ANSWER: 43.8 cm, 84 cm²
Chapter 11
Find the perimeter and area of each figure.
Round to the nearest tenth if necessary.
1. SOLUTION: The triangle shown is a 45-45-90 triangle, so the
height of the (assumed) parallelogram is 7 and the
length of the sides are
2. SOLUTION: Find the height of the triangle with the Pythagorean
theorem.
.
ANSWER: 43.8 cm, 84 cm²
2. Find the length of the long side of the triangle.
SOLUTION: Find the height of the triangle with the Pythagorean
theorem.
ANSWER: 45.8 in., 72 in.²
Find the length of the long side of the triangle.
Find the area of each trapezoid, rhombus, or
kite.
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ANSWER: ANSWER: Chapter
11
45.8 in., 72 in.²
Find the area of each trapezoid, rhombus, or
kite.
5. ANSWER: 195 in.²
7. SOLUTION: SOLUTION: ANSWER: 44 mm²
6. ANSWER: 190 cm²
Find the indicated measure. Round to the
nearest tenth.
10. The area of a circle is 201 square meters. Find the
radius.
SOLUTION: SOLUTION: Find the height. If you draw the height from the edge
of the bottom base to the top base, you form a right
triangle with side length 8 and hypotenuse 17.
ANSWER: 8m
11. Find the diameter of a circle with an area of 79
square feet.
SOLUTION: ANSWER: 195 in.²
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ANSWER: 10 ft
12. Page 2
ANSWER: Chapter
8 m 11
11. Find the diameter of a circle with an area of 79
square feet.
SOLUTION: ANSWER: 18.8 cm²
Find the area of each shaded sector. Round to
the nearest tenth if necessary.
13. SOLUTION: ANSWER: 10 ft
12. ANSWER: 288.3 in.²
Find the area of each regular polygon. Round to
the nearest tenth if necessary.
15. SOLUTION: ANSWER: 18.8 cm²
SOLUTION: The hexagon can be converted into 6 equilateral
triangles with sides of 14 mm. We can split one of
these triangles into a 30-60-90 right triangle to find
the apothem.
Find the area of each shaded sector. Round to
the nearest tenth if necessary.
13. The height of the triangle, and the length of the
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ANSWER: 288.3 in.²
apothem, is
Find the area.
.
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ANSWER: Chapter
288.311
in.²
ANSWER: 509.2 mm²
Find the area of each regular polygon. Round to
the nearest tenth if necessary.
15. SOLUTION: The hexagon can be converted into 6 equilateral
triangles with sides of 14 mm. We can split one of
these triangles into a 30-60-90 right triangle to find
the apothem.
The height of the triangle, and the length of the
apothem, is
Find the area.
.
ANSWER: 509.2 mm²
16. SOLUTION: The equilateral triangle can be split into two 30-60-90
triangles to find the height.
The height is
.
ANSWER: 110.9 ft²
17. SOLUTION: The pentagon can be split into 5 congruent triangles.
The height of one of these triangles is the apothem.
16. SOLUTION: The equilateral triangle can be split into two 30-60-90
triangles to find the height.
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Find the base of the triangle.
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ANSWER: Chapter
11
110.9 ft²
ANSWER: 85.6 m²
17. Find the area of each figure. Round to the
nearest tenth if necessary.
18. SOLUTION: The pentagon can be split into 5 congruent triangles.
The height of one of these triangles is the apothem.
SOLUTION: The area of the rectangle is 9(21) = 189
The area of the sector is one-fourth of the area of a
circle with radius 9.
The total area is about 189 + 63.6 = 252.6.
ANSWER: 252.6 cm²
For each pair of similar figures, use the given
areas to find the scale factor from the blue to
the green figure. Then find x.
22. Find the base of the triangle.
The base of the triangle = 2b = 12 cos 54. Now we
can find the perimeter, and then the area.
SOLUTION: ANSWER: 85.6 m²
Find the area of each figure. Round to the
nearest tenth if necessary.
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area of- Powered
the rectangle
is 9(21)
= 189
The area of the sector is one-fourth of the area of a
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23. The total area is about 189 + 63.6 = 252.6.
ANSWER: Chapter
252.611
cm²
For each pair of similar figures, use the given
areas to find the scale factor from the blue to
the green figure. Then find x.
22. ANSWER: 23. SOLUTION: SOLUTION: ANSWER: ANSWER: 23. SOLUTION: eSolutions Manual - Powered by Cognero
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