Quadratic_Equations_..

Quadratic Equations Quiz 1
Key
Name _________________________________________
Period _____ Date ________
Directions:
Read each question fully and carefully. Answer each question completely.
You must show your work. Each question is worth five (5) points.
1. Solve by completing the square:
x 2 ο€­ 6x  2 ο€½ 0
π‘₯ 2 βˆ’ 6π‘₯ = βˆ’2
π‘₯ 2 βˆ’ 6π‘₯ + 9 = 7
π‘₯βˆ’3 2 =7
π‘₯βˆ’3=± 7
π‘₯ = 3± 7
Subtract 2
Add βˆ’6/2 2 = 9
Write as perfect square
Square root
Solution
2. Solve using the quadratic formula:
4 x2  2 x  1 ο€½ 0
π‘Ž=4
𝑏=2
π‘₯=
π‘₯=
;𝑏± 𝑏 2 ;4π‘Žπ‘
2π‘Ž
;2± 4;16
8
1
π‘₯ = βˆ’4 ±
3
4
𝑐=1
=
=
;2± 22 ;4βˆ™4βˆ™1
Quadratic Formula
2βˆ™4
;2± ;12
8
=
;2±π‘– 4 3
8
𝑖
Solution
3. Solve the following problem. Approximate answers involving radicals to the
nearest hundredth.
Find the dimensions of a rectangle whose perimeter is 10 cm and whose area
is 3 cm2.
π‘π‘’π‘Ÿπ‘–π‘šπ‘’π‘‘π‘’π‘Ÿ = 2𝑀 + 2β„Ž = 10 π‘π‘š
π‘Žπ‘Ÿπ‘’π‘Ž = 𝑀 βˆ™ β„Ž = 3 π‘π‘š2
β„Ž =5βˆ’π‘€
solve perimeter equation for h
h
𝑀 5βˆ’π‘€ =3
substitute into area equation
2
5𝑀 βˆ’ 𝑀 = 3
simplify
w
𝑀 2 βˆ’ 5𝑀 + 3 = 0
standard form
π‘Ž=1
𝑏 = βˆ’5
𝑐=3
𝑀=
𝑀=
; ;5 ±
;5 2 ;4βˆ™1βˆ™3
Quadratic Formula
2βˆ™1
5 ± 25 βˆ’ 12 5 ± 13
=
2
2
Dimensions:
0.70 cm ο‚΄ 4.30 cm
-1-
Quadratic Equations Quiz 1
Key
Name _________________________________________
Period _____ Date ________
Directions:
Read each question fully and carefully. Answer each question completely.
You must show your work. Each question is worth five (5) points.
1. Solve by completing the square:
x 2 ο€­ 5x ο€½ 3
π‘₯ 2 βˆ’ 5π‘₯ +
5 2
π‘₯βˆ’2
25
=
5
37
Add βˆ’5/2
4
2
=
25
4
Write as perfect square
4
37
π‘₯βˆ’2=±
π‘₯=
=
4
37
Square root
4
5± 37
Solution
2
2. Solve using the quadratic formula:
3x 2  9 x ο€½ ο€­2
3π‘₯ 2 + 9π‘₯ + 2 = 0
π‘Ž=3
π‘₯=
π‘₯=
Add 2
𝑏=9
;𝑏± 𝑏 2 ;4π‘Žπ‘
2π‘Ž
;9± 81;24
6
𝑐=2
=
=
;9± 92 ;4βˆ™3βˆ™2
Quadratic Formula
2βˆ™3
;9± 57
Solution
6
3. Solve the following problem. Approximate answers involving radicals to the
nearest hundredth.
A sidewalk of uniform width has area 180 ft2 and surrounds a flower bed that
is 11 ft wide and 13 ft long. Find the width of the sidewalk.
π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘†π‘–π‘‘π‘’π‘€π‘Žπ‘™π‘˜ = 2 π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π΅π‘œπ‘‘π‘‘π‘œπ‘š + 2 π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ 𝑆𝑖𝑑𝑒
w
13ο‚’
11ο‚’
Bottom
Side
𝐴 = 2 βˆ™ 11𝑀 + 2 βˆ™ 13 + 2𝑀 𝑀 = 180
Area of Sidewalk
22𝑀 + 26𝑀 + 4𝑀 2 = 180
4𝑀 2 + 48𝑀 βˆ’ 180 = 0
Standard Form
𝑀 2 + 12𝑀 βˆ’ 45 = 0
Simplify
𝑀=
;12± 122 ;4βˆ™1βˆ™ ;45
Quadratic Formula
2βˆ™1
𝑀=
;12± 144:180
𝑀=
;12±18
2
2
=
;12± 324
= βˆ’15, 3
𝑀 = 3 𝑓𝑑
2
Solution
Width cannot be negative
-2-
Quadratic Equations Quiz 1
Key
Name _________________________________________
Period _____ Date ________
Directions:
Read each question fully and carefully. Answer each question completely.
You must show your work. Each question is worth five (5) points.
1. Solve by completing the square:
x2 ο€­ 8x  3 ο€½ 0
π‘₯ 2 βˆ’ 8π‘₯ = βˆ’3
π‘₯ 2 βˆ’ 8π‘₯ + 16 = 13
π‘₯ βˆ’ 4 2 = 13
π‘₯ βˆ’ 4 = ± 13
π‘₯ = 4 ± 13
Subtract 3
Add βˆ’8/2 2 = 16
Write as perfect square
Square root
Solution
2. Solve using the quadratic formula:
3x 2  3x  1 ο€½ 0
π‘Ž=3
𝑏=3
π‘₯=
π‘₯=
;𝑏± 𝑏 2 ;4π‘Žπ‘
2π‘Ž
;3± 9;12
6
1
π‘₯ = βˆ’2 ±
3
6
=
=
𝑐=1
;3± 32 ;4βˆ™3βˆ™1
Quadratic Formula
2βˆ™3
;3± ;3
6
=
;3±π‘– 3
6
𝑖
Solution
3. Solve the following problem. Approximate answers involving radicals to the
nearest hundredth.
Find the dimensions of a rectangle whose perimeter is 42 cm and whose area
is 20 cm2.
h
w
π‘π‘’π‘Ÿπ‘–π‘šπ‘’π‘‘π‘’π‘Ÿ = 2𝑀 + 2β„Ž = 42 π‘π‘š
π‘Žπ‘Ÿπ‘’π‘Ž = 𝑀 βˆ™ β„Ž = 20 π‘π‘š2
β„Ž = 21 βˆ’ 𝑀
𝑀 21 βˆ’ 𝑀 = 20
21𝑀 βˆ’ 𝑀 2 = 20
𝑀 2 βˆ’ 21𝑀 + 20 = 0
π‘Ž=1
𝑏 = βˆ’21
𝑐 = 20
𝑀=
𝑀=
; ;21 ±
;21 2 ;4βˆ™1βˆ™20
2βˆ™1
solve perimeter equation for h
substitute into area equation
simplify
standard form
Quadratic Formula
21 ± 441 βˆ’ 80 21 ± 361 21 ± 19
=
=
2
2
2
Dimensions:
1.00 cm ο‚΄ 20.00 cm
-3-
Quadratic Equations Quiz 1
Key
Name _________________________________________
Period _____ Date ________
Directions:
Read each question fully and carefully. Answer each question completely.
You must show your work. Each question is worth five (5) points.
1. Solve by completing the square:
x2  5x ο€½ 3
25
π‘₯ 2 + 5π‘₯ +
5 2
π‘₯+2
=
5
37
Add 5/2
4
2
=
25
4
Write as perfect square
4
37
π‘₯+2=±
π‘₯=
=
4
37
Square root
4
;5± 37
Solution
2
2. Solve using the quadratic formula:
4 x 2 ο€­ 7 x ο€½ ο€­2
4π‘₯ 2 βˆ’ 7π‘₯ + 2 = 0
π‘Ž=4
π‘₯=
π‘₯=
Add 2
𝑏 = βˆ’7
;𝑏± 𝑏 2 ;4π‘Žπ‘
2π‘Ž
7± 49;32
8
=
=
𝑐=2
;7 2 ;4βˆ™4βˆ™2
7±
Quadratic Formula
2βˆ™4
7± 17
Solution
8
3. Solve the following problem. Approximate answers involving radicals to the
nearest hundredth.
A sidewalk of uniform width has area 352 ft2 and surrounds a flower bed that
is 17 ft wide and 19 ft long. Find the width of the sidewalk.
π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘†π‘–π‘‘π‘’π‘€π‘Žπ‘™π‘˜ = 2 π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π΅π‘œπ‘‘π‘‘π‘œπ‘š + 2 π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ 𝑆𝑖𝑑𝑒
w
19ο‚’
17ο‚’
Bottom
Side
𝐴 = 2 βˆ™ 17𝑀 + 2 βˆ™ 19 + 2𝑀 𝑀 = 352
Area of Sidewalk
34𝑀 + 38𝑀 + 4𝑀 2 = 352
4𝑀 2 + 72𝑀 βˆ’ 352 = 0
Standard Form
𝑀 2 + 18𝑀 βˆ’ 88 = 0
Simplify
𝑀=
;18± 182 ;4βˆ™1βˆ™ ;88
Quadratic Formula
2βˆ™1
𝑀=
;18± 324:352
𝑀=
;18±26
2
2
=
;18± 676
= βˆ’22, 4
𝑀 = 4 𝑓𝑑
2
Solution
Width cannot be negative
-4-