ECH-X (UT-120)
ECH-X (UT-120)
¶ß±Ó¬fl¡ ¬Û±Í¬Sê˜ ( B.D.P.)
ø˙鬱¬ı¯∏«±ôL ¬Û¬ı˛œé¬± ( Term End Examination )
øάÀ¸•§¬ı˛, 2013 › Ê≈√Ú, 2014
[’±] ø¬ıøSê˚˛±-Œfl¡Ã˙˘¸˝√√
(i)
ø¬ıøSê˚˛±&ø˘ÀÓ¬
Erythro-1-bromo-1,2diphenylpropane
‹ø26√fl¡ ¬Û±Í¬Sê˜ ( Elective )
√˙˜ ¬ÛS ( 10th Paper : Organic Chemistry-I )
¸˜˚˛ – ≈√˝◊√ ‚KI◊±¬
۔̫˜±Ú – 50
(ii)
9, 10 – phenanthraquinone
5
Full Marks : 50
[ ˜±ÀÚ¬ı˛ &èQ – 70% ]
[‡] [’]
Weightage of Marks : 70%
1,4-ά±˝◊√ ’…±ø˜ÀÚ±Ú…±¬ÛÔø˘Ú
ŒÔÀfl¡ fl¡œˆ¬±À¬ı
[’±] ø¬ıøSê˚˛±-Œfl¡Ã˙˘ ¸˝√√À˚±À· ÚœÀ‰¬¬ı˛ ø¬ıøSê˚˛±øȬÀÓ¬
ά◊»¬Ûiß ¬Û√±Ô« ˚¬Û√±Ô«&ø˘ ø˘‡≈Úº
EtO2 CCH2 CH2 CH2 CH2 CO2 Et
10 × 2 = 20
Œ˚-Œfl¡±ÀÚ± ≈íøȬ õ∂Àùü¬ı˛ ά◊M√¬ı˛ ø√Ú –
6
[fl¡] [’] ø¬ıøSê˚˛±-Œfl¡Ã˙˘¸˝√√ ÚœÀ‰¬¬ı˛ ø¬ıøSê˚˛±øȬÀÓ¬ Œ˚
Œ˚÷ ˚Œ˚÷&ø˘ ά◊»¬Ûiß ˝√√À¬ı Ó¬± ø˘‡≈Úº
¤¬ı— õ∂øÓ¬øȬ fl¡±¬ı«Ú˚’ø'ÀÊ√Ú-¤¬ı˛ ¸—fl¡¬ı˛Ì
ά◊À~‡ fl¡èÚ º
ø¬ıøSê˚˛±øȬ¬ı˛ ø¶öøÓ¬˙øMê√ Œ˘‡ø‰¬S ’ÇÚ fl¡èÚ ¤¬ı—
Œ˘‡ø‰¬SøȬ¬ı˛ Ó¬±»¬Û˚« ά◊À~‡ fl¡èÚº
¬ÛÀ¬ı˛¬ı˛ ¬Û‘ᬱ˚˛ ^©Ü¬ı…
4
!
NaOEt
[
+
[·] [’] øÚ•ßø˘ø‡Ó¬ Œ˚÷&ø˘¬ı˛ fl¡é¬fl¡ ø‰¬S ’ÇÚ fl¡èÚ
CHCl2 " CF3 # # ##$ ........
B.Sc-5754-Y
5
˙Ó¬±«¬ıø˘¸˝√√ ø¬ıøSê˚˛± Ò±¬Û&ø˘ ø˘‡≈Ú º
ø¬ıˆ¬±· - fl¡
!
+
’…±ÚÔ˱ø¸√Ú ¸—Àù≠¯∏Ì fl¡¬ı˛À¬ıÚ ∑ ø¬ıøSê˚˛fl¡ ¤¬ı—
¬Ûø¬ı˛ø˜Ó¬ › ˚Ô±˚Ô Î¬◊M√ À¬ı˛¬ı˛ Ê√Ú… ø¬ıÀ˙¯∏ ˜”˘… Œ√›˚˛± ˝√√À¬ıº
’qX ¬ı±Ú±Ú, ’¬Ûø¬ı˛26√ißÓ¬± ¤¬ı— ’¬Ûø¬ı˛©®±¬ı˛ ˝√√ô¶±é¬À¬ı˛¬ı˛ Œé¬ÀS Ú•§¬ı˛ Œfl¡ÀȬ
ŒÚ›˚˛± ˝√√À¬ıº ά◊¬Û±ÀôL õ∂Àùü¬ı˛ ˜”˘…˜±Ú ¸”ø‰¬Ó¬ ’±ÀÂ√º
1º
ÚœÀ‰¬¬ı˛
ά◊»¬Ûiß Œ˚÷&ø˘ ø˘‡≈Ú –
¬ı˛¸±˚˛Ú ( Chemistry )
Time : 2 hours
2
!
B.Sc-5754-Y
!
(i)
CH2 = CH " CH = C = O
(ii)
CH2 = CH " CH = CH2
3
ECH-X (UT-120)
[’±] øàø¬ı˛›ÀÊ√øÚfl¡ (stereogenic) Œfl¡f ¬ı˘ÀÓ¬
øfl¡ Œ¬ı±Á¡±˚˛ ∑ ¤fl¡±øÒfl¡ øàø¬ı˛›ÀÊ√øÚfl¡¡ Œfl¡f˚≈Mê√
Œ˚÷&ø˘ fl¡œ ¸¬ı«√±˝◊√ ’õ∂øÓ¬¸˜ ˝√√˚˛ ∑ ά◊¬Û˚≈Mê√
ά◊√±˝√√¬ı˛Ì¸˝√√ ¬ı…±‡…± fl¡èÚ º
[˝◊√] ά◊√±˝√√¬ı˛Ì¸˝√√ Œ¬ı˛ÀÊ√±Ú…±k ˙øMê√¬ı˛ ¸—:± ø√Ú º
¸±˝◊√Àflv¡±À˝√√ø'Ú-Œfl¡ ˝√√±˝◊√ÀE±ÀÊ√ÀÚ˙Ú fl¡¬ı˛À˘
"1
120 kJ.mol
Ó¬±¬Û˙øMê√ øÚ·«Ó¬ ˝√√˚˛ º
Œ¬ıÚøÊ√ÚÀfl¡
˝√√±˝◊√ÀE±ÀÊ√ÀÚ˙Ú
fl¡¬ı˛À˘
"1
208 kJ.mol
Ó¬±¬Û˙øMê√ øÚ·«Ó¬ ˝√√˚˛ º
!
Œ¬ıÚøÊ√ÀÚ¬ı˛ Œ¬ı˛ÀÊ√±Ú…±k ˙øMê√ ·ÌÚ± fl¡èÚº
3 +2 +5
!
[‚] [’√] ø˜Ô±˝◊√˘ ¸±˝◊√Àflv¡±À˝√√À'ÀÚ¬ı˛ Œ‰¬˚˛±¬ı˛ ¬ı˛+¬Û&ø˘
øÚά◊˜…±Ú ’øˆ¬Àé¬¬Û ¸—Àfl¡ÀÓ¬ ’ÇÚ fl¡èÚ ¤¬ı—
Ó¬±À√¬ı˛ ¶ö±ø˚˛ÀQ¬ı˛ Ó≈¬˘Ú± fl¡èÚº ˙øMê√ Œ˘‡ø‰¬ÀS¬ı˛
¸±˝√√±À˚… Œ‰¬˚˛±¬ı˛ › ŒÚÃfl¡± ’±fl‘¡øÓ¬ ¤¬ı— Œ‰¬˚˛±¬ı˛ ›
Œ˜±‰¬Î¬ˇ±ÀÚ± ŒÚÃfl¡± ¬ı˛+À¬Û¬ı˛ ˜ÀÒ… ˙øMê√ ¬Û±Ô«fl¡…
Œ√‡±Ú º
ECH-X (UT-120)
4
ø¬ıˆ¬±· - ‡¡
2º
6 × 3 = 18
Œ˚-Œfl¡±ÀÚ± øÓ¬ÚøȬ õ∂Àùü¬ı˛ ά◊M√¬ı˛ ø√Ú –
[fl¡] ∆Ê√¬ı Œ˚÷ ¸—Àù≠¯∏ÀÌ øÚ•ßø˘ø‡Ó¬ ø¬ıfl¡±¬ı˛fl¡&ø˘¬ı˛
2×3
¬ı…¬ı˝√√±¬ı˛ ά◊À~‡ fl¡èÚ –
[’] ¢∂œ·Ú±Î«¬ ø¬ıfl¡±¬ı˛fl¡
[’±] ›¸ø˜˚˛±˜ ŒÈ¬À¬∏C±'±˝◊√ά
[˝◊√] Œˆ¬Ê√± ˝◊√Ô±À¬ı˛ Œ¸±øά˚˛±˜ Ò±Ó≈¬
[‡] [’]
CH3CHOHCH = CH Br-¤¬ı˛
¸¬ıfl¡˚˛øȬ
¸y±¬ı… øS˜±øSfl¡ ¸˜±¬ı˚˛¬ı ’ÇÚ fl¡èÚ ¤¬ı—
¸˜±¬ı˚˛¬ı&ø˘¬ı˛ ø¬ıÚ…±¸
!
R/S
¤¬ı—
E/Z
øÚÀ«√˙
fl¡èÚº
[’±]
(+)-2-’±À˚˛±Àά±’À"√√Ú-¤¬ı˛
¸±ÀÔ ¬ÛȬ±ø¸˚˛±˜
’±À˚˛±Î¬±˝◊√ά-¤¬ı˛ ’…±ø¸ÀȬ±Ú ^±¬ıÀfl¡ õ∂dÓ¬
[’±] øSê˚˛±-Œfl¡Ã˙˘¸˝√√ øÚ•ßø˘ø‡Ó¬ ø¬ıøSê˚˛±øȬÀÓ¬
ά◊»¬Ûiß ¬Û√±Ô«-¤¬ı˛ Ú±˜ ά◊À~‡ fl¡èÚº
^¬ıÌøȬ ø˜ø|Ó¬ fl¡À¬ı˛ ø¬ıøSê˚˛± fl¡¬ı˛±ÀÚ± ˝√√˘º
^¬ıÌøȬ¬ı˛ ’±À˘±fl¡¸øSê˚˛Ó¬± Sê˜˙ fl¡˜ÀÓ¬ Ô±Àfl¡
¤¬ı— ’¬ıÀ˙À¯∏ ˙”Ú… ˝√√˚˛º — ¬Û˚«À¬ıé¬ÌøȬ ¬ı…±‡…±
6
B.Sc-5754-Y
+
fl¡èÚº
4
[¬ÛÀ¬ı˛¬ı˛ ¬Û‘ᬱ˚˛ ^©Ü¬ı…
B.Sc-5754-Y
4+2
ECH-X (UT-120)
[·] øÚ•ßø˘ø‡Ó¬ ¬Ûø¬ı˛¬ıÓ«¬Ú&ø˘ øfl¡ˆ¬±À¬ı ¸•Ûiß fl¡¬ı˛À¬ıÚ ∑
2×3
ECH-X (UT-120)
[‰¬] [’] ¸˜
2
’±Ìø¬ıfl¡
’Ú≈¬Û±ÀÓ¬¬ı˛
Ȭ˘≈˝◊√Ú,
Ú±˝◊√À¬∏C±À¬ıÚøÊ√ÀÚ¬ı˛ ø˜|ÌÀfl¡ ¸˜ ’±Ìø¬ıfl¡
[’] Œ¬ıÚøÊ√Ú "
"#
’Ú≈¬Û±ÀÓ¬¬ı˛ ’…±ø¸È¬±˝◊√˘ Œflv¡±¬ı˛±˝◊√ά › ’øÓ¬ø¬ı˛Mê√
¬Ûø¬ı˛˜±Ì ’Ú±^« ’…±˘≈ø˜øÚ˚˛±˜ Œflv¡±¬ı˛±˝◊√ά-¤¬ı˛
[’±]! ¬1,3-ø¬ıά◊Ȭ±Î¬±˝◊√Ú "
"#
ø˜|À̬ı˛ ¸±ÀÔ ø¬ıøSê˚˛± fl¡¬ı˛±ÀÚ± ˝√√˘º ø¬ıøSê˚˛±
[˝◊√] ¬’…±ø¸øȬø˘Ú "
"# ø¸¸ƒ-2-ø¬ıά◊øȬں
!
[‚] fl¡±¬ı˛Ì¸˝√√ øÚÀ‰¬¬ı˛ øÚÀ«√˙ ’Ú≈˚±˚˛œ ¸±Ê√±Ú –
2×3
[’] I"!, F " , Cl" , Br"
[Ê√˘œ˚˛
¬^¬ıÀÌ
øÚά◊øflv¡À˚˛±øÙ¬ø˘ø¸øȬ¬ı˛
S꘬ıÒ«˜±Ú
˜±Ú
’Ú≈˚±˚˛œ ]
! [’±] HO, C H O, CH " COO, (CH ) CO
2 5
3
33
[鬱¬ı˛œ˚˛ ÒÀ˜«¬ı˛ S꘬ıÒ«˜±Ú ˜±Ú ’Ú≈˚±˚˛œ ]
[˝◊√] ø¬ıøSê˚˛±Ê√±Ó¬ Œ˚÷&ø˘ ø˘‡≈Ú –
Œ˙À¯∏ ά◊Mê√ ø˜|ÀÌ Œfl¡±Úƒ Œfl¡±Úƒ Œ˚÷ øfl¡
’Ú≈¬Û±ÀÓ¬ Ô±fl¡À¬ı Ó¬± ø˘‡≈Úº ø¬ıøSê˚˛±-Œfl¡Ã˙˘¸˝√√
¬ı…±‡…± fl¡èÚº
[’±] øÚ•ßø˘ø‡Ó¬
¬ı˛+¬Û±ôL¬ı˛øȬ
øfl¡¬ı˛+À¬Û
¸•Û±√Ú
fl¡¬ı˛À¬ıÚ ∑
!
[˝◊√] øÚ•ßø˘ø‡Ó¬ fl¡±À¬ı«±fl¡…±È¬±˚˛ÚøȬ¬ı˛ fl¡…±ÀÚ±øÚfl¡…±˘
·Í¬Ú&ø˘ ’ÇÚ fl¡èÚ ¤¬ı— ¤À√¬ı˛ ˜ÀÒ…
Œfl¡±ÚƒøȬ¬ı˛ ’±À¬Ûøé¬fl¡ ’¬ı√±Ú ¸¬ı ŒÔÀfl¡ Œ¬ı˙œ
[„√√] øÚø«√©Ü ά◊√±˝√√¬ı˛Ì¸˝√√ øÚ•ßø˘ø‡Ó¬ ø¬ı¯∏˚˛&ø˘ ¸•§Àg Ȭœfl¡±
ø˘‡≈Ú –
[’] ¤©Ü±À¬ı˛¬ı˛ ’±^«ø¬ıÀù≠¯∏À̬ı˛ Œé¬ÀS A AL1 ø¬ıøSê˚˛±
Œfl¡Ã˙˘
[’±] ¬¬ı·±È«¬-fl≈¡fl¡ ¬ÛXøÓ¬ ¡Z±¬ı˛± øÙ¬Ú±ÚøÔËÚ ¸—Àù≠¯∏Ì º
!
3+3
B.Sc-5754-Y
[
¬ÛÀ¬ı˛¬ı˛ ¬Û‘ᬱ˚˛ ^©Ü¬ı…
fl¡±¬ı˛Ì¸˝√√ ø˘‡≈Úº
3+1+2
B.Sc-5754-Y
3
3º
ECH-X (UT-120)
ø¬ıˆ¬±· - ·¡
Œ˚-Œfl¡±ÀÚ± ‰¬±¬ı˛øȬ¬ õ∂Àùü¬ı˛ ά◊M√¬ı˛ ø√Ú –
3 × 4 = 12
[fl¡] ¬∏C±k-1,3-ά±˝◊√ø˜Ô±˝◊√˘ ¸±˝◊√Àflv¡±À˝√√À'Ú ’±À˘±fl¡ øÚø¶ç¡˚˛
— ø¬ı¯∏˚˛øȬ ¬ı…±‡…± fl¡èÚº
3
[‡] øÚ•ßø˘ø‡Ó¬ Œ˚÷&ø˘¬ı˛ ¬ IUPAC ÛXøÓ¬ÀÓ¬ Ú±˜fl¡¬ı˛Ì
fl¡èÚ –
3
[’] Cl " CH2 CHI CH (CH3).CH2 CH2 Br
[’±]
!
[˝◊√]
ECH-X (UT-120)
4
[„√√] øÚ•ßø˘ø‡Ó¬ Œ˚÷&ø˘¬ı˛ Œ¬ı˛ø¸ø˜fl¡ ø˜|ÌÀfl¡ fl¡œ
¬Û‘Ôfl¡œfl¡¬ı˛Ì fl¡¬ı˛± ˚±À¬ı ∑
11 ×2
2
[‰¬] [’¬] øÚ•ßø˘ø‡Ó¬ ŒÊ√±Àάˇ¬ı˛ Œ˚÷&ø˘¬ı˛ øÚÀ«√ø˙Ó¬ [*]
fl¡±¬ı«ÀÚ¬ı˛ Œfl¡±ÚƒøȬÀÓ¬ ˝◊√À˘fl¡¬∏C!Ú ‚ÚQ Œ¬ıø˙ ∑
¬ı…±‡…± fl¡èÚ º
[·] øÚ•ßø˘ø‡Ó¬ Œ˚÷&ø˘¬ı˛ fl¡±˝◊√¬ı˛±˘ fl¡±¬ı«Ú ¬Û¬ı˛˜±Ì≈&ø˘Àfl¡
R–/S – ¡Z±¬ı˛± ø‰¬ø˝êÓ¬ fl¡èÚ –
3
[‚] [ƒ’] ≈√øȬ ¬Û‘Ôfl¡ ’…±˘øfl¡Ú Œ˚÷Àfl¡ ¬Û‘Ôfl¡ˆ¬±À¬ı
S꘬Û˚±«À˚˛ ά±˝◊√À¬ı±À¬ı˛Ú › 鬱¬ı˛œ˚˛ ˝√√±˝◊√ÀE±ÀÊ√Ú
¬Û±¬ı˛’'±˝◊√ά ^¬ıÀ̬ı˛ ¸±ÀÔ ø¬ıøSê˚˛± ‚Ȭ±ÀÚ± ˝√√À˘
2-ø¬ıά◊Ȭ±Ú˘
ά◊»¬Ûiß ˝√√˚˛º ’…±˘øfl¡Ú
Œ˚÷&ø˘Àfl¡ ˙Ú±Mê√ fl¡èÚº ø¬ıøSê˚˛±&ø˘ ά◊À~‡
fl¡èÚº
[’±] øÚÀ•ß ¬ıøÌ«Ó¬ ø¬ıøSê˚˛±˚˛ ά◊»¬Ûiß Œ˚÷øȬ ø˘‡≈Ú º
[’±¬] øÚ•ßø˘ø‡Ó¬ Œ˚÷&ø˘Àfl¡ ¬ı˛±¸±˚˛øÚfl¡ ¬Û¬ı˛œé¬±¬ı˛
˜±Ò…À˜ ¬Û±Ô«fl¡… fl¡èÚ –
Œflv¡±À¬ı˛±À¬ıÚøÊ√Ú, ¸±˝◊√Àflv¡±À˝√√'±˝◊√˘ Œflv¡±¬ı˛±˝◊√άº
2+1
11 ×2
[Â√] øfl¡¬ı˛+À¬Û ¬ı˛+¬Û±ôL¬ı˛&ø˘ ‚Ȭ±À¬ıÚ ∑
2
˝◊√Ô±˝◊√˘ ø˜Ô±˝◊√˘ øfl¡ÀȬ±Ú
!
2+1
B.Sc-5754-Y
[¬ÛÀ¬ı˛¬ı˛ ¬Û‘ᬱ˚˛ ^©Ü¬ı…
B.Sc-5754-Y
ECH-X (UT-120)
ECH-X (UT-120)
( English Version )
(b)
Special credit will be given for precise and correct
answer. Marks will be deducted for spelling
mistakes, untidiness and illegible handwriting.
The figures in the margin indicate full marks.
EtO2 CCH2 CH2 CH2 CH2 CO2 Et
6+4
C)
1.
Answer any two questions :
A)
(a)
(a)
10 × 2 = 20
CHCl2 " CF3 # # ##$ .........
Draw the potential energy diagram for
!
point
out
the
characteristics of the curve.
(b)
Identify the product(s) with mechanism :
(i)
(a)
(i)
CH2 = CH " CH = C = O
(ii)
CH2 = CH " CH = CH2
always
9, 10 – phenanthraquinone
asymmetric
(c)
?
Explain
with
Define Resonance energy with example.
Heat of hydrogenation of cyclohexene is
120 kJ.mol
"1
"1
and that of benzene is
1,4-diaminonaphthalene ? Show the
208 kJ.mol
steps with reagents and conditions.
! of benzene.
energy
[
of
suitable examples.
How will you prepare anthracene from
B.Sc-5754-Y
state
! Are the compounds with such centres
Erythro-1-bromo-1,2-
5+5
B)
the
!
(b) What is meant by stereogenic centre ?
diphenylpropane
(ii)
indicating
hybridisation of each carbon/oxygen.
NaOEt
and
Draw the orbital picture of the following
compounds
Predict the product(s) with mechanism.
reaction
Identify the product(s) with mechanism:
!
Group-A
the
2
¬ÛÀ¬ı˛¬ı˛ ¬Û‘ᬱ˚˛ ^©Ü¬ı…
B.Sc-5754-Y
!
. Calculate the resonance
3+2+5
3
D)
(a)
ECH-X (UT-120)
Draw the chair conformations of methyl
cyclohexane
in
Newman
ECH-X (UT-120)
B)
(a)
possible
stereoisomers
and
of
designate
them as R/S/E/Z.
formula and compare their stabilities.
! (b)
(+)-2-Iodooctane is treated with KI in
the energy differences between chair
acetone solvent. The optical activity of
and
the solution
boat,
chair
and
twist
boat
will decline to zero.
Explain the observation.
conformations.
(b)
all
CH3CHOHCH = CH Br
projection
With the help of energy diagram show
Draw
4
Predict the product with mechanism :
C)
4+2
How would you carry out the following
transformations :
2×3
(a)
6+4
Group -B
2.
Answer any three questions :
A)
Write the uses of the following reagents in
(b)
6 × 3 = 18
(c)
.
the synthesis of organic compounds :
2×3
(i)
(ii)
D)
indicated below :
Grignard reagent
(a)
Osmium tetroxide
I" , F " , Cl" , Br"
order
(iii) Sodium metal in moist ether.
!
B.Sc-5754-Y
Arrange the following, with reasons, as
[¬ÛÀ¬ı˛¬ı˛ ¬Û‘ᬱ˚˛ ^©Ü¬ı…
of
solution )
B.Sc-5754-Y
(
in
the
nucleophilicity
increasing
in
aqueous
ECH-X (UT-120)
(b)
ECH-X (UT-120)
HO, C 2 H5 O, CH3 " COO, (CH3)3 CO ( in
2
(b)
Carry out the following transformation :
(c)
Write
the increasing order of basic character)
! (c)
Identify the products.
the
canonical
forms
of
the
following carbocation and indicate with
reason, the most contributing canonical
form :
2×3
E)
Write notes on the following with example :
(a)
3+1+2
A AL1 mechanism in case of hydrolysis
Group-C
of ester.
! (b)
Synthesis of Phenanthrene by BogertCook method.
F)
(a)
3+3
3.
Answer any four questions :
(A)
(B)
of
acetyl
presence
of
aluminium
chloride
chloride
excess
?
with
(b)
!
(c)
mechanism involved.
B.Sc-5754-Y
[
¬ÛÀ¬ı˛¬ı˛ ¬Û‘ᬱ˚˛ ^©Ü¬ı…
3
Give the IUPAC names of the following
(a)
in
anhydrous
Explain
is
compounds :
nitrobenzene is treated with equimolar
proportion
cyclohexane
optically inactive. — Explain.
What would be the product composition
if an equimolar mixture of toluene and
Trans-1,3-dimethyl
3 × 4 = 12
B.Sc-5754-Y
Cl " CH2 CHI CH (CH3).CH2 CH2 Br
3
3
(C)
ECH-X (UT-120)
Assign R–/S – descriptors for the chiral
centres in the following compounds :
ECH-X (UT-120)
(F)
4
(a) Which compound of the following
3
pair
will
have
higher
electron
density at the marked ( * ) carbon
atom ? Explain.
(D)
(a) Two
different
alkenes
produce
2-butanol when treated separately
with
diborane
followed
by
treatment with alkaline hydrogen
peroxide
solution.
Identify
(b) Distinguish between the following
the
alkenes. Write down the reactions
compounds
with
the
help
of
involved.
(b)
chemical reaction :
Identify the product :
Chlorobenzene, Cyclohexylchloride
Ethyl methyl ketone
2+1
2+1
(E)
Explain whether the following recemic
(G)
How would you convert ?
1
compounds would be resolvable :
!
11 × 2
2
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2
×2