C our ses Jua n Luis Her r er a C or t ijo Mathematical Biostatistics Boot Camp by Brian Caffo Feedback — Week 3 Quiz You submitted this quiz on Wed 1 May 2013 5:43 PM CEST (UTC +0200). You got a score of 6.00 out of 6.00. GENERAL Home Question 1 Syllabus You meet a person at the bus stop and strike up a conversation. In the conversation, the person gives the strange answer that at least one of his two Grading Policy children is a girl. Thinking on this, you decide to do a probability calculation. Assuming only that genders are iid with 50% probability each, what is the chance of a two child family having two girls given the information that at least one is a girl? Faculty Your Answer Score Explanation Github Repository 1/3 LEARNING ACTIVITIES Video Lectures 1/2 0 Quizzes 1/4 Discussion Forums Course Wiki 1.00 1 Homework COMMUNITY Total 1.00 / 1.00 Question Explanation This is a strange problem and the answer depends on exactly how you word the question. See the explanation of this problem here: http://en.wikipedia.org/wiki/Boy_or_Girl_paradox Join a Meetup Help Articles Question 2 A web site (www.medicine.ox.ac.uk/bandolier/band64/b64-7.html) for home pregnancy tests cites the following: "When the subjects using the test were women who collected and tested their own samples, the overall sensitivity was 75%. Specificity was also low, in the range 52% to 75%." Suppose a subject has a positive test. Assume the lower bound for the specificity. What number is closest to the multiplier of the pre-test odds of pregnancy to obtain the post-test odds of pregnancy given a positive test result? Your Answer Score Explanation 2.5 1 2 1.5 1.00 0 .5 Total 1.00 / 1.00 Question Explanation The DLR for a positive test is .75/(1 − .52) = 1.5625 . Question 3 A web site (www.medicine.ox.ac.uk/bandolier/band64/b64-7.html) for home pregnancy tests cites the following: "When the subjects using the test were women who collected and tested their own samples, the overall sensitivity was 75%. Specificity was also low, in the range 52% to 75%." Assume the lower value for the specificity. Suppose a subject has a positive test and that 30% of women taking pregnancy tests are actually pregnant. What number is closest to the probability of pregnancy given the positive test? Your Answer 10% 90% 50% 30% 60% Score Explanation 40% 1.00 70% 20% 80% Total 1.00 / 1.00 Question Explanation P(Preg|+) = P(+|Preg)P(Preg) P(+|Preg)P(Preg)+P(+|Pregc )P(Pregc ) = .75×.30 .75×.30+(1−.52)×(1−.3) ≈ 0.40 Question 4 Let X1 … XK be independent Poisson counts with means ti λ for some known value ti . Recall the Poison mass function with mean μ is x = 0, 1, … . What is the maximum likelihood estimate for λ? Your Answer Score μx e−μ for x! Explanation (∑Kk=1 xk )/n (∑Kk=1 xk ) × (∑Kk=1 tk ) (∑Kk=1 xk )/(∑Kk=1 tk) 1.00 (∑Kk=1 tk)/(∑Kk=1 xk ) Total 1.00 / 1.00 Question Explanation x! from the denominator, the likelihood is proportional to ∏Kk=1(tkλ)xk e−tk λ ∝λ λ∑k=1 xk e−λ ∑k=1 tk . Taking the derivative with respect to λ K K and solving this for 0 yields the solution (∑ k=1 xk )/(∑ k=1 tk) K Dropping the K Question 5 Suppose that a person is flipping a biased coin with success probability p . She flips the coin 10 times yielding 1 head. Consider two possibilities: 1) the person planned on flipping the coin ten times and got one head, 2) the person planned to flip the coin until the first head and it took ten times. What can you say about the likelihood in these two circumstances? Your Answer Score Explanation The likelihoods are different (up to constants of proportionality) depending on which case is true. You can't calculate a likelihood in setting 2. The likelihood associated with p is identical (up to constants of proportionality) in either case. 1.00 You can't calculate a likelihood in setting 1. Total 1.00 / 1.00 Question Explanation The likelihood is identical p 1 (1 − p)9 in either case (geometric or Bernoulli trials). As far as the likelihood is concerned, all that matters is that there were 10 flips and 1 head. The intention of the flipper is irrelevant. Question 6 Let X be a uniform random variable with support of length 1, but where we don't know where it starts. So that the density is f (x) = 1 for x ∈ (θ, θ + 1) and 0 otherwise. We observe a random variable from this distribution, say x1 . What does the likelihood look like? Your Answer Score Explanation A point at x1 . A parabola. A horizontal line between x1 and x1 A diagonal line from x1 to x1 − 1. 1.00 + 1. Total 1.00 / 1.00 MathJax no longer loads a default configuration file; you must specify such files x Question explicitly. This page seems to use the older default Explanation config/MathJax.js file, and so needs to be updated. This is explained further at The density is f (x) = I(θθ − x1 > −1) = I(x1 > θ > x1 − 1). Therefore, the likelihood is a flat line between x1 and x1 − 1. http://www.mathjax.org/help/configuration
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