = 56km
Question 5
Find the Area and Circumference of
the following figure…
A = pr2
C = 2pr
p = 3.14
3.3m
A = 34.19m2
C = 20.72m
Question 6
Find the Area and Perimeter of a
rectangle with
L = 4x and W = 3x + 1.
A = L x W A = (4x)(3x + 1)
A = 12x2 + 4x
P = 2L + 2W
A = 12x2 + 4x
P = 2(4x) + 2(3x + 1) P = 14x + 2
Question 7
Find the Area and Perimeter of a
rectangle with
L = (x + 3) and W = (2x – 1).
A = L x W A = (x + 3)(2x - 1)
A = 2x2 + 6x –x – 3 = 2x2 + 5x - 3
P = 2L + 2W = 2(x + 3) + 2(2x – 1)
P = 2x + 6 + 4x – 2 = 6x + 4
A = 2x2 + 5x - 3
P = 6x + 4
Question 8
Given that the area of a rectangle is
250ft2 and the length is 25ft, find the
width and perimeter.
A=LxW
250 = 25W
W = 10ft
P = 2L + 2W
P = 2(25) + 2(10)
P = 70ft
W = 10ft
P = 70ft
Question 9
Given a trapezoid has Area 46m2, B1 = 8m,
and H = 4m. Find the length of B2.
A = (½)(H)(B1 + B2)
46 = (½)(4)(8 + B2)
46 = (2)(8 + B2)
46 = 16 + 2B2
30 = 2B2
15 = B2
B2 = 15m
Question 10
Given a triangle that has an Area of 24in2
and a Base of 8in, find the Height of the
triangle.
A = (½)BH
24 = (½)(8)H
24 = 4H
6=H
H = 6in
Question 11
Find the area and perimeter.
2
3
6
9
1
6
1
45
9
5
8
P = 46
A = 66
Question 12
The classroom has 450 square feet
of tile. You measure the length of
the classroom as 30ft. Calculate the
width of the room and the perimeter
of the room.
A=LxW
450 = 30W
15 = W
P = 2L + 2W
P = 2(30) + 2(15) = 90
W = 15ft
P = 90ft
Question 13
Your aunt’s backyard is surrounded by an
82 yard fence. The width of the
backyard is 60 feet. Calculate the length
and area in feet.
82 yards = 246 feet
P = 2L + 2W
246 = 2L + 2(60)
246 = 2L + 120
126 = 2L
63 = L
A = L x W A = 63 x 60 = 3780
L = 63ft
A = 3780ft2
Question 14
Find the distance, midpoint, and slope
given the following points:
(12, 3) and (4, -3)
2
2




x

x

y

y
2
1
Distance: 2 1
Midpoint:
Slope:
 x 2  x1 y 2  y 1 
,


2 
 2
y 2  y1
x 2  x1
Distance: 10
Midpoint: (8, 0)
Slope:
¾