PSA (1WS) I. Factor each completely. (5) 1. x2 y + x = 2. 3x3 − 5x2

PSA (1WS)
I. Factor each completely. (5)
1. x 2 y + x =
2. 3x 3 − 5x 2 =
3. 3y 5 − 6y 4 + 9y 3 =
4. 5c 3 −10c 2 +15c =
5. 32m 3n −16m 2 n + 8mn =
II. General Directions: (30)
1. Write on the first blank the letter corresponding to the name of the given or
polynomial found in column A.
2. Write on the second blank the letter corresponding to the name of the
factor(s) obtained found in column B.
3. Factor completely.
4. The answer can be repeated.
5. Check the legend below.
Given
Column
A
Column
B
__ __ ________________________________ 1.
y 2 + 4y + 4
A. DTS
F. TBC
__ __ ________________________________ 2.
y 2 −16
B. PST
G. TIB
__ __ ________________________________ 3.
a3 + 8
C. STC
H. TSP
__ __ ________________________________ 4.
1 − y3
D. DTC
I. None
__ __ ________________________________ 5.
36y 2 +12yz + z 2
E. None
__ __ ________________________________ 6.
16x 2 − 25
__ __ ________________________________ 7.
125x 3 + y 3
__ __ ________________________________ 8.
27x 3 − y 6
__ __ ________________________________ 9.
7n 2 +14np +14 p 2
__ __ ________________________________ 10.
25x 2 − 30xy + 9y 2