First/Last Name Per- Algebra 2 – Parabola Extravaganza Worksheet

First/Last Name
Algebra 2 – Parabola Extravaganza Worksheet
Per-
1. Find the axis of symmetry for each parabola below.
a) vertex at V( 5, 16 )
b) zeros at 3 and 26
c) roots at −5 and 19
d) y = 2(x − 7)(x + 9)
2
e) y = 3x −10x + 7
2
f) y = 4(x − 2) + 6
2. If one root is 25 and the vertex is V( −3, 2 ), find the other root.
3. What is the y-coordinate of the vertex of a parabola with exactly one real root?
4. What is the y-coordinate of every root of every vertical parabola?
5. Consider the vertex of a parabola, it provides some important information.
The x-coordinate is the
The y-coordinate is the
2
6. Use the leading coefficients below to analyze the graph of y = ax + bx + c .
a=5
opens ( up / down )
more ( narrow / wide ) than standard
a = −3
opens ( up / down )
more ( narrow / wide ) than standard
a= 1
opens ( up / down )
more ( narrow / wide ) than standard
opens ( up / down )
more ( narrow / wide ) than standard
2
a = −4
3
sketch the parabola
7.
Given the following information,
place 3 points on the table of
values, then sketch the parabola.
the roots are −1 and 5
the vertex is (2, −3)
x
y
8.
Below you will find the table of values for three different quadratic equations.
Without actually graphing the quadratic equations, you should be able to inspect
each table and tell me about the roots and the axis of symmetry of the parabolas.
Determine the exact roots (if possible), or the range in which the roots occur.
x
1
2
3
4
5
y
9
0
−3
0
9
x
13
15
16
17
18
19
y
52
2
−4
−8
−4
2
root 1
root 2
axis of
symmetry
9. Given the quadratic equation: y = 3x
2
–18x + 24
a) Find the axis of symmetry.
b) Find the vertex.
c) Does the parabola open up or down?
d) Is there a maximum or a minimum value?
What is it?
e) Is this parabola more narrow or wide than its parent graph?
f)
Find the y-intercept.
g) Graph the quadratic equation, then find the roots.
x
y
x
20
23
25
27
38
y
−11
−34
−67
−67
4
1
10. Given the quadratic equation: y = – / 4 x
2
+ 5
a)
Find the axis of symmetry.
b)
Find the vertex.
c)
Does the parabola open up or down?
d)
Is there a maximum or a minimum value?
e)
Is this parabola more narrow or wide than its parent graph?
f)
Find the y-intercept.
g)
Graph the quadratic equation, then find the roots.
x
What is it?
y
11. Given the quadratic equation: y = 2(x–3)(x+1)
a)
Find the axis of symmetry.
b)
Find the vertex.
c)
Does the parabola open up or down?
d)
Is there a maximum or a minimum value?
e)
Is this parabola more narrow or wide than its parent graph?
f)
Find the y-intercept.
g)
Graph the quadratic equation, then find the roots.
x
y
What is it?
12. Given the quadratic equation: y =
½ (x+4) 2 – 3
a)
Find the axis of symmetry.
b)
Find the vertex.
c)
Does the parabola open up or down?
d)
Is there a maximum or a minimum value?
e)
Is this parabola more narrow or wide than its parent graph?
f)
Find the y-intercept.
g)
Graph the quadratic equation, then find the roots.
x
What is it?
y
y = 2x 2 – 7x – 15
13.
Find the vertex of the quadratic equation:
14.
Consider the quadratic formula. When you find the discriminant, D= b – 4ac
it tells you about the nature of the roots of the quadratic equation.
2
If the discriminant is positive, there are
real roots.
If the discriminant is zero, there are
real roots.
If the discriminant is negative, there are
real roots.
How can you tell if the real roots are rational or irrational?
15.
2
16.
2
Use the discriminant
to determine the
nature of the roots of the
quadratic equations below.
D= b – 4ac
2
Do not find the actual roots.
Find the number of real roots.
If the roots are real, determine
if they are rational or irrational.
2
2
y = 3x + 6x + 3
y = 5x − 5x + 2
y = 5x + 4x − 3
y = 5x + 5x − 10
D=
D=
D=
D=
# of real roots
# of real roots
# of real roots
# of real roots
rational or irrational
rational or irrational
rational or irrational
rational or irrational
Match the graphs below with the possible discriminant (D) value.
D = 81
A
B
C
D = −4
D=0
D = 18
17.
Use the Quadratic Formula to solve the quadratic equations.
2
0 = 2x + 9x − 5
2
0 = x + 3x + 7
2
0 = x + 3x − 9
x=
−b ± b2 − 4ac
2a
2
0 = x + 2x + 1