1. Sample Space and Probability Part V: Coun8ng‐2 ECE 302 Fall 2009 TR 3‐4:15pm Purdue University, School of ECE Prof. Ilya Pollak Par88ons • How many ways are there to divide n items into r groups so that the i‐th group has ni items (where n1 + n2 + … + nr = n)? • Example: if r = 2, the answer is € n ways of forming the first group n1 n − n1 objects remain n − n1 ways of forming the second group n 2 n − n 2 objects remain n n − n1 n − n1 −… − n r−1 Answer : ⋅…⋅ nr n1 n 2 n! (n − n1 )! (n − n1 −… − n r−1 )! = ⋅ ⋅…⋅ n1!(n − n1 )! n 2!(n − n1 − n 2 )! n r!(n − n − n r−1 1 −… r )! −n = 0!=1 = n! n1!n 2!…n r! n These are denoted and called multinomial coefficients. n1,n 2 ,…,n r The reason for this name is that n n n n ( x1 + x 2 + … + x r ) = ∑ n ,n ,…,n x1 1 x 2 2 ⋅…⋅ x rnr 1 2 r n1 +n 2 +…+n r = n Example (p. 68) • 90 students, including Joe and Jane, are to be split into 3 classes of equal size, at random. • What is the probability that Joe and Jane end up in the same class? Example • 90 students, including Joe and Jane, are to be split into 3 classes of equal size, at random. • What is the probability that Joe and Jane end up in the same class? Example • 90 students, including Joe and Jane, are to be split into 3 classes of equal size, at random. • What is the probability that Joe and Jane end up in the same class? Example • 90 students, including Joe and Jane, are to be split into 3 classes of equal size, at random. • What is the probability that Joe and Jane end up in the same class? A simpler method • Place Joe in one class. A simpler method • Place Joe in one class. • For Jane, there are 89 total possibili8es, of which 29 put her in the same class with Joe. A simpler method • Place Joe in one class. • For Jane, there are 89 total possibili8es, of which 29 put her in the same class with Joe. • Answer: 29/89.
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