Page 1 of 7
5.1
Graphing Quadratic Functions
What you should learn
GOAL 1
Graph quadratic
functions.
GOAL 2 Use quadratic
functions to solve real-life
problems, such as finding
comfortable temperatures
in Example 5.
Why you should learn it
RE
GRAPHING A QUADRATIC FUNCTION
A quadratic function has the form y = ax2 + bx + c
where a ≠ 0. The graph of a quadratic function is
U-shaped and is called a parabola.
2
y
y ⴝ x2
2
For instance, the graphs of y = x and y = ºx are
shown at the right. The origin is the lowest point on
the graph of y = x2 and the highest point on the graph of
y = ºx2. The lowest or highest point on the graph of a
quadratic function is called the vertex.
The graphs of y = x2 and y = ºx2 are symmetric about
the y-axis, called the axis of symmetry. In general, the
axis of symmetry for the graph of a quadratic function
is the vertical line through the vertex.
2
vertex
2
x
axis of
symmetry
y ⴝ ⴚx 2
FE
䉲 To model real-life objects,
such as the cables of the
Golden Gate Bridge in
Example 6.
AL LI
GOAL 1
ACTIVITY
Developing
Concepts
1
Investigating Parabolas
Use a graphing calculator to graph each of these functions in the same
1
2
viewing window: y = ᎏᎏx2, y = x2, y = 2x2, and y = 3x2.
1
2
Repeat Step 1 for these functions: y = ºᎏᎏx2, y = ºx2, y = º2x2, and
2
y = º3x2.
3
What are the vertex and axis of symmetry of the graph of y = ax2?
4
Describe the effect of a on the graph of y = ax2.
In the activity you examined the graph of the simple quadratic function y = ax2.
The graph of the more general function y = ax2 + bx + c is described below.
CONCEPT
SUMMARY
T H E G R A P H O F A Q UA D R AT I C F U N C T I O N
The graph of y = ax 2 + bx + c is a parabola with these characteristics:
•
The parabola opens up if a > 0 and opens down if a < 0. The parabola is
wider than the graph of y = x 2 if |a| < 1 and narrower than the graph of
y = x 2 if |a| > 1.
•
The x-coordinate of the vertex is ºᎏᎏ.
•
The axis of symmetry is the vertical line x = ºᎏᎏ.
b
2a
b
2a
5.1 Graphing Quadratic Functions
249
Page 2 of 7
EXAMPLE 1
Graphing a Quadratic Function
Graph y = 2x2 º 8x + 6.
SOLUTION
y
Note that the coefficients for this function are a = 2,
(0, 6)
b = º8, and c = 6. Since a > 0, the parabola opens up.
(4, 6)
Find and plot the vertex. The x-coordinate is:
º8
2(2)
b
2a
x = º ᎏ ᎏ = ºᎏᎏ = 2
1
(3, 0)
The y-coordinate is:
(1, 0)
y = 2(2)2 º 8(2) + 6 = º2
x
(2, ⫺2)
So, the vertex is (2, º2).
STUDENT HELP
Skills Review
For help with symmetry,
see p. 919.
Draw the axis of symmetry x = 2.
Plot two points on one side of the axis of symmetry, such as (1, 0) and (0, 6). Use
symmetry to plot two more points, such as (3, 0) and (4, 6).
Draw a parabola through the plotted points.
..........
The quadratic function y = ax2 + bx + c is written in standard form. Two other
useful forms for quadratic functions are given below.
V E RT E X A N D I N T E R C E P T F O R M S O F A Q UA D R AT I C F U N C T I O N
FORM OF QUADRATIC FUNCTION
CHARACTERISTICS OF GRAPH
Vertex form: y = a(x º h) + k
The vertex is (h, k).
2
The axis of symmetry is x = h.
Intercept form: y = a(x º p)(x º q)
The x-intercepts are p and q.
The axis of symmetry is halfway
between (p, 0) and (q, 0).
For both forms, the graph opens up if a > 0 and opens down if a < 0.
EXAMPLE 2
STUDENT HELP
Look Back
For help with graphing
functions, see p. 123.
Graphing a Quadratic Function in Vertex Form
1
2
Graph y = ºᎏᎏ(x + 3)2 + 4.
y
(⫺3, 4)
SOLUTION
2
The function is in vertex form y = a(x º h) + k
4
(⫺1, 2)
(⫺5, 2)
1
2
where a = ºᎏᎏ, h = º3, and k = 4. Since a < 0,
the parabola opens down. To graph the function, first plot
the vertex (h, k) = (º3, 4). Draw the axis of symmetry
x = º3 and plot two points on one side of it, such as
(º1, 2) and (1, º4). Use symmetry to complete the graph.
250
Chapter 5 Quadratic Functions
1
(⫺7, ⫺4)
x
(1, ⫺4)
Page 3 of 7
EXAMPLE 3
Graphing a Quadratic Function in Intercept Form
Graph y = º(x + 2)(x º 4).
SOLUTION
y (1, 9)
The quadratic function is in intercept form
y = a(x º p)(x º q) where a = º1, p = º2, and
q = 4. The x-intercepts occur at (º2, 0) and (4, 0).
The axis of symmetry lies halfway between these
points, at x = 1. So, the x-coordinate of the vertex
is x = 1 and the y-coordinate of the vertex is:
y = º(1 + 2)(1 º 4) = 9
⫺2
1
The graph of the function is shown.
..........
STUDENT HELP
Skills Review
For help with multiplying
algebraic expressions,
see p. 937.
4
2
x
You can change quadratic functions from intercept form or vertex form to standard
form by multiplying algebraic expressions. One method for multiplying expressions
containing two terms is FOIL. Using this method, you add the products of the First
terms, the Outer terms, the Inner terms, and the Last terms. Here is an example:
F
O
I
L
(x + 3)(x + 5) = x2 + 5x + 3x + 15 = x2 + 8x + 15
Methods for changing from standard form to intercept form or vertex form will be
discussed in Lessons 5.2 and 5.5.
EXAMPLE 4
Writing Quadratic Functions in Standard Form
Write the quadratic function in standard form.
a. y = º(x + 4)(x º 9)
b. y = 3(x º 1)2 + 8
SOLUTION
a. y = º(x + 4)(x º 9)
Write original function.
= º(x2 º 9x + 4x º 36)
Multiply using FOIL.
= º(x2 º 5x º 36)
Combine like terms.
= ºx2 + 5x + 36
Use distributive property.
b. y = 3(x º 1)2 + 8
Write original function.
= 3(x º 1)(x º 1) + 8
Rewrite (x º 1)2.
= 3(x2 º x º x + 1) + 8
Multiply using FOIL.
= 3(x2 º 2x + 1) + 8
Combine like terms.
2
= 3x º 6x + 3 + 8
Use distributive property.
= 3x2 º 6x + 11
Combine like terms.
5.1 Graphing Quadratic Functions
251
Page 4 of 7
GOAL 2
RE
FE
L
AL I
Temperature
USING QUADRATIC FUNCTIONS IN REAL LIFE
EXAMPLE 5
Using a Quadratic Model in Standard Form
Researchers conducted an experiment to determine temperatures at which people feel
comfortable. The percent y of test subjects who felt comfortable at temperature x
(in degrees Fahrenheit) can be modeled by:
y = º3.678x2 + 527.3x º 18,807
What temperature made the greatest percent of test subjects comfortable? At that
temperature, what percent felt comfortable? 䉴 Source: Design with Climate
SOLUTION
Since a = º3.678 is negative, the graph of the
quadratic function opens down and the function has
a maximum value. The maximum value occurs at:
b
2a
527.3
2(º3.678)
x = ºᎏᎏ = ºᎏᎏ ≈ 72
The corresponding value of y is:
X=71.691489 Y=92.217379
y = º3.678(72)2 + 527.3(72) º 18,807 ≈ 92
䉴
The temperature that made the greatest percent of test subjects comfortable was
about 72°F. At that temperature about 92% of the subjects felt comfortable.
EXAMPLE 6
Using a Quadratic Model in Vertex Form
CIVIL ENGINEERING The Golden Gate Bridge in San Francisco has two towers that
FOCUS ON
CAREERS
rise 500 feet above the road and are connected by suspension cables as shown. Each
cable forms a parabola with equation
1
8960
y = ᎏᎏ (x º 2100)2 + 8
where x and y are measured in feet.
䉴 Source: Golden Gate Bridge, Highway and
Transportation District
a. What is the distance d between
the two towers?
b. What is the height ¬ above the
road of a cable at its lowest point?
RE
FE
L
AL I
CIVIL ENGINEER
INT
Civil engineers
design bridges, roads, buildings, and other structures.
In 1996 civil engineers held
about 196,000 jobs in the
United States.
NE
ER T
CAREER LINK
www.mcdougallittell.com
252
SOLUTION
a. The vertex of the parabola is (2100, 8), so a cable’s lowest point is 2100 feet
from the left tower shown above. Since the heights of the two towers are the
same, the symmetry of the parabola implies that the vertex is also 2100 feet
from the right tower. Therefore, the towers are d = 2(2100) = 4200 feet apart.
b. The height ¬ above the road of a cable at its lowest point is the y-coordinate of
the vertex. Since the vertex is (2100, 8), this height is ¬ = 8 feet.
Chapter 5 Quadratic Functions
Page 5 of 7
GUIDED PRACTICE
✓
Concept Check ✓
Vocabulary Check
Skill Check
✓
?.
1. Complete this statement: The graph of a quadratic function is called a(n) 㛭㛭㛭
2. Does the graph of y = 3x2 º x º 2 open up or down? Explain.
3. Is y = º2(x º 5)(x º 8) in standard form, vertex form, or intercept form?
Graph the quadratic function. Label the vertex and axis of symmetry.
4. y = x2 º 4x + 7
5. y = 2(x + 1)2 º 4
6. y = º(x + 2)(x º 1)
1
7. y = ºᎏᎏx2 º 2x º 3
3
3
8. y = ºᎏᎏ(x º 4)2 + 6
5
5
9. y = ᎏᎏx(x º 3)
2
Write the quadratic function in standard form.
10. y = (x + 1)(x + 2)
11. y = º2(x + 4)(x º 3)
12. y = 4(x º 1)2 + 5
13. y = º(x + 2)2 º 7
1
14. y = ºᎏᎏ(x º 6)(x º 8)
2
2
15. y = ᎏᎏ(x º 9)2 º 4
3
CONNECTION The equation given in Example 5 is based on temperature
preferences of both male and female test subjects. Researchers also analyzed data
for males and females separately and obtained the equations below.
16. SCIENCE
Males: y = º4.290x2 + 612.6x º 21,773
Females: y = º6.224x2 + 908.9x º 33,092
What was the most comfortable temperature for the males? for the females?
PRACTICE AND APPLICATIONS
STUDENT HELP
Extra Practice
to help you master
skills is on p. 945.
MATCHING GRAPHS Match the quadratic function with its graph.
17. y = (x + 2)(x º 3)
18. y = º(x º 3)2 + 2
B. y
y
A.
19. y = x2 º 6x + 11
C.
1
y
1
1
3
x
x
1
1
x
GRAPHING WITH STANDARD FORM Graph the quadratic function. Label the
vertex and axis of symmetry.
STUDENT HELP
20. y = x2 º 2x º 1
21. y = 2x2 º 12x + 19
22. y = ºx2 + 4x º 2
23. y = º3x2 + 5
1
24. y = ᎏᎏx2 + 4x + 5
2
1
25. y = ºᎏᎏx2 º x º 3
6
HOMEWORK HELP
Example 1: Exs. 17–25
Example 2: Exs. 17–19,
26–31
Example 3: Exs. 17–19,
32–37
Example 4: Exs. 38–49
Examples 5, 6: Exs. 51–54
GRAPHING WITH VERTEX FORM Graph the quadratic function. Label the
vertex and axis of symmetry.
26. y = (x º 1)2 + 2
27. y = º(x º 2)2 º 1
28. y = º2(x + 3)2 º 4
29. y = 3(x + 4)2 + 5
1
30. y = ºᎏᎏ(x + 1)2 + 3
3
5
31. y = ᎏᎏ(x º 3)2
4
5.1 Graphing Quadratic Functions
253
Page 6 of 7
FOCUS ON
APPLICATIONS
GRAPHING WITH INTERCEPT FORM Graph the quadratic function. Label the
vertex, axis of symmetry, and x-intercepts.
32. y = (x º 2)(x º 6)
33. y = 4(x + 1)(x º 1)
34. y = º(x + 3)(x + 5)
1
35. y = ᎏᎏ(x + 4)(x + 1)
3
1
36. y = ºᎏᎏ(x º 3)(x + 2)
2
37. y = º3x(x º 2)
WRITING IN STANDARD FORM Write the quadratic function in standard form.
RE
FE
L
AL I
TORQUE, the focus
INT
of Ex. 51, is the
“twisting force” produced
by the crankshaft in a car’s
engine. As torque increases,
a car is able to accelerate
more quickly.
38. y = (x + 5)(x + 2)
39. y = º(x + 3)(x º 4)
40. y = 2(x º 1)(x º 6)
41. y = º3(x º 7)(x + 4)
42. y = (5x + 8)(4x + 1)
43. y = (x + 3)2 + 2
44. y = º(x º 5)2 + 11
45. y = º6(x º 2)2 º 9
46. y = 8(x + 7)2 º 20
47. y = º(9x + 2)2 + 4x
7
48. y = ºᎏᎏ(x + 6)(x + 3)
3
1
3
49. y = ᎏᎏ(8x º 1)2 º ᎏᎏ
2
2
50.
NE
ER T
APPLICATION LINK
VISUAL THINKING In parts (a) and (b), use a graphing calculator to
examine how b and c affect the graph of y = ax 2 + bx + c.
a. Graph y = x2 + c for c = º2, º1, 0, 1, and 2. Use the same viewing window
www.mcdougallittell.com
for all the graphs. How do the graphs change as c increases?
b. Graph y = x2 + bx for b = º2, º1, 0, 1, and 2. Use the same viewing
window for all the graphs. How do the graphs change as b increases?
51.
AUTOMOBILES The engine torque y (in foot-pounds) of one model
of car is given by
y = º3.75x2 + 23.2x + 38.8
where x is the speed of the engine (in thousands of revolutions per minute).
Find the engine speed that maximizes torque. What is the maximum torque?
52.
SPORTS Although a football field appears to be flat, its surface is actually
shaped like a parabola so that rain runs off to either side. The cross section of a
field with synthetic turf can be modeled by
y
y = º0.000234(x º 80)2 + 1.5
where x and y are measured in feet. What is the
field’s width? What is the maximum height of
the field’s surface? 䉴 Source: Boston College
53.
surface of
football field
Not drawn to scale
x
PHYSIOLOGY Scientists determined that the rate y (in calories per minute)
at which you use energy while walking can be modeled by
y = 0.00849(x º 90.2)2 + 51.3,
50 ≤ x ≤ 150
where x is your walking speed (in meters per minute). Graph the function on the
given domain. Describe how energy use changes as walking speed increases.
What speed minimizes energy use? 䉴 Source: Bioenergetics and Growth
INT
STUDENT HELP
NE
ER T
HOMEWORK HELP
Visit our Web site
www.mcdougallittell.com
for help with problem
solving in Ex. 54.
CONNECTION The woodland jumping
mouse can hop surprisingly long distances given its
small size. A relatively long hop can be modeled by
54. BIOLOGY
y
2
9
y = ºᎏᎏx(x º 6)
where x and y are measured in feet. How far can a
woodland jumping mouse hop? How high can it hop?
䉴 Source: University of Michigan Museum of Zoology
254
Chapter 5 Quadratic Functions
Not drawn to scale
x
Page 7 of 7
Test
Preparation
55. MULTI-STEP PROBLEM A kernel of popcorn contains water that expands
when the kernel is heated, causing it to pop. The equations below give the
“popping volume” y (in cubic centimeters per gram) of popcorn with moisture
content x (as a percent of the popcorn’s weight). 䉴 Source: Cereal Chemistry
Hot-air popping: y = º0.761x2 + 21.4x º 94.8
Hot-oil popping: y = º0.652x2 + 17.7x º 76.0
a. For hot-air popping, what moisture content maximizes popping volume?
What is the maximum volume?
b. For hot-oil popping, what moisture content maximizes popping volume?
What is the maximum volume?
c. The moisture content of popcorn typically ranges from 8% to 18%. Graph
the equations for hot-air and hot-oil popping on the interval 8 ≤ x ≤ 18.
d.
★ Challenge
Writing Based on the graphs from part (c), what general statement can
you make about the volume of popcorn produced from hot-air popping versus
hot-oil popping for any moisture content in the interval 8 ≤ x ≤ 18?
56. LOGICAL REASONING Write y = a(x º h)2 + k and y = a(x º p)(x º q) in
standard form. Knowing that the vertex of the graph of y = ax 2 + bx + c occurs
b
2a
at x = ºᎏᎏ, show that the vertex for y = a(x º h)2 + k occurs at x = h and that
EXTRA CHALLENGE
p+q
2
the vertex for y = a(x º p)(x º q) occurs at x = ᎏᎏ.
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MIXED REVIEW
SOLVING LINEAR EQUATIONS Solve the equation. (Review 1.3 for 5.2)
57. x º 2 = 0
58. 2x + 5 = 0
59. º4x º 7 = 21
60. 3x + 9 = ºx + 1
61. 6(x + 8) = 18
62. 5(4x º 1) = 2(x + 3)
63. 0.6x = 0.2x + 2.8
7x
3x
11
64. ᎏᎏ º ᎏᎏ = ᎏᎏ
8
5
2
1
5x
x
1
65. ᎏᎏ + ᎏᎏ = ᎏᎏ º ᎏᎏ
4
12
6
2
GRAPHING IN THREE DIMENSIONS Sketch the graph of the equation. Label
the points where the graph crosses the x-, y-, and z-axes. (Review 3.5)
66. x + y + z = 4
67. x + y + 2z = 6
68. 3x + 4y + z = 12
69. 5x + 5y + 2z = 10
70. 2x + 7y + 3z = 42
71. x + 3y º 3z = 9
USING CRAMER’S RULE Use Cramer’s rule to solve the linear system.
(Review 4.3)
72. x + y = 1
73. 2x + y = 5
º5x + y = 19
3x º 4y = 2
75. 5x + 2y + 2z = 4
76. x + 3y + z = 5
3x + y º 6z = º4
ºx º y º z = 1
78.
ºx + y + z = 7
2x º 7y + 5z = 28
74. 7x º 10y = º15
x + 2y = º9
77. 2x º 3y º 9z = 11
6x + y º z = 45
9x º 2y + 4z = 56
WEATHER In January, 1996, rain and melting snow caused the depth of the
Susquehanna River in Pennsylvania to rise from 7 feet to 22 feet in 14 hours.
Find the average rate of change in the depth during that time. (Review 2.2)
5.1 Graphing Quadratic Functions
255
Page 1 of 8
5.2
Solving Quadratic Equations by
Factoring
What you should learn
GOAL 1 Factor quadratic
expressions and solve
quadratic equations by
factoring.
GOAL 1
FACTORING QUADRATIC EXPRESSIONS
You know how to write (x + 3)(x + 5) as x2 + 8x + 15. The expressions x + 3 and
x + 5 are binomials because they have two terms. The expression x2 + 8x + 15 is
a trinomial because it has three terms. You can use factoring to write a trinomial
as a product of binomials. To factor x2 + bx + c, find integers m and n such that:
GOAL 2 Find zeros of
quadratic functions, as
applied in Example 8.
x2 + bx + c = (x + m)(x + n)
= x2 + (m + n)x + mn
Why you should learn it
RE
FE
䉲 To solve real-life
problems, such as finding
appropriate dimensions for a
mural in Ex. 97.
AL LI
So, the sum of m and n must equal b and the product of m and n must equal c.
EXAMPLE 1
Factoring a Trinomial of the Form x 2 + bx + c
Factor x2 º 12x º 28.
SOLUTION
You want x2 º 12x º 28 = (x + m)(x + n) where mn = º28 and m + n = º12.
Factors of º28 (m, n)
Sum of factors (m + n)
䉴
º1, 28
1, º28
º2, 14
2, º14
º4, 7
4, º7
27
º27
12
º12
3
º3
The table shows that m = 2 and n = º14. So, x2 º 12x º 28 = (x + 2)(x º 14).
..........
To factor ax2 + bx + c when a ≠ 1, find integers k, l, m, and n such that:
ax2 + bx + c = (kx + m)(lx + n)
= klx2 + (kn + lm)x + mn
Therefore, k and l must be factors of a, and m and n must be factors of c.
EXAMPLE 2
Factoring a Trinomial of the Form ax 2 + bx + c
Factor 3x2 º 17x + 10.
SOLUTION
You want 3x2 º 17x + 10 = (kx + m)(lx + n) where k and l are factors of 3 and
m and n are (negative) factors of 10. Check possible factorizations by multiplying.
STUDENT HELP
(3x º 10)(x º 1) = 3x2 º 13x + 10
(3x º 1)(x º 10) = 3x2 º 31x + 10
Skills Review
For help with factoring,
see p. 938.
(3x º 5)(x º 2) = 3x2 º 11x + 10
(3x º 2)(x º 5) = 3x2 º 17x + 10 ✓
256
䉴
The correct factorization is 3x2 º 17x + 10 = (3x º 2)(x º 5).
Chapter 5 Quadratic Functions
Page 2 of 8
As in Example 2, factoring quadratic expressions often involves trial and error.
However, some expressions are easy to factor because they follow special patterns.
S P E C I A L FA C TO R I N G PAT T E R N S
PATTERN NAME
PATTERN
EXAMPLE
Difference of Two Squares
a2 º b2 = (a + b)(a º b)
x 2 º 9 = (x + 3)(x º 3)
Perfect Square Trinomial
a2 + 2ab + b2 = (a + b)2
x 2 + 12x + 36 = (x + 6)2
a2 º 2ab + b2 = (a º b)2
x 2 º 8x + 16 = (x º 4)2
EXAMPLE 3
Factoring with Special Patterns
Factor the quadratic expression.
a. 4x2 º 25 = (2x)2 º 52
Difference of two squares
= (2x + 5)(2x º 5)
2
b. 9y + 24y + 16 = (3y)2 + 2(3y)(4) + 42
Perfect square trinomial
= (3y + 4)2
c. 49r 2 º 14r + 1 = (7r)2 º 2(7r)(1) + 12
= (7r º 1)
Perfect square trinomial
2
..........
A monomial is an expression that has only one term. As a first step to factoring, you
should check to see whether the terms have a common monomial factor.
EXAMPLE 4
Factoring Monomials First
Factor the quadratic expression.
STUDENT HELP
Study Tip
It is not always possible
to factor a trinomial
into a product of two
binomials with integer
coefficients. For
instance, the trinomial
x 2 + x º 1 in part (d) of
Example 4 cannot be
factored. Such trinomials
are called irreducible.
a. 5x2 º 20 = 5(x2 º 4)
b. 6p2 + 15p + 9 = 3(2p2 + 5p + 3)
= 5(x + 2)(x º 2)
c. 2u2 + 8u = 2u(u + 4)
= 3(2p + 3)( p + 1)
d. 4x2 + 4x º 4 = 4(x2 + x º 1)
..........
You can use factoring to solve certain quadratic equations. A quadratic equation
in one variable can be written in the form ax2 + bx + c = 0 where a ≠ 0. This is
called the standard form of the equation. If the left side of ax2 + bx + c = 0 can
be factored, then the equation can be solved using the zero product property.
Z E R O P R O D U C T P R O P E RT Y
Let A and B be real numbers or algebraic expressions. If AB = 0, then
A = 0 or B = 0.
5.2 Solving Quadratic Equations by Factoring
257
Page 3 of 8
Solving Quadratic Equations
EXAMPLE 5
Solve (a) x2 + 3x º 18 = 0 and (b) 2t2 º 17t + 45 = 3t º 5.
STUDENT HELP
Look Back
For help with
solving equations,
see p. 19.
SOLUTION
a. x2 + 3x º 18 = 0
Write original equation.
(x + 6)(x º 3) = 0
x+6=0
x = º6
䉴
Factor.
or
xº3=0
or
x=3
Write original equation.
2t2 º 20t + 50 = 0
Write in standard form.
2
t º 10t + 25 = 0
Divide each side by 2.
(t º 5)2 = 0
Factor.
tº5=0
Use zero product property.
t=5
RE
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Crafts
Solve for x.
The solutions are º6 and 3. Check the solutions in the original equation.
b. 2t2 º 17t + 45 = 3t º 5
䉴
Use zero product property.
Solve for t.
The solution is 5. Check the solution in the original equation.
Using a Quadratic Equation as a Model
EXAMPLE 6
You have made a rectangular stained glass window that is
2 feet by 4 feet. You have 7 square feet of clear glass to create
a border of uniform width around the window. What should
the width of the border be?
x
x
x
x
4 ⫹ 2x
4
SOLUTION
PROBLEM
SOLVING
STRATEGY
VERBAL
MODEL
Area of
Area of
= Area of border º
border
window
and window
2
x
x
x
x
2 ⫹ 2x
LABELS
Width of border = x
(feet)
Area of border = 7
(square feet)
Area of border and window = (2 + 2x)(4 + 2x)
(square feet)
Area of window = 2 • 4 = 8
(square feet)
ALGEBRAIC
MODEL
7 = (2 + 2x)(4 + 2x) º 8
2
0 = 4x + 12x º 7
Write in standard form.
0 = (2x + 7)(2x º 1)
Factor.
2x + 7 = 0
x = º3.5
䉴
258
Write algebraic model.
or
or
2x º 1 = 0
x = 0.5
Use zero product property.
Solve for x.
Reject the negative value, º3.5. The border’s width should be 0.5 ft, or 6 in.
Chapter 5 Quadratic Functions
Page 4 of 8
GOAL 2
FINDING ZEROS OF QUADRATIC FUNCTIONS
In Lesson 5.1 you learned that the x-intercepts of the graph of y = a(x º p)(x º q)
are p and q. The numbers p and q are also called zeros of the function because the
function’s value is zero when x = p and when x = q. If a quadratic function is given
in standard form y = ax2 + bx + c, you may be able to find its zeros by using
factoring to rewrite the function in intercept form.
EXAMPLE 7
Finding the Zeros of a Quadratic Function
Find the zeros of y = x2 º x º 6.
SOLUTION
STUDENT HELP
Study Tip
In Example 7 note that
º2 and 3 are zeros of the
function and x-intercepts
of the graph. In general,
functions have zeros and
graphs have x-intercepts.
Use factoring to write the function in intercept form.
y = x2 º x º 6
= (x + 2)(x º 3)
䉴
The zeros of the function are º2 and 3.
✓CHECK Graph y = x2 º x º 6. The graph passes
through (º2, 0) and (3, 0), so the zeros are º2 and 3.
..........
From Lesson 5.1 you know that the vertex of the graph of y = a(x º p)(x º q) lies
on the vertical line halfway between ( p, 0) and (q, 0). In terms of zeros, the function
has its maximum or minimum value when x equals the average of the zeros.
EXAMPLE 8
INT
STUDENT HELP
NE
ER T
HOMEWORK HELP
Visit our Web site
www.mcdougallittell.com
for extra examples.
Using the Zeros of a Quadratic Model
BUSINESS You maintain a music-oriented Web site that allows subscribing
customers to download audio and video clips of their favorite bands. When the
subscription price is $16 per year, you get 30,000 subscribers. For each $1 increase
in price, you expect to lose 1000 subscribers. How much should you charge to
maximize your annual revenue? What is your maximum revenue?
SOLUTION
Revenue = Number of subscribers • Subscription price
Let R be your annual revenue and let x be the number of $1 price increases.
R = (30,000 º 1000x)(16 + x)
= (º1000x + 30,000)(x + 16)
= º1000(x º 30)(x + 16)
The zeros of the revenue function are 30 and º16. The value of x that maximizes R
30 + (º16)
2
is the average of the zeros, or x = ᎏᎏ = 7.
䉴
To maximize revenue, charge $16 + $7 = $23 per year for a subscription.
Your maximum revenue is R = º1000(7 º 30)(7 + 16) = $529,000.
5.2 Solving Quadratic Equations by Factoring
259
Page 5 of 8
GUIDED PRACTICE
✓
Concept Check ✓
Vocabulary Check
1. What is a zero of a function y = ƒ(x)?
x 2 + 4x + 3 = 8
2. In Example 2, how do you know that m and n must
(x + 3) (x + 1) = 8
be negative factors of 10?
3. ERROR ANALYSIS A student solved
x + 3 = 8 or x + 1 = 8
2
Skill Check
✓
x = 5 or x = 7
x + 4x + 3 = 8 as shown. Explain the student’s
mistake. Then solve the equation correctly.
Factor the expression.
4. x2 º x º 2
5. 2x2 + x º 3
6. x2 º 16
7. y2 + 2y + 1
8. p2 º 4p + 4
9. q2 + q
Solve the equation.
10. (x + 3)(x º 1) = 0
11. x2 º 2x º 8 = 0
12. 3x2 + 10x + 3 = 0
13. 4u2 º 1 = 0
14. v2 º 14v = º49
15. 5w2 = 30w
Write the quadratic function in intercept form and give the function’s zeros.
16. y = x2 º 6x + 5
17. y = x2 + 6x + 8
18. y = x2 º 1
19. y = x2 + 10x + 25
20. y = 2x2 º 2x º 24
21. y = 3x2 º 8x + 4
22.
URBAN PLANNING You have just planted a
rectangular flower bed of red roses in a park near
your home. You want to plant a border of yellow
roses around the flower bed as shown. Since you
bought the same number of red and yellow roses,
the areas of the border and inner flower bed will be
equal. What should the width x of the border be?
x
x
x
x
8 ft
x
PRACTICE AND APPLICATIONS
STUDENT HELP
Extra Practice
to help you master
skills is on p. 945.
FACTORING x 2 + bx + c Factor the trinomial. If the trinomial cannot be
factored, say so.
23. x2 + 5x + 4
24. x2 + 9x + 14
25. x2 + 13x + 40
26. x2 º 4x + 3
27. x2 º 8x + 12
28. x2 º 16x + 51
29. a2 + 3a º 10
30. b2 + 6b º 27
31. c2 + 2c º 80
32. p2 º 5p º 6
33. q2 º 7q º 10
34. r 2 º 14r º 72
FACTORING ax 2 + bx + c Factor the trinomial. If the trinomial cannot be
factored, say so.
260
35. 2x2 + 7x + 3
36. 3x2 + 17x + 10
37. 8x2 + 18x + 9
38. 5x2 º 7x + 2
39. 6x2 º 9x + 5
40. 10x2 º 19x + 6
41. 3k 2 + 32k º 11
42. 11m2 + 14m º 16
43. 18n2 + 9n º 14
44. 7u2 º 4u º 3
45. 12v2 º 25v º 7
46. 4w2 º 13w º 27
Chapter 5 Quadratic Functions
x
12 ft
x
x
Page 6 of 8
FACTORING WITH SPECIAL PATTERNS Factor the expression.
STUDENT HELP
HOMEWORK HELP
Example 1: Exs. 23–34
Example 2: Exs. 35–46
Example 3: Exs. 47–55
Example 4: Exs. 56–64
Example 5: Exs. 65–79
Example 6: Exs. 90, 91,
97, 98
Example 7: Exs. 80–88
Example 8: Exs. 99–101
47. x2 º 25
48. x2 + 4x + 4
49. x 2 º 6x + 9
50. 4r 2 º 4r + 1
51. 9s2 + 12s + 4
52. 16t 2 º 9
53. 49 º 100a2
54. 25b2 º 60b + 36
55. 81c2 + 198c + 121
FACTORING MONOMIALS FIRST Factor the expression.
56. 5x2 + 5x º 10
57. 18x2 º 2
58. 3x 2 + 54x + 243
59. 8y2 º 28y º 60
60. 112a2 º 168a + 63
61. u2 + 7u
62. 6t2 º 36t
63. ºv2 + 2v º 1
64. 2d 2 + 12d º 16
EQUATIONS IN STANDARD FORM Solve the equation.
65. x2 º 3x º 4 = 0
66. x2 + 19x + 88 = 0
67. 5x2 º 13x + 6 = 0
68. 8x2 º 6x º 5 = 0
69. k2 + 24k + 144 = 0
70. 9m2 º 30m + 25 = 0
71. 81n2 º 16 = 0
72. 40a2 + 4a = 0
73. º3b2 + 3b + 90 = 0
EQUATIONS NOT IN STANDARD FORM Solve the equation.
74. x2 + 9x = º20
75. 16x2 = 8x º 1
76. 5p2 º 25 = 4p2 + 24
77. 2y2 º 4y º 8 = ºy2 + y
78. 2q2 + 4q º 1 = 7q2 º 7q + 1
79. (w + 6)2 = 3(w + 12) º w2
FINDING ZEROS Write the quadratic function in intercept form and give the
function’s zeros.
80. y = x2 º 3x + 2
81. y = x2 + 7x + 12
82. y = x2 + 2x º 35
83. y = x2 º 4
84. y = x2 + 20x + 100
85. y = x2 º 3x
86. y = 3x2 º 12x º 15
87. y = ºx2 + 16x º 64
88. y = 2x2 º 9x + 4
89. LOGICAL REASONING Is there a formula for factoring the sum of two squares?
You will investigate this question in parts (a) and (b).
a. Consider the sum of squares x2 + 9. If this sum can be factored, then there are
integers m and n such that x2 + 9 = (x + m)(x + n). Write two equations
relating the sum and the product of m and n to the coefficients in x2 + 9.
b. Show that there are no integers m and n that satisfy both equations you wrote
in part (a). What can you conclude?
90.
QUILTING You have made a quilt
that is 4 feet by 5 feet. You want to use
the remaining 10 square feet of fabric
to add a decorative border of uniform
width. What should the width of the
border be?
91.
CONSTRUCTION A high school
wants to double the size of its parking
lot by expanding the existing lot as
shown. By what distance x should the
lot be expanded?
5.2 Solving Quadratic Equations by Factoring
261
Page 7 of 8
STUDENT HELP
Skills Review
For help with areas of
geometric figures,
see p. 914.
GEOMETRY
CONNECTION
Find the value of x.
92. Area of rectangle = 40
93. Area of rectangle = 105
x
x
xⴙ3
2x ⴙ 1
94. Area of triangle = 22
95. Area of trapezoid = 114
2x ⴚ 1
x
x
3x ⴚ 1
4x ⴙ 3
x
96. VISUAL THINKING Use the diagram shown at the right.
a. Explain how the diagram models the factorization
x2 + 5x + 6 = (x + 2)(x + 3).
b. Draw a diagram that models the factorization
2
x + 7x + 12 = (x + 3)(x + 4).
1 1 1
x
1
1
CONNECTION As part of Black History Month in February, an artist is
creating a mural on the side of a building. A painting of Dr. Martin Luther King,
Jr., will occupy the center of the mural and will be surrounded by a border of
uniform width showing other prominent African-Americans. The side of the
building is 50 feet wide by 30 feet high, and the artist wants to devote 25% of the
available space to the border. What should the width of the border be?
97. ART
FOCUS ON
APPLICATIONS
98.
99.
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ENVIRONMENT
Ecology gardens
are often used to conduct
research with different plant
species under a variety of
growing conditions.
100.
ENVIRONMENT A student environmental
group wants to build an ecology garden as
shown. The area of the garden should be
800 square feet to accommodate all the
species of plants the group wants to grow.
A construction company has donated 120 feet
of iron fencing to enclose the garden. What
should the dimensions of the garden be?
x ft
(60 – x) ft
ATHLETIC WEAR A shoe store sells about 200 pairs of a new basketball
shoe each month when it charges $60 per pair. For each $1 increase in price,
about 2 fewer pairs per month are sold. How much per pair should the store
charge to maximize monthly revenue? What is the maximum revenue?
HOME ELECTRONICS The manager of a home electronics store is
considering repricing a new model of digital camera. At the current price of
$680, the store sells about 70 cameras each month. Sales data from other stores
indicate that for each $20 decrease in price, about 5 more cameras per month
would be sold. How much should the manager charge for a camera to maximize
monthly revenue? What is the maximum revenue?
CONNECTION Big Bertha, a cannon used in World War I, could
fire shells incredibly long distances. The path of a shell could be modeled by
y = º0.0196x2 + 1.37x where x was the horizontal distance traveled (in miles)
and y was the height (in miles). How far could Big Bertha fire a shell? What was
the shell’s maximum height? 䉴 Source: World War I: Trenches on the Web
101. HISTORY
262
Chapter 5 Quadratic Functions
Page 8 of 8
Test
Preparation
102. MULTIPLE CHOICE Suppose x2 + 4x + c = (x + m)(x + n) where c, m, and n
are integers. Which of the following are not possible values of m and n?
A
¡
C
¡
B
¡
D
¡
m = 2, n = 2
m = º2, n = º2
m = º1, n = 5
m = 1, n = 3
103. MULTIPLE CHOICE What are all solutions of 2x2 º 11x + 16 = x2 º 3x?
A
¡
2, 6
B
¡
º4
C
¡
D
¡
º4, 4
4
104. MULTIPLE CHOICE Given that 4 is a zero of y = 3x2 + bx º 8, what is the
value of b?
★ Challenge
A
¡
º40
B
¡
º10
C
¡
D
¡
º8
2
105. MULTICULTURAL MATHEMATICS The following problem is from the
Chiu chang suan shu, an ancient Chinese mathematics text. Solve the problem.
(Hint: Use the Pythagorean theorem.)
A rod of unknown length is used to measure the dimensions of
a rectangular door. The rod is 4 ch’ih longer than the width of
the door, 2 ch’ih longer than the height of the door, and the
same length as the door’s diagonal. What are the dimensions
of the door? (Note: 1 ch’ih is slightly greater than 1 foot.)
EXTRA CHALLENGE
www.mcdougallittell.com
MIXED REVIEW
ABSOLUTE VALUE Solve the equation or inequality. (Review 1.7)
106. |x| = 3
107. |x º 2| = 6
108. |4x º 9| = 2
109. |º5x + 4| = 14
110. |7 º 3x| = º8
111. |x + 1| < 3
112. |2x º 5| ≤ 1
113. |x º 4| > 7
114.
|ᎏ13ᎏx + 1| ≥ 2
GRAPHING LINEAR EQUATIONS Graph the equation. (Review 2.3)
115. y = x + 1
116. y = º2x + 3
117. y = 3x º 5
5
118. y = ºᎏᎏx + 7
2
119. x + y = 4
120. 2x º y = 6
121. 3x + 4y = º12
122. º5x + 3y = 15
123. y = 2
124. y = º3
125. x = º1
126. x = 4
GRAPHING QUADRATIC FUNCTIONS Graph the function. (Review 5.1 for 5.3)
127. y = x2 º 2
128. y = 2x2 º 5
129. y = ºx2 + 3
130. y = (x + 1)2 º 4
131. y = º(x º 2)2 + 1
132. y = º3(x + 3)2 + 7
1
133. y = ᎏᎏx2 º 1
4
1
134. y = ᎏᎏ(x º 4)2 º 6
2
2
135. y = ºᎏᎏ(x + 1)(x º 3)
3
136.
COMMUTING You can take either the subway or the bus to your afterschool job. A round trip from your home to where you work costs $2 on the
subway and $3 on the bus. You prefer to take the bus as often as possible but can
afford to spend only $50 per month on transportation. If you work 22 days each
month, how many of these days can you take the bus? (Review 1.5)
5.2 Solving Quadratic Equations by Factoring
263
Page 1 of 7
5.3
Solving Quadratic Equations by
Finding Square Roots
What you should learn
GOAL 1 Solve quadratic
equations by finding square
roots.
GOAL 2 Use quadratic
equations to solve real-life
problems, such as finding
how long a falling stunt man
is in the air in Example 4.
GOAL 1
A number r is a square root of a number s if r 2 = s. A positive number s has two
square roots denoted by s and ºs. The symbol is a radical sign, the number
s beneath the radical sign is the radicand, and the expression s is a radical.
For example, since 32 = 9 and (º3)2 = 9, the two square roots of 9 are 9 = 3
and º9 = º3. You can use a calculator to approximate s when s is not a perfect
square. For instance, 2 ≈ 1.414.
ACTIVITY
Why you should learn it
Developing
Concepts
1
Investigating Properties of Square Roots
Evaluate the two expressions. What do you notice about the square root of
a product of two numbers?
a. 3
6, 4 • 9
AL LI
FE
RE
䉲 To model real-life
quantities, such as the height
of a rock dropped off the
Leaning Tower of Pisa
in Ex. 69.
SOLVING QUADRATIC EQUATIONS
2
b. 8
, 4 • 2
c. 3
0, 3 • 10
Evaluate the two expressions. What do you notice about the square root of
a quotient of two numbers?
a.
4
ᎏ49ᎏ , ᎏ
9
b.
2
5
ᎏ225ᎏ, ᎏ
2
c.
1
9
ᎏ179ᎏ, ᎏ
7
In the activity you may have discovered the following properties of square roots.
You can use these properties to simplify expressions containing square roots.
P R O P E RT I E S O F S Q UA R E R O O T S ( a > 0 , b > 0 )
Product Property: a
b
= a
• b
Quotient Property:
a = a
ᎏ
ᎏ
ᎏ
b
b
A square-root expression is considered simplified if (1) no radicand has a perfectsquare factor other than 1, and (2) there is no radical in a denominator.
EXAMPLE 1
Using Properties of Square Roots
Simplify the expression.
a. 2
4 = 4 • 6 = 26
c.
264
7
7
=ᎏ
ᎏ17ᎏ6 = ᎏ
4
16
Chapter 5 Quadratic Functions
b. 6
• 15 = 90 = 9 • 10 = 310
d.
7 2
7
14
ᎏᎏ = ᎏ • ᎏ = ᎏ
2
2
2 2
Page 2 of 7
7
2
In part (d) of Example 1, the square root in the denominator of ᎏ was
eliminated by multiplying both the numerator and the denominator by 2.
This process is called rationalizing the denominator.
You can use square roots to solve some types of quadratic equations. For instance,
if s > 0, then the quadratic equation x2 = s has two real-number solutions: x = s
and x = ºs. These solutions are often written in condensed form as x = ±s.
The symbol ±s is read as “plus or minus the square root of s.”
EXAMPLE 2
Solving a Quadratic Equation
Solve 2x2 + 1 = 17.
SOLUTION
Begin by writing the equation in the form x2 = s.
2x2 + 1 = 17
Write original equation.
2x2 = 16
Subtract 1 from each side.
x2 = 8
䉴
Divide each side by 2.
x = ±8
Take square roots of each side.
x = ±22
Simplify.
The solutions are 22 and º22.
✓CHECK
You can check the solutions algebraically
by substituting them into the original equation. Since
this equation is equivalent to 2x2 º 16 = 0, you can
also check the solutions by graphing y = 2x2 º 16
and observing that the graph’s x-intercepts appear to
be about 2.8 ≈ 22 and º2.8 ≈ º22.
EXAMPLE 3
INT
STUDENT HELP
NE
ER T
HOMEWORK HELP
Visit our Web site
www.mcdougallittell.com
for extra examples.
Solving a Quadratic Equation
1
3
Solve ᎏᎏ(x + 5)2 = 7.
SOLUTION
1
ᎏᎏ(x + 5)2 = 7
3
Write original equation.
(x + 5)2 = 21
Multiply each side by 3.
x + 5 = ±21
x = º5 ± 21
䉴
Take square roots of each side.
Subtract 5 from each side.
The solutions are º5 + 21 and º5 º 21.
✓CHECK
Check the solutions either by substituting them into the original equation
1
3
or by graphing y = ᎏᎏ(x + 5)2 º 7 and observing the x-intercepts.
5.3 Solving Quadratic Equations by Finding Square Roots
265
Page 3 of 7
GOAL 2
USING QUADRATIC MODELS IN REAL LIFE
When an object is dropped, its speed continually increases, and therefore its height
above the ground decreases at a faster and faster rate. The height h (in feet) of the
object t seconds after it is dropped can be modeled by the function
h = º16t 2 + h0
where h0 is the object’s initial height. This model assumes that the force of air
resistance on the object is negligible. Also, the model works only on Earth. For
planets with stronger or weaker gravity, different models are used (see Exercise 71).
RE
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Movies
EXAMPLE 4
Modeling a Falling Object’s Height with a Quadratic Function
A stunt man working on the set of a movie is to fall out of a window 100 feet above
the ground. For the stunt man’s safety, an air cushion 26 feet wide by 30 feet long by
9 feet high is positioned on the ground below the window.
a. For how many seconds will the stunt man fall before he reaches the cushion?
b. A movie camera operating at a speed of 24 frames per second records the stunt
man’s fall. How many frames of film show the stunt man falling?
SOLUTION
a. The stunt man’s initial height is h0 = 100 feet, so his height as a function of time
is given by h = º16t2 + 100. Since the top of the cushion is 9 feet above the
ground, you can determine how long it takes the stunt man to reach the cushion
by finding the value of t for which h = 9 . Here are two methods:
Method 1:
䉴
Make a table of values.
t
0
1
2
3
h
100
84
36
º44
From the table you can see that h = 9 at a value of t between t = 2 and t = 3.
It takes between 2 sec and 3 sec for the stunt man to reach the cushion.
Method 2:
Solve a quadratic equation.
h = º16t2 + 100
Write height function.
9 = º16t2 + 100
Substitute 9 for h.
º91 = º16t2
91
ᎏᎏ = t 2
16
ᎏ1ᎏ6 = t
91
2.4 ≈ t
䉴
Subtract 100 from each side.
Divide each side by –16.
Take positive square root.
Use a calculator.
It takes about 2.4 seconds for the stunt man to reach the cushion.
b. The number of frames of film that show the stunt man falling is given by the
product (2.4 sec)(24 frames/sec), or about 57 frames.
266
Chapter 5 Quadratic Functions
Page 4 of 7
GUIDED PRACTICE
Vocabulary Check
Concept Check
✓
1. Explain what it means to “rationalize the denominator” of a quotient containing
✓
2. State the product and quotient properties of square roots in words.
square roots.
3. How many real-number solutions does the equation x2 = s have when s > 0?
Skill Check
✓
when s = 0? when s < 0?
Simplify the expression.
9
4. 4
8.
5. 1
2
ᎏ126ᎏ5
9.
ᎏ79ᎏ
6. 4
5
7. 3
• 27
1
10. ᎏ
3
11.
ᎏ52ᎏ
Solve the equation.
12. x2 = 64
13. x2 º 9 = 16
14. 4x2 + 7 = 23
x2
15. ᎏᎏ º 2 = 0
6
16. 5(x º 1)2 = 50
1
17. ᎏᎏ(x + 8)2 = 14
2
18.
ENGINEERING At an engineering school, students are challenged to design
a container that prevents an egg from breaking when dropped from a height of
50 feet. Write an equation giving a container’s height h (in feet) above the
ground after t seconds. How long does the container take to hit the ground?
PRACTICE AND APPLICATIONS
STUDENT HELP
USING THE PRODUCT PROPERTY Simplify the expression.
Extra Practice
to help you master
skills is on p. 946.
8
19. 1
20. 4
8
21. 2
7
22. 5
2
23. 7
2
24. 1
75
25. 9
8
26. 6
0
5
27. 27
• 7
28. 8
• 2
29. 3
• 12
30. 32
0 • 65
31. 1
2 • 2
32. 6
• 10
33. 43
• 21
34. 8
• 6 • 3
USING THE QUOTIENT PROPERTY Simplify the expression.
35.
1
ᎏᎏ
9
36.
ᎏ44ᎏ9
37.
ᎏ326ᎏ5
38.
0
ᎏ
ᎏ180
1
39.
ᎏ13ᎏ6
40.
ᎏ161ᎏ4
41.
ᎏ735ᎏ6
42.
ᎏ146ᎏ09
5
44. ᎏ
17
45.
6
ᎏᎏ
5
46.
4
ᎏ
ᎏ114
1
ᎏ118ᎏ3
49.
ᎏ435ᎏ2
50.
4
ᎏᎏ
ᎏ175ᎏ • 3
2
43. ᎏ
3
47.
7
ᎏᎏ
8
48.
STUDENT HELP
HOMEWORK HELP
Example 1:
Example 2:
Example 3:
Example 4:
Exs. 19–50
Exs. 51–59
Exs. 60–68
Exs. 69–73
SOLVING QUADRATIC EQUATIONS Solve the equation.
51. x2 = 121
52. x2 = 90
53. 3x2 = 108
54. 2x2 + 5 = 41
55. ºx2 º 12 = º87
p2
58. 6 º ᎏᎏ = º4
8
56. 7 º 10u2 = 1
5q2
q2
59. ᎏᎏ º ᎏᎏ = 72
6
3
v2
57. ᎏᎏ º 1 = 11
25
5.3 Solving Quadratic Equations by Finding Square Roots
267
Page 5 of 7
SOLVING QUADRATIC EQUATIONS Solve the equation.
60. 2(x º 3)2 = 8
61. 4(x + 1)2 = 100
62. º3(x + 2)2 = º18
63. 5(x º 7)2 = 135
64. 8(x + 4)2 = 9
65. 2(a º 6)2 º 45 = 53
1
66. ᎏᎏ(b º 8)2 = 7
4
67. (2r º 5)2 = 81
(s + 1)2
12
15
68. ᎏᎏ º ᎏᎏ = ᎏᎏ
5
2
10
CONNECTION According to legend, in 1589 the Italian scientist Galileo
Galilei dropped two rocks of different weights from the top of the Leaning Tower
of Pisa. He wanted to show that the rocks would hit the ground at the same time.
Given that the tower’s height is about 177 feet, how long would it have taken for
the rocks to hit the ground?
69. HISTORY
70.
ORNITHOLOGY Many birds drop shellfish onto
rocks to break the shell and get to the food inside.
Crows along the west coast of Canada use this technique
to eat whelks (a type of sea snail). Suppose a crow drops
a whelk from a height of 20 feet, as shown.
FOCUS ON
APPLICATIONS
䉴 Source: Cambridge Encyclopedia of Ornithology
a. Write an equation giving the whelk’s height h
(in feet) after t seconds.
20 ft
b. Use the Table feature of a graphing calculator to find
h when t = 0, 0.1, 0.2, 0.3, . . . , 1.4, 1.5. (You’ll need
to scroll down the table to see all the values.) To the
nearest tenth of a second, how long does it take for
the whelk to hit the ground? Check your answer by
solving a quadratic equation.
L
AL I
INT
RE
FE
ASTRONOMY The
acceleration due to
gravity on the moon is about
5.3 ft/sec2. This means that
the moon’s gravity is only
about one sixth as strong as
Earth’s.
71.
ASTRONOMY On any planet, the height h (in feet) of a falling object
t seconds after it is dropped can be modeled by
g
2
h = ºᎏᎏt2 + h0
where h0 is the object’s initial height and g is the acceleration (in feet per second
squared) due to the planet’s gravity. For each planet in the table, find the time it
takes for a rock dropped from a height of 200 feet to hit the ground.
NE
ER T
APPLICATION LINK
www.mcdougallittell.com
Planet
g (ft/sec2)
Earth
Mars
Jupiter
Neptune
Pluto
32
12
81
36
2.1
䉴 Source: STARLab, Stanford University
72.
OCEANOGRAPHY The equation h = 0.019s2 gives the height h (in feet) of
the largest ocean waves when the wind speed is s knots. How fast is the wind
blowing if the largest waves are 15 feet high? 䉴 Source: Encyclopaedia Britannica
STUDENT HELP
Skills Review
For help with the
Pythagorean theorem,
see p. 917.
268
73.
TELEVISION The aspect ratio of a TV screen
is the ratio of the screen’s width to its height. For
most TVs, the aspect ratio is 4:3. What are the
width and height of the screen for a 27 inch TV?
(Hint: Use the Pythagorean theorem and the fact
that TV sizes such as 27 inches refer to the length
of the screen’s diagonal.)
Chapter 5 Quadratic Functions
27
4x
3x
Page 6 of 7
Test
Preparation
74. MULTI-STEP PROBLEM Building codes often require that buildings be able
to withstand a certain amount of wind pressure. The pressure P (in pounds per
square foot) from wind blowing at s miles per hour is given by P = 0.00256s2.
䉴 Source: The Complete How to Figure It
a. You are designing a two-story library. Buildings this tall are often required to
withstand wind pressure of 20 lb/ft2. Under this requirement, how fast can the
wind be blowing before it produces excessive stress on a building?
b. To be safe, you design your library so that it can withstand wind pressure of
40 lb/ft2. Does this mean that the library can survive wind blowing at twice
the speed you found in part (a)? Justify your answer mathematically.
c.
★ Challenge
Writing
Use the pressure formula to explain why even a relatively small
increase in wind speed could have potentially serious effects on a building.
75. SCIENCE
For a bathtub with a rectangular base, Torricelli’s law
implies that the height h of water in the tub t seconds after it begins draining is
given by
2πd 2 3 2
h = h
0 º ᎏt
CONNECTION
lw
where l and w are the tub’s length and width, d is the diameter of the drain, and
h0 is the water’s initial height. (All measurements are in inches.) Suppose you
completely fill a tub with water. The tub is 60 inches long by 30 inches wide by
25 inches high and has a drain with a 2 inch diameter.
a. Find the time it takes for the tub to go from being full to half-full.
b. Find the time it takes for the tub to go from being half-full to empty.
EXTRA CHALLENGE
c. CRITICAL THINKING Based on your results, what general statement can you
make about the speed at which water drains?
www.mcdougallittell.com
MIXED REVIEW
SOLVING SYSTEMS Solve the linear system by graphing. (Review 3.1)
76. x + y = 5
77. x º y = º1
ºx + 2y = 4
78. º3x + y = 7
3x + y = 5
79. 2x º 3y = 9
2x + y = 2
80. x + 4y = 4
4x º 3y = 3
81. 2x + 3y = 6
3x º 2y = 12
x º 6y = 18
MATRIX OPERATIONS Perform the indicated operation(s). (Review 4.1)
82.
68
84. º4
º1
2
º34
+ º510
5
º4
º1
8
º4
º2
83.
º27 30 º º69
85. º2
1220
10
º9
4
º1
+ 7 150
11
º7
WRITING IN STANDARD FORM Write the quadratic function in standard form.
(Review 5.1 for 5.4)
86. y = (x + 5)(x º 2)
87. y = (x º 1)(x º 8)
88. y = (2x + 7)(x + 4)
89. y = (4x + 9)(4x º 9)
90. y = (x º 3)2 + 1
91. y = 5(x + 6)2 º 12
5.3 Solving Quadratic Equations by Finding Square Roots
269
Page 7 of 7
QUIZ 1
Self-Test for Lessons 5.1–5.3
Graph the function. (Lesson 5.1)
1. y = x2 º 2x º 3
1
3. y = ºᎏᎏ(x + 5)(x º 1)
3
2. y = 2(x + 2)2 + 1
Solve the equation. (Lesson 5.2)
4. x2 º 6x º 27 = 0
5. 4x2 + 21x + 20 = 0
6. 7t2 º 4t = 3t2 º 1
Simplify the expression. (Lesson 5.3)
4
7. 5
9.
4
10. ᎏ
1
2
ᎏ356ᎏ
SWIMMING The drag force F (in pounds) of water on a swimmer can be
modeled by F = 1.35s2 where s is the swimmer’s speed (in miles per hour). How
fast must you swim to generate a drag force of 10 pounds? (Lesson 5.3)
INT
11.
8. 72
• 10
NE
ER T
Telescopes
APPLICATION LINK
www.mcdougallittell.com
THEN
THE FIRST TELESCOPE is thought to have been made in 1608 by Hans Lippershey,
NOW
RECENTLY “liquid mirrors” for telescopes have been made by
a Dutch optician. Lippershey’s telescope, called a refracting telescope, used lenses
to magnify objects. Another type of telescope is a reflecting telescope. Reflecting
telescopes magnify objects with parabolic mirrors, traditionally made from glass.
y
spinning reflective liquids, such as mercury. A cross section
of the surface of a spinning liquid is a parabola with equation
π 2ƒ 2
16
ƒ
π 2ƒ 2R2
32
x
y = ᎏx 2 º ᎏ
where ƒ is the spinning frequency (in revolutions per second)
and R is the radius (in feet) of the container.
R
1. Write an equation for the surface of a liquid before it is spun. What does the
equation tell you about the location of the x-axis relative to the liquid?
2. Suppose mercury is spun with a frequency of 0.5 revolution/sec in a container
with radius 2 feet. Write and graph an equation for the mercury’s surface.
π 2ƒ 2R2
π 2ƒ 2
3. Find the x-intercepts of the graph of y = ᎏx 2 º ᎏ. Does changing the
16
32
spinning frequency affect the x-intercepts? Explain.
Galileo first uses a
refracting telescope for
astronomical purposes.
Maria Mitchell is first
to use a telescope to
discover a comet.
1609
1668
Isaac Newton builds first
reflecting telescope.
270
Chapter 5 Quadratic Functions
1987
1847
Liquid mirrors are first used
to do astronomical research.
Page 1 of 9
5.4
Complex Numbers
What you should learn
GOAL 1 Solve quadratic
equations with complex
solutions and perform
operations with complex
numbers.
GOAL 1
OPERATIONS WITH COMPLEX NUMBERS
Not all quadratic equations have real-number solutions. For instance, x 2 = º1 has
no real-number solutions because the square of any real number x is never negative.
To overcome this problem, mathematicians created an expanded system of numbers
苶1苶. Note that i 2 = º1. The
using the imaginary unit i, defined as i = 兹º
imaginary unit i can be used to write the square root of any negative number.
GOAL 2 Apply complex
numbers to fractal geometry.
T H E S Q UA R E R O O T O F A N E G AT I V E N U M B E R
Why you should learn it
RE
FE
䉲 To solve problems, such
as determining whether a
complex number belongs to
the Mandelbrot set
in Example 7.
AL LI
PROPERTY
EXAMPLE
1. If r is a positive real number,
then 兹º
苶r苶 = i 兹r苶.
兹º
苶5
苶 = i 兹5
苶
2. By Property (1), it follows that
(i 兹r苶)2 = ºr.
(i 兹5苶)2 = i 2 • 5 = º5
EXAMPLE 1
Solving a Quadratic Equation
Solve 3x 2 + 10 = º26.
SOLUTION
3x 2 + 10 = º26
3x 2 = º36
x 2 = º12
䉴
Write original equation.
Subtract 10 from each side.
Divide each side by 3.
x = ±兹º
苶1苶2苶
Take square roots of each side.
x = ±i兹1苶2苶
Write in terms of i.
x = ±2i兹3苶
Simplify the radical.
The solutions are 2i兹3苶 and º2i兹3苶.
..........
A complex number written in standard form is
a number a + bi where a and b are real numbers.
The number a is the real part of the complex number,
and the number bi is the imaginary part. If b ≠ 0,
then a + bi is an imaginary number. If a = 0 and
b ≠ 0, then a + bi is a pure imaginary number.
The diagram shows how different types of complex
numbers are related.
272
Chapter 5 Quadratic Functions
Complex Numbers (a ⫹ bi)
Real
Numbers
(a ⫹ 0i )
5
2
ⴚ1
3
π
兹2
Imaginary
Numbers
(a ⫹ bi, b ⫽ 0)
2 ⴙ 3i
5 ⴚ 5i
Pure
Imaginary
Numbers
(0 ⫹ bi, b ⫽ 0)
ⴚ4i
6i
Page 2 of 9
Just as every real number corresponds to a point on the real number line, every
complex number corresponds to a point in the complex plane. As shown in the next
example, the complex plane has a horizontal axis called the real axis and a vertical
axis called the imaginary axis.
EXAMPLE 2
Plotting Complex Numbers
Plot the complex numbers in the complex plane.
a. 2 º 3i
b. º3 + 2i
imaginary
c. 4i
4i
SOLUTION
⫺3 ⫹ 2i
a. To plot 2 º 3i, start at the origin, move 2 units to the
i
right, and then move 3 units down.
1
real
b. To plot º3 + 2i, start at the origin, move 3 units to the
left, and then move 2 units up.
2 ⫺ 3i
c. To plot 4i, start at the origin and move 4 units up.
..........
Two complex numbers a + bi and c + di are equal if and only if a = c and b = d.
For instance, if x + yi = 8 º i, then x = 8 and y = º1.
To add (or subtract) two complex numbers, add (or subtract) their real parts and their
imaginary parts separately.
Sum of complex numbers: (a + bi) + (c + di) = (a + c) + (b + d)i
Difference of complex numbers: (a + bi) º (c + di) = (a º c) + (b º d)i
EXAMPLE 3
Adding and Subtracting Complex Numbers
Write the expression as a complex number in standard form.
a. (4 º i) + (3 + 2i)
b. (7 º 5i) º (1 º 5i)
c. 6 º (º2 + 9i) + (º8 + 4i)
SOLUTION
a. (4 º i) + (3 + 2i) = (4 + 3) + (º1 + 2)i
=7+i
Definition of complex addition
Standard form
b. (7 º 5i) º (1 º 5i) = (7 º 1) + (º5 + 5)i
Definition of complex subtraction
= 6 + 0i
Simplify.
=6
Standard form
c. 6 º (º2 + 9i) + (º8 + 4i) = [(6 + 2) º 9i] + (º8 + 4i)
Subtract.
= (8 º 9i) + (º8 + 4i)
Simplify.
= (8 º 8) + (º9 + 4)i
Add.
= 0 º 5i
Simplify.
= º5i
Standard form
5.4 Complex Numbers
273
Page 3 of 9
To multiply two complex numbers, use the distributive property or the FOIL method
just as you do when multiplying real numbers or algebraic expressions. Other
properties of real numbers that also apply to complex numbers include the associative
and commutative properties of addition and multiplication.
Multiplying Complex Numbers
EXAMPLE 4
Write the expression as a complex number in standard form.
a. 5i(º2 + i)
b. (7 º 4i)(º1 + 2i)
c. (6 + 3i)(6 º 3i)
SOLUTION
a. 5i(º2 + i) = º10i + 5i2
Distributive property
= º10i + 5(º1)
Use i 2 = º1.
= º5 º 10i
Standard form
b. (7 º 4i)(º1 + 2i) = º7 + 14i + 4i º 8i2
Use FOIL.
= º7 + 18i º 8(º1)
Simplify and use i 2 = º1.
= 1 + 18i
Standard form
2
c. (6 + 3i)(6 º 3i) = 36 º 18i + 18i º 9i
Use FOIL.
= 36 º 9(º1)
Simplify and use i 2 = º1.
= 45
Standard form
..........
In part (c) of Example 4, notice that the two factors 6 + 3i and 6 º 3i have the form
a + bi and a º bi. Such numbers are called complex conjugates. The product of
complex conjugates is always a real number. You can use complex conjugates to
write the quotient of two complex numbers in standard form.
Dividing Complex Numbers
EXAMPLE 5
5 + 3i
1 º 2i
Write the quotient ᎏᎏ in standard form.
SOLUTION
The key step here is to multiply the numerator and the denominator by the complex
conjugate of the denominator.
5 + 3i
5 + 3 i 1 + 2i
ᎏᎏ = ᎏᎏ • ᎏᎏ
1 º 2i
1 º 2 i 1 + 2i
5 + 10i + 3i + 6i2
1 + 2i º 2i º 4i
Use FOIL.
º1 + 13i
5
Simplify.
= ᎏᎏ
2
= ᎏᎏ
1
5
13
5
= ºᎏᎏ + ᎏ ᎏ i
274
Multiply by 1 + 2i, the conjugate of 1 º 2i.
Chapter 5 Quadratic Functions
Standard form
Page 4 of 9
FOCUS ON
PEOPLE
GOAL 2
USING COMPLEX NUMBERS IN FRACTAL GEOMETRY
In the hands of a person who understands fractal geometry, the complex plane can
become an easel on which stunning pictures called fractals are drawn. One very
famous fractal is the Mandelbrot set, named after mathematician Benoit Mandelbrot.
The
–iMandelbrot set is the black region in the complex plane below. (The points in
the colored regions are not part of the Mandelbrot set.)
1
–i
RE
FE
L
AL I
BENOIT
MANDELBROT
was born in Poland in 1924,
came to the United States in
1958, and is now a professor
at Yale University. He pioneered the study of fractal
geometry in the 1970s.
–i
–1
1
–i
–2
–1
1
–i
–3
–2
–1
1
–4
–3
–2
–1
–4
–3
–2
–4
–3
1
–1
–i
–2
1
–3
–1
–4
–i
–2
–4
–3
1
To understand how the Mandelbrot set is constructed, you need to know how the
absolute value of a complex number is defined.
–4
–1
A B S O L U T E VA L U E O F A C O M P L E X N U M B E R
–2
–3
The absolute value of a complex number z = a + bi, denoted |z|, is a
nonnegative real number defined as follows:
苶2苶+
苶苶
b2苶
|z| = 兹a
–4
Geometrically, the absolute value of a complex number is the number’s
distance from the origin in the complex plane.
EXAMPLE 6
Finding Absolute Values of Complex Numbers
Find the absolute value of each complex number. Which number is farthest from the
origin in the complex plane?
a. 3 + 4i
b. º2i
c. º1 + 5i
SOLUTION
a. |3 + 4i| = 兹3
苶2苶+
苶苶42苶 = 兹2苶5苶 = 5
b. |º2i| = |0 + (º2i)| = 兹0
苶2苶+
苶苶(º
苶2苶苶
)2 = 2
c. |º1 + 5i| = 兹(º
苶1苶苶
) 2苶
+苶52苶 = 兹2苶6苶 ≈ 5.10
Since º1 + 5i has the greatest absolute value, it is
farthest from the origin in the complex plane.
z ⫽ ⫺1 ⫹ 5i
|z|ⴝ 兹26
z ⫽ ⫺2i
imaginary
z ⫽ 3 ⫹ 4i
3i
|z|ⴝ 5
|z|ⴝ 2
5.4 Complex Numbers
4
real
275
Page 5 of 9
The following result shows how absolute value can be used to tell whether a given
complex number belongs to the Mandelbrot set.
COMPLEX NUMBERS IN THE MANDELBROT SET
To determine whether a complex number c belongs to the Mandelbrot set,
consider the function ƒ(z) = z 2 + c and this infinite list of complex numbers:
z0 = 0, z1 = ƒ(z0), z2 = ƒ(z1), z3 = ƒ(z2), . . .
•
If the absolute values |z0|, |z1|, |z2|, |z3|, . . . are all less than some fixed
number N, then c belongs to the Mandelbrot set.
•
If the absolute values |z0|, |z1|, |z2|, |z3|, . . . become infinitely large,
then c does not belong to the Mandelbrot set.
EXAMPLE 7
Determining if a Complex Number Is in the Mandelbrot Set
Tell whether the complex number c belongs to the Mandelbrot set.
a. c = i
b. c = 1 + i
c. c = º2
SOLUTION
a. Let ƒ(z) = z2 + i.
z0 = 0
|z0| = 0
z1 = ƒ(0) = 02 + i = i
|z1| = 1
z2 = ƒ(i) = i2 + i = º1 + i
|z2| = 兹2苶 ≈ 1.41
z3 = ƒ(º1 + i) = (º1 + i) + i = ºi
|z3| = 1
z4 = ƒ(ºi) = (ºi)2 + i = º1 + i
|z 4| = 兹2苶 ≈ 1.41
2
At this point the absolute values alternate between 1 and 兹2苶, and so all
the absolute values are less than N = 2. Therefore, c = i belongs to the
Mandelbrot set.
b. Let ƒ(z) = z2 + (1 + i).
z0 = 0
|z 0 | = 0
z1 = ƒ(0) = 02 + (1 + i) = 1 + i
|z 1| ≈ 1.41
z2 = ƒ(1 + i) = (1 + i) + (1 + i) = 1 + 3i
|z 2| ≈ 3.16
z3 = ƒ(1 + 3i) = (1 + 3i)2 + (1 + i) = º7 + 7i
|z 3 | ≈ 9.90
2
2
z4 = ƒ(º7 + 7i) = (º7 + 7i) + (1 + i) = 1 º 97i
|z 4 | ≈ 97.0
The next few absolute values in the list are (approximately) 9409, 8.85 ª 107,
and 7.84 ª 1015. Since the absolute values are becoming infinitely large,
c = 1 + i does not belong to the Mandelbrot set.
c. Let ƒ(z) = z 2 + (º2), or ƒ(z) = z 2 º 2. You can show that z0 = 0, z1 = º2, and
zn = 2 for n > 1. Therefore, the absolute values of z0, z1, z2, z3, . . . are all less
than N = 3, and so c = º2 belongs to the Mandelbrot set.
276
Chapter 5 Quadratic Functions
Page 6 of 9
GUIDED PRACTICE
Vocabulary Check
Concept Check
Skill Check
✓
? and
1. Complete this statement: For the complex number 3 º 7i, the real part is 㛭㛭㛭
✓
2. ERROR ANALYSIS A student thinks that the complex conjugate of º5 + 2i
✓
? .
the imaginary part is 㛭㛭㛭
is 5 º 2i. Explain the student’s mistake, and give the correct complex conjugate
of º5 + 2i.
3. Geometrically, what does the absolute value of a complex number represent?
Solve the equation.
4. x2 = º9
5. 2x2 + 3 = º13
6. (x º 1)2 = º7
Write the expression as a complex number in standard form.
7. (1 + 5i) + (6 º 2i)
8. (4 + 3i) º (º2 + 4i)
3 º 4i
10. ᎏᎏ
1+i
9. (1 º i)(7 + 2i)
Find the absolute value of the complex number.
11. 1 + i
12. 3i
13. º2 + 3i
14. 5 º 5i
15. Plot the numbers in Exercises 11–14 in the same complex plane.
16. FRACTAL GEOMETRY Tell whether c = 1 º i belongs to the Mandelbrot set.
Use absolute value to justify your answer.
PRACTICE AND APPLICATIONS
STUDENT HELP
SOLVING QUADRATIC EQUATIONS Solve the equation.
Extra Practice
to help you master
skills is on p. 946.
17. x2 = º4
18. x2 = º11
19. 3x2 = º81
20. 2x2 + 9 = º41
21. 5x2 + 18 = 3
22. ºx2 º 4 = 14
23. 8r 2 + 7 = 5r 2 + 4
24. 3s2 º 1 = 7s2
25. (t º 2)2 = º16
26. º6(u + 5)2 = 120
1
27. ºᎏᎏ(v + 3)2 = 7
8
28. 9(w º 4)2 + 1 = 0
PLOTTING COMPLEX NUMBERS Plot the numbers in the same complex plane.
29. 4 + 2i
30. º1 + i
31. º4i
32. 3
33. º2 º i
34. 1 + 5i
35. 6 º 3i
36. º5 + 4i
STUDENT HELP
ADDING AND SUBTRACTING Write the expression as a complex number in
HOMEWORK HELP
standard form.
Example 1:
Example 2:
Example 3:
Example 4:
Example 5:
Example 6:
Example 7:
Exs. 17–28
Exs. 29–36
Exs. 37–46
Exs. 47–55
Exs. 56–63
Exs. 64–71
Exs. 72–79
37. (2 + 3i) + (7 + i)
38. (6 + 2i) + (5 º i)
39. (º4 + 7i) + (º4 º 7i)
40. (º1 º i) + (9 º 3i)
41. (8 + 5i) º (1 + 2i)
42. (2 º 6i) º (º10 + 4i)
43. (º0.4 + 0.9i) º (º0.6 + i)
44. (25 + 15i) º (25 º 6i)
45. ºi + (8 º 2i) º (5 º 9i)
46. (30 º i) º (18 + 6i) + 30i
5.4 Complex Numbers
277
Page 7 of 9
MULTIPLYING Write the expression as a complex number in standard form.
47. i(3 + i)
48. 4i(6 º i)
49. º10i(4 + 7i)
50. (5 + i)(8 + i)
51. (º1 + 2i)(11 º i)
52. (2 º 9i)(9 º 6i)
53. (7 + 5i)(7 º 5i)
54. (3 + 10i)2
55. (15 º 8i)2
DIVIDING Write the expression as a complex number in standard form.
8
56. ᎏᎏ
1+i
2i
57. ᎏᎏ
1ºi
º5 º 3i
58. ᎏᎏ
4i
3+i
59. ᎏᎏ
3ºi
2 + 5i
60. ᎏᎏ
5 + 2i
º7 + 6 i
61. ᎏᎏ
9 º 4i
兹1苶0苶
62. ᎏ
兹1苶0苶 º i
6 º i兹2苶
63. ᎏ
6 + i兹2苶
ABSOLUTE VALUE Find the absolute value of the complex number.
64. 3 º 4i
65. 5 + 12i
66. º2 º i
67. º7 + i
68. 2 + 5i
69. 4 º 8i
70. º9 + 6i
71. 兹1
苶1苶 + i兹5苶
MANDELBROT SET Tell whether the complex number c belongs to the
Mandelbrot set. Use absolute value to justify your answer.
STUDENT HELP
Skills Review
For help with
disproving statements
by counterexample,
see p. 927.
72. c = 1
73. c = º1
74. c = ºi
75. c = º1 º i
76. c = 2
77. c = º1 + i
78. c = º0.5
79. c = 0.5i
LOGICAL REASONING In Exercises 80–85, tell whether the statement is true
or false. If the statement is false, give a counterexample.
80. Every complex number is an imaginary number.
81. Every irrational number is a complex number.
82. All real numbers lie on a single line in the complex plane.
83. The sum of two imaginary numbers is always an imaginary number.
84. Every real number equals its complex conjugate.
85. The absolute values of a complex number and its complex conjugate are
always equal.
86. VISUAL THINKING The graph shows how
imaginary
you can geometrically add two complex
numbers (in this case, 3 + 2i and 1 + 4i) to
find their sum (in this case, 4 + 6i). Find each
of the following sums by drawing a graph.
a. (2 + i) + (3 + 5i)
4 ⫹ 6i
4i
1
i
b. (º1 + 6i) + (7 º 4i)
2i
3
4
real
COMPARING REAL AND COMPLEX NUMBERS Tell whether the property is
true for (a) the set of real numbers and (b) the set of complex numbers.
87. If r, s, and t are numbers in the set, then (r + s) + t = r + (s + t).
88. If r is a number in the set and |r| = k, then r = k or r = ºk.
89. If r and s are numbers in the set, then r º s = s º r.
90. If r, s, and t are numbers in the set, then r(s + t) = rs + rt.
91. If r and s are numbers in the set, then |r + s| = |r| + |s|.
278
Chapter 5 Quadratic Functions
Page 8 of 9
FOCUS ON
CAREERS
92. CRITICAL THINKING Evaluate 兹º
苶4苶 • 兹º
苶9苶 and 兹3苶6苶. Does the rule
兹a苶 • 兹b苶 = 兹a苶b苶 on page 264 hold when a and b are negative numbers?
93.
Writing Give both an algebraic argument and a geometric argument
explaining why the definitions of absolute value on pages 50 and 275 are
consistent when applied to real numbers.
94. EXTENSION: ADDITIVE AND MULTIPLICATIVE INVERSES The additive
inverse of a complex number z is a complex number za such that z + za = 0.
The multiplicative inverse of z is a complex number zm such that z • zm = 1.
Find the additive and multiplicative inverses of each complex number.
a. z = 1 + i
b. z = 3 º i
c. z = º2 + 8i
ELECTRICITY In Exercises 95 and 96, use the following information.
RE
FE
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AL I
ELECTRICIAN
INT
An electrician
installs, maintains, and
repairs electrical systems.
This often involves working
with the types of circuits
described in Exs. 95 and 96.
NE
ER T
CAREER LINK
www.mcdougallittell.com
Electrical circuits may contain several types
of components such as resistors, inductors,
and capacitors. The resistance of each
component to the flow of electrical current is
the component’s impedance, denoted by Z.
The value of Z is a real number R for a resistor
of R ohms (⍀), a pure imaginary number Li
for an inductor of L ohms, and a pure
imaginary number ºCi for a capacitor of
C ohms. Examples are given in the table.
95.
b.
2⍀
INT
Visit our Web site
www.mcdougallittell.com
for help with problem
solving in Exs. 95 and 96.
Resistor
3⍀
3
Inductor
5⍀
5i
Capacitor
6⍀
º6i
c.
2⍀ 8⍀
8⍀
6⍀
15 ⍀
7⍀
HOMEWORK HELP
Z
12 ⍀
5⍀
NE
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Symbol
SERIES CIRCUITS A series circuit is a type of circuit found in switches,
fuses, and circuit breakers. In a series circuit, there is only one pathway through
which current can flow. To find the total impedance of a series circuit, add the
impedances of the components in the circuit. What is the impedance of each
series circuit shown below? (Note: The symbol
denotes an alternating current
source and does not affect the calculation of impedance.)
a.
STUDENT HELP
Component
4⍀
PARALLEL CIRCUITS Parallel circuits are used in household lighting and
96.
appliances. In a parallel circuit, there is more than one pathway through which
current can flow. To find the impedance Z of a parallel circuit with two pathways,
first calculate the impedances Z1 and Z2 of the pathways separately by treating
each pathway as a series circuit. Then apply this formula:
Z 1Z 2
Z1 + Z2
Z=ᎏ
What is the impedance of each parallel circuit shown below?
a.
3⍀
Z1
4⍀
b.
6⍀
2⍀
5⍀
Z2
Z1
3⍀
c.
8⍀
9⍀
4⍀
Z2
5⍀
Z1
2⍀
7⍀
5.4 Complex Numbers
Z2
279
Page 9 of 9
Test
Preparation
★ Challenge
QUANTITATIVE COMPARISON In Exercises 97–99, choose the statement that
is true about the given quantities.
A
¡
B
¡
C
¡
D
¡
The quantity in column A is greater.
The quantity in column B is greater.
The two quantities are equal.
The relationship cannot be determined from the given information.
Column A
Column B
97.
|5 + 4i|
|3 º 6i|
98.
|º6 + 8i|
|º10i|
99.
|2 + bi| where b < º1
|兹3苶 + ci| where 0 < c < 1
100. POWERS OF i In this exercise you will investigate a pattern that appears when
the imaginary unit i is raised to successively higher powers.
a. Copy and complete the table.
Power of i
i1
i2
i3
i4
i5
i6
i7
i8
Simplified form
i
º1
ºi
?
?
?
?
?
b. Writing Describe the pattern you observe in the table. Verify that the
pattern continues by evaluating the next four powers of i.
EXTRA CHALLENGE
www.mcdougallittell.com
c. Use the pattern you described in part (b) to evaluate i 26 and i 83.
MIXED REVIEW
EVALUATING FUNCTIONS Evaluate ƒ(x) for the given value of x. (Review 2.1)
101. ƒ(x) = 4x º 1 when x = 3
102. ƒ(x) = x2 º 5x + 8 when x = º4
103. ƒ(x) = |ºx + 6| when x = 9
104. ƒ(x) = 2 when x = º30
SOLVING SYSTEMS Use an inverse matrix to solve the system. (Review 4.5)
105. 3x + y = 5
106. x + y = 2
5x + 2y = 9
107. x º 2y = 10
7x + 8y = 21
3x + 4y = 0
SOLVING QUADRATIC EQUATIONS Solve the equation. (Review 5.3 for 5.5)
108. (x + 4)2 = 1
109. (x + 2)2 = 36
110. (x º 11)2 = 25
111. º(x º 5)2 = º10
112. 2(x + 7)2 = 24
113. 3(x º 6)2 º 8 = 13
CONNECTION The table shows the cumulative number N
(in thousands) of DVD players sold in the United States from the end of
February, 1997, to time t (in months). Make a scatter plot of the data.
Approximate the equation of the best-fitting line. (Review 2.5)
INT
114. STATISTICS
280
t
1
2
3
4
5
6
7
N
34
69
96
125
144
178
213
NE
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8
9
10
11
12
269 307 347
383
416
DATA UPDATE of DVD Insider data at www.mcdougallittell.com
Chapter 5 Quadratic Functions
Page 1 of 8
5.5
Completing the Square
What you should learn
GOAL 1 Solve quadratic
equations by completing the
square.
GOAL 2 Use completing the
square to write quadratic
functions in vertex form, as
applied in Example 7.
GOAL 1
SOLVING QUADRATIC EQUATIONS BY
COMPLETING THE SQUARE
Completing the square is a process that allows you to write an expression of the
form x2 + bx as the square of a binomial. This process can be illustrated using an
area model, as shown below.
b
x
x2
x
Why you should learn it
bx
FE
䉲 To solve real-life
problems, such as finding
where to position a fire
hose in Ex. 91.
AL LI
RE
b
2
x
x
x2
( )x
b
2
( )x
()
b
2
b
2
b 2
2
冉 b2 冊
2
You can see that to complete the square for x2 + bx, you need to add ᎏᎏ , the area
of the incomplete corner of the square in the second diagram. This diagram models
the following rule:
冉 b2 冊 = 冉x + ᎏb2ᎏ冊
x2 + bx + ᎏᎏ
2
2
Completing the Square
EXAMPLE 1
Find the value of c that makes x2 º 7x + c a perfect square trinomial. Then write the
expression as the square of a binomial.
SOLUTION
In the expression x2 º 7x + c, note that b = º7. Therefore:
冉 b2 冊 = 冉ᎏº2ᎏ7 冊 = ᎏ449ᎏ
c = ᎏᎏ
2
2
Use this value of c to write x2 º 7x + c as a perfect square trinomial, and then as the
square of a binomial.
49
4
x2 º 7x + c = x2 º 7x + ᎏᎏ
冉
冊
7 2
2
= x º ᎏᎏ
Perfect square trinomial
冉 冊
b
Square of a binomial: x + }}
2
2
..........
In Lesson 5.2 you learned how to solve quadratic equations by factoring. However,
many quadratic equations, such as x2 + 10x º 3 = 0, contain expressions that cannot
be factored. Completing the square is a method that lets you solve any quadratic
equation, as the next example illustrates.
282
Chapter 5 Quadratic Functions
Page 2 of 8
EXAMPLE 2
Solving a Quadratic Equation if the Coefficient of x 2 Is 1
Solve x2 + 10x º 3 = 0 by completing the square.
SOLUTION
x2 + 10x º 3 = 0
STUDENT HELP
x2 + 10x = 3
Study Tip
In Example 2 note that
you must add 25 to both
sides of the equation
x 2 + 10x = 3 when
completing the square.
x2 + 10x + 52 = 3 + 25
(x + 5)2 = 28
x + 5 = ±兹2苶8苶
䉴
Write original equation.
Write the left side in the form x 2 + bx.
冉冊
2
10
Add }}
2
2
= 5 = 25 to each side.
Write the left side as a binomial squared.
Take square roots of each side.
x = º5 ± 兹2苶8苶
Solve for x.
x = º5 ± 2兹7苶
Simplify.
The solutions are º5 + 2兹7苶 and º5 º 2兹7苶.
✓CHECK
You can check the solutions by
substituting them back into the original
equation. Alternatively, you can graph
y = x2 + 10x º 3 and observe that the
x-intercepts are about 0.29 ≈ º5 + 2兹7苶
and º10.29 ≈ º5 º 2兹7苶.
..........
Zero
X=-10.2915
Y=0
If the coefficient of x2 in a quadratic equation is not 1, you should divide each side of
the equation by this coefficient before completing the square.
EXAMPLE 3
Solving a Quadratic Equation if the Coefficient of x 2 Is Not 1
Solve 3x2 º 6x + 12 = 0 by completing the square.
SOLUTION
3x2 º 6x + 12 = 0
2
x º 2x + 4 = 0
x2 º 2x = º4
x2 º 2x + (º1) 2 = º4 + 1
(x º 1)2 = º3
x º 1 = ±兹º
苶3苶
䉴
Write original equation.
Divide each side by the coefficient of x 2.
Write the left side in the form x 2 + bx.
冉 冊
º2
Add }}
2
2
= (º1)2 = 1 to each side.
Write the left side as a binomial squared.
Take square roots of each side.
x = 1 ± 兹º
苶3苶
Solve for x.
x = 1 ± i 兹3苶
Write in terms of the imaginary unit i.
The solutions are 1 + i兹3苶 and 1 º i兹3苶.
✓CHECK
Because the solutions are imaginary, you cannot check them graphically.
However, you can check the solutions algebraically by substituting them back into
the original equation.
5.5 Completing the Square
283
Page 3 of 8
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Traffic Engineering
Using a Quadratic Equation to Model Distance
EXAMPLE 4
On dry asphalt the distance d (in feet) needed for a car to stop is given by
d = 0.05s2 + 1.1s
where s is the car’s speed (in miles per hour). What speed limit should be posted on a
road where drivers round a corner and have 80 feet to come to a stop?
SOLUTION
d = 0.05s2 + 1.1s
2
80 = 0.05s + 1.1s
1600 = s2 + 22s
1600 + 121 = s2 + 22s + 112
1721 = (s + 11)2
±兹1苶7苶2苶1苶 = s + 11
º11 ± 兹1苶7苶2苶1苶 = s
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Landscape Design
Substitute 80 for d.
Divide each side by the coefficient of s 2.
冉冊
22
Add }}
2
2
= 112 = 121 to each side.
Write the right side as a binomial squared.
Take square roots of each side.
Solve for s.
s ≈ 30 or s ≈ º52
䉴
Write original equation.
Use a calculator.
Reject the solution º52 because a car’s speed cannot be negative. The posted
speed limit should be at most 30 miles per hour.
Using a Quadratic Equation to Model Area
EXAMPLE 5
You want to plant a rectangular garden along part of a 40 foot side of your house. To
keep out animals, you will enclose the garden with wire mesh along its three open
sides. You will also cover the garden with mulch. If you have 50 feet of mesh and
enough mulch to cover 100 square feet, what should the garden’s dimensions be?
SOLUTION
Draw a diagram. Let x be the length of the sides of the garden perpendicular to the
house. Then 50 º 2x is the length of the third fenced side of the garden.
x(50 º 2x) = 100
x
50 – 2x
x
house
50x º 2x2 = 100
garden
2
º2x + 50x = 100
x2 º 25x = º50
40 ft
x2 º 25x + (º12.5)2 = º50 + 156.25
2
(x º 12.5) = 106.25
x º 12.5 = ±兹1苶0苶6苶.2
苶5苶
䉴
284
Length ª Width = Area
Distributive property
Write the x 2-term first.
Divide each side by º2.
Complete the square.
Write as a binomial squared.
Take square roots of each side.
x = 12.5 ± 兹1苶0苶6苶.2
苶5苶
Solve for x.
x ≈ 22.8 or x ≈ 2.2
Use a calculator.
Reject x = 2.2 since 50 º 2x = 45.6 is greater than the house’s length. If
x = 22.8, then 50 º 2x = 4.4. The garden should be about 22.8 feet by 4.4 feet.
Chapter 5 Quadratic Functions
Page 4 of 8
GOAL 2
WRITING QUADRATIC FUNCTIONS IN VERTEX FORM
Given a quadratic function in standard form, y = ax2 + bx + c, you can use
completing the square to write the function in vertex form, y = a(x º h)2 + k.
Writing a Quadratic Function in Vertex Form
EXAMPLE 6
INT
STUDENT HELP
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HOMEWORK HELP
Visit our Web site
www.mcdougallittell.com
for extra examples.
Write the quadratic function y = x2 º 8x + 11 in vertex form. What is the vertex of
the function’s graph?
SOLUTION
y = x2 º 8x + 11
2
? = (x º 8x + 㛭㛭㛭
? ) + 11
y + 㛭㛭㛭
Prepare to complete the square for x 2 º 8x.
y + 16 = (x2 º 8x + 16) + 11
Add }
y + 16 = (x º 4)2 + 11
Write x 2 º 8x + 16 as a binomial squared.
y = (x º 4)2 º 5
䉴
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Agriculture
Write original function.
冉º82 冊 = (º4) = 16 to each side.
2
2
Solve for y.
The vertex form of the function is y = (x º 4)2 º 5. The vertex is (4, º5).
EXAMPLE 7
Finding the Maximum Value of a Quadratic Function
The amount s (in pounds per acre) of sugar produced from sugarbeets can be
modeled by the function
s = º0.0655n2 + 7.855n + 5562
where n is the amount (in pounds per acre) of nitrogen fertilizer used. How much
fertilizer should you use to maximize sugar production? What is the maximum
amount of sugar you can produce?
䉴 Source: Sugarbeet Research and Education Board of Minnesota and North Dakota
SOLUTION
The optimal amount of fertilizer and the maximum amount of sugar are the
coordinates of the vertex of the function’s graph. One way to find the vertex is
to write the function in vertex form.
s = º0.0655n2 + 7.855n + 5562
s = º0.0655(n2 º 120n) + 5562
? ) = º0.0655(n2 º 120n + 㛭㛭㛭
? ) + 5562
s º 0.0655( 㛭㛭㛭
s º 0.0655(3600) = º0.0655(n2 º 120n + 3600) + 5562
s º 236 = º0.0655(n º 60)2 + 5562
s = º0.0655(n º 60)2 + 5798
䉴
The vertex is approximately (60, 5798). To maximize sugar production, you
should use about 60 pounds per acre of nitrogen fertilizer. The maximum amount
of sugar you can produce is about 5800 pounds per acre.
5.5 Completing the Square
285
Page 5 of 8
GUIDED PRACTICE
Vocabulary Check
✓
1. Describe what it means to “complete the square” for an expression of the form
Concept Check
✓
2. Which method for solving quadratic
x2 + bx.
equations—factoring or completing the
square—is more general? Explain.
3. ERROR ANALYSIS A student tried to write
Skill Check
✓
y = ºx2 º 6x + 4 in vertex form as shown.
Explain the student’s mistake. Then write the
correct vertex form of the function.
y=
y=
y + 9=
y + 9=
y=
ºx 2 º 6x + 4
º(x 2 + 6x) + 4
º(x 2 + 6x + 9) + 4
º(x + 3) 2 + 4
º(x + 3) 2 º 5
Find the value of c that makes the expression a perfect square trinomial. Then
write the expression as the square of a binomial.
4. x2 + 2x + c
5. x2 + 14x + c
6. x2 º 6x + c
7. x2 º 10x + c
8. x2 + 5x + c
9. x2 º 13x + c
Solve the equation by completing the square.
10. x2 + 4x = º1
11. x2 º 2x = 4
12. x2 º 16x + 76 = 0
13. x2 + 8x + 9 = 0
14. 2x2 + 12x = 4
15. 3x2 º 12x + 93 = 0
Write the quadratic function in vertex form and identify the vertex.
16. y = x2 + 12x
17. y = x2 º 4x + 7
18. y = x2 º 8x + 31
19. y = x2 + 10x + 17
20. y = ºx2 + 14x º 45
21. y = 2x2 + 4x º 4
22.
LANDSCAPE DESIGN Suppose the homeowner in Example 5 has 60 feet
of wire mesh to put around the garden and enough mulch to cover an area of
140 square feet. What should the dimensions of the garden be?
PRACTICE AND APPLICATIONS
STUDENT HELP
REWRITING EXPRESSIONS Write the expression as the square of a binomial.
Extra Practice
to help you master
skills is on p. 946.
23. x2 + 16x + 64
24. x2 + 20x + 100
25. x2 º 24x + 144
26. x2 º 38x + 361
27. x2 + x + 0.25
28. x2 º 1.4x + 0.49
9
29. x2 º 3x + ᎏᎏ
4
1
1
30. x2 + ᎏᎏx + ᎏᎏ
6
144
4
4
31. x2 º ᎏᎏx + ᎏᎏ
9
81
COMPLETING THE SQUARE Find the value of c that makes the expression a
perfect square trinomial. Then write the expression as the square of a binomial.
286
32. x2 º 12x + c
33. x2 + 18x + c
34. x2 + 26x + c
35. x2 º 44x + c
36. x2 + 9x + c
37. x2 º 11x + c
38. x2 º 23x + c
39. x2 + 15x + c
40. x2 º 0.2x + c
41. x2 º 5.8x + c
42. x2 + 1.6x + c
43. x2 + 9.4x + c
2
44. x2 º ᎏᎏx + c
7
10
45. x2 + ᎏᎏx + c
3
17
46. x2 + ᎏᎏx + c
8
Chapter 5 Quadratic Functions
Page 6 of 8
COEFFICIENT OF X 2 IS 1 Solve the equation by completing the square.
STUDENT HELP
HOMEWORK HELP
Example 1: Exs. 23–46
Example 2: Exs. 47–54,
63–64
Example 3: Exs. 55–72
Example 4: Exs. 89–91
Example 5: Exs. 92, 93
Example 6: Exs. 73–84
Example 7: Exs. 94, 95
47. x2 + 2x = 9
48. x2 º 12x = º28
49. x2 + 20x + 104 = 0
50. x2 + 3x º 1 = 0
51. u2 º 4u = 2u + 35
52. v2 º 17v + 200 = 13v º 43
53. m2 + 1.8m º 1.5 = 0
4
14
54. n2 º ᎏᎏn º ᎏᎏ = 0
3
9
COEFFICIENT OF X 2 IS NOT 1 Solve the equation by completing the square.
55. 2x2 º 12x = º14
56. º3x2 + 24x = 27
57. 6x2 + 84x + 300 = 0
58. 4x2 + 40x + 280 = 0
59. º4r 2 + 21r = r + 13
60. 3s2 º 26s + 2 = 5s2 + 1
61. 0.4t2 + 0.7t = 0.3t º 0.2
w2
w
13
62. ᎏᎏ º ᎏᎏ + ᎏᎏ = 0
24
2
6
SOLVING BY ANY METHOD Solve the equation by factoring, by finding
square roots, or by completing the square.
63. x2 + 4x º 12 = 0
64. x2 º 6x º 15 = 0
65. 9x2 º 23 = 0
66. 2x2 + 9x + 7 = 0
67. 3x2 + x = 2 x º 6
68. 4(x + 8)2 = 144
69. 7k2 + 10k º 100 = 2k2 + 55
70. 14b2 º 19b + 4 = º11b2 + 11b º 5
71. 0.01p2 º 0.22p + 2.9 = 0
q2
9 q2
72. ᎏᎏ º ᎏᎏ = 18
4
20
WRITING IN VERTEX FORM Write the quadratic function in vertex form and
identify the vertex.
73. y = x2 º 6x + 11
74. y = x2 º 2x º 9
75. y = x2 + 16x + 14
76. y = x2 + 26x + 68
77. y = x2 º 3x º 2
78. y = x2 + 7x º 1
79. y = ºx2 + 20x º 80
80. y = ºx2 º 14x º 47
81. y = 3x2 º 12x + 1
82. y = º2x2 º 2x º 7
83. y = 1.4x2 + 5.6x + 3
2
4
84. y = ᎏᎏx2 º ᎏᎏx
3
5
CONNECTION
Find the value of x.
STUDENT HELP
GEOMETRY
Skills Review
For help with areas of
geometric figures,
see p. 914.
85. Area of rectangle = 100
86. Area of triangle = 40
x
x
xⴙ8
x ⴙ 10
87. Area of trapezoid = 70
88. Area of parallelogram = 54
x
x⫺5
xⴙ4
3x
x
5.5 Completing the Square
287
Page 7 of 8
FOCUS ON
PEOPLE
89.
TRAFFIC ENGINEERING For a road covered with dry, packed snow, the
formula for a car’s stopping distance given in Example 4 becomes:
d = 0.08s2 + 1.1s
Show that, in snowy conditions, a driver cannot safely round the corner in
Example 4 when traveling at the calculated speed limit of 30 miles per hour.
What is a safe speed limit if the road is covered with snow?
90.
SPORTS Jackie Joyner-Kersee won the women’s heptathlon during the 1992
Olympics in Barcelona, Spain. Her throw in the shot put, one of the seven events
in the heptathlon, can be modeled by
y = º0.0241x2 + x + 5.5
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where x is the shot put’s horizontal distance traveled (in feet) and y is its
corresponding height (in feet). How long was Joyner-Kersee’s throw?
JACKIE JOYNERKERSEE became
one of the greatest female
athletes in history despite
having severe asthma as a
child and as an adult. She
has won six Olympic medals:
three gold, one silver, and
two bronze.
91.
FIREFIGHTING In firefighting, a good water stream can be modeled by
y = º0.003x2 + 0.62x + 3
where x is the water’s horizontal distance traveled (in feet) and y is its
corresponding height (in feet). If a firefighter is aiming a good water stream at
a building’s window 25 feet above the ground, at what two distances can the
firefighter stand from the building?
92.
CORRALS You have 240 feet of
wooden fencing to form two adjacent
rectangular corrals as shown. You
want each corral to have an
area of 1000 square feet.
4
a. Show that w = 80 º ᎏᎏ ¬.
3
w
L
L
Not drawn to scale
b. Use your answer from part (a) to find the possible dimensions of each corral.
93.
POTTERY You are taking a pottery class. As an assignment, you are given
a lump of clay whose volume is 200 cubic centimeters and asked to make a
cylindrical pencil holder. The pencil holder should be 9 centimeters high and
have an inner radius of 3 centimeters. What thickness x should your pencil holder
have if you want to use all the clay? (Hint: The volume of clay equals the
difference of the volumes of two cylinders.)
3 cm
Not drawn to scale
3 cm
x cm
x cm
9 cm
x cm
Pencil holder
94. BIOLOGY
CONNECTION
Top view
x cm
Side view
When a gray kangaroo jumps, its path through the air
can be modeled by
y = º0.0267x2 + 0.8x
where x is the kangaroo’s horizontal distance traveled (in feet) and y is its
corresponding height (in feet). How high can a gray kangaroo jump? How
far can it jump?
288
Chapter 5 Quadratic Functions
Page 8 of 8
In a fireplace, the heat loss q (in Btu/ft3) resulting from
hot gases escaping through the chimney can be modeled by
95. SCIENCE
CONNECTION
q = º0.00002T 2 + 0.0203T º 1.24
where T is the temperature (in degrees Fahrenheit) of the gases. (This model
assumes an indoor temperature of 65°F.) For what gas temperature is heat loss
maximized? What is the maximum heat loss? 䉴 Source: Workshop Math
Test
Preparation
96. MULTIPLE CHOICE If x 2 º 28x + c is a perfect square trinomial, what is the
value of c?
A
¡
B
¡
º14
C
¡
28
D
¡
196
784
97. MULTIPLE CHOICE What are the solutions of x 2 + 12x + 61 = 0?
A
¡
B
¡
º1, º11
C
¡
º6 ± 5i
D
¡
º6 ± 兹9苶7苶
º6 ± i兹6苶1苶
98. MULTIPLE CHOICE What is the vertex form of y = 2x 2 º 8x + 3?
★ Challenge
A
¡
C
¡
B
¡
D
¡
y = 2(x º 2)2 º 5
y = 2(x º 4)2 º 29
y = 2(x º 2)2 + 3
y = 2(x º 4)2 + 3
CRITICAL THINKING Exercises 99 and 100 should be done together.
99. Graph the two functions in the same coordinate plane.
EXTRA CHALLENGE
www.mcdougallittell.com
a. y = x 2 + 2x
b. y = x2 + 4x
y = (x + 1)
y = (x + 2)
2
c. y = x2 º 6x
2
冉
冊
y = (x º 3)2
b 2
100. Compare the graphs of y = x2 + bx and y = x + ᎏᎏ . What happens to the
2
graph of y = x2 + bx when you complete the square for x2 + bx?
MIXED REVIEW
EVALUATING EXPRESSIONS Evaluate b 2 º 4ac for the given values of a, b,
and c. (Review 1.2 for 5.6)
101. a = 1, b = 5, c = 2
102. a = 3, b = º8, c = 7
103. a = º5, b = 0, c = 2.6
104. a = 11, b = 4, c = º1
105. a = 16, b = º24, c = 9
106. a = º1.4, b = 2, c = º0.5
EQUATIONS OF LINES Write an equation in slope-intercept form of the line
through the given point and having the given slope. (Review 2.4)
107. (3, 1), m = 2
108. (2, º4), m = 1
109. (º7, 10), m = º5
110. (º8, º8), m = º3
1
111. (6, 9), m = ᎏᎏ
3
5
112. (11, º2), m = ºᎏᎏ
4
SYSTEMS OF LINEAR INEQUALITIES Graph the system of inequalities.
(Review 3.3)
113. x ≥ 2
y≤3
116. y < x º 2
x º 3y ≤ 6
114. y > º1
y<2
117. 3x º 2y < 8
2x + y > 0
115. x ≥ 0
x+y<4
118. y ≤ 2x + 3
y ≥ 2x º 3
5.5 Completing the Square
289
Page 1 of 8
5.6
The Quadratic Formula and the
Discriminant
What you should learn
GOAL 1 Solve quadratic
equations using the quadratic
formula.
GOAL 2 Use the quadratic
formula in real-life situations,
such as baton twirling in
Example 5.
GOAL 1
In Lesson 5.5 you solved quadratic equations by completing the square for
each equation separately. By completing the square once for the general equation
ax 2 + bx + c = 0, you can develop a formula that gives the solutions of any
quadratic equation. The formula for the solutions is called the quadratic formula.
A derivation of the quadratic formula appears on page 895.
T H E Q UA D R AT I C F O R M U L A
Why you should learn it
Let a, b, and c be real numbers such that a ≠ 0. The solutions of the
quadratic equation ax 2 + bx + c = 0 are:
䉲 To solve real-life
problems, such as finding the
speed and duration of a thrill
ride in Ex. 84.
AL LI
ºb ± 兹b
苶2苶º
苶苶4a苶c苶
2a
x = ᎏᎏᎏ
FE
RE
SOLVING EQUATIONS WITH THE QUADRATIC FORMULA
Remember that before you apply the quadratic formula to a quadratic equation, you
must write the equation in standard form, ax 2 + bx + c = 0.
EXAMPLE 1
Solving a Quadratic Equation with Two Real Solutions
Solve 2x 2 + x = 5.
SOLUTION
2x 2 + x = 5
Write original equation.
2x 2 + x º 5 = 0
Write in standard form.
苶苶4a苶c苶
ºb ± 兹b苶2苶º
x = ᎏᎏᎏ
2a
苶苶4(2
苶)(
苶º
苶5苶)苶
º1 ± 兹1苶2苶º
2(2)
a = 2, b = 1, c = º5
º1 ± 兹4苶1苶
4
Simplify.
x = ᎏᎏᎏ
x = ᎏᎏ
䉴
Quadratic formula
The solutions are
º1 + 兹4苶1苶
4
x = ᎏᎏ ≈ 1.35
and
º1 º 兹4苶1苶
4
x = ᎏᎏ ≈ º1.85.
✓CHECK
2
Graph y = 2x + x º 5 and note that
the x-intercepts are about 1.35 and about º1.85.
Zero
X=1.3507811 Y=0
5.6 The Quadratic Formula and the Discriminant
291
Page 2 of 8
Solving a Quadratic Equation with One Real Solution
EXAMPLE 2
Solve x 2 º x = 5x º 9.
SOLUTION
x 2 º x = 5x º 9
Write original equation.
x 2 º 6x + 9 = 0
a = 1, b = º6, c = 9
6 ± 兹(º
苶6苶苶
)苶
º苶4(1
苶)(
苶9苶)苶
2(1)
Quadratic formula
x=ᎏ
6 ± 兹0苶
2
Simplify.
x=3
Simplify.
2
x = ᎏᎏᎏ
䉴
The solution is 3.
✓CHECK
Graph y = x 2 º 6x + 9 and note that the
only x-intercept is 3. Alternatively, substitute 3 for
x in the original equation.
32 º 3 · 5(3) º 9
Zero
X=3
9 º 3 · 15 º 9
Y=0
6=6✓
Solving a Quadratic Equation with Two Imaginary Solutions
EXAMPLE 3
INT
STUDENT HELP
NE
ER T
HOMEWORK HELP
Visit our Web site
www.mcdougallittell.com
for extra examples.
Solve ºx 2 + 2x = 2.
SOLUTION
ºx 2 + 2x = 2
Write original equation.
ºx 2 + 2x º 2 = 0
a = º1, b = 2, c = º2
º2 ± 兹2苶苶º
苶苶4(º
苶1苶)(
苶º
苶2苶)苶
2
x = ᎏᎏᎏ
2(º1)
º2 ± 兹º
苶4苶
º2
Simplify.
x = ᎏᎏ
º2 ± 2i
º2
Write using the imaginary unit i.
x=1±i
Simplify.
x = ᎏᎏ
䉴
Quadratic formula
The solutions are 1 + i and 1 º i.
✓CHECK
Graph y = ºx 2 + 2x º 2 and note that
there are no x-intercepts. So, the original equation
has no real solutions. To check the imaginary
solutions 1 + i and 1 º i, substitute them into the
original equation. The check for 1 + i is shown.
º(1 + i)2 + 2(1 + i) · 2
º2i + 2 + 2i · 2
2=2✓
292
Chapter 5 Quadratic Functions
Page 3 of 8
In the quadratic formula, the expression b2 º 4ac under the radical sign is called the
discriminant of the associated equation ax 2 + bx + c = 0.
ºb ± 兹b苶2苶º
苶苶4a苶c苶
2a
x = ᎏᎏ
discriminant
You can use the discriminant of a quadratic equation to determine the equation’s
number and type of solutions.
NUMBER AND TYPE OF SOLUTIONS OF A QUADRATIC EQUATION
Consider the quadratic equation ax 2 + bx + c = 0.
•
•
•
If b2 º 4ac > 0, then the equation has two real solutions.
If b2 º 4ac = 0, then the equation has one real solution.
If b2 º 4ac < 0, then the equation has two imaginary solutions.
EXAMPLE 4
Using the Discriminant
Find the discriminant of the quadratic equation and give the number and type of
solutions of the equation.
a. x 2 º 6x + 10 = 0
b. x 2 º 6x + 9 = 0
c. x 2 º 6x + 8 = 0
SOLUTION
EQUATION
DISCRIMINANT
SOLUTION(S)
ax 2 + bx + c = 0
b 2 º 4ac
x = ᎏᎏ
2a
(º6)2 º 4(1)(10) = º4
Two imaginary: 3 ± i
a. x 2 º 6x + 10 = 0
2
ºb ± 兹b苶苶2 º
苶苶4a苶c苶
2
b. x º 6x + 9 = 0
(º6) º 4(1)(9) = 0
One real: 3
c. x 2 º 6x + 8 = 0
(º6)2 º 4(1)(8) = 4
Two real: 2, 4
..........
In Example 4 notice that the number of real
solutions of x 2 º 6x + c = 0 can be changed just
by changing the value of c. A graph can help you
see why this occurs. By changing c, you can move
the graph of
y = x 2 º 6x + c
y
1
1
3
x
⫺1
up or down in the coordinate plane. If the graph
is moved too high, it won’t have an x-intercept
and the equation x 2 º 6x + c = 0 won’t have a
real-number solution.
y = x2 º 6x + 10
2
Graph is above x-axis (no x-intercept).
y = x º 6x + 9
Graph touches x-axis (one x-intercept).
y = x2 º 6x + 8
Graph crosses x-axis (two x-intercepts).
5.6 The Quadratic Formula and the Discriminant
293
Page 4 of 8
GOAL 2
USING THE QUADRATIC FORMULA IN REAL LIFE
In Lesson 5.3 you studied the model h = º16t 2 + h0 for the height of an object that
is dropped. For an object that is launched or thrown, an extra term v0 t must be added
to the model to account for the object’s initial vertical velocity v0.
h = º16t 2 + h0
Models
Object is dropped.
2
h = º16t + v0 t + h0
Labels
Object is launched or thrown.
h = height
(feet)
t = time in motion
(seconds)
h0 = initial height
(feet)
v0 = initial vertical velocity
(feet per second)
The initial vertical velocity of a launched object can be positive, negative, or zero. If
the object is launched upward, its initial vertical velocity is positive (v0 > 0). If the
object is launched downward, its initial vertical velocity is negative (v0 < 0). If the
object is launched parallel to the ground, its initial vertical velocity is zero (v0 = 0).
v0 < 0
v0 > 0
v0 = 0
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Entertainment
EXAMPLE 5
Solving a Vertical Motion Problem
A baton twirler tosses a baton into the air. The baton leaves the twirler’s hand 6 feet
above the ground and has an initial vertical velocity of 45 feet per second. The twirler
catches the baton when it falls back to a height of 5 feet. For how long is the baton in
the air?
SOLUTION
Since the baton is thrown (not dropped), use the model h = º16t 2 + v0 t + h0 with
v0 = 45 and h0 = 6. To determine how long the baton is in the air, find the value of t
for which h = 5.
䉴
294
h = º16t 2 + v0 t + h0
Write height model.
5 = º16t 2 + 45t + 6
h = 5, v 0 = 45, h 0 = 6
0 = º16t 2 + 45t + 1
a = º16, b = 45, c = 1
t = ᎏᎏ
º45 ± 兹2苶0苶8苶9苶
º32
Quadratic formula
t ≈ º0.022 or t ≈ 2.8
Use a calculator.
Reject the solution º0.022 since the baton’s time in the air cannot be negative.
The baton is in the air for about 2.8 seconds.
Chapter 5 Quadratic Functions
Page 5 of 8
GUIDED PRACTICE
✓
Concept Check ✓
Vocabulary Check
1. In the quadratic formula, what is the expression b2 º 4ac called?
2. How many solutions does a quadratic equation have if its discriminant
is positive? if its discriminant is zero? if its discriminant is negative?
3. Describe a real-life situation in which you can use the model
Skill Check
✓
h = º16t 2 + v0 t + h0 but not the model h = º16t 2 + h0.
Use the quadratic formula to solve the equation.
4. x 2 º 4x + 3 = 0
5. x 2 + x º 1 = 0
6. 2x 2 + 3x + 5 = 0
7. 9x 2 + 6x º 1 = 0
8. ºx 2 + 8x = 1
9. 5x 2 º 2x + 37 = x2 + 2x
Find the discriminant of the quadratic equation and give the number and type
of solutions of the equation.
10. x 2 + 5x + 2 = 0
11. x 2 + 2x + 5 = 0
12. 4x 2 º 4x + 1 = 0
13. º2x 2 + 3x º 7 = 0
14. 9x 2 + 12x + 4 = 0
15. 5x 2 º x º 13 = 0
16.
BASKETBALL A basketball player passes the ball to a teammate who
catches it 11 ft above the court, just above the rim of the basket, and slam-dunks
it through the hoop. (This play is called an “alley-oop.”) The first player releases
the ball 5 ft above the court with an initial vertical velocity of 21 ft/sec. How
long is the ball in the air before being caught, assuming it is caught as it rises?
PRACTICE AND APPLICATIONS
STUDENT HELP
Extra Practice
to help you master
skills is on p. 946.
EQUATIONS IN STANDARD FORM Use the quadratic formula to solve
the equation.
17. x 2 º 5x º 14 = 0
18. x 2 + 3x º 2 = 0
19. x 2 º 2x º 4 = 0
20. x 2 + 10x + 22 = 0
21. x 2 + 6x + 58 = 0
22. ºx 2 + 7x º 19 = 0
23. 5x 2 + 3x º 1 = 0
24. 3x 2 º 11x º 4 = 0
25. 2x 2 + x + 1 = 0
26. 6p2 º 8p + 3 = 0
27. º7q2 + 2q + 9 = 0
28. 8r 2 + 4r + 5 = 0
29. º4t 2 º 9t º 3 = 0
30. 9u2 º 12u + 85 = 0
31. 10v2 + 8v º 1 = 0
EQUATIONS NOT IN STANDARD FORM Use the quadratic formula to solve
the equation.
STUDENT HELP
HOMEWORK HELP
Examples 1–3: Exs. 17–55
Example 4: Exs. 56–64
Example 5: Exs. 74–80
32. x 2 + 4x = º20
33. x 2 º 2x = 99
34. x 2 + 14 = 10x
35. x 2 = 8x º 35
36. ºx 2 º 3x = º7
37. ºx 2 = 16x + 46
38. 3x 2 + 6x = º2
39. 8x 2 º 8x = 1
40. 5x 2 + 9x = ºx 2 + 5x + 1
41. 40x º 7x 2 = 101 º 3x 2
42. º16k2 = 20k2 + 24k + 5
43. 13n2 + 11n º 9 = 4n2 º n º 4
44. 3(d º 1)2 = 4d + 2
45. 3.5y2 + 2.6y º 8.2 = º0.4y2 º 6.9y
5.6 The Quadratic Formula and the Discriminant
295
Page 6 of 8
SOLVING BY ANY METHOD Solve the equation by factoring, by finding
square roots, or by using the quadratic formula.
46. 6x 2 º 12 = 0
47. x 2 º 3x º 15 = 0
48. x 2 + 4x + 29 = 0
49. x 2 º 18x + 32 = 0
50. 4x 2 + 28x = º49
51. 3(x + 4)2 = º27
52. º2u2 + 5 = 3u2 º 10u
53. 11m2 º 1 = 7m2 + 2
54. º9v2 + 35v º 30 = 1 º v
55. 20p2 + 6p = 6p2 º 13p + 3
USING THE DISCRIMINANT Find the discriminant of the quadratic equation
and give the number and type of solutions of the equation.
56. x 2 º 4x + 10 = 0
57. x 2 + 3x º 6 = 0
58. x 2 + 14x + 49 = 0
59. 3x 2 º 10x º 5 = 0
60. 64x 2 º 16x + 1 = 0
61. º2x 2 º 5x º 4 = 0
62. 7r 2 º 3 = 0
63. s2 兹5
苶 + s + 兹5苶 = 0
64. º4t 2 + 20t º 25 = 0
VISUAL THINKING In Exercises 65–67, the graph of a quadratic function
y = ax 2 + bx + c is shown. Tell whether the discriminant of ax 2 + bx + c = 0
is positive, negative, or zero.
65.
y
66.
y
67.
y
x
x
FOCUS ON
CAREERS
x
THE CONSTANT TERM Find all values of c for which the equation has (a) two
real solutions, (b) one real solution, and (c) two imaginary solutions.
68. x2 º 2x + c = 0
69. x2 + 4x + c = 0
70. x2 + 10x + c = 0
71. x2 º 8x + c = 0
72. x2 + 6x + c = 0
73. x2 º 12x + c = 0
74. CRITICAL THINKING Explain why the height model h = º16t 2 + v0 t + h 0
applies not only to launched or thrown objects, but to dropped objects as well.
(Hint: What is the initial vertical velocity of a dropped object?)
75.
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WEB DEVELOPER
INT
Web developers use
hypertext markup language
(HTML) to create electronic
pages for the World Wide
Web. A Web browser
translates HTML into pages
that can be viewed on a
computer screen.
NE
ER T
CAREER LINK
www.mcdougallittell.com
296
DIVING In July of 1997, the first Cliff Diving World Championships were
held in Brontallo, Switzerland. Participants performed acrobatic dives from
heights of up to 92 feet. Suppose a cliff diver jumps from this height with an
initial upward velocity of 5 feet per second. How much time does the diver have
to perform acrobatic maneuvers before hitting the water?
䉴 Source: World High Diving Federation
76.
WORLD WIDE WEB A Web developer
is creating a Web site devoted to mountain
climbing. Each page on the Web site will have
frames along its top and left sides showing the
name of the site and links to different parts of
the site. These frames will take up one third of
the computer screen. What will the width x of
the frames be on the screen shown?
Chapter 5 Quadratic Functions
Click on
one of the
buttons
below to go
to different
parts of
our site.
x
x
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11 in.
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VOLLEYBALL In a volleyball game, a player on one team spikes the ball
over the net when the ball is 10 feet above the court. The spike drives the ball
downward with an initial vertical velocity of º55 feet per second. Players on
the opposing team must hit the ball back over the net before the ball touches
the court. How much time do the opposing players have to hit the spiked ball?
78.
AVIATION The length l (in feet) of runway needed for a small airplane
to land is given by l = 0.1s2 º 3s + 22 where s is the airplane’s speed (in feet
per second). If a pilot is landing a small airplane on a runway 2000 feet long,
what is the maximum speed at which the pilot can land?
79.
TELECOMMUNICATIONS For the years 1989–1996, the amount A (in
billions of dollars) spent on long distance telephone calls in the United States
can be modeled by A = 0.560t 2 + 0.488t + 51 where t is the number of years
since 1989. In what year did the amount spent reach $60 billion?
INT
77.
80.
NE
ER T
DATA UPDATE of Statistical Abstract of the United States data at www.mcdougallittell.com
EARTH SCIENCE The volcanic cinder cone Puu Puai in Hawaii was formed
in 1959 when a massive “lava fountain” erupted at Kilauea Iki Crater, shooting
lava hundreds of feet into the air. When the eruption was most intense, the height
h (in feet) of the lava t seconds after being ejected from the ground could be
modeled by h = º16t 2 + 350t. 䉴 Source: Volcano World
a. What was the initial vertical velocity of the lava? What was the lava’s
maximum height above the ground?
b. CHOOSING A METHOD For how long was the lava in the air? Solve the
problem either by factoring or by using the quadratic formula.
Test
Preparation
QUANTITATIVE COMPARISON In Exercises 81–83, choose the statement that
is true about the given quantities.
A
¡
B
¡
C
¡
D
¡
The quantity in column A is greater.
The quantity in column B is greater.
The two quantities are equal.
The relationship cannot be determined from the given information.
Column A
★ Challenge
Column B
81.
Discriminant of x º 6x º 1 = 0
Discriminant of x2 + 5x º 4 = 0
82.
Discriminant of x 2 + 2kx + 1 = 0
Discriminant of kx2 + 3x º k = 0
83.
Least zero of ƒ(x) = x2 º 10x + 23
Greatest zero of ƒ(x) = x2 º 2x º 2
84.
2
THRILL RIDES The Stratosphere Tower in Las Vegas is 921 feet tall and has
a “needle” at its top that extends even higher into the air. A thrill ride called the
Big Shot catapults riders 160 feet up the needle and then lets them fall back to
the launching pad. 䉴 Source: Stratosphere Tower
a. The height h (in feet) of a rider on the Big Shot can be modeled by
h = º16t 2 + v0 t + 921 where t is the elapsed time (in seconds) after launch
and v0 is the initial vertical velocity (in feet per second). Find v0 using the fact
that the maximum value of h is 921 + 160 = 1081 feet.
b. A brochure for the Big Shot states that the ride up the needle takes 2 seconds.
EXTRA CHALLENGE
www.mcdougallittell.com
Compare this time with the time given by the model h = º16t 2 + v0 t + 921
where v0 is the value you found in part (a). Discuss the model’s accuracy.
5.6 The Quadratic Formula and the Discriminant
297
Page 8 of 8
MIXED REVIEW
SOLVING LINEAR INEQUALITIES Solve the inequality. Then graph your
solution. (Review 1.6 for 5.7)
85. 3x + 6 > 12
86. 16 º 7x ≥ º5
87. º2(x + 9) ≤ 8
88. 10x + 3 < 6x º 1
89. 4 ≤ 5x º 11 ≤ 29
3
90. ᎏᎏx + 20 ≤ 14 or 1 > 8 º x
2
GRAPHING LINEAR INEQUALITIES Graph the inequality. (Review 2.6 for 5.7)
91. y > x
92. y ≤ º2x
93. y < 3x º 2
94. x + y > 5
95. 2x º 3y ≥ 12
96. 7x + 4y ≤ º28
ABSOLUTE VALUE FUNCTIONS Graph the function. (Review 2.8)
97. y = |x º 3|
100. y = 3|x + 4|
98. y = |x| + 2
99. y = º2|x| º 1
1
102. y = ᎏᎏ|x º 5| º 4
2
101. y = |x + 2| + 3
QUIZ 2
Self-Test for Lessons 5.4–5.6
Write the expression as a complex number in standard form. (Lesson 5.4)
1. (7 + 5i) + (º2 + 11i)
2. (º1 + 8i) º (3 º 2i)
3. (4 º i)(6 + 7i)
1 º 3i
4. ᎏᎏ
5+i
Plot the numbers in the same complex plane and find their absolute values.
(Lesson 5.4)
5. 2 + 4i
6. º5i
7. º3 + i
8. 4 + 3i
9. º4
3
7
10. ºᎏᎏ º ᎏᎏi
2
2
Solve the quadratic equation by completing the square. (Lesson 5.5)
11. x2 + 8x = º14
12. x2 º 2x + 17 = 0
13. 4p2 º 40p º 8 = 0
14. 3q2 + 20q = º2q2 º 19
Write the quadratic function in vertex form. (Lesson 5.5)
15. y = x2 + 6x + 1
16. y = x2 º 18x + 50
17. y = º2x2 + 8x º 7
Use the quadratic formula to solve the equation. (Lesson 5.6)
18. x2 + 2x º 10 = 0
19. x2 º 16x + 73 = 0
20. 3w2 + 3w = 4w2 + 4
21. 14 + 2y º 25y2 = 42y + 6
22.
298
ENTERTAINMENT A juggler throws a ball into the air, releasing it 5 feet
above the ground with an initial vertical velocity of 15 ft/sec. She catches the
ball with her other hand when the ball is 4 feet above the ground. Using the
model h = º16t 2 + v0 t + h0, find how long the ball is in the air. (Lesson 5.6)
Chapter 5 Quadratic Functions
Page 1 of 7
5.7
Graphing and Solving
Quadratic Inequalities
What you should learn
GOAL 1 Graph quadratic
inequalities in two variables.
Solve quadratic
inequalities in one variable,
as applied in Example 7.
GOAL 1
In this lesson you will study four types of quadratic inequalities in two variables.
GOAL 2
Why you should learn it
RE
y < ax2 + bx + c
y ≤ ax2 + bx + c
y > ax2 + bx + c
y ≥ ax2 + bx + c
The graph of any such inequality consists of all solutions (x, y) of the inequality.
The steps used to graph a quadratic inequality are very much like those used to graph
a linear inequality. (See Lesson 2.6.)
G R A P H I N G A Q UA D R AT I C I N E Q UA L I T Y I N T W O VA R I A B L E S
To graph one of the four types of quadratic inequalities shown above, follow
these steps:
FE
䉲 To solve real-life
problems, such as finding the
weight of theater equipment
that a rope can support in
Exs. 47 and 48.
AL LI
QUADRATIC INEQUALITIES IN TWO VARIABLES
STEP 1
Draw the parabola with equation y = ax 2 + bx + c. Make the parabola
dashed for inequalities with < or > and solid for inequalities with ≤
or ≥.
STEP 2
Choose a point (x, y) inside the parabola and check whether the point
is a solution of the inequality.
STEP 3
If the point from Step 2 is a solution, shade the region inside the
parabola. If it is not a solution, shade the region outside the parabola.
EXAMPLE 1
Graphing a Quadratic Inequality
Graph y > x2 º 2x º 3.
SOLUTION
Follow Steps 1–3 listed above.
1
Graph y = x2 º 2x º 3. Since the inequality
symbol is >, make the parabola dashed.
2
Test a point inside the parabola, such as (1, 0).
y > x 2 º 2x º 3
y
1
(1, 0)
4
x
?
0 > 12 º 2(1) º 3
0 > º4 ✓
So, (1, 0) is a solution of the inequality.
3
Shade the region inside the parabola.
5.7 Graphing and Solving Quadratic Inequalities
299
Page 2 of 7
RE
FE
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Carpentry
Using a Quadratic Inequality as a Model
EXAMPLE 2
You are building a wooden bookcase. You want to
choose a thickness d (in inches) for the shelves so
that each is strong enough to support 60 pounds of
books without breaking. A shelf can safely support
a weight of W (in pounds) provided that:
W ≤ 300d 2
d in.
48 in.
12 in.
a. Graph the given inequality.
b. If you make each shelf 0.75 inch thick, can it support a weight of 60 pounds?
SOLUTION
Look Back
For help with graphing
inequalities in two
variables, see p. 108.
a. Graph W = 300d 2 for nonnegative values
of d. Since the inequality symbol is ≤,
make the parabola solid. Test a point inside
the parabola, such as (0.5, 240).
W ≤ 300d 2
?
240 ≤ 300(0.5)2
Safe weight (lb)
STUDENT HELP
240 75
W
300
(0.5, 240)
250
200
W ≤ 300d 2
150
100
(0.75, 60)
50
0
0
0.5 1.0 1.5 d
Thickness (in.)
Since the chosen point is not a solution, shade
the region outside (below) the parabola.
b. The point (0.75, 60) lies in the shaded region of the graph from part (a), so
(0.75, 60) is a solution of the given inequality. Therefore, a shelf that is 0.75 inch
thick can support a weight of 60 pounds.
..........
Graphing a system of quadratic inequalities is similar to graphing a system of linear
inequalities. First graph each inequality in the system. Then identify the region in the
coordinate plane common to all the graphs. This region is called the graph of the system.
EXAMPLE 3
Graphing a System of Quadratic Inequalities
Graph the system of quadratic inequalities.
y ≥ x2 º 4
y < ºx2 º x + 2
Inequality 1
Inequality 2
SOLUTION
y
2
Graph the inequality y ≥ x º 4. The graph is the red
y ≥ x2 ⴚ 4
2
region inside and including the parabola y = x º 4.
Graph the inequality y < ºx 2 º x + 2. The graph is
the blue region inside (but not including) the parabola
y = ºx 2 º x + 2.
Identify the purple region where the two graphs overlap.
This region is the graph of the system.
300
Chapter 5 Quadratic Functions
1
3
y < ⴚx 2 ⴚ x ⴙ 2
x
Page 3 of 7
GOAL 2
QUADRATIC INEQUALITIES IN ONE VARIABLE
One way to solve a quadratic inequality in one variable is to use a graph.
•
To solve ax 2 + bx + c < 0 (or ax 2 + bx + c ≤ 0), graph y = ax 2 + bx + c and
identify the x-values for which the graph lies below (or on and below) the x-axis.
•
To solve ax 2 + bx + c > 0 (or ax 2 + bx + c ≥ 0), graph y = ax 2 + bx + c and
identify the x-values for which the graph lies above (or on and above) the x-axis.
EXAMPLE 4
STUDENT HELP
Look Back
For help with solving
inequalities in one
variable, see p. 41.
Solving a Quadratic Inequality by Graphing
Solve x 2 º 6x + 5 < 0.
SOLUTION
y
The solution consists of the x-values for which the graph of
y = x 2 º 6x + 5 lies below the x-axis. Find the graph’s
x-intercepts by letting y = 0 and using factoring to solve for x.
1
5
1
3
2
0 = x º 6x + 5
x
0 = (x º 1)(x º 5)
x = 1 or x = 5
y ⴝ x 2 ⴚ 6x ⴙ 5
Sketch a parabola that opens up and has 1 and 5 as x-intercepts.
The graph lies below the x-axis between x = 1 and x = 5.
䉴
The solution of the given inequality is 1 < x < 5.
EXAMPLE 5
Solving a Quadratic Inequality by Graphing
Solve 2x 2 + 3x º 3 ≥ 0.
SOLUTION
The solution consists of the x-values for which the
graph of y = 2x 2 + 3x º 3 lies on and above the
x-axis. Find the graph’s x-intercepts by letting y = 0
and using the quadratic formula to solve for x.
y
1
2.19
y ⴝ 2x 2 ⴙ 3x ⴚ 3
0.69
4
x
0 = 2x2 + 3x º 3
º3 ± 兹3苶2苶º
苶苶4(2
苶)(
苶º
苶3苶)苶
2(2)
x = º3 ± 兹苶33苶
4
x = x ≈ 0.69 or x ≈ º2.19
Sketch a parabola that opens up and has 0.69 and º2.19 as x-intercepts. The graph
lies on and above the x-axis to the left of (and including) x = º2.19 and to the right
of (and including) x = 0.69.
䉴
The solution of the given inequality is approximately x ≤ º2.19 or x ≥ 0.69.
5.7 Graphing and Solving Quadratic Inequalities
301
Page 4 of 7
You can also use an algebraic approach to solve a quadratic inequality in one
variable, as demonstrated in Example 6.
Solving a Quadratic Inequality Algebraically
EXAMPLE 6
Solve x2 + 2x ≤ 8.
SOLUTION
First write and solve the equation obtained by replacing the inequality symbol with
an equals sign.
x2 + 2x ≤ 8
Write original inequality.
x2 + 2x = 8
Write corresponding equation.
x2 + 2x º 8 = 0
Write in standard form.
(x + 4)(x º 2) = 0
Factor.
x = º4 or x = 2
Zero product property
The numbers º4 and 2 are called the critical x-values of the inequality x2 + 2x ≤ 8.
Plot º4 and 2 on a number line, using solid dots because the values satisfy the
inequality. The critical x-values partition the number line into three intervals. Test
an x-value in each interval to see if it satisfies the inequality.
6
4
ⴚ5
3
Test x = º5:
(º5)2 + 2(º5) = 15 8
䉴
2
1
0
1
2
Test x = 0:
02 + 2(0) = 0 ≤ 8 ✓
3
4
Test x = 3:
32 + 2(3) = 15 8
The solution is º4 ≤ x ≤ 2.
Using a Quadratic Inequality as a Model
EXAMPLE 7
DRIVING For a driver aged x years, a study found that the driver’s reaction time V(x)
(in milliseconds) to a visual stimulus such as a traffic light can be modeled by:
V(x) = 0.005x2 º 0.23x + 22,
FOCUS ON
APPLICATIONS
16 ≤ x ≤ 70
At what ages does a driver’s reaction time tend to be greater than 25 milliseconds?
䉴 Source: Science Probe!
SOLUTION
You want to find the values of x for which:
V(x) > 25
0.005x2 º 0.23x + 22 > 25
L
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RE
FE
DRIVING Driving
simulators help
drivers safely improve their
reaction times to hazardous
situations they may
encounter on the road.
302
Zero
X=56.600595 Y=0
0.005x2 º 0.23x º 3 > 0
Graph y = 0.005x2 º 0.23x º 3 on the domain 16 ≤ x ≤ 70. The graph’s x-intercept
is about 57, and the graph lies above the x-axis when 57 < x ≤ 70.
䉴
Drivers over 57 years old tend to have reaction times greater than 25 milliseconds.
Chapter 5 Quadratic Functions
Page 5 of 7
GUIDED PRACTICE
Vocabulary Check
Concept Check
Skill Check
✓
1. Give one example each of a quadratic inequality in one variable and a quadratic
✓
2. How does the graph of y > x 2 differ from the graph of y ≥ x 2?
✓
inequality in two variables.
3. Explain how to solve x 2 º 3x º 4 > 0 graphically and algebraically.
Graph the inequality.
4. y ≥ x 2 + 2
5. y ≤ º2x 2
6. y < x 2 º 5x + 4
Graph the system of inequalities.
7. y ≤ ºx 2 + 3
8. y ≥ ºx 2 + 3
2
9. y ≥ ºx 2 + 3
2
y ≥ x + 2x º 4
y ≤ x 2 + 2x º 4
y ≥ x + 2x º 4
Solve the inequality.
10. x 2 º 4 < 0
13.
11. x 2 º 4 ≥ 0
12. x 2 º 4 > 3x
ARCHITECTURE The arch of the Sydney Harbor Bridge in Sydney,
Australia, can be modeled by y = º0.00211x 2 + 1.06x where x is the distance
(in meters) from the left pylons and y is the height (in meters) of the arch above
the water. For what distances x is the arch above the road?
y
pylon
52 m
x
PRACTICE AND APPLICATIONS
STUDENT HELP
Extra Practice
to help you master
skills is on p. 947.
MATCHING GRAPHS Match the inequality with its graph.
14. y ≥ x 2 º 4x + 1
A.
5
15. y < x 2 º 4x + 1
y
16. y ≤ ºx 2 º 4x + 1
y
B.
y
C.
1
1
1
1
x
x
2x
STUDENT HELP
HOMEWORK HELP
Example 1: Exs. 14–28
Example 2: Exs. 47–49
Example 3: Exs. 29–34,
49
Examples 4, 5: Exs. 35–40
Example 6: Exs. 41–46
Example 7: Exs. 50, 51
GRAPHING QUADRATIC INEQUALITIES Graph the inequality.
17. y ≥ 3x 2
18. y ≤ ºx 2
19. y > ºx 2 + 5
20. y < x 2 º 3x
21. y ≤ x 2 + 8x + 16
22. y ≤ ºx 2 + x + 6
23. y ≥ 2x 2 º 2x º 5
24. y ≥ º2x 2 º x + 3
25. y > º3x 2 + 5x º 4
1
2
26. y < ºx 2 º 2x + 4
4
3
27. y > x 2 º 12x + 29
28. y < 0.6x 2 + 3x + 2.4
5.7 Graphing and Solving Quadratic Inequalities
303
Page 6 of 7
FOCUS ON
CAREERS
GRAPHING SYSTEMS Graph the system of inequalities.
29. y ≥ x 2
2
y≤x +3
32. y ≥ x 2 + 2x + 1
2
30. y < º3x 2
1
y ≥ ºx 2 º 5
2
31. y > x 2 º 6x + 9
33. y < 3x 2 + 2x º 5
34. y ≤ 2x 2 º 9x + 8
y < ºx 2 + 6x º 3
2
y ≥ x º 4x + 4
y > ºx 2 º 6x º 4
y ≥ º2x + 1
SOLVING BY GRAPHING Solve the inequality by graphing.
RE
FE
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SET DESIGNER
INT
A set designer
creates the scenery, or sets,
used in a theater production.
The designer may make
scale models of the sets
before they are actually
built.
35. x 2 + x º 2 < 0
36. 2x 2 º 7x + 3 ≥ 0
37. ºx 2 º 2x + 8 ≤ 0
38. ºx 2 + x + 5 > 0
39. 3x 2 + 24x ≥ º41
3
40. ºx 2 + 4x º 8 < 0
4
SOLVING ALGEBRAICALLY Solve the inequality algebraically.
41. x 2 + 3x º 18 ≥ 0
42. 3x 2 º 16x + 5 ≤ 0
43. 4x 2 < 25
44. ºx 2 º 12x < 32
45. 2x 2 º 4x º 5 > 0
1
46. x 2 + 3x ≤ º6
2
NE
ER T
CAREER LINK
www.mcdougallittell.com
THEATER In Exercises 47 and 48, use the following information.
You are a member of a theater production crew. You use manila rope and wire rope
to support lighting, scaffolding, and other equipment. The weight W (in pounds) that
can be safely supported by a rope with diameter d (in inches) is given below for both
types of rope. 䉴 Source: Workshop Math
Manila rope: W ≤ 1480d 2
Wire rope: W ≤ 8000d 2
1
47. Graph the inequalities in separate coordinate planes for 0 ≤ d ≤ 1.
2
48. Based on your graphs, can 1000 pounds of theater equipment be supported by
1
1
a inch manila rope? by a inch wire rope?
2
2
49.
HEALTH For a person of height h (in inches), a healthy weight W
(in pounds) is one that satisfies this system of inequalities:
19h 2
703
W ≥ and
25 h 2
703
W ≤ Graph the system for 0 ≤ h ≤ 80. What is the range of healthy weights for a
person 67 inches tall? 䉴 Source: Parade Magazine
SOLVING INEQUALITIES In Exercises 50–52, you may want to use a
graphing calculator to help you solve the problems.
INT
STUDENT HELP
NE
ER T
HOMEWORK HELP
Visit our Web site
www.mcdougallittell.com
for help with problem
solving in Exs. 50–52.
50.
FORESTRY Sawtimber is a term for trees that are suitable for sawing into
lumber, plywood, and other products. For the years 1983–1995, the unit value y
(in 1994 dollars per million board feet) of one type of sawtimber harvested in
California can be modeled by
y = 0.125x 2 º 569x + 848,000,
400 ≤ x ≤ 2200
where x is the volume of timber harvested (in millions of board feet).
䉴 Source: California Department of Forestry and Fire Protection
a. For what harvested timber volumes is the value of the timber at least $400,000
per million board feet?
b. LOGICAL REASONING What happens to the unit value of the timber as the
volume harvested increases? Why would you expect this to happen?
304
Chapter 5 Quadratic Functions
Page 7 of 7
51.
MEDICINE In 1992 the average income I (in dollars) for a doctor aged
x years could be modeled by:
I = º425x 2 + 42,500x º 761,000
INT
For what ages did the average income for a doctor exceed $250,000?
Test
Preparation
NE
ER T
DATA UPDATE of American Almanac of Jobs and Salaries data at www.mcdougallittell.com
52. MULTI-STEP PROBLEM A study of driver reaction times to audio stimuli found
that the reaction time A(x) (in milliseconds) of a driver can be modeled by
A(x) = 0.0051x 2 º 0.319x + 15,
16 ≤ x ≤ 70
where x is the driver’s age (in years). 䉴 Source: Science Probe!
a. Graph y = A(x) on the given domain. Also graph y = V(x), the reaction-time
model for visual stimuli from Example 7, in the same coordinate plane.
b. For what values of x in the interval 16 ≤ x ≤ 70 is A(x) < V(x)?
c.
★ Challenge
Writing Based on your results from part (b), do you think a driver would
react more quickly to a traffic light changing from green to yellow or to the
siren of an approaching ambulance? Explain.
y
The area A of the region
bounded by a parabola and a horizontal line is given by
53. GEOMETRY
CONNECTION
h
2
3
A = bh where b and h are as defined in the diagram.
Find the area of the region determined by each pair
of inequalities.
EXTRA CHALLENGE
www.mcdougallittell.com
a. y ≤ ºx2 + 4x
b
x
b. y ≥ x2 º 4x º 5
y≥0
y≤3
MIXED REVIEW
SOLVING FOR A VARIABLE Solve the equation for y. (Review 1.4)
54. 3x + y = 1
55. 8x º 2y = 10
56. º2x + 5y = 9
1
1
11
57. x + y = º
6
3
12
58. xy º x = 2
x º 3y
59. = 7x
4
SOLVING SYSTEMS Solve the system of linear equations. (Review 3.6 for 5.8)
60. 5x º 3y º 2z = º17
ºx + 7y º 3z = 6
3x + 2y + 4z = 13
61. x º 4y + z = º14
2x + 3y + 7z = º15
º3x + 5y º 5z = 29
COMPLEX NUMBERS Write the expression as a complex number in standard
form. (Review 5.4)
62. (3 + 4i) + (10 º i)
63. (º11 º 2i) + (5 + 2i)
64. (9 + i) º (4 º i)
65. (5 º 3i) º (º1 + 2i)
66. 6i(8 + i)
67. (7 + 3i)(2 º 5i)
1
68. 3ºi
4 º 3i
69. 9 + 2i
5.7 Graphing and Solving Quadratic Inequalities
305
Page 1 of 7
E X P L O R I N G DATA
A N D S TAT I S T I C S
5.8
GOAL 1
What you should learn
GOAL 1 Write quadratic
functions given characteristics of their graphs.
GOAL 2 Use technology to
find quadratic models for
data, such as the fuel economy data in Examples 3 and 4.
Why you should learn it
WRITING QUADRATIC FUNCTIONS
In Lesson 5.1 you learned how to graph a given quadratic function. In this lesson you
will write quadratic functions when given information about their graphs.
EXAMPLE 1
Writing a Quadratic Function in Vertex Form
y
Write a quadratic function for the parabola shown.
SOLUTION
1
(4, 1)
Because you are given the vertex (h, k) = (2, º3),
use the vertex form of the quadratic function.
x
1
y = a(x º h)2 + k
vertex:
(2, 3)
y = a(x º 2)2 º 3
Use the other given point, (4, 1), to find a.
FE
䉲 To solve real-life
problems, such as determining the effect of wind
on a runner’s performance
in Ex. 36.
AL LI
RE
Modeling with Quadratic
Functions
䉴
1 = a(4 º 2)2 º 3
Substitute 4 for x and 1 for y.
1 = 4a º 3
Simplify coefficient of a.
4 = 4a
Add 3 to each side.
1=a
Divide each side by 4.
A quadratic function for the parabola is y = (x º 2)2 º 3.
EXAMPLE 2
Writing a Quadratic Function in Intercept Form
y
Write a quadratic function for the parabola shown.
SOLUTION
(1, 2)
Because you are given the x-intercepts p = º2 and
q = 3, use the intercept form of the quadratic function.
y = a(x º p)(x º q)
y = a(x + 2)(x º 3)
Use the other given point, (º1, 2), to find a.
2 = a(º1 + 2)(º1 º 3)
Substitute º1 for x and 2 for y.
2 = º4a
Simplify coefficient of a.
1
2
Divide each side by º4.
º = a
䉴
306
1
2
A quadratic function for the parabola is y = º(x + 2)(x º 3).
Chapter 5 Quadratic Functions
1
2
1
3
x
Page 2 of 7
ACTIVITY
Developing
Concepts
Writing a Quadratic in Standard Form
In this activity you will write a quadratic function in standard form,
y = ax 2 + bx + c, for the parabola in Example 2.
1
The parabola passes through (º2, 0), (º1, 2), and (3, 0). Substitute the
coordinates of each point into y = ax 2 + bx + c to obtain three equations
in a, b, and c. For instance, the equation for (º2, 0) is:
0 = a(º2)2 + b(º2) + c, or
0 = 4a º 2b + c
2
Solve the system from Step 1 to find a, b, and c. Use these values to write
a quadratic function in standard form for the parabola.
3
As a check of your work, use multiplication to write the function
1
2
y = º(x + 2)(x º 3) from Example 2 in standard form. Your answer
should match the function you wrote in Step 2.
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Fuel Economy
EXAMPLE 3
Finding a Quadratic Model for a Data Set
A study compared the speed x (in miles per hour) and the average fuel economy y
(in miles per gallon) for cars. The results are shown in the table. Find a quadratic
model in standard form for the data. 䉴 Source: Transportation Energy Data Book
Speed, x
Fuel economy, y
Speed, x
Fuel economy, y
15
20
25
30
35
40
22.3
25.5
27.5
29.0
28.8
30.0
45
50
55
60
65
70
29.9
30.2
30.4
28.8
27.4
25.3
SOLUTION
Plot the data pairs (x, y) in a coordinate plane.
y
Estimate the coordinates of three points on the
parabola, such as (20, 25), (40, 30), and (60, 28).
Substitute the coordinates of the points into the
model y = ax 2 + bx + c to obtain a system of
three linear equations.
400a + 20b + c = 25
1600a + 40b + c = 30
STUDENT HELP
Look Back
For help with solving
systems of three linear
equations, see pp. 177,
217, and 231.
3600a + 60b + c = 28
Fuel economy (mi/gal)
Draw the parabola you think best fits the data.
(40, 30)
30
(60, 28)
28
26
(20, 25)
24
22
0
0
20
40
60
80
x
Speed (mi/h)
Solve the linear system. The solution is a = º0.00875, b = 0.775, and c = 13.
䉴
A quadratic model for the data is y = º0.00875x 2 + 0.775x + 13.
5.8 Modeling with Quadratic Functions
307
Page 3 of 7
FOCUS ON
CAREERS
GOAL 2
USING TECHNOLOGY TO FIND QUADRATIC MODELS
In Chapter 2 you used a graphing calculator to perform linear regression on a data set
in order to find a linear model for the data. A graphing calculator can also be used to
perform quadratic regression. Quadratic regression produces a more accurate
quadratic model than the procedure in Example 3 because it uses all the data points.
The model given by quadratic regression is called the best-fitting quadratic model.
EXAMPLE 4
Using Quadratic Regression to Find a Model
FUEL ECONOMY Use the fuel economy data given in Example 3 to complete
RE
FE
L
AL I
AUTOMOTIVE
DESIGNER
INT
Automotive designers help
conceive of and develop
new cars. They have to
consider such factors
as a car’s appearance,
performance, and fuel
economy (the focus of
Example 4).
parts (a) and (b).
a. Use a graphing calculator to find the best-fitting quadratic model for the data.
b. Find the speed that maximizes a car’s fuel economy.
SOLUTION
a. Enter the data into two lists of
a graphing calculator.
NE
ER T
L1
L2
15
22.3
20
25.5
25
27.5
30
29
35
28.8
L2(5)=28.8
CAREER LINK
www.mcdougallittell.com
Make a scatter plot of the data. Note
that the points show a parabolic trend.
L3
Use the quadratic regression
feature to find the best-fitting
quadratic model for the data.
Check how well the model fits the
data by graphing the model and the
data in the same viewing window.
QuadReg
y=ax2+bx+c
a=-.0081968032
b=.7458891109
c=13.47215285
䉴
INT
STUDENT HELP
NE
ER T
KEYSTROKE HELP
Visit our Web site
www.mcdougallittell.com
to see keystrokes for
several models of
calculators.
The best-fitting quadratic model is y = º0.00820x 2 + 0.746x + 13.5.
b. You can find the speed that maximizes fuel
economy by using the Maximum feature of
a graphing calculator, as shown at the right.
You can also find the speed algebraically using
the formula for the x-coordinate of a parabola’s
vertex from Lesson 5.1:
b
2a
Maximum
X=45.4988
Y=30.4407
0.746
2(º0.00820)
x = º = º ≈ 45
䉴
308
The speed that maximizes a car’s fuel economy is about 45 miles per hour.
Chapter 5 Quadratic Functions
Page 4 of 7
GUIDED PRACTICE
Vocabulary Check
Concept Check
Skill Check
✓
1. Complete this statement: When you perform quadratic regression on a set of
✓
2. How many points are needed to determine a parabola if one of the points is the
✓
?.
data, the quadratic model you obtain is called the 㛭㛭㛭
vertex? if none of the points is the vertex?
Write a quadratic function in the specified form for the parabola shown.
3. vertex form
4. intercept form
5. standard form
y
y
y
vertex:
(1, 3)
(4, 2)
1
1
1
(1, 2)
1
x
2
1
1
1
(1, 1)
x
x
(0, 4)
(2, 4)
REAL ESTATE The table shows the average sale price p of a house in
6.
Suffolk County, Massachusetts, for various years t since 1988. Use a system
of equations to write a quadratic model for the data. Check your model by
performing quadratic regression on a graphing calculator.
Years since 1988, t
INT
Average sale price
(thousands of dollars), p
NE
ER T
0
2
4
6
8
10
165
154.5
124.5
115
128
165
DATA UPDATE of Boston Globe data at www.mcdougallittell.com
PRACTICE AND APPLICATIONS
STUDENT HELP
Extra Practice
to help you master
skills is on p. 947.
WRITING THE VERTEX FORM Write a quadratic function in vertex form for the
parabola shown.
y
7.
(0, 2)
2
vertex:
(2, 2)
y
9.
vertex:
(1, 4)
1
STUDENT HELP
y
8.
x
vertex:
1 (1, 0)
x
(2, 2)
1
1
x
(1, 3)
HOMEWORK HELP
Example 1: Exs. 7–15,
34
Example 2: Exs. 16–24,
35
Example 3: Exs. 25–33,
36–38
Example 4: Exs. 37, 38
WRITING THE VERTEX FORM Write a quadratic function in vertex form whose
graph has the given vertex and passes through the given point.
10. vertex: (2, º1)
point: (4, 3)
13. vertex: (0, 0)
point: (º2, º12)
11. vertex: (º4, 6)
point: (º1, 9)
14. vertex: (1, º10)
point: (º3, 54)
12. vertex: (4, 5)
point: (8, º3)
15. vertex: (º6, º7)
point: (0, º61)
5.8 Modeling with Quadratic Functions
309
Page 5 of 7
WRITING THE INTERCEPT FORM Write a quadratic function in intercept form
for the parabola shown.
y
16.
y
17.
2
1
3
1
1
y
18.
x
1
(3, 3)
2
3 x
2
0
4 x
(1, 6)
(1, 4)
WRITING THE INTERCEPT FORM Write a quadratic function in intercept form
whose graph has the given x-intercepts and passes through the given point.
19. x-intercepts: 1, 4
20. x-intercepts: º2, 2
21. x-intercepts: º1, 6
point: (3, 2)
point: (º4, 8)
point: (1, º20)
23. x-intercepts: 3, 9
24. x-intercepts: º5, 0
22. x-intercepts: º10, º8
point: (º7, º15)
point: (14, 77)
point: (º3, 18)
WRITING THE STANDARD FORM Write a quadratic function in standard form
for the parabola shown.
25.
26.
y
27.
y
(0, 4)
y
(2, 7)
(0, 1)
(1, 2)
(5, 4)
1
1
(3, 2)
x
1
(4, 0)
(3, 2)
1
1
x
(5, 4)
x
WRITING THE STANDARD FORM Write a quadratic function in standard form
whose graph passes through the given points.
INT
STUDENT HELP
NE
ER T
28. (º1, 5), (0, 3), (3, 9)
29. (1, 2), (3, 4), (6, º8)
30. (º2, º1), (1, 11), (2, 27)
31. (º4, º7), (º3, 3), (3, º21)
32. (º3, º4), (º1, 0), (9, º10)
33. (º6, 46), (2, 14), (4, 56)
34.
HOMEWORK HELP
Visit our Web site
www.mcdougallittell.com
for help with problem
solving in Exs. 34 and 35.
BOTANY Amaranth is a type of vegetable commonly grown in Asia, West
Africa, and the Caribbean. When amaranth plants are grown in rows, the height
that the plants attain is a quadratic function of the spacing between plants within
a row. According to one study, the minimum height of the plants, about 16 cm,
occurred when the plants were spaced about 27 cm apart. The study also found
that the plants grew to about 20 cm when spaced about 40 cm apart. Write a
quadratic model giving the plant height h as a function of the spacing s.
䉴 Source: Center for New Crops and Plant Products, Perdue University
35.
TRANSPORTATION The surfaces of
some roads are shaped like parabolas to
allow rain to run off to either side. (This is
also true of football fields; see Exercise 52
on page 254.) Write a quadratic model for
the surface of the road shown.
䉴 Source: Massachusetts Highway Department
310
Chapter 5 Quadratic Functions
y
road surface
0.2 ft
17 ft
24 ft
Not drawn to scale
x
Page 6 of 7
FOCUS ON
PEOPLE
36.
37.
RE
FE
L
AL I
Wind speed (m/sec), s
º6
º4
º2
0
2
Change in finishing
time (sec), t
2.28
1.42
0.67
0
º0.57
4
6
º1.05 º1.42
AGRICULTURE Researchers compared protein intake to average shoulder
and kidney weight for a group of pigs. The results are shown in the table.
Use systems of equations to write quadratic models for the shoulder weight s and
kidney weight k as a function of the protein intake p. Check your models using
the quadratic regression feature of a graphing calculator.
MARK MCGWIRE
hit 70 home runs
during the 1998 Major
League Baseball season,
breaking Roger Maris’s
record of 61. McGwire’s
longest home run traveled
545 ft (166 m).
INT
RUNNING The table shows how wind affects a runner’s performance in
the 200 meter dash. Positive wind speeds correspond to tailwinds, and negative
wind speeds correspond to headwinds. Positive changes in finishing time mean
worsened performance, and negative changes mean improved performance. Use
a system of equations to write a quadratic model for the change t in finishing
time as a function of the wind speed s. 䉴 Source: The Physics of Sports
䉴 Source: Livestock Research for Rural Development
195
238
297
341
401
427
8130
8740
9680
9690
9810
8990
239
287
288
334
379
373
Protein intake (g/day), p
Shoulder weight (g), s
Kidney weight (g), k
NE
ER T
APPLICATION LINK
www.mcdougallittell.com
38.
BASEBALL The table shows the distance (in meters) traveled by a baseball
hit at various angles and with different types of spin. (In each case the initial
speed of the ball off the bat is assumed to be 40 m/sec.) Use systems of equations
to write three quadratic models—one for each type of spin—that give the
distance d as a function of the angle A. Check your models using the quadratic
regression feature of a graphing calculator. 䉴 Source: The Physics of Sports
Test
Preparation
Angle
10°
15°
30°
36°
42°
45°
48°
54°
60°
Distance
(backspin)
61.2
83.0
130.4
139.4
143.2
142.7
140.7
132.8
119.7
Distance
(no spin)
58.3
79.7
126.9
136.6
140.6
140.9
139.3
132.5
120.5
Distance
(topspin)
56.1
76.3
122.8
133.2
138.3
139.0
137.8
132.1
120.9
39. MULTI-STEP PROBLEM The table shows the time t it takes to boil a potato
whose smallest diameter (that is, whose shortest distance through the center)
is d. 䉴 Source: Dr. Peter Barham, University of Bristol
Diameter (mm), d
20
25
30
35
40
45
50
Boiling time (min), t
27
42
61
83
109
138
170
t
a. Find the ratios . Does boiling time vary directly with diameter? Explain.
d
b. Find the ratios t. What do you notice?
d2
c. Use the result of part (b) to write a quadratic model for t as a function of d.
Find the time needed to boil a potato whose smallest diameter is 55 mm.
5.8 Modeling with Quadratic Functions
311
Page 7 of 7
★ Challenge
CONNECTION Let R be the maximum
number of regions into which a circle can be divided
using n chords. For example, the diagram shows that
R = 4 when n = 2. Copy and complete the table. Then
write a quadratic model giving R as a function of n.
40. GEOMETRY
EXTRA CHALLENGE
www.mcdougallittell.com
n
0
1
2
3
4
5
6
R
?
?
4
?
?
?
?
2
3
1
4
MIXED REVIEW
EVALUATING EXPRESSIONS Evaluate the expression for the given value of
the variable. (Review 1.2 for 6.1)
41. x 2 º 4 when x = 3
42. x 5 when x = 2
43. 3u3 + 10 when u = º4
44. ºv4 + 2v + 7 when v = º1
SOLVING SYSTEMS Solve the system using either the substitution method
or the linear combination method. (Review 3.2)
45. x º y = 4
x+y=2
48.
46. 2x º y = 0
47. 3x + 2y = º2
5x + 3y = 11
4x + 7y = 19
HEALTH You belong to a health maintenance organization (HMO).
Each year, you pay the HMO an insurance premium of $1800. In addition,
you pay $15 for each visit to your doctor’s office and $10 for each prescription.
Write an equation for the annual cost C of your health plan as a function of your
number v of office visits and number p of prescriptions. (Review 3.5)
QUIZ 3
Self-Test for Lessons 5.7 and 5.8
Graph the inequality. (Lesson 5.7)
1. y > x 2 + 2
2. y ≥ ºx 2 º x + 3
3. y ≤ 2x 2 º 12x + 15
Graph the system of inequalities. (Lesson 5.7)
4. y ≥ x 2
2
y ≤ 2x º 1
5. y > x 2 º 2x º 3
2
y < ºx + 2x + 3
6. y > ºx 2 º 4x
y ≤ x 2 + 7x + 10
Write a quadratic function in the specified form whose graph has the given
characteristics. (Lesson 5.8)
7. vertex form
vertex: (5, º2)
point on graph: (4, 0)
10.
312
8. intercept form
x-intercepts: º3, 1
point on graph: (2, º5)
9. standard form
points on graph:
(º4, 8), (º2, 1), (2, 5)
COMPUTERS Using an algorithm called insertion sort, a common
minicomputer can sort N numbers from least to greatest in t milliseconds where
t = 0.00339N 2 + 0.00143N º 5.95. How many numbers can the minicomputer
sort in less than 1 second (1000 milliseconds)? Write your answer as an
inequality. (Lesson 5.7)
Chapter 5 Quadratic Functions